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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 22151. |
Formula for mid point.. |
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Answer» Y Okkkkk yaar ,chal aaj hi friendship day manate hain Yaar dil churane wale to bahut hain मैंने कभी सोचा तक नहीं थाकी ऐसा दिन भी आएगामेरे सीने में बैठा दिलकिसी और का हो जायेगा sabko apni gf dusro se alag hi lgti h X1+ X2/2 and Y1 +Y2/2....... |
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| 22152. |
Using elimination method2x+3y=8 4x+6y=7 |
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Answer» Infinite many solution☺️☺️☺️☺️ Since a1/a2 = b1/b2 is not = c1/c2 Hence it is inconsistent with no solutions No solution he bhai example no. 12 pg56 NCERT dekh le ok |
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| 22153. |
If Sn of AP=n×n.Find a10 |
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| 22154. |
Chapter 3 ex 3.2 questions 3 |
| Answer» Bhai question 3 mein konsa part | |
| 22155. |
Kis kis ke pre board exams ho gye |
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Answer» Yar tum to ek question ko hi lekar beth gyi , us samay mera mood thik nhi tha Na abhi baki he answer thik hena mera divanshu sir bolo |
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| 22156. |
Solve for x :(a-b) x^2+(b-c)x+(c-a)=0 |
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| 22157. |
If tanA = ntanB and sinA = msinB , then prove that cos square A = m square - 1 upon n square + 1 |
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| 22158. |
tanA/1-tanA - cotA/1-cotA = CosA+sinA/ cosA- sinA |
| Answer» Change the tanA and cotA into sinA and CosAThen solve | |
| 22159. |
SinA-2sin 2A = tanA |
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| 22160. |
if p(x, y) is any point joining the points A( a,0) and B (0, b) then show that x/a + y/b= 1 |
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Answer» thank u soo so much?? These points are collinear so using the formula of area of triangle the area will be equal to 00=1/2|a(y-b)+x(b-0)+0(0-y)||ay-ab+xb-0+0|ay-ab+xb=0ay+xb=abay+xb/ab=1 Taking lcm x/a+y/b = 1 Hence proved plz answer bata do |
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| 22161. |
Exercise 3.1 ke tino ke Solutions bajo koyi |
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| 22162. |
If points R (x,y) lies on line segment joining points P(a,b)and (b,a). Then prove that x+y=a+b |
| Answer» According to the question, R(x, y) is a point on the line segment joining the points P(a, b) and Q(b, a)Let point R(x + y) divides the line joining P(a,b) and Q(b,a) in the ratio {tex}\\lambda{/tex}\xa0: 1.{tex}\\therefore x = \\frac { \\lambda b + a } { \\lambda + 1 }{/tex}\xa0{tex}y = \\frac { \\lambda a + b } { \\lambda + 1 }{/tex}Adding, {tex}x+y=\\frac { \\lambda b + a + \\lambda a + b } { \\lambda + 1 }{/tex}{tex}= \\frac { \\lambda ( a + b ) + 1 \\times ( a + b ) } { \\lambda + 1 }{/tex}{tex}= \\frac { ( \\lambda + 1 ) \\times ( a + b ) } { \\lambda + 1 } = a + b{/tex}{tex}\\Rightarrow x+y=a+b{/tex}Hence Proved. | |
| 22163. |
SecA+tanA=p find value of cosecA |
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Answer» P8pp P+1 , _1 |
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| 22164. |
Find the sum of all three digit numbers which leave the remainder 2 when divisible by 5 |
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| 22165. |
Please tell all formulas of surface area and volume |
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Answer» Area of circle, circumference of circle and area of sector are not the formulae of surface area and volume Area of circle πr2 , circumstances of circle 2πr ,area of sector teta/360×πr2 Bht saare formulae h |
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| 22166. |
An A.P consists of 50terms of which 3rd term is 12 and the last term is 106 . find the 29th term . |
| Answer» Let the first term and the common difference of the AP be a and d respectively.3rd term = 12 ..... Given{tex} \\Rightarrow {/tex}\xa0a + (3 - 1)d\xa0= 12\xa0{tex}\\because {a_n} = a + (n - 1)d{/tex}{tex} \\Rightarrow {/tex}\xa0a + 2d = 12 ......... (1)Last term = 106 ........ Given{tex} \\Rightarrow {/tex}\xa0So the term = 106\xa0{tex}\\because {/tex}\xa0The AP consists of 50 terms{tex} \\Rightarrow {/tex}\xa0a + (50 - 1)d = 106{tex} \\Rightarrow {/tex}\xa0a + 49d = 106 ........ (2)Solving (1) and (2), we geta = 8d = 2Therefore, 29th term of the AP= 9 + (29 - 1)d\xa0{tex}\\because {a_n} = a + (n - 1)d{/tex}= 9 + 28d= 8 + (28) (2)= 8 + 56= 64 | |
| 22167. |
Middle terms splitting |
| Answer» ???? | |
| 22168. |
Plz explain BPT |
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| 22169. |
For what value of p,the points(2,1),(p,-1)and(-1,3) are collinear? |
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Answer» and apply area of triangle to solve this Ya, shreya is ryt.. Take area of the three points equal to zero and u will get the answer. sry * this hope 5his help u value of p is 5 |
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| 22170. |
√5 is an irration no |
| Answer» Yes..... | |
| 22171. |
If one root of 5x+13x+k =0 is the reciprocal of the other root ,then find the value of k |
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Answer» K is 5 5x or 5xsq. |
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| 22172. |
3m+1,3m+2 |
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| 22173. |
If the Hcf of 657 and 963 is expressible in the form of 657x+963×(-15),find the value of x |
| Answer» Given numbers are 657 and 963 .Here, 657 < 963\xa0By using Euclid\'s Division algorithmm , we get963 = (657 × 1) + 306Here , remainder = 306 .So, On taking 657 as new dividend and 306 as the new divisor and then apply Euclid\'s Division lemma, we get657 = (306 × 2) + 45Here, remainder = 45\xa0So, On taking 306\xa0as new dividend and 45\xa0as the new divisor and then apply Euclid\'s Division lemma, we get306 = (45 × 6) + 36Here, remainder = 36So, On taking 45\xa0as new dividend and 36\xa0as the new divisor and then apply Euclid\'s Division lemma, we get45 = (36 × 1) + 9Here, remainder = 9So, On taking 36\xa0as new dividend and 9\xa0as the new divisor and then apply Euclid\'s Division lemma, we get36 = (9 × 4) + 0Here , remainder = 0 and last divisor is 9.\xa0Hence, HCF of 657 and 963 = 9.∴ 9 = 657x + 963(-15)⇒ 9 = 657x - 14445⇒ 657x = 9 + 14445⇒ 657x = 14454⇒x = 14454/657⇒ x =22 | |
| 22174. |
The HCF and LCM of two numbers are 9 and 360 respectivity.If one number is 45,find the other number |
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Answer» 72 is the answer HCF×LCM=product of two numbers360×9=45×oth.number3240=45×oth.no3240÷45=oth.noOth no=72 72 Use hcf×lcm=product of both numbSrs |
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| 22175. |
Tan a=cot b find a and b |
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Answer» b=90-a and a=90-b a=90-b and b=90-a |
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| 22176. |
X2+5kx+16=0 |
| Answer» K=+8/5 and k= -8/5 | |
| 22177. |
X, ÿ, Z is an AP there. Find the value of (x+y-z) (y+z-x) |
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| 22178. |
In given figure in what ratio does P divide AB internally? |
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Answer» Exactly where is the figure??????? Where is the figure |
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| 22179. |
In example 3 , chapter 14 , how to find h (class size, for using step deviation method). |
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Answer» H = upper limit - lower limit Please help me with answer ? |
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| 22180. |
Find the value of k for which one root is quadratic polynomial is Kx2-14x+8is six time the other |
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Answer» Pooja g nhi h ye question Puja ji answer aa gya thanks? Puja ji nhi ho rha? Puja ji plz explain Anyone online |
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| 22181. |
Example 4 chapter 7 pg :- 160 |
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Answer» Thnku chetna ji.. Yess u are right Aashu It is already solved there in ncert.. |
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| 22182. |
What is chance that will contains 53mondays in a leap year |
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Answer» The probablity of 53 mondays in a leap year is 2/7... The probability of having 53 Mondays in a leap year is 2/7 |
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| 22183. |
Which book is the best for board exam other than ncert???? |
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Answer» R d sharma it contain different types of questions and sample paper of arihant Mathematics? |
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| 22184. |
Find the value of k if the points (8, 1), (k, -4), (2, -5) are collinear. |
| Answer» Area of triangle=1÷2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]0=1/2[8(-4-(-5))+k(-5-1)+2(1-(-4))]0=1/2[8(1)+k(-6)+2(5)]0=1/2[8-6k+10]0=1/2[-6k+18]0=1/2×2[-k+3]0=-k+3-3=-k3=k | |
| 22185. |
If the HCF of 85and 153 is expressive in the form of 85m-153 then find the value of m |
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| 22186. |
But theorem |
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Answer» But theorem? what happen |
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| 22187. |
Maths Paper will be very hard this year? |
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Answer» Yes 73 percent ncrt and other to reffreance R u asking or informing? no it will n\'t difficult |
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| 22188. |
How to do spliting the middle term |
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| 22189. |
If 21th term of an A.P.is 43,find the 41 term |
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Answer» Please solve full 86 + a or shayad 83 |
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| 22190. |
What is the centroid formula in coordinate geometry |
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Answer» Thnxx! Coordinates of the centroid G are[ (x1+x2+x3) / 3, (y1+y2+y3\xa0) / 3] By 3 chhhoot gya lga llena X1+x2+x3 and same 4 y coordinate |
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| 22191. |
If sin theta + cos theta=1,then the value of sin 2theta= |
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| 22192. |
If p is an prime number then p is number |
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Answer» P is an integer and it\'s two divisors r 1 and P itself. Odd number except 2 No P 4 pawan |
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| 22193. |
If 4th term of an A. P is 0 prove that 25th term of an A. P is 3time its 11th term |
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Answer» Propely handwritten A+3D=0A=-3DA+24D=-3D+24D=21DA+10D=-3D+11D=7DHence proved.If u can give ur no. Then i will send on WhatsApp |
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| 22194. |
If I opt for biotech as an optional subject what career opportunities would this subject offer? |
| Answer» Plz do tell...I have to submit my sub opt form tomorrow ? | |
| 22195. |
Solve this quadratic equation3(7x+1/5x-3)-4(5x-3/7x+1)=11 |
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Answer» But i got my answer No i am not on gradeup Are you on gradeup Is there any other way There is no Picture option so it will be very difficult to write answer here |
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| 22196. |
Solve by factorisation method3√5x2+25x+ 10√5 |
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Answer» Thanks Split middle term and put, 15x+10x. Take common 3 root 5x( x + root5)+10(x + root 5). Yu will get, x= -root 5, , -10/3root5. |
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| 22197. |
Prove cosA - sinA + 1 / cosA +sinA -1 = cosecA + cotA |
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| 22198. |
Smallest composite no. |
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Answer» 4 is answer How mohan kumar... 4 |
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| 22199. |
Find the value k for which the point A(k+1,2k) B(3k,2k+3) and C(5k-1,5k)are collinear |
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Answer» Sirf 2 hoga 2,1/2 value rkh kr dekh lena ho skta koi satisfy kare aur koi nhi For collinear points area of triangle is equal to 0 Whar |
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| 22200. |
Is ncert enough to get 90 in maths |
| Answer» Bro paper is of just 80 | |