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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 22401. |
Prove that (sinteta+coseteta)^2+(costeta+secteta)^2=7+tan^2teta+cot^2teta. |
| Answer» In 1st line it will. be (sin +cosec)^2 | |
| 22402. |
If the hcf of 210 and 55 is expressible in the form 210*5+55y then find y |
| Answer» Applying Euclid division lemna on 210 and 55, we get210 = 55 × 3 + 45☺️☺️55 = 45 × 1 + 10 ☺️45 = 4 × 10 + 5 ☺️10 = 5 × 2 + 0 ☺️☺️We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.☺️∴ 5 = 210 × 5 + 55y☺️⇒ 55y = 5 - 1050 = -1045☺️☺️∴ y = -19 | |
| 22403. |
Find the median in an arranged series of an even number of in terms? |
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| 22404. |
If today is Wednesday what will be the day after 84 days? |
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Answer» Hi know me on. Fb raajz mohit Raunak ji where are yu mujhe apse bat krni hai Answer is Wednesday as when we divide 84 by 7 no odd day is left Pehli baat aaj Tuesday h Calendar mein dekh lo? I think Thursday |
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| 22405. |
ABCD is a trapezium in which the diagonals intersect each other at O .Prove that AO/BO&CO/DO |
| Answer» Given: A trapezium ABCD, In which AB\xa0{tex}\\parallel{/tex} CD and its diagonals AC and BD intersect at O.To Prove: {tex}\\frac{{AO}}{{OC}} = \\frac{{BO}}{{OD}}{/tex}Construction: Through O draw OE||ABproof: In {tex}\\triangle {/tex}ADC, OE {tex}\\parallel{/tex} DC,Hence {tex}\\frac{{AE}}{{ED}} = \\frac{{AO}}{{OC}}{/tex} .....(i).....[By BPT]Again in {tex}\\triangle {/tex}ABD, we have OE\xa0{tex}\\parallel{/tex} AB,hence {tex}\\frac{{DE}}{{EA}} = \\frac{{DO}}{{OB}}{/tex} ........[By BPT]{tex}\\Rightarrow {/tex}{tex}\\frac{{EA}}{{ED}} = \\frac{{OB}}{{OD}}{/tex} .....(ii)......[Using invertendo]{tex}\\therefore {/tex} From (i) and (ii), we.{tex}\\frac{{OB}}{{OD}} = \\frac{{AO}}{{OC}}{/tex}H once proved | |
| 22406. |
(tan A +2)(2tan A =1) =5tanA +sec²A |
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| 22407. |
solve graphically the system of linear equation : 2x+y=8 ; x+1=2 |
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Answer» Check it again This que. is wrong because in secod eq.there is no y Hii renu Sorry this Q.only done in graph Hii |
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| 22408. |
Study ke liye kaun sa sample paper best hai |
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Answer» Pr ncert s bss 33% aata h Mujhe to ncert hi yaad ho jaye wo kitna haya Shivdas and sons Xam idea....is the best... Hii Jo cbse ne upload kiye the |
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| 22409. |
What should i do to get good marks in my boards |
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Answer» Be consistent in your study Jst you study hard and don\'t waste your time on social media... if you bored by studying many hours then i think you have to go for playing a vdio game for mind refresment or listen some songs for some time... i think it will help you to score good marks. Vlcm..... Thanks a lottt Dea do hrdwrk...... N stay frm social media |
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| 22410. |
Write the HCF and LCM of the smallest odd composite number and the smallest odd prime number |
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Answer» HCF =3 and LCM= 9 9 Hewhahwjwj |
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| 22411. |
The sum of two number is 23 and the sum of their recipocal is 23 upon 120.Find the numbers |
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Answer» 8 and 15 15 and 8 ( by assuming the no\'s) |
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| 22412. |
Write the coordinate of the point such that the line 5x-3y=18 meets y axis |
| Answer» (0,-6) | |
| 22413. |
Find the value of `k` so that the following quadratic equestion has equal roots.... 2x2-(k-2)x+1=0 |
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Answer» b2-4ac=0-(k-2)^2-4×2×1(-K+2)^2-8K^2+4-4k-8K^2-4k-4=0K^2-(2+2)k-4=0K^2-2k-2k-4=0K(k-2)-2(k-2)(K-2)(k-2)K=2,k=2Hence the value of k is 2 Anushka...i use it bt the eq. i get was.. k square - 4k-4=0 The equation is. 2x2-(k-2)x+1=0 U can use the formula" b square - 4ac=0" Can you write the equation once again |
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| 22414. |
4x-3y-10=0,8x-2y=20 by cross-multiplication method |
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| 22415. |
If secA+tanA=p,then find the value of cosecA |
| Answer» CosecA= p2+/2p+1 ÷ p2-1 | |
| 22416. |
Aaj kaun kaun study kiya hai daily routine ke jaise |
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Answer» Mera routine toh ek din bhi nahi chal pata Me |
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| 22417. |
If tanA=9/x,then find the 9(x-9/x) |
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Answer» Mera question sahi hai? Ye ans dekho 9{cosA-sinA\\cosA} Please check the question........ Fast dea Plx qstn seede cnd klo...... I vl try Koi ans bata sakta hai? |
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| 22418. |
Of the of the three angle of triangle i |
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Answer» Oyee asia Please check yur question........ |
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| 22419. |
What is value of tanπ/8 |
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| 22420. |
Maths me full marks kaise lae |
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Answer» Time management for only maths Hard work and keep practise Practice practice and only practice ? Happy New Year bhai Bhai ye koi question thodi hYe to sirf wish ya imagination h?? |
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| 22421. |
Find the area of minor segment of circle of radius 42cm,if length of the corresponding arc is 44cm |
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Answer» Angle=44/2πr×360=44/2×7/22×1/42×360=60°So area=60/360×22/7×42×42=925 cm\u200b\u200b\u200b\u200b\u200b2 Thita 60 degrees hoga 924cm sq. |
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| 22422. |
4x^2-4a^x+(a^4-b^4)=0 |
| Answer» X=(4a2+√16a4-4×4×(a\u200b\u200b\u200b\u200b\u200b\u200b4\u200b\u200b\u200b\u200b\u200b-b\u200b\u200b\u200b4))/8=(a^2-+b^2)/2 | |
| 22423. |
Total surface area cone |
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Answer» Surface area of cone: π×r×(l+r)= πr(l+r) πr(l+r) |
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| 22424. |
Which questions are important from triangles chapter?? |
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Answer» Yes my dear i m from Gujarat Example 14 and question no. 14anf15 of ex 6.5 are most important they will defenitely come in boards as one of these question have been repeated since last 5 years All the theorems are important. Anshika pal are you form gujart Theorems or 6.4 and 6.5 both are most important ... All The chapter like circles, triangle are very intresting and are very intellectual. So all questions are very important |
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| 22425. |
What is the other name of salt solution |
| Answer» Brine | |
| 22426. |
Optional of chapter name triangle Question number-6 |
| Answer» Superman punch | |
| 22427. |
Write sin theta in term of cos theta |
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Answer» Sin theta = Plus / minus root under 1- cos2 theta ....... Sorry for below ans. ..........typing mistake Sin2 theta = 1- cos2 theta Root under sin2 theta = root under 1- cos2 thetaSin theta = plus / minus root under 1- cos 2 theta Hope it helps u ?☺ Sin theta = root 1 - cos square theta. |
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| 22428. |
Find the 20th term from the last term of the A.P 3,8,13,.........,253 |
| Answer» 158. | |
| 22429. |
Which term of the A.P :3,8,13,18,...., Is 78 |
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Answer» 16th term an=a+(n-1)dan=78a=3d=5n=?Put these values in the above formula u get ur ans. 16th term... |
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| 22430. |
Find the sum and the product of the polynomial 3x-3 |
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| 22431. |
4n square +5n -636 |
| Answer» (4n)2 + 53n - 48n - 636n(4+53) - 12(4n+53)(n-12) (n+53){n=12}. {n=-53} | |
| 22432. |
Explain why 7×11×13+13 and 7×6×5×4×3×2×1+5 are composite numbers. |
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Answer» 5(7.6.1.4.3.2.1)+1 , 5is a composit number 13(7.11.1)+1 , 13is a composit number 1001+13=10141014 is composite |
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| 22433. |
The surface area of cube is equal to surface area of sphere the find the ratio of their volumes. |
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| 22434. |
What is the hcf smallest prime numberand the smallest comoposite number |
| Answer» Smallest prime number = 2Smallest composite number = 4Factors of 2 are 1 and 2Factors of 4 are 1, 2 and 4Highest common factor (HCF) = 2 | |
| 22435. |
Is it better to solve ncert only for board exams ..?? |
| Answer» Yes because it will carry you apx 50 marks and 30 will by your skill | |
| 22436. |
If secA=x+1/x then prove secA*tanA=2x or 1/2x |
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| 22437. |
Find \'k\' for which the following equation has equal roots.(K-2)xsquare+2(k-2)x+2=0 |
| Answer» k=4 | |
| 22438. |
If a and b are the roots of xsqure+ax-b=0 then find a and b |
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Answer» x\u200b\u200b\u200b\u200b\u200b\u200b2\u200b\u200b\u200b\u200b\u200b +ax-b=0a+b=-a so b=-2aAnd ab=-b so a=-b/b=-1and b=-2a=2 b=2 and a=-1 |
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| 22439. |
Find the sum of those integers from 1 to 500 which are multiples of 2 or 5 |
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Answer» Sorry there was mistakenSum even numbers from 1to 500 areS2=1/4×500×502=62750......(1)The multiples of 5 not included are5,15,25,.....495If n are terms then 495=5+(n-1)×10490=10n-10. n=50So S5=50/2×(5+495)=25×500=12500Total sum S2+S5==62750+12500=75250\xa0 Multiples of 2 are2,4,6....500S\u200b\u200b\u200b\u200b\u200b\u200b2 =250/2×(2+500)=125×251=31375Multiples of not included are5,15,25,35......495If n are the numbers then495=5+(n-2)×10490+20=5n, n=510/2=255S\u200b\u200b\u200b\u200b\u200b\u200b5\xa0=255/2×(5+595)=600×255/5=76500Total sum =32375+76500=108875\xa0\xa0 12750 |
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| 22440. |
formula of chapter 8 |
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Answer» Trignometry Please write chapter name also |
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| 22441. |
A=1.25,d=0.25 |
| Answer» So.. What | |
| 22442. |
Sir is ka 10 years solved sample paper ha kya |
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| 22443. |
Congruence |
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| 22444. |
Solve the following equation by quadratic formula : a/x-a + b/ x-b = 2c/x-c |
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Answer» A / (x - a) + b / (x - b) = 2c / (x - c)\xa0=> [a(x - b) + b (x - a)] / (x - a) (x - b) = 2c / (x - c)\xa0=> [(a + b) x - 2ab] (x - c) = 2c [x^2 - (a + b)x + ab]\xa0=> (a + b) x^2 - [2ab + c(a + b)]x + 2abc = 2cx^2 - 2c(a + b)x + 2abc\xa0=> (a + b - 2c) x^2 = (2ab + ac + bc - 2ca - 2bc) x\xa0=> (a + b - 2c) x^2 = (2ab - ca - bc) x\xa0=> x = 0\xa0or x = (2ab - ca - bc) / (a + b - 2c) Kuch given h Agar kisi ko bhi iska solution aata ho toh pls jaldi bhejo |
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| 22445. |
1+cot°+tan°](sin°-cos°) |
| Answer» I think question is incomplete..Please check it .... | |
| 22446. |
Even i practise sums thoroughly but not able to get more marks .i alwlys loose 5 or 6 marks |
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Answer» Have proper time managment and check your paper & calculations thorougly That\'s my pleasure ashu For ur suggestion For what Thnks kaku I cant give any suggestion becoz i too have this querry ... Just remember all the forms of solutions, theorems and formulae |
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| 22447. |
Which term of an AP: 21; 18; 15;....... is -81? |
| Answer» formula is = a+(n-1)×d-81=21+(n-1)×(-3)-81=21+(n-1)×(-3)-81=21-3n+3-81=24-3n-81-24=-3n-105=-3n105=3n105÷3=n35=n | |
| 22448. |
Draw a line segment of length 8 cm and divide it internally in the ratio 4:5. |
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Answer» Bro it\'s a question. Why |
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| 22449. |
What is the main inishiative to use polynomials |
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| 22450. |
(1+tan thita+sec thita)(1+cot thita- cosec thita) |
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Answer» Ya, it will be 2 Any more Reduce tan cot sec cosec to sin by cos ,cos by sin ,1 by cos and 1 by sin resp. and then calculate It will be 2 |
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