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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 21501. |
if Cosec A - cot A = 1/3 then find the value of cosec A + cot A. |
| Answer» 3....... | |
| 21502. |
Cosec A - cot A = 1/3 then find the value of cosec A + cot A . |
| Answer» 3....... | |
| 21503. |
How we get all the zeros if we given only one of them |
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Answer» I use second time negative is by wronhg typing The correction is positive When one zero is given negative ,other zero is negative ,ex-√x ,-√x When use methode to find other two zero (a-√x),(a+√x) |
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| 21504. |
If sinA + cosA =√2 find the value of tanA + cotA |
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Answer» How?? 2....... |
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| 21505. |
Root 2 ka value |
| Answer» 1.414 | |
| 21506. |
In an equilateral triangle ABC, AD is perpendicular to BC, prove that AD²=3BD² |
| Answer» According to the question,\xa0{tex}\\triangle ABC {/tex}\xa0is an equilateral triangle.In {tex}\\triangle{/tex}ABD, using Pythagoras theorem,{tex}\\Rightarrow{/tex} AB2 = AD2 + BD2{tex}\\Rightarrow{/tex} BC2 = AD2 + BD2, (as AB = BC = CA){tex}\\Rightarrow{/tex} (2 BD)2 = AD2 + BD2, (perpendicular is the median in an equilateral triangle){tex}\\Rightarrow{/tex} 4BD2 - BD2 = AD2{tex}\\therefore{/tex}\xa03BD2 = AD2 | |
| 21507. |
Pythagoras ki puchna |
| Answer» Pythagoras ask that Python is great or dinosaurus | |
| 21508. |
Prove that _/5 is irrational number |
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Answer» It is clearly given there...hope yu can understand Bohat bada hai....itna kese likhu? Aap ncert me dekh lo No tell me?????????? See frm ncert |
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| 21509. |
if m=pcos^3A +3pcos^2 A×sinA,n=3psin^3A+psin^2A×cosA. prove that (m+n)^(2÷3)+(m-n)^(2÷3)=2p^(2÷3) |
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| 21510. |
X+1/x-1+x-2/x+2=4-2x+3/x-2 solve for x |
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| 21511. |
find a quadratic polynomial whose sum and product of zeros are respectively 3 and 2 |
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Answer» Put formulax2-(sum of zero)x+(product of zero)and now put the values =x2-3x+2 x to the power square... x2 - 3x +2 |
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| 21512. |
(1+cosA+sinA)/1+cosA-sinA = 1+sinA/cosA |
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Answer» Divide each term by sin A. find a quadratic polynomial whose sum and product of zeros are respectively 3and2 |
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| 21513. |
Chapter triangle se kitne marks k question aate h or kitne question aate hai?? |
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Answer» chapter 11,6,10 me se 15 marks ke question aate hai Triangle se do theorem must important h 1) Pythagoras and 2) thales Ayush tmne bhai kisko kahaa? 8 mark ka ayega triangle chapter aur ek question 4 marks ka ayega aur baki 4 marks,1,2 marks ke questions cover karege Bhai sunn |
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| 21514. |
How root 4+root 9 is rational |
| Answer» √4+√9=2+3=5. Rational number | |
| 21515. |
Proof of converse of BPT theorum |
| Answer» Converse of Basic Proportionality TheoremStatement If a line divides any two sides of a triangle (Δ) in the same ratio, then the line must be parallel (||) to the third side.DiagramGiven In ΔABC, D and E are the two points of AB and AC respectively, such that, AD/DB = AE/EC.To Prove DE || BCProof In ΔABC,given, AD/DB = AE/EC ----- (1) Let us assume that in ΔABC, the point F is an intersect on the side AC. So we can apply the Thales Theorem, AD/DB = AF/FC ----- (2) Simplify, in (1) and (2) == AE/EC = AF/FC Add 1 on both sides, == (AE/EC) + 1 = (AF/FC) + 1 == (AE+EC)/EC = (AF+FC)/FC == AC/EC = AC/FC == EC = FC From the above, we can say that the points E and F coincide on AC. i.e., DF coincides with DE. Since DF is parallel to BC, DE is also parallel BCHence theConverse of Basic Proportionality theroremis proved. | |
| 21516. |
Tell what do you mean by covalent bond |
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Answer» Covalent bond: The bond formed by mutual sharing of valency electrons in order to get stable electronic configuration of nearest inert gas is called covalent bond. Generally this bond is formed between non metals.Based on type of atoms participated in the bonding, covalent bond is classified into two types. They are (i) polar covalent bonding (ii) Non-polar covalent bonding Covalent bond is the bond between two or more atoms in which electrons are shared between the atoms to form covalent compound. |
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| 21517. |
Show that any positive odd integer is of the form 5q+1,or 5q+2 ,or 5q+3, 5q+4 |
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Answer» Thanks you Let x be any positive integerThen x = 5q or x = 5q+1 or x = 5q+4 for integer x.If x = 5q, x2\xa0= (5q)2\xa0= 25q2\xa0= 5(5q2) = 5n (where n = 5q2\xa0)If x = 5q+1, x2\xa0= (5q+1)2\xa0= 25q2+10q+1 = 5(5q2+2q)+1 = 5n+1 (where n = 5q2+2q )If x = 5q+4, x2\xa0= (5q+4)2\xa0= 25q2+40q+16 = 5(5q2\xa0+ 8q + 3)+ 1 = 5n+1 (where n = 5q2+8q+3 )∴in each of three cases x2\xa0is either of the form 5q or 5q+1\xa0or 5q+4 and for integer q. |
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| 21518. |
5q + 1= |
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Answer» What is your question???????????? Q=-1/5 |
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| 21519. |
If tan theta =1/2 and theta is an acute angle, then show that 1/2 sin theta into cos theta=1/5 |
| Answer» In ∆ABC , angle C=theta Then, AB=1. BC=2Also. AC=√5(1/2×1/√5)(2/√5)=(1/2√5×2/√5)=1/5 | |
| 21520. |
Find the 31st term of an AP whose 11th term is 38 and 16th term is 73. |
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Answer» a+10d=38 : 1 , a+15d=73 :22-1=a+15d-a-10d=73-38=5d=35d=7a=38-10d=- 3231st term=a+30d=-32+210=178 A+10d=38A+15d=73 -5d=-53d d=53/5 |
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| 21521. |
If SecA - tanA=4Then find cosecA |
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| 21522. |
A cubic cm of gold is drawn into a wire 0.1mm in diameter, find the length of the wire |
| Answer» Given,Volume of gold = 1 cm3\xa0= 1000 mm3\xa0......(1)Diameter of wire = 0.1 mmRadius of wire =\xa0{tex}\\frac { 0.1 } { 2 }{/tex}\xa0= 0.05 mmLet, the length of the wire = h mmAccording to the question,Volume of wire = Volume of gold{tex}\\Rightarrow {/tex} πr2h = 1000 .( Since, wire is cylindrical & from (1) ){tex}\\Rightarrow π× ( 0.05 ) ^ { 2 } \\times h{/tex}\xa0= 1000{tex}\\Rightarrow \\frac { 22 } { 7 } \\times 0.0025 \\times h{/tex}\xa0= 1000{tex}\\Rightarrow h = \\frac { 1000 \\times 7 } { 22 \\times 0.0025 }{/tex}mm{tex}\\Rightarrow{/tex}\xa0h = 127272.72 mm{tex}\\Rightarrow{/tex}\xa0h = 127.27 m(approx.) | |
| 21523. |
Prove that1+cot^2A÷1+cosecA=cosecA |
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| 21524. |
Optional exercise will also come |
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Answer» nahi ncert book ke optional ke niche likh rakha hai Yaa it can come No |
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| 21525. |
To find the value of K if the points A(2,3) B(4,K) and C(6,-3) are collinear |
| Answer» If the points are collinear than there wold be no triangle formI. E area=01/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]=0\t[2(k+3)+4(-3-3)+6(3-k)=0\t2k+6-24+18-6k=0\t-4k=0\tk=0Hence for k=0 the points will be collinear. | |
| 21526. |
10.1 therom |
| Answer» Tangent at any point on circle is perpendicular to radius of circle through point of contact | |
| 21527. |
If the sum of first n terms of an A.P. is an^2+bn, find its common difference. |
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| 21528. |
Guys when we multiple a into b why they are not multiply or divide |
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Answer» Its simple because they are all in algebra not in numerics Because they are in algebra not in numeric form we can multiply the same algebra that is. a, a or b, b Because they are in form of algebra not in numeric form |
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| 21529. |
Sec theta +tan theta equal to p find cosec theta |
| Answer» 1+p2/p2-1 is the correct answer you need to its sol. Tell me again | |
| 21530. |
12+o1.3 |
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Answer» Plz tell again your question ???? 21 |
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| 21531. |
In triangle.ABC it is given that de //bc if ad =3cm db =2 cm and de=6cm find bc |
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Answer» 10 cm 10 cm 10cm |
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| 21532. |
the sum of three number in AP is 27 and their product is 405 . find the common difference. |
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Answer» D=6 D = 6 I think d=6 D=12 Let 3 number be à-d,a,a+da-d+a+a+d=27(given)3a=27a=9(a-d)a(a+d)=405Substitute a=9 in this equation and solve it |
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| 21533. |
234-4 |
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Answer» 230 What is your question?????? 230 |
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| 21534. |
Find the greatest 6 digit number which are divisible by 18 24 and 16 |
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| 21535. |
Show that the tangents at the end points of a diameter of a circle are parallel. |
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Answer» We know that tangent are drawn to the point of contact is perpendicular to its radius so parellel tangents have each 90 deg. Angle but these are also the alternate interior angle so lines are parallel Just show the alternate angles are equal means 90 deg. then the line will be parallel |
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| 21536. |
Which stream should i choose after 10th |
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Answer» you should go in football No maths or arts Are you sure Vishaka Then choose commerce phe Nothing... My career is in sports Which subject you like most |
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| 21537. |
Is all questions come from n.c.e.r.t. books only in mathematics? Plz answer this |
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Answer» 80% ncert 20% from outsidw No.but 70percent I got cbse sample papers... Anyone want that Most of the ques. come from NCERT but not all....as far as I know....but for sure the methods to solve/prove those ques. is based on NCERT if we are able to understand ques. |
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| 21538. |
solve pair of linear equation:(a-b)x +(a+b)y=a*a-2ab-b*b And (a+b)(x+y)=a*a+b*b |
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| 21539. |
If one zero of quadratic polynomial x square minus x minus into 2 plus 2k is 4 find the value of k |
| Answer» X^2-x-(2+2k)=0(4)^2 - 4-(2+2k)=016-4-2-2k=010-2k=0-2k=-10K=5 | |
| 21540. |
How to nake linear eq in two variable |
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| 21541. |
If m and n are prime positive integers prove that root m + root n is an irrational number |
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| 21542. |
I am forgetting the sum very soon what should I do to remember it for a long time |
| Answer» Which sum | |
| 21543. |
If the sum of n terms of an AP is 2n + 5 then prove that aN =4n+3 |
| Answer» Since,. Sn=2n+5. Therefore,. Sn-1=2(n-1)+5 Or,. =2n+3. We Know that,. An=Sn-Sn-1. Or,. =2n-1-(2n+3). Or,. = -4 Since, value of n donot exist Therefore this donot form any A.P. Please check your question Sn must be 2n²+5 | |
| 21544. |
1/sec a -tan a - 1/cos a = 1/cos a - 1/seca + tan a |
| Answer» \xa0We have,\xa0{tex} \\frac{1}{{\\sec A + \\tan A}} - \\frac{1}{{\\cos A}} = \\frac{1}{{\\cos A}} - \\frac{1}{{\\sec A - \\tan A}}{/tex}{tex}\\Rightarrow \\frac{1}{{\\sec A + \\tan A}} + \\frac{1}{{\\sec A - \\tan A}} = \\frac{1}{{\\cos A}} + \\frac{1}{{\\cos A}}{/tex}LHS\xa0{tex}= \\frac{1}{{\\sec A + \\tan A}} + \\frac{1}{{\\sec A - \\tan A}}{/tex}{tex}= \\frac{{\\sec A - \\tan A + \\sec A + \\tan A}}{{(\\sec A + \\tan A)(\\sec A - \\tan A)}}{/tex}{tex}= \\frac{{2\\sec A}}{{{{\\sec }^2}A - {{\\tan }^2}A}}{/tex}\xa0{tex} \\left[ {\\because (a + b)(a - b) = ({a^2} - {b^2}} \\right]{/tex}{tex}= \\frac{{2\\sec A}}{1}{/tex}\xa0{tex} \\left[ {\\because {{\\sec }^2}A - {{\\tan }^2}A = 1} \\right]{/tex}= 2secARHS\xa0{tex}= \\frac{1}{{\\cos A}} + \\frac{1}{{\\cos A}}{/tex}{tex}= \\frac{{1 + 1}}{{\\cos A}}{/tex}{tex}= \\frac{2}{{\\cos A}}{/tex}= 2 secALHS = RHS\xa0 | |
| 21545. |
In triangle ABC, AB=3, BC=4, AC=5, then the radius of the circle touching all the three sides is ? |
| Answer» radius is 1 unit | |
| 21546. |
Find the, find the greatest number by which 18 24 and 16 are divisible |
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Answer» 2 is the greatest number by which 18,16,24 are divisible 2 2 |
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| 21547. |
Find the positive root of √3 X square + 6 is equal to 9 |
| Answer» {tex}\\sqrt { 3 x ^ { 2 } + 6 } = 9{/tex}3x2 + 6 = 813x2 = 81 - 6 = 75x2\xa0= 25{tex}\\therefore{/tex}\xa0x = ± 5Hence, Positive root = 5 | |
| 21548. |
If \'d\' is the HCF of 45 and 27. Find x and y satisfying d = 27x + 45y. |
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Answer» The numbers are :-45 and 27Lets find their HCFBY Euclid\'s division Lemma :-a = bq + r45 = 27 x 1 + 1827 = 18 x 1 + 918 = 9 x 2 + 0HCF = d = 9Given:-d = 27x+45y9 = 27x + 45y9 = 27 - 18 x 118 = 45 - 27 x 1\xa0Therefore ,9 = 27 - [ 45 x 27 x 1 ] x 1= 27 x 2 - 45\xa09 = 27 x 2 + 45 x [ -1 ]x = 2y = -1 These Have infinitely many solution |
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| 21549. |
Find roots by completing square |
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Answer» Firstly make sure that nothing is in denominator of x2 then add and subtract the half of the coefficient of x and do there square Of which polynomial.????? |
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| 21550. |
Find the value of k when the distance between the points (3,2k) and (4,1) is √10 units. |
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Answer» Boy Answer is +2 |
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