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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 21351. |
Find the value of \'a\' and \'b\' so that 8x^4+14x^3-2x^2+ax+b is exactly divisible by 4x^2+3x-2. |
| Answer» a=-7 and b=2 | |
| 21352. |
What is the section formula |
| Answer» the coordinates of the point P(x, y) which divides the line segment joining the points A(x1, y1) and B(x2, y2), internally, in the ratio m1 : m2 are { (m1x2 + m2x1)/(m1 + m2 ) , (m1y2 + m2y1)/(m1 + m2 ) } .This is known as the section formula.Refer ExamFear video lessons for ProofThe mid-point of the line segment joining the points P(x1, y1) and Q(x2, y2) is [(x1+x2)/2 ,(y1+y2)/2] | |
| 21353. |
If sin thita =cos thita what is the value of thita |
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Answer» Value of thita=45 The only value of theta is 45. If theta 45 then sin theta = cos theta. 45 |
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| 21354. |
If cotA=12/5,then find value of(sinA+CosA)×CosecA is: |
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Answer» Cos tita =sin tita=1So clearly tita =45 17/5 |
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| 21355. |
2+2+4-5-2 |
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Answer» 2 + 2 + 4 - 5 - 2= 4 + 4 - 5 - 2= 8 - 5 - 2= 3 - 2= 1 +1 +1 |
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| 21356. |
Find a distance of point (x,y) from origin. |
| Answer» _/x^2+y^2 | |
| 21357. |
If the mth term of A.p is n and the nth term of A.P is m find the (mn)th term? |
| Answer» | |
| 21358. |
P is a prime number p is an.......... Number |
| Answer» It can only be divided by own or 1..... | |
| 21359. |
The median of the following data is 35 find X |
| Answer» The question is incomplete. The answer is with respect to the given question:Q.If the median of the data is 35, find x in the data given below ,if 45 is changed to 33,find the new median.24,27,28,31,34,x,37,40,42,45Given observations are\xa024,27,28,31,34,x,37,40,42,45Median of the given data = (34 + x)/2 [Since there are even number of observations]Given median = 45Hence, (34 + x)/2 = 4534 + x = 90x = 90 - 34 = 56 | |
| 21360. |
If sec theta +tan theta is equal to p then find the value of cosec theta |
| Answer» | |
| 21361. |
The mth term of A.p is n and the nth term of A.p is m. Then find the rth term of A.p? |
| Answer» a | |
| 21362. |
How can. Make trigonometry identities easier for class 10th.......... |
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Answer» Try to read the ncert theory and solve the questions more and more times that u see hard that may help u Nothing is easier our thinking makes it os |
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| 21363. |
What is difference between binary fisson and multiple fisson? |
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Answer» Binarry fission occurs in amoeba and multiple fission occurs in Plasmodium. In bin fi. 1 divides into 2 but in mf 1 divides into many |
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| 21364. |
How can i find median class |
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Answer» By formula L+[n/2-cf÷f]h By formula |
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| 21365. |
Solve for x and y ax+by=a+b/23x+5y=4 |
| Answer» 1/2=x=y | |
| 21366. |
SinA/CotA+CosecA=SinA/CotA-CosecA +2 |
| Answer» Bhai ye ques. khaa se liya h | |
| 21367. |
∆ABC is right angled at B and D is the mid point of BC.prove that AC square =4AD square -3AB square |
| Answer» | |
| 21368. |
Find the value of p, for which one root of quadratic equation PX2-14X+8=0is 6 times the other |
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Answer» P=+-3 Given\xa0px2-14x+8=0let a and b be the roots of the equationb=6asum of roots = -b/aproduct of roots = c/ahere a=p , b=-14 , c=8a+b=14/pab=8/pa+6a=14/p7a=14/pa=2/pa*6a=8/p6a2=8/p3a2=4/p3*(2/p)2=4/p3*4/p2=4/pp=3 |
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| 21369. |
Prove the theorem of alternate segment |
| Answer» Alternate Segment:If a chord is drawn through the point of contact of a tangent to a circle, then the angles which this chord makes with the given tangent are equal respectively to the angles formed in the corresponding alternate segments.Given : is the tangent to the circle with centre O. AB is the chord drawn at the point of contact A.C and D are two points on the circumference such that they lie on either side of the chord.To Prove: (i) and (ii) Construction: Draw the diameter AOE and draw EB.Proof: In the figure, (radius is perpendicular to the tangent at the point of contact) (1)In DEAB (Angle in a semi-circle) (2)From (1) and (2)But, (Angles in the same segment)Now, consider cyclic quadrilateral ACBD. (Opposite angles) .(4)And (Linear pair)But (5)From (4) and (5)Hence proved. | |
| 21370. |
If an=5-11n, then find the middle term |
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Answer» n is not given so we can\'t say Dash dash dash |
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| 21371. |
1/sec a+tana-1/cosa =1/cosa-1/seca-tana |
| Answer» | |
| 21372. |
If 4 sinA =3 find the value of x if underoot cosec2A -cot2A/sec2A-1 2cot A=underoot 7/x+cos A |
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Answer» 2cotA is in multiplication Sec2A-1 is joint or joint or not |
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| 21373. |
CosA_SinA+1CosA+SinA_1=CosecA + CotA |
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Answer» Yes I think iam right In book ch 8 nd ex is 8 .5 q 5 |
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| 21374. |
If the mth termof an AP is 1/n and nth term is 1/m then show that its (mn)th term is 1 |
| Answer» | |
| 21375. |
The 17th term of an AP exceeds its 10th term by 7.Find the common difference |
| Answer» 1 | |
| 21376. |
0/0=? |
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Answer» ???? =0????? 0 |
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| 21377. |
2÷2= |
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Answer» 1?? 1 |
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| 21378. |
1/a+1/b+1/x=1/a+b+x |
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Answer» Take LCM and cross multiple X= -a, -b |
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| 21379. |
The circumference of a circle exceeds its diameter by 16.8 CM find the circumference of the circle |
| Answer» 24.64cm | |
| 21380. |
9m,9m+1or9m+8 |
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Answer» See example of ncert maths chapter 1 and link to the question Complete yur question plz....... U wanna proof cube Please type the ryt question ???? |
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| 21381. |
Find the sum of "n" term of the series :[4 - 1/n] + [4 - 2/n] + [4 - 3/n] + ............... |
| Answer» this is an APa=4-1/n ,d=-1/nso Sn=n/2{ 2(4-1/n) +(n-1)(-1/n)}=n/2 x (8-2/n-1+1/n)=n/2 x(7-1/n)=n/2 x (7n-1)/n=(7n-1)/2 | |
| 21382. |
Solve for x X upon X+1 whole square - 5x upon x+1 = -6 |
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| 21383. |
If thr point (x,y) be the equidistant from the points A(a+b, b-a) nd B(a-b,a+b) ,provr that bx-ay=0 |
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| 21384. |
In maths how many marks we get by the ncert book |
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Answer» if it is perfect then 90% 8o % 70% is from ncert and easy 80 marks 80 |
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| 21385. |
Find the nature root of the qudratic equation. (x-2)* -2(x+1)=0* is Square |
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| 21386. |
Formula\'s of chapter trigonometry class 10 |
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Answer» all formulas are mention in the book Ncert book mae hai sab kuch |
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| 21387. |
prove that : SinA/secA+ tan A -1 + cosA / cosecA+cotA--1 =1 |
| Answer» | |
| 21388. |
Tell all the formals of all chapters of math ncert |
| Answer» Open your ncert book | |
| 21389. |
SinA+cosA=square root 2 cosA. Prove that 3sinA=2 |
| Answer» | |
| 21390. |
Find the probability of getting 53 Friday\'s in a leap year |
| Answer» 2/7 | |
| 21391. |
Show that an even integer is of the form of 6q or 6q+ 2 or 6q+4.where q is a positive integers |
| Answer» Let p be any positive integerBy division algorithm, p = 6q + r, where 0 {tex} \\leqslant {/tex}r< 6Here r=0,1,2,3,4,5Therefore,values of p are : 6q, 6q + 1, 6q + 2, 6q + 3, 6q + 4, 6q + 5Now 6q+1,6q+3 and 6q+5 are odd numbers because q is a positive integer.Hence 6q, 6q + 2, 6q + 4 are even integers because they are next positive number to the odd numbers 6q-1,6q+1 and 6q+3 respectively\xa0 | |
| 21392. |
If the roots of the quardiatic eq. p(q-r)x2+q(r-p)x+r(p-q)=0 are equal,show that 1/p+1/r=2/q |
| Answer» pls answer yaae | |
| 21393. |
fin the value of the expression (CosecA -sinA) (secA-cosA)(tanA+cotA) |
| Answer» To prove:(cosecA - sinA) (secA - cosA) (tanA + cotA) = 1LHS\xa0{tex}= (\\cos ecA - \\sin A)(\\sec A - \\cos A)(\\tan A + \\cot A){/tex}{tex} = \\left( {\\frac{1}{{\\sin A}} - \\sin A} \\right)\\left( {\\frac{1}{{\\cos A}} - \\cos A} \\right)\\left( {\\frac{{\\sin A}}{{\\cos A}} + \\frac{{\\cos A}}{{\\sin A}}} \\right){/tex}\xa0{tex}\\left[ \\begin{gathered} \\because \\cos ecA = \\frac{1}{{\\sin A}},\\sec A = \\frac{1}{{\\cos A}}, \\hfill \\\\ \\tan A = \\frac{{\\sin A}}{{\\cos A}},\\cot A = \\frac{{\\cos A}}{{\\sin A}} \\hfill \\\\ \\end{gathered} \\right]{/tex}{tex} = \\left( {\\frac{{1 - {{\\sin }^2}A}}{{\\sin A}}} \\right)\\left( {\\frac{{1 - {{\\cos }^2}A}}{{\\cos A}}} \\right)\\left( {\\frac{{{{\\sin }^2}A + {{\\cos }^2}A}}{{\\cos A\\sin A}}} \\right){/tex}{tex} = \\frac{{{{\\cos }^2}A}}{{\\sin A}} \\times \\frac{{{{\\sin }^2}A}}{{\\cos A}} \\times \\frac{1}{{\\cos A\\sin A}}{/tex}\xa0{tex}\\left[ \\begin{gathered} \\because 1 - {\\sin ^2}A = {\\cos ^2}A,1 - {\\cos ^2}A = {\\sin ^2}A, \\hfill \\\\ {\\sin ^2}A + {\\cos ^2}A = 1 \\hfill \\\\ \\end{gathered} \\right]{/tex}{tex} = \\frac{{\\cos A \\times \\cos A}}{{\\sin A}} \\times \\frac{{\\sin A \\times \\sin A}}{{\\cos A}} \\times \\frac{1}{{\\cos A\\sin A}}{/tex}= 1= RHS | |
| 21394. |
What is the mean of 1st ten prime numbers? |
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Answer» 1.29 is answer 2 is also the answer.how? 2,3,5,7,11,13,17,19,23, 29..?? |
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| 21395. |
If the point P(x,y) is equidistant from the points Q(a+b,b-a) and R(a-b,a+b).Then prove that bx=ay |
| Answer» How to add image | |
| 21396. |
Which term of the AP 3,8,13,18,........,is 73? |
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Answer» 15 Its 15th trm. Apply the formula An=A+(n-1)D 15 |
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| 21397. |
If 1/a+b+x =a+b+x/abx. Then find the value of x.please answer the question.????????????????? |
| Answer» | |
| 21398. |
Please explain BPT THOEREM |
| Answer» Theorm : In a right triangle, the sq. Of the hyp. is equal to the sum of the sq. Of the other two sides.Proof : In a right ∆ ABC right angled at B.Prove : AC ka 2 = AB ka 2 + BC ka 2 BD is parrallel to AC∆ADB ~ ∆ ABC AD/AB = AB/AC ( side are propotional)AD.AC = AB ka 2∆BDC ~∆ABCCD/BC =BC / ACCD. AC = BC ka 2 AD.AC. + CD.AC = AB ka 2 + BC ka 2AC (AD + CD) = AB ka 2 + BC ka 2AC.AC. = AB ka 2 + BC ka 2AC ka 2 = AB ka 2 + BC ka 2 | |
| 21399. |
Root 5 is a irrational number |
| Answer» Let root 5 be a rational numberThen, √5= a/b Now by squaring both sides 5= a²/b²= 5b² = a²............(1)Here 5 divides a²,Therefore 5 also divides a.Now let a= 5c where c is an integerNow by squaring both side, = A²= 25c² = 5b² = 25c². ( A²= 5b² from above) = B² = 5c²Here 5 divides b squareTherefore 5 also divides b.Here a and b both have common factor 5So our assumption was wrongTherefore root 5 is an irrational number | |
| 21400. |
A,B,C are interior angles of ∆ABC . Prove that cosec(A+B/2) = sec C/2. |
| Answer» cosec(A+B)/2= cosec(180-C)/2. [since A+B+C=180]= cosec (180/2 - C/2)= cosec (90 - C/2)= sec C/2 | |