Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 20901. |
Which term of the AP 24 ,21 ,18,15.....is the first negative twrm ? |
|
Answer» Ops !it is 10the term and 10th term is-3 10 th term -3 |
|
| 20902. |
How do we find average of 2 given average |
| Answer» | |
| 20903. |
Cos2 67-sin2 23 what is the value |
|
Answer» Cos2(90 -23)-sin2 23Sin2 23- sin2 23=0Using identity cos(90-any angle)=sin any angle It will be 0 0 |
|
| 20904. |
Kisi ko exam pata h |
| Answer» Kiska | |
| 20905. |
Given triangleABC _ triangle pqr if ab-pq=1|3 then find ar ∆abc|ar∆pqr |
| Answer» 1/9 | |
| 20906. |
Preparation ho gai ky sbki????? |
|
Answer» Or tumhari Hmm meri toh almost ho gai h... Tumhari ho gai paper kaise gaye tumhare |
|
| 20907. |
(b-c)X2 +(c-a)X +(a-b)=0 |
| Answer» | |
| 20908. |
Express sin A in terms of cot A |
| Answer» | |
| 20909. |
Given triangle ABC or triangle PQR of AB/PQ=1/3 then find arABC/arPQR |
| Answer» No | |
| 20910. |
LCM×HCF=product of two nombers |
| Answer» | |
| 20911. |
If triangle ABC~ triangle RPQ,AB=3,BC=5,AC=6,RP=6 and find PQ =10 then find QR. |
| Answer» QR = 12 | |
| 20912. |
If x=3 is one root of the quadratic of x x -2k -6=0 then find the value of k |
| Answer» Given quadratic equation is x2 - 2kx - 6 = 0If x = 3 is one root of the equation,then (3)2 - 2k(3) - 6 = 0{tex}\\therefore{/tex}\xa09 - 6k - 6 = 0{tex}\\Rightarrow{/tex}-6k = -3{tex}\\Rightarrow{/tex}\xa0k =\xa0{tex}\\frac{1}{2}{/tex} | |
| 20913. |
In an AP the common difference (d) and seventh term is 4 then find first term |
| Answer» A = -20 | |
| 20914. |
If sin (A-B)=1/2 and sin (A+B)=1 ,then find the value of A&B |
| Answer» A =60°, B = 30° | |
| 20915. |
If x-3 is one of the root of the equation of x2+2kx-6 then find the value of k |
| Answer» K=1/2x-3=0X=3 | |
| 20916. |
What is the formula of minor segment, major segment, sectors, major sector, minor sector |
| Answer» | |
| 20917. |
HCF and LCM of 404 and 96 and verify that HCF ×LCM =product of two no |
| Answer» Prime factorisation of 404 and 96 is:404 = 2\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa0101404 = 22\xa0{tex}\\times{/tex}\xa010196 = 2\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa0396 = 25\xa0{tex}\\times{/tex}\xa03{tex}\\therefore{/tex}\xa0HCF(404,96 )= 22 = 4LCM(404, 96 ) = 101\xa0{tex}\\times{/tex}\xa025\xa0{tex}\\times{/tex}\xa03LCM( 404, 96) = 9696now we have to verify that,HCF(404, 96)\xa0{tex}\\times{/tex}LCM(404, 96) = 404{tex}\\times{/tex}96Hence,LHS = HCF\xa0{tex}\\times{/tex}\xa0LCM= 4\xa0{tex}\\times{/tex}\xa09696 = 38784\xa0RHS= Product of numbers =404\xa0{tex}\\times{/tex}\xa096 = 38784Since, LHS=RHSi.e. HCF\xa0{tex}\\times{/tex}\xa0LCM = Product of 404 and 96.hence verified | |
| 20918. |
Given √2 is irrational number prove (5+3√3)is an irrational number |
| Answer» | |
| 20919. |
HCF and LCM of 404 and 96 and verify that HCF ×LCM = product of two no. |
| Answer» Prime factorisation of 404 and 96 is:404 = 2\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa0101404 = 22\xa0{tex}\\times{/tex}\xa010196 = 2\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa0396 = 25\xa0{tex}\\times{/tex}\xa03{tex}\\therefore{/tex}\xa0HCF(404,96 )= 22 = 4LCM(404, 96 ) = 101\xa0{tex}\\times{/tex}\xa025\xa0{tex}\\times{/tex}\xa03LCM( 404, 96) = 9696now we have to verify that,HCF(404, 96)\xa0{tex}\\times{/tex}LCM(404, 96) = 404{tex}\\times{/tex}96Hence,LHS = HCF\xa0{tex}\\times{/tex}\xa0LCM = 4\xa0{tex}\\times{/tex}\xa09696 = 38784\xa0RHS= Product of numbers =404\xa0{tex}\\times{/tex}\xa096 = 38784Since, LHS=RHSi.e. HCF\xa0{tex}\\times{/tex}\xa0LCM = Product of 404 and 96.hence verified | |
| 20920. |
If x=3 is one root of the quadratib of x2-2kx-6=0 |
| Answer» 1/2 | |
| 20921. |
Find the sum of first 8 multiple of x |
|
Answer» Sn= (8/2)(2x+(8-1)x)=4(9x)= 36x Sorry it\'s wrong Sn = (8/2)(2x + 7*8)=8(x+28) |
|
| 20922. |
This time for class 10th result will come in cgpa or percentage or grading system |
|
Answer» % Percentage Percentage |
|
| 20923. |
If areas of two similar triangles are equal than prove that they are congruent |
|
Answer» If area is equal then the square of ratios of similar part will be equal to one and hence all similar parts will be equal and bySSS congruency ....they will be congruent Kya question pucha h whaaa |
|
| 20924. |
guys plss help krdo btado yrr answers plss...i will be so thankful to u |
| Answer» | |
| 20925. |
In an ap the common difference is D and 7 term (a7)154,then find the first term |
|
Answer» a=-770 First term is 22? |
|
| 20926. |
Prove that the tangent at the extermities of any chord make equal angles with the chord |
| Answer» \xa0Let AB be a chord of a circle with centre O, and let AP and BP be the tangents at A and B respectively. Let the two tangents AP and BP meets at P.\xa0Now Join OP. Suppose OP meets AB at C and the chord AB=AC+BC.We have to prove that\xa0{tex}\\angle P A C = \\angle P B C{/tex}In two triangles PCA and PCB, we havePA = PB\xa0[{tex} \\because{/tex}Tangents from an external point are equal]{tex}\\angle A P C = \\angle B P C{/tex}\xa0[{tex} \\because {/tex}\xa0PA and\xa0PB are equally inclined to OP]and, PC = PC [Common]So, by SAS-criterion of congruence, we obtain{tex}\\Delta P A C \\cong \\Delta P B C{/tex}{tex}\\Rightarrow \\quad \\angle P A C = \\angle P B C{/tex} | |
| 20927. |
Kuchh important question batau dosto |
|
Answer» Ha thanks k ki value find krne wala 4 chapter se aur surface area and volume se questions 7,8,9of exercise 13.3 |
|
| 20928. |
Best of luck to all of you for maths exam I wish you all do well |
|
Answer» Thanks and same 2 u Thnk n same to you... Same to you dear....???? Haa shayad apki dua hii kaam krr jae thnk uu for wishing??? |
|
| 20929. |
What is hcf of smallest prime number and smallest composite number |
| Answer» | |
| 20930. |
If the area of two similar triangles are equal prove that they are congruent |
|
Answer» Hope i was able to make you understand.... You can do so by equating the ratio of the two triangles with the square of the ratios of the two corresponding sides. From there you can find that those sides will come out ti be equal as the areas of two triangles were equal so they will cancel out each other. Likewise you can prove for other sides too. Then, by using the sss criterion of congruence, you can prove them congruent Yes |
|
| 20931. |
Cos2 67-sin2 23 |
|
Answer» 0 0 |
|
| 20932. |
Best of luck All of you |
|
Answer» Thanks Same to you and thank you Same to you Thanks Thnkuu soo vala much?? |
|
| 20933. |
What is the value of cos square 67°-sin square23° |
| Answer» cos2 67° -\xa0sin2 23°= cos2\xa067°\xa0- sin2\xa0(90°- 67°)= cos2\xa067° - cos2\xa067° [since, sin(90o-a) = cos a]= 0 | |
| 20934. |
Find distance of point p(x,y) from origin |
| Answer» √x^2 + y^2 | |
| 20935. |
2morrow....maths? |
|
Answer» And all the best for tomorrow ? Maths exam is not to be done by being tensed Be tension free and do ur best tomorrow ok So much tensed O I\'m not bro.......I\'m girl? Yeah bro R u tensed ? |
|
| 20936. |
Of A(5,2)B(2,-2)andC(2,x)with angle B=90degre then find the valu of x |
|
Answer» Sankalp Kumar par ans 1 h X = 2 Use area of a triangle formula...u may get d ans Corrdinate geometry Which lesson |
|
| 20937. |
Find distance of P(x,y) from origin |
| Answer» PO=root x²+y² | |
| 20938. |
How is the board math paper |
|
Answer» It would be very tough I am ????joking IT MUST BE SIMPLE Pata kya....??? |
|
| 20939. |
o ritik you didn\'t answered |
|
Answer» Thnxxx i hope it would be yr tooo best exam. Nothing I got that now bye bye and wish your 2moro\'s ppr will be your best ppr ever What m???? |
|
| 20940. |
Guys exam is today it\'s 28 the march nowR u excited or tensed or relaxed or enjoying ? |
|
Answer» Yeah Ooo really ! I am feeling like ki mughe " 1 year baad kesse jail se nikala ja raha hai...."????? Same here Aisha Ok good night ritik Exited Both relaxed and enjoying but now going to sleep |
|
| 20941. |
Friends kal Sham ko btana ki paper kaisa gaya hai math ka |
|
Answer» Evening 5 pm Yeah Which time in evening ? It aaj sham it is already 12..08 Time?? |
|
| 20942. |
explain why( 17 *5* 11* 3*2 + 2*11)is a composite number |
|
Answer» Can be factorised as product of primes, 2*11*(...) Take 2 common outside and solve it later u will find find 2 factors which shows it is composite |
|
| 20943. |
Okk Guys☺??ALL THE BEST ????If any confusion.. u can ask... GOOD LUCK FOR EXAM |
|
Answer» Thanks and Same to you too?? Thanks ?? 2 ........u too best of luck Thanks..... at last tomorrow.....last exam. Thnx alll Thanx and same 2 u Good night Thanks Same 2 u.. ☺☺ |
|
| 20944. |
3 + root2 is irrational if root 2 is irrational given |
|
Answer» Let us assume that 3+root2 is rational.i.e 3+root2=p/q(p and q are rational no.)Now, 3+root2=p/q root2=(p-3q)/q Since,(p-3q)/q are rational no.Therefore root2 is also rational no. which is contradictory as we know root2 is irrational.Therefore,3+root2 is irrational. Proved.... Explain plz Yes |
|
| 20945. |
All the best guys...........For mathematics exam luv uh...? |
|
Answer» All the best ? Best of luck ☺️ Thanks and Same to you too? |
|
| 20946. |
Important for exam questions |
|
Answer» Hmm Abb kya keroge important jaan ker.. Exam bus start he hone wala hai... ? ? |
|
| 20947. |
Find thé distance of point p(x,y) from thé origin |
| Answer» Under root x²+y² | |
| 20948. |
How to adjust the class interval when class mark is not the same |
| Answer» | |
| 20949. |
ohhohhh maths ?? |
| Answer» | |
| 20950. |
How to do maths paper |
|
Answer» khushbu rehenedo in jese logo pr apna dhayan mt do sun gao ke gamar ye app tere pitaji ne nhi bnaya What the hell u wrote OK muY son Answers By writing... |
|