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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 22601. |
Merry Christmas to all of you and gd night?????????????? |
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Answer» Same to u pooja jiiiiiii abd good ? ????????????? Same 2 u Same to u simar Merry christmas riya Hi riya Same to u pooja ji Same to you |
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| 22602. |
How can i solve the problem of chapter 8 on identities based question |
| Answer» By understanding the basic concepts and practice is must............ | |
| 22603. |
Ajay is yashomani maurya. Am i right yashomani? |
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| 22604. |
How can i solve the questions of chapter 13 of rate of water flowing in 3km/hr or any thing |
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| 22605. |
Guys Kya maths me do paper h means standard level or higher level plz reply plz. |
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Answer» Yes next year se hai but kaash abi hota na? but koi baat nhi after all tab bhi toh padhna hi hai☺️ Yes but this parten start in next year not this year |
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| 22606. |
R.s aggarwal class 110th questions no 77 |
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Answer» Do not mind it happens sometimes in hurry Okay Miss take ho gae thae Kaun se jamane ho 110 class me jo pad rahe ho .......... riya please read my tip given to you below U mean class 10 Which class is ths 110th. |
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| 22607. |
What is the meaning of mathematics...... |
| Answer» The study of numbers, quantities or shapes is the meaning of mathematics. | |
| 22608. |
x/2_y/9=6, x/7+y/3 =5 |
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Answer» What is produced sexual First take lcm and make the equation and solved it by any method Riya take the l.c.m of eqn and form two eqn. Now slve it as usual ..... Rishabh yu are correct......x=14 and y=9 But kasa please solution out x = 14 and y = 9 Eqn mann kar karo banjayega. |
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| 22609. |
Sin cos =cosec + tan |
| Answer» This question is totally wrong Ye question kuch ase hona chaia tha Sin + cos = cosec + tan agar accha lage to like Karna ??? | |
| 22610. |
Trisector means |
| Answer» Jo kisi be chej ko 3 barabar hisso m cut cur rha ho use trisector khete h OK agar accha lage to like Karna ??? | |
| 22611. |
What is similar triangle |
| Answer» The triangle which have equal sides | |
| 22612. |
What is the mean fi |
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Answer» Frequency of the observation. frequency |
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| 22613. |
Prove that pythagoras theorem |
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Answer» Then we will prove Pythagoras theorem We have right angled triagle " H square =P square+B square Let a triangle are Abc |
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| 22614. |
Solve :-49^(n+1)×7^n-(343)^n÷7^3m×2^4=3÷343a) m=n b)m=(n-1)c)m=(n+1)d)(m-n)=2 |
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| 22615. |
Hlo Prashant maths ka paper kaisa gya |
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Answer» Hmmm batao exam kaisa tha.... Ha prashant jii batiye aur kuch questions share kijuye |
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| 22616. |
Which coordinate is absicca |
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Answer» X-axis The x - coordinate of a point is its perpendicular distance from the y – axis measured along the x -axis. The x - coordinate is also called the abscissa.The y - coordinate of a point is its perpendicular distance from the x – axis measured along the y – axis. The y - coordinate is also called the ordinate.Origin has zero distance from both the axes so that its abscissa and ordinate are both zero. Therefore, the coordinates of the origin are (0, 0). (X,Y) |
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| 22617. |
When will the result of 10th will be declare ?? |
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Answer» Pakka. A Paper se phale result ki padi h Pehle paper toh hone do bro !! In first week of june |
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| 22618. |
x/2+y+2/5=0 |
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Answer» कोई हिन्दी का सिलेबस बतादो प्लीज़ {tex}\\begin{array}{l}\\;\\frac{\\mathrm x}2+\\mathrm y+\\frac25\\;=\\;0\\\\\\frac{5\\;\\mathrm x\\;+10\\mathrm y+4}{10}\\;=\\;0\\\\5\\mathrm x\\;+\\;10\\mathrm y\\;+\\;4\\;=\\;0\\end{array}{/tex} |
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| 22619. |
Why is sec theta always greater than 1? |
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Answer» Because it is the ratio of hypotenuse and base.And we know that hypotenuse is always greater than base.At zero degree they both are equal so its value is 1 at0\' Because it is identity |
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| 22620. |
X square =100 |
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Answer» X=10 or X=-10 X=10 x2 = 100x = √100x = √102x = 10 |
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| 22621. |
Prove(SinA+cosecA)2+(cosA+secA)2=1/tanA+cotA |
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| 22622. |
If SecA=x+1/4x.prove that SecA+TanA=2x or 1/2x |
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| 22623. |
If A+B=90° and SecA=5/3,then find the value of cosec B |
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Answer» 5/3 A+B=90° ->B=90°-A , also SecA=5/3. ->Cosec(90°-A)=5/3. ->CosecB=5/3 |
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| 22624. |
Chapter name=circleExercise=10.2Ouestion number=12 |
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Answer» Ye itna jaruri nhi h.ye paper me nhi aata simply take area firstly by heron\'s formula then we know that tangents are equal in length so let tangents from a be of x cm then apply heron\'s formula and simply area of three triangles.use result of both the cases it\'ll provide You with The vale of x and add 8 and 6 to get desirable result. Andare Will be 15 , 13 cm |
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| 22625. |
Explain triangles theorem 6.1 in hindi |
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Answer» Jab hm traingle ke beach me ek line khecte h .to vo do equal parts me divide ho jata h I learn it in english |
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| 22626. |
ax + by - a + b= 0 , bx - ay - a - b =0Solve for x and y |
| Answer» ax + by = a - b multiply by abx - ay = a + b multiply by b{tex}\\Rightarrow{/tex} x = 1{tex}\\therefore{/tex} a + by = a - bby = -by = -1{tex}\\therefore{/tex} x = 1y = -1 | |
| 22627. |
If the points A(1,2),B(0,0)andC(a,b) are collinear ,then what is the relation between a and b |
| Answer» 2a=b | |
| 22628. |
9-9/9-9=2 prove that in one minute |
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Answer» 9/9=3*3-3*3/3*3-3*3=(3-3)(3+3)/3(3-3)=3+3/3=6/3=2 Hence proved I do it 9-9/9-93×3-3×3/3×3-3×3(3-3)(3+3)/(3-3)(3+3)3+3/3+39/91Hence proved Not possible |
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| 22629. |
Guys......datesheet aa gayi h 7 march ko first exam h maths ka |
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Answer» Datesheet has been released To kya kahna chahti thi Sorry m pagal nahi khana chati thi galti se likh diya Are pagal aa gayi h january me aayegi. |
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| 22630. |
ax/b-by/a= a+b , ax-by=2ab solve |
| Answer» X=-b,y=-3a | |
| 22631. |
Find the HCF by euclid division algorithm of the numbers 92690 , 7378 , 7161. |
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Answer» Start answer in downward sorry....... Mistake Sorry.......??????7378=4154×1+3224 (remainder≠0)4154=3224×1+930(remainder≠0)3224=930×3+434(remainder≠0)930=434×2+62(remainder≠0)434=62×7+0(remainder=0). therefore,HCF(92690,7378)=627161=62×115+3162=31×2=0Therefore,HCF(7161,62)=31Hence,HCF(92690,7378,7161)=31 By using euclid division algorithm92690=7378×12+4154 |
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| 22632. |
If the perimeter of a semi circular protractor is 36cm find its diameter |
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Answer» Sorry yr radius galat find go use solve kar lo Perimeter of semi circular protactor=36cm 2πr =36cm 2×22/7×r=36cm. 44r=36cm×7 r=36cmx7/44 r=126/11cm |
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| 22633. |
Tan2A + cot2A = sec2Acosec2A - 2 |
| Answer» V | |
| 22634. |
Find the value of. \'k\'. If the quadratic equation |
| Answer» By putting quadratic formula | |
| 22635. |
If sec(-) + tan(-) = p, then find th value of cosec(-). |
| Answer» {tex}sec\\ \\theta+ tan\\ \\theta = p{/tex} ...(i)Also {tex}sec^2\xa0\\theta - tan^2 \\theta = 1{/tex}{tex}\\Rightarrow{/tex}\xa0(sec\xa0{tex}\\theta{/tex}\xa0- tan\xa0{tex}\\theta{/tex}) (sec\xa0{tex}\\theta{/tex}\xa0+ tan\xa0{tex}\\theta{/tex}) = 1{tex}\\Rightarrow{/tex}\xa0p(sec\xa0{tex}\\theta{/tex}\xa0-\xa0tan\xa0{tex}\\theta{/tex}) = 1[using equation (i)]{tex}\\Rightarrow{/tex}\xa0sec\xa0{tex}\\theta{/tex}\xa0-\xa0tan\xa0{tex}\\theta{/tex}\xa0{tex}=\\frac{1}{p}{/tex}\xa0...(ii)(ii) - (i) we get{tex}-2 tan{/tex}\xa0{tex}\\theta{/tex}\xa0{tex}=\\frac{1-p^{2}}{p}{/tex}{tex}\\Rightarrow{/tex}- tan\xa0{tex}\\theta{/tex}\xa0{tex}=\\frac{1-p^{2}}{2 p}{/tex}{tex}\\Rightarrow{/tex}- cot\xa0{tex}\\theta{/tex}\xa0{tex}=\\frac{2 p}{1-p^{2}}{/tex}cot\xa0{tex}\\theta{/tex}\xa0{tex}=\\left(\\frac{2 p}{1-p^{2}}\\right)^{2}{/tex}{tex}=\\frac{-4 p^{2}}{\\left(1-p^{2}\\right)^{2}}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}cosec^2{/tex}\xa0{tex}\\theta{/tex}\xa0- 1\xa0{tex}=\\frac{-4 p^{2}}{\\left(1-p^{2}\\right)^{2}}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}cosec^2{/tex}\xa0{tex}\\theta{/tex}\xa0{tex}=\\frac{-4 p^{2}}{\\left(1-p^{2}\\right)^{2}}+1=\\frac{-4 p^{2}+\\left(1-p^{2}\\right)^{2}}{\\left(1-p^{2}\\right)^{2}}{/tex}{tex}cosec^2{/tex}\xa0{tex}\\theta{/tex}\xa0{tex}=\\frac{-4 p^{2}+1+p^{4}-2 p^{2}}{\\left(1-p^{2}\\right)^{2}}{/tex}{tex}=\\frac{\\left(1+p^{2}\\right)^{2}}{\\left(1-p^{2}\\right)^{2}}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}cosec\\\xa0\\theta{/tex}\xa0{tex}=\\frac{1+p^{2}}{1-p^{2}}{/tex} | |
| 22636. |
2x + 3y - 5=0,. 6x +ky -15=0 find |
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Answer» Welcome sis Thanks bhai to good K = 9. For what value of k is the infinite solution of following equation body ?2x + 3y- 5 = 0, 6x + Ky - 15 =0 |
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| 22637. |
Give me all chapters marks in matha for 10 standard |
| Answer» Graph 6marks , vividh prasnmala 10marks ,real number 8marks ,mean , mode , median 6 marks, probability 10marks, cunstruction 20marks, road safety 20 marks. | |
| 22638. |
In a figure, angle BTO=30°find angle ATO, Where O is centre of the circle |
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Answer» Yeh class 10 ka hi question hai ! Par language thori unclear hai Kis class main ho app Bhai .... in ATO &BTO TO = TO (common side) angle OBT = angle OAT (=90°) OA = OB (radii) ATO congruent to BTO [SAS]\u200b angle ATO = angle BTO = 30°\u200b |
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| 22639. |
find the quadratic polynomial whose zeroes are (5 + √2) and (5 - √2). |
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Answer» X^2-( alpha + beta)x+(alpha×beta)X^2-(6+root2)x+5-root2 I cn not answer in this phone because in my board alpha and bita are not there |
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| 22640. |
What is the formula of cone |
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Answer» Csa or tsa Good |
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| 22641. |
Find the value of x for which numbers (5x+2),(4x-1)(x+2)are in AP???????? |
| Answer» Since {tex}(5x+2), (4x-1)\\ and\\ (x+2){/tex} are in AP, we have\xa0{tex}(4x-1)-(5x+2)=(x+2)-(4x-1){/tex}{tex}\\Rightarrow{/tex}\xa0{tex}4x-1-5x-2=x+2-4x+1{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}-x-3=-3x+3{/tex}{tex}\\Rightarrow{/tex}\xa02x = 6{tex}\\Rightarrow{/tex}\xa0x = 3. | |
| 22642. |
Find the area of the square that can be inscribed in a circle of radius 8cm. |
| Answer» The radius of circle = 8cmdiameter = 8 × 2 = 16cmThe diameter of circle = diagonal of square = 16cmarea of square = (diagonal)²/2 = 16²/2 = 256/2 = 128cm² | |
| 22643. |
Find the distance between the point (0,0)and (a cos thata ,a sin thata) |
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Answer» 1 It\'ll be 1 UtuIt will 1 Distance will be 1... Distance is 1 O Distance = 1 |
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| 22644. |
Find the zeros of polynomial xsquare minus 7x minus 3 |
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Answer» It is very easy Clear ho gya First find a, b and c then the value of a,b and c in quadratic formula. - b ± √b²-4ac/2a Plzz give ur solution Rishabh ji This equation is solve by quadratic formula X = 7 ± √61/ 2 Check your question |
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| 22645. |
What is the value of a for which (3,a)is on 2x--3y=5 |
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Answer» Answer with whole process Sulution not answer 1/3 |
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| 22646. |
What is the figure for - a cylinder with raised hemisphere? |
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| 22647. |
A tringle is given there side are 2 3 4 prove that it is titeangletringle |
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Answer» thats not possible .sguare of 4 isnt equal to sum of square of 2 and 3 This is not possible because it is not phythagorian tripletMeans sq.of small two digits is not equal to yhe sq.of large digit.i.e Sq.of2+sq.of3=13Sq.of4=16Which is not equal. |
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| 22648. |
Give reason.Why maths is boring.mental subject |
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Answer» yes, we understand all maths but we have to do more and more practice. Anyone online Same here i too like maths No maths is not boring..... It is an interesting subject...... I like maths...... ?? Because it refresh and do exercise of our brain in a boring manner. Maths not a boring subject but it is hard when we do not practice |
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| 22649. |
Prove that the tangents drawn at the ends of diameter of a circle are parallel |
| Answer» Given: PQ is a diameter of a circle with centre O.The lines AB and CD are the tangents at P and Q respectively.To Prove: AB {tex}\\parallel{/tex} CDProof: Since AB is a tangent to the circle at P and OP is the radius through the point of contact.{tex}\\therefore{/tex}{tex}\\angle{/tex}OPA = 90o ........ (i)[The tangent at any point of a circle is\xa0{tex}\\perp{/tex} to the radius through the point of contact]{tex}\\because{/tex}\xa0CD is a tangent to the circle at Q and OQ is the radius through the point of contact.{tex}\\therefore{/tex}{tex}\\angle{/tex}OQD = 90o ........ (ii)[The tangent at any point of a circle is {tex}\\perp{/tex} to the radius through the point of contact]From eq. (i) and (ii), {tex}\\angle{/tex}OPA = {tex}\\angle{/tex}OQDBut these form a pair of equal alternate angles also,{tex}\\therefore{/tex}\xa0AB {tex}\\parallel{/tex} CD | |
| 22650. |
Formulas of chapter polynomial and linear equation |
| Answer» I have that formulas pic how can i send u | |