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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 22301. |
What is the formula of sum of terms in arthimatics progression |
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Answer» Sn=n/2[2a+(n-1)d] Sn=n/2(a+l) where l is the last term Sn=n/2 [2a+(n-1)d] |
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| 22302. |
What is a segement |
| Answer» Segment is a line which have a starting point and a ending point | |
| 22303. |
4^x+3.2^x+3+128=0 |
| Answer» The value of x =-108 | |
| 22304. |
If 2x+3y=6 find x and y |
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Answer» X=6-3y/2 2x=6-3y |
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| 22305. |
2x+3y=68x+3y=9 |
| Answer» In equation 1 2x+3y=6 multiply by 4 in whole equation we get 8x + 12y = 24. Let this is equation m.Equation 2 8x + 3y = 9.Subtract equation m-eq.2 we get9y = 15 y= 15/9y=5/3.Putting the value of y in eq.12x + 5 = 6 2x = 1x= 1/2. We get both the value | |
| 22306. |
If ?ABC ~? PQR. AB/PQ=1/3FIND AR.ABC/AR.PQR |
| Answer» Ar.ABC/Ar.PQR =(AB)sq/(PQ)sq=(1)²/(3)² 1/9 Ar.ABC/Ar.PQR=1/9 | |
| 22307. |
0 zero kya haii |
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Answer» Zero is a number discovered by aryabhatta (indian) it is the mid value of all the integers on a number line. Ye BHI koi question hai? |
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| 22308. |
Online answer |
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| 22309. |
Find all the values of p and q so that 1,-2,are zeroes of the polynomial (f()×)=×3 |
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| 22310. |
Prove that under root 2 is equal to irrational |
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Answer» NCERT book ka chapter 1 ke example number 9 ki tarha hoga √2 |
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| 22311. |
If cose=√3 and cot=1 find sin(a+b) |
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| 22312. |
What is a real no |
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Answer» Same difference between a number line is called real number. Real no is a no that can found on no line Every counting number is a real number |
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| 22313. |
Any clash of clan player? |
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Answer» Th 12 rush and th 10 maxed Roman u a coc player Anshika u r online Anishka in which th Yes me I am |
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| 22314. |
Solve sec-tan=7 so find sec+tan |
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Answer» 1/7 1/7 1/7 |
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| 22315. |
2plus 2 |
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Answer» Aap nursary class mai padte ho kya 4 2+2=42 and 2 is 22 4 and 22?? Katai zeher type ka question tha bhai kahar dha dia 4 22 |
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| 22316. |
Find zeroes of cubic polynomial p(x)=x3+6x2-x-30. If product of two zeroes is -6. |
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| 22317. |
What is meaning of co-prime |
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| 22318. |
Which sample question paper is good for tge board exam |
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Answer» Ead36 paper bank We can get knowledge kes type ke question ate hai just for practice its good |
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| 22319. |
Volume of a sphere |
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Answer» U r ryt anushka ji Ji aap itne intelligent hai ki kisi ko koi shak kaise ho sakta hai Koi shak 4/3 pie r cube 4 /3 pi r cube |
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| 22320. |
(Cos2+1)(cot2-1)+1=0 |
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| 22321. |
What are the way to study trigonometry |
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Answer» First of all u learn all the trigonometric identities , ratios . Then you do trigonometry better..... Learn all formula for better study Practice more and more and learn all the identities. |
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| 22322. |
Find the value of (s) of Kif the quadratic equation 3× |
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| 22323. |
What is hel\'s theorm |
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Answer» But i want it\'s proof Thales thoerm is that-Two triangles are equal if their corresponding sides are in same ratio and corresponding angles are equal |
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| 22324. |
A coin is tossed once what is the probability of getting a tail |
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Answer» 1/2 1/2 1/2 1/2 |
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| 22325. |
if a cos |
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Answer» Plzz complete your q Plzz compete your question. Ya puja is right plz complete ur question Complete your question |
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| 22326. |
x square - 25 x +100Find the zerozeroes of polynomial ? |
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Answer» Board exam date sheet7-3-19 - Maths13-3-19- Science16-3-19- Sanskrit 19-3-19- Hindi 23-3-19- English 29-3-19- Social science Are u online himanshi? By quadratic formula X=20 and X=5 Two Zeroes of the given polynomial are 20 and 5 x2 - 25x + 100 = 0 x2 - 20x - 5x + 100 = 0\xa0x ( x - 20) - 5(x - 20)= 0 (x -5) ( x-20) = 0x - 5 = 0 or x - 20 = 0x = 5 or x = 20\xa0 |
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| 22327. |
If the LCM of (a,b) = 26460,HCF of (a,b) = 27 and b = 540,find a. |
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Answer» H.C.F. X L.C.M. = product of number27 X 26460 = a X 540a = 27 X 26460/540a = 2646/2 a = 1323 answer A=1323......\' a=1323....? Value of a=1323 |
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| 22328. |
Cosec square (B+C/2)_tan square (A/2)=1 |
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Answer» A+B+C = 180B+C =180- ADivide both sides by 2Cosec square (B/2 + C/2) = Cosec square (180/2-A/2)Cosec square (B+C/2) = Cosec square (90-A/2)Cosec square ( B +C/2) = Tan square (A/2)Proved Cosec^2 (b+c/2)-tan^2(a/2)=1L.H.S: =cosec^2(b+c/2)-cot^2(90-a/2) =cosec^2(b+c/2)-cot^2(b+c/2) =cosec^2-cot^2 =1 R.H.S |
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| 22329. |
Ogive |
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Answer» It is a graph which shows the cumulative frequency. In less than type ogive the graph line starts from down with raising upwards and in more than type ogive it starts from upwards decreasing downwards. Graph |
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| 22330. |
Who use sample paper osawal |
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Answer» Ya i have made I use Together with....sample papers..... I m a girl Self aasement bana liya ho bhai 1st ka Ya me |
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| 22331. |
Sec theta +tan theta =P prove p square -1 divided by p square +1 |
| Answer» ( sec + tan )^2 - 1/ ( sec + tan )^2 + 1== sec^2 + tan^2 + 2tan sec - 1/ sec^2 + tan^2 + 2tan sec + 1== tan^2 + tan^2 + 2tan sec/ sec^2 + sec^2 + 2 ten sec== 2tan ( tan + sec )/ 2sec ( sec + tan )== tan/sec == sin | |
| 22332. |
What is the power of a constant?? |
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| 22333. |
Is ncert enough for math |
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Answer» U should practice full ncert but some extra book too Yes, but you to analyse it completely. |
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| 22334. |
how to prove triangle ch. Question in easy way. |
| Answer» Hiiiiii | |
| 22335. |
What is in theorem 6.6 in ncert chapter triangles |
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Answer» For more detail open your NCERT book The ratio of the areas of two similar triangles is equal to the squares of there corresponding sides...... |
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| 22336. |
If the hcf of 657 and 963 is expressible in the form of 657x plus 963x(-15)find x. |
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Answer» 963=657×1+306657=306×2+45306=45×6 + 3645=36×1+936=9×4+0So HCF=9Hence 657x +963x(-15)=9657x-14445=9657x=14445+9657x=14454x=22 ans\xa0 Hindi ... Mene to direct solve kardia bina hcf nikale and finally i got right answer 108 ?? I think 108 or 1/108 i m not sure check it and tell me the answer if u get that ok Samaj me aa gaya ?? Pehle HCF nikalo phir usko ess equation (. 657x+963x(-15)) ke equal put kar do and you will get a linear equation then solve for x |
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| 22337. |
THE median of following date is 5 .Find X and Y . C.I 0 TO 1000. FI 2 5 X 12 17 20 Y 9 7 4 |
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| 22338. |
Find the value of k for which the roots of the quad.equation xkipower 2 +k(4x+k-1)+2=0 are equal |
| Answer» x\u200b\u200b\u200b\u200b\u200b\u200b2\u200b\u200b\u200b\u200b\u200b+k(4x+k-1)+2=0X\u200b\u200b\u200b\u200b\u200b\u200b2+4kx+k\u200b\u200b\u200b\u200b\u200b\u200b2\u200b\u200b\u200b\u200b\u200b-k+2=0If roots are equal thenb\u200b\u200b\u200b\u200b\u200b\u200b2=4acHere a=1,b=4k c=k\u200b\u200b\u200b\u200b\u200b\u200b2\u200b\u200b\u200b\u200b\u200b-k+2So (4k)^2=4×1×(k^2-k+2)4k^2=k^2-k+23k^2+k-2=03k^2+3k-2k-2=03k(k+1)-2(k+1)=0(3k-2)(k+1)=0k=2/3, .- 1 | |
| 22339. |
If the quadratic equation (1+a2)b2x2+2abcx+(c2-m2)=0in x has equal roots , prove that c2=m2(1+a2). |
| Answer» Here A=(1+a^2)b^2,B=2abc C=c^2-m^2If roots are equal thenB^2=4AC4a^2b^2c^2=4(1+a^2)b^2(c^2-m^2)a2b2c2=(b2+a2b2)(c2-m2)=b2c2-b2m2+a2b2c2-m2a2b2Or b2c2=b2m2+m2a2b2b2C2=b2m2(1+a2)c2=m2(1+a2) provedSorry I am facing problem in writing powers | |
| 22340. |
Which term of AP 20, 19 1/4, 18 1/2, 17 3/4........... is the first negative term? |
| Answer» 21stterm | |
| 22341. |
If a right angled tringle ABCAB=12BC=17AC=17Find the area of the tringle |
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Answer» It is not possible of having a right triangle ABC if AB=12 BC=17 and AC=17 102 sq units |
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| 22342. |
144$¢``×ase |
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Answer» Plz question ko acche se type kare .... Mai samji nahi ? (-2+4)(2-8)(x+y)=2+4 |
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| 22343. |
What is less than type |
| Answer» Wts ur ques? | |
| 22344. |
Find k x^2+(x-k-k+1)+2 and find alpha + beta - alpha ×beta |
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| 22345. |
What is the probablity of sundays in leap year |
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Answer» Isme practice karne jaisa kuch ni hain Right answer..... Hmm I don\'t know mai es chapter ki practice karungi Ya hi.. Its 2/7 |
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| 22346. |
Draw a circle of radius 5cm which are inclined to each other at angle 60° |
| Answer» The tangents can be constructed in the following manner:Step 1Draw a circle of radius 5 cm and with centre as O.Step 2Take a point A on the circumference of the circle and join OA. Draw a perpendicular to OA at point A.Step 3Draw a radius OB, making an angle of 120° (180° − 60°) with OA.Step 4Draw a perpendicular to OB at point B. Let both the perpendiculars intersect at point P. PA and PB are the required tangents at an angle of 60°.JustificationThe construction can be justified by proving that ∠APB = 60°By our construction∠OAP = 90°∠OBP = 90°And ∠AOB = 120°We know that the sum of all interior angles of a quadrilateral = 360°∠OAP + ∠AOB + ∠OBP + ∠APB = 360°90° + 120° + 90° + ∠APB = 360°∠APB = 60°This justifies the construction. | |
| 22347. |
Sja yh h ki banjar jamin hu m ...Aur glti yai h ki ishq baarish sai ho gya ?? |
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Answer» Mansi or atul. Yaar yhan pe sirf aap dona ka hi dil tuta hua h. So please is topic ko chod do na Koi nhi kapil ji...?? Yrr bs sb ka dil tut rkha h to sb feling share kr rhe h bs... Yaar kya ho gaya hao sabko ????? Sab aise depressing shayari kyo post kar rahe ho |
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| 22348. |
The mean of 25 observation is 27 and each observation is decreased by 7 what will be the new mean. ? |
| Answer» We know mean ,Mean =\xa0{tex}\\frac{\\text{Sum of given observations}}{\\text{Total number of observations}}{/tex}Mean of 25 observations = 27Therefore, Sum of 25 observations = 27\xa0{tex}\\times{/tex}\xa025 = 675If 7 is subtracted from every number, then the sum = 675 - (25\xa0{tex}\\times{/tex}\xa07){tex}= 675 - 175 = 500{/tex}Then, new mean=\xa0{tex} \\frac { 500 } { 25 } = 20{/tex} | |
| 22349. |
I want to know that which lesson has to be practiced more in maths |
| Answer» I think trignometry | |
| 22350. |
How can we find the equations for upstream and downstreqm in 1uadratic equations |
| Answer» For upstream we have to use (x-y). And for downstream (x+y) in equation. | |