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22651.

Pls tell chapter vise waitage for board exam of class 10 maths

Answer» You can see by this app only
Number system - 06, Algebra - 20, Coordinate geometry - 06, Geometry - 15, Trigonometry - 12, Mensuration - 10, Statistics and probability - 11 hope it will help you ☺☺☺☺☺
22652.

If sec theta +tan theta=p then find value of cosec theta.

Answer» Hey I got the answer it can be solved by sec square - tan square theta
Hi , sorry I am not getting your point.
Hi
P square +1/p square -1 and -1
22653.

4/x –3=5/2x+3

Answer» 4/x-3=5/2x+34/x-5/2x=68x-5x=12x²3x=12x²3=12x²/x3=12xX=3/12X=1/4
22654.

1x+2y

Answer» I agree with rashi
Right
Jazzy aap plz ek baar check kar lo ki question thik hai ya nhi,may be question incomplete hai.
It has no answer because in this equation two variable
22655.

Use Euclid division leema to show that cube of any positive integer is of the from 9m,9m+1or9m+8

Answer» According to Euclid Division Lemma,a=bq+r,b
Let x be any positive integer. Then, it is of the form 3q or, 3q + 1 or, 3q + 2.So, we have the following cases :Case I : When x = 3q.then, x3 = (3q)3 = 27q3 = 9 (3q3) = 9m, where m = 3q3.Case II : When x = 3q + 1then, x3 = (3q + 1)3= 27q3 + 27q2 + 9q + 1= 9 q (3q2 + 3q + 1) + 1= 9m + 1, where m = q (3q2 + 3q + 1)Case III. When x = 3q + 2then, x3 = (3q + 2)3= 27 q3 + 54q2 + 36q + 8= 9q (3q2 + 6q + 4) + 8= 9 m + 8, where m = q (3q2 + 6q + 4)Hence, x3 is either of the form 9 m or 9 m + 1 or, 9 m + 8.

Bshshshghdh
22656.

1-sin01+sin0

Answer» Ya the answer is correct. ( cos square theta).
Hi
=(1-sinΦ)(1+sinΦ)=1-sin²Φ=Cos²Φ
What\'s the question bro I can\'t understand??
22657.

Perimeter of trangle

Answer» Sum of all sides of triangle
Perimeter of polygon = addition of all sidesPerimeter of triangle = Adding all 3 sidesPerimeter of equilateral triangle= 3 × side
AB + BC + CA (add all three sides of ∆)
A+b+c
22658.

If 1 polynomial is divided by other polynomial and get remainder Give me a example with answer

Answer»
22659.

If px squar +3x+q=0 has two roots x=-1,x=-2,find p-q

Answer» Nice
px2 + 3x + q = 0x = 1p + 3 + q = 0p + q = -3 .......... (i)x = -2p(-2)2 + 3(-2) + q = 04p - 6 + q = 04p + q = 6 ........... (ii)Subtract (i) and (ii)3p = 9p = 9/3 = 3Put it in (i)3 + q = -3q = -3 -3q = -6
22660.

Area of the minor segment and major segment

Answer» The segment of a circle divides it into two region namely major segment and minor segment. The segment having larger area is known as the major segment and the segment having smaller area is known as minor segment.Area of minor segment = θ/360 πr2Area of major segment = area of minor segment –Area of triangle\xa0
22661.

8.2

Answer» Which question
Aapka question kya hai Bhai ?
22662.

If the point A(a,2) is equidistant from the points B(8,-2) andC(2,-2),find the value of a

Answer» we have that:AB = ACsoAB² = AC²then:(a-8)² + (2 + 2)² = (a-2)² + (2+2)²a²- 16a + 64 +16 = a²- 4a + 4 +16-16a + 64 = -4a + 4-16a + 4a =4 - 64-12a = -60;12a = 60;a = 60/12 = 5;a = 5The value of a is 5.\xa0
22663.

Cos - sin =✓sin prove that Cos + sin =✓sin

Answer» Ur question may be wrong
22664.

If a/b=b/c then the value of 1/b-c + 1/b-a is ____

Answer»
22665.

How many ordered pairs of (x,y) integers satisfy x/15=36/y?

Answer»
22666.

find the value of r

Answer» Incomplete question...
22667.

Prove that the points (3,0),(6,4),(-1,3)are the vertices of a right angled isosceles triangle

Answer» Given A(3, 0), B(6, 4) and C(-1, 3)AB2\xa0= (3 - 6)2\xa0+ (0 - 4)2\xa0= 9 + 16 = 25BC2\xa0= (6 + 1)2\xa0+ (4 - 3)2\xa0= 49 + 1 = 50CA2\xa0= (-1 - 3)2\xa0+ (3 - 0)2\xa0= 16 + 9 = 25AB2\xa0= CA2\xa0or, AB = CATriangle is isocelesAlso, 25 + 25 = 50or, AB2\xa0+ CA2\xa0= BC2Since, pythagoras theorem is verified, therefore triangle is right-angled triangle.
22668.

If tan A= ntan B and sin A= msinB , then prove that cos squre A = m square -1 / n square -1

Answer» Given,\xa0tan A = n tan B{tex} \\Rightarrow{/tex} tanB = {tex}\\frac{1}{n}{/tex}tan A{tex}\\Rightarrow{/tex}\xa0cotB =\xa0{tex}\\frac { n } { \\tan A }{/tex}..........(1)Also given,\xa0sin A = m sin B{tex}\\Rightarrow{/tex}\xa0sin B =\xa0{tex}\\frac{1}{m}{/tex}sin A{tex}\\Rightarrow{/tex}\xa0cosec B =\xa0{tex}\\frac { m } { \\sin A }{/tex}.....(2)We know that, cosec2B - cot2B = 1, hence from (1) & (2) :-{tex} \\quad \\frac { m ^ { 2 } } { \\sin ^ { 2 } A } - \\frac { n ^ { 2 } } { \\tan ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } } { \\sin ^ { 2 } A } - \\frac { n ^ { 2 } \\cos ^ { 2 } A } { \\sin ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } - n ^ { 2 } \\cos ^ { 2 } A } { \\sin ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow{/tex}\xa0m2 - n2cos2A = sin2A{tex}\\Rightarrow{/tex}\xa0m2 - n2cos2A = 1 - cos2A{tex}\\Rightarrow{/tex}\xa0m2 - 1 = n2cos2A - cos2A{tex}\\Rightarrow{/tex}\xa0m2 - 1 = (n2 - 1) cos2A{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } - 1 } { n ^ { 2 } - 1 } ={/tex}\xa0cos2A
22669.

9609 root

Answer» 98.02
22670.

draw a triangle ABCwith sides 6cm ,8cm,9cm

Answer» First you draw a line of 9cm then take angle on scale of 6 and 8 cm mark an arc then draw a line
22671.

The length of the shadow of a person is √3 times of its hight. Find the angle of elevation of sun

Answer» 30° is angle of elevation of sun ⛅
30°
Let the height of the person be hTherefore, the height of the shadow is /3 h.Tan=h÷/3hTan=1÷/3Tan30=1÷/3Therefore angle of elevation is 30°
22672.

Gdj

Answer» Hi
22673.

The perimeter of a sector of a circle of radius 8 cm is 25 m find the area of sector

Answer» Sry....this solution is wrong
If perimeter and radius is given,we can find the length of the arc.25=8+8+length of arcLength of the arc =25-16=9cmNow we can find the angle of the sector 9cm= angle÷360×2×22÷7×8Angle=5670÷88Area of the sector=angle÷360×22÷7×8×8 =5670×22×8×8÷88×360×7 =36cmsq.
22674.

CosecA+1= cosACosecA-1 1-sinA

Answer»
22675.

Tignomentri me kitne formule h

Answer» अनगिनत
22676.

If sinA=1/3 then find the value of 2 cot2A +2

Answer» 18....
22677.

Sin2/sin7

Answer» Sin of small angle is same as the angles so here the value is 2/7
22678.

Chapter 14 in maths question important

Answer» Example 8 this type of questions Will come and exercise 14.3 question 2 and exercise 14.3 is very important one question of 5 marks will come always
In NCRT book
22679.

Cos +tan/sin+cos 1

Answer» What is the 1,^or°
22680.

55.23 + 23.56

Answer» 78.79
78.79
78.79
22681.

draw a line segment of length 7.6 cm and divide it in the ratio 5:8 measure the parts

Answer» Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and ∠ABC = 60°. Then construct a triangle whose sides are of the corresponding sides of the triangle ABC.triangle whose sides are times the corres ponding sides of the isosceles triangle.
answer?
22682.

X=p sec+q tan and y=p tan +q sec prove x^2-y^2=p^2-q^2

Answer»
22683.

Find points at which ,pair of equations x=a and y=b intersect, when graphically represent

Answer» intersecting at (a, b)
22684.

How score 100% maths.

Answer» Learn all formula and lots of practice again and again....... Keeps practice........
Do pratice again and again
Just keep studying ,u will score best
Work out well
22685.

Sin theta equal to cos theta then find the value of theta

Answer» Usme baat krege
Apna ek ques. Send kr
Kumkum
Hii
Hlo shivangi & Sushma
Thete = 45°
45
22686.

State the fundamental theorem of arithematic

Answer» Thanks karuna
Every composite number can be expressed as a product of primes ,and this factorisation is unique,apart from the order in which the prime factors occur
22687.

If cosec theta + Cot theta = x , find the value of cosec theta - Cot theta

Answer» By identity cosec2a - cot2a =1Using identity a2-b2=[a+b][a-b] we have(Coseca+cota) (coseca- cota)=1 (by identiy at top)= x(coseca- cota)= 1( given =x)(coseca-cota)= 1/x ANSWER!!
Cosec²Q-Cot²Q= 1...(CosecQ-CotQ) x (Cosec+CotQ) = 1....(CosecQ-CotQ) X (x) = 1.....CosecQ-CotQ = 1/x..
22688.

2x+

Answer»
22689.

Find the distance between the points (a cos thita , a sin thita ) and ( - a cos thita , a sin thita)

Answer» How u do this sushma ca u explain
2cos thita
Please answer me
22690.

Find the value of cos([email\xa0protected])[email\xa0protected]÷[email\xa0protected]

Answer»
22691.

Whai is polynomial

Answer» It is a degree of constant
Polynomial is a degrre of constant
22692.

proof ^5.is.iresenal

Answer» It is √5 is irrational prove that
22693.

Find the value of p for which one of quadratic equation pxka square - 14x+a =0 is 6 times the other

Answer» Let\xa0{tex}\\alpha{/tex}\xa0and\xa0{tex}6\\alpha{/tex}\xa0be the roots of equation.We have, {tex}px^2-14x+8=0{/tex} where a= p, b = -14, c = 8Sum of zeroes{tex} = -\\frac ba = -\\frac{-14}{p}{/tex}{tex}\\alpha +6\\alpha=\\frac{14}{p}{/tex}{tex}7\\alpha = \\frac{14}{p}{/tex}{tex}\\alpha = \\frac2p{/tex}............(i)Also, Product of the zeroes\xa0{tex} = \\frac 8p=\\frac ca{/tex}{tex}\\alpha \\times 6\\alpha = \\frac 8p{/tex}{tex}6\\alpha^2=\\frac 8p{/tex}From (i){tex}6(\\frac{2}{p})^2=\\frac 8p{/tex}{tex}6\\times \\frac {4}{p^2}=\\frac 8p{/tex}{tex}\\frac{6}{p^2}=\\frac2p{/tex}{tex}\\frac 62=\\frac{p^2}{p}{/tex}{tex}Hence, \\ p=3{/tex}
22694.

Derivation

Answer» Of what
22695.

Prove of theorem 6.3 of ch6 in ncert book

Answer» Ye to book me hai hi
22696.

Ogive method from stats Ch.

Answer» Means???
22697.

Tan1(

Answer» Pls tell me what the method of ogive from stats Ch.
22698.

cbse deleted lessons

Answer» In mathematics all the 15 chapters are coming none of the chapter is deleted.
22699.

(a+b) (a-b) =

Answer» a2-b2
22700.

Can the 6n ,n being a natural number ,end with the digit 5 ? Give reason

Answer» No , as any no. ending with 5 have its multiples An odd number and 5 . Here 6 is even so it is not possible