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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 22951. |
What is the value of sin 18 |
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Answer» Convert 18⁰ into radiant angke and use pythagoras theorem Cos(90°-18°) *cos(90°-18°) (90°-18°) It isnt there in 10th syllabus but u can write it as cos (90°-18°) |
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| 22952. |
prove circle circumscribing a rectalgle is a square |
| Answer» First draw a circle under square give the point name a of square a,b,c,d and circle point p,q,r,s.as=aq1equation,bs =br2equation,dp=dq3equ,pc =pr 4equation. Reason tangent drawn from external point ate equal.by adding all the equation we have,ab+dc=ad+bc.so,ab=dcand ad =bc hence ab =ad which are the opposite side of square. Hence proved | |
| 22953. |
In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550.Find the AP |
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Answer» Given:Sum of first ten terms of an AP = -150Sum of next ten terms of an AP =-550To find:APSolution:Sum of n terms of an AP Sum of first 10 terms -150 = 5(2a+9d)-150=10a+45d…..(i)Sum of next 10 terms -150-550=10(2a+19d)-700=10(2a+19d)-70=2a+19d …….(ii)Combining 1 and 2, we getMultiplying (ii) by 5-350=10a+95d….(iii)Subtracting (i) from (iii) we get,-350+150=10a+95d-10a-45d-200=50dd=-4substitute d=-4 in equation (i) we get-150=10a+45d-150=10a+45(-4)-150=10a-18010a=-150+18010a=30a=3hence, a=3 and d=-4The AP will be a, a+d, a+2d, a+3d,…Then the AP will be 3, -1, -5, -9,…." Given:Sum of first ten terms of an AP = -150Sum of next ten terms of an AP =-550To find:APSolution:Sum of n terms of an AP Sum of first 10 terms -150 = 5(2a+9d)-150=10a+45d…..(i)Sum of next 10 terms -150-550=10(2a+19d)-700=10(2a+19d)-70=2a+19d …….(ii)Combining 1 and 2, we getMultiplying (ii) by 5-350=10a+95d….(iii)Subtracting (i) from (iii) we get,-350+150=10a+95d-10a-45d-200=50dd=-4substitute d=-4 in equation (i) we get-150=10a+45d-150=10a+45(-4)-150=10a-18010a=-150+18010a=30a=3hence, a=3 and d=-4The AP will be a, a+d, a+2d, a+3d,…Then the AP will be 3, -1, -5, -9,…." So .. Given that Sum of first 10 terms is -150 and of next 10 is -550 soS10 =-150-150 = 10/2(2a+(10-1)d=2a+9d = -30 .....(1) And again given that sum of next ten terms is -550So -150 +(-550)=-770-770= 20/2(2a+(20-1)d)=2a+19d=-70......(2)By applying elimination b/w bothWe get 10d = -40d= -4...Putting d=-4 in eq 1....2a+9(-4) = -302a-36 =-302a = 6 a = 3So Ap would be .... 3 , -1,-5,-9,..... Hope it will help you:)..... Have a nice day !! |
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| 22954. |
If 2under root 45 + 3 under root 20 upon 2 under root 5 on simplification give rational or irational |
| Answer» It gives rational number and the answer is 6 | |
| 22955. |
If sin theta minus cos theta is 0 then find the value of sin4theta plus cos 4 theta |
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Answer» 8cos theta Hiii 1 |
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| 22956. |
Prove that √5 is a unnatural number |
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Answer» So easy So east |
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| 22957. |
R s agarwal ch 2 page 51 examples 1 |
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| 22958. |
m-0.25n+1by2-(-n)+2m+3by2n-5by4n |
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| 22959. |
Is standard paper means regular paper? |
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Answer» If we have opted for standard, we should be prepared for questions of a higher profile question set, i.e. beyond NCERT level. (If we wanna score.) Yes, this paper level is most likely to the level of previous ones |
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| 22960. |
Exercise 2.3 question number 1 sub number 4 |
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| 22961. |
In the figure, Angle BED = Angle BDE and E is the mid-point of BC. Prove that AF/CF = AD/BE. |
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| 22962. |
What is the value of π? |
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Answer» 22/7 3.14 22/7 or 3.14 22/7 or 3.142857142857143\u202c or 3.14 22/7 |
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| 22963. |
Exerice 10.2 |
| Answer» 12 13 10 | |
| 22964. |
Exerice 10.2 13 12 10 9 |
| Answer» Exerice 10.2 12. 13. 10. 9 | |
| 22965. |
The first term of an A.P is -7 and the common difference 5, find its 18th term and general term |
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Answer» a=78 and general term=5n-12 Exerice 10.2 13 12 11 10 9 78 |
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| 22966. |
Show that sec⁴A(1- sin⁴A) - 2tan²A = 1 |
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| 22967. |
The first and the last term of an ap are 17 and 350 respectively. If the common difference is |
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Answer» Q is wrong A |
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| 22968. |
CosQ = underroot y2 - p2Find the value of sinQ+CosQ Sir plzz solve step by step |
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| 22969. |
Which term of an ap 6 13 20 27 is 98 more than its 24th term |
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Answer» a24=a+23da24=6+23*7a24=6+161a24=167an=a24+98an=167+98a+(n-1)d=2656+(n-1) 7=265(n-1)7=259n-1=37n=38 I know the answer but I want solution of this question 38th |
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| 22970. |
Pythagoras theroum |
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Answer» Hey how r u sis....? Hii☺ Hello sis.... The square of hypotenuse is equal to the sum of square of base and perpendicular.. |
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| 22971. |
Some of those integer between1 and 500 which are multiples of 2 or 5. |
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Answer» Total term=49 Sorry 12250** If \'and\' then 10500 is correct answer.? Or ya and? |
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| 22972. |
Prove that for any positive integer n,n3-n is divisible by 6. |
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| 22973. |
In the figure angle A =90° , AD perpendicular to BC . If BD=2 and CD =8 ,find AD. |
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Answer» AD=4 Where is figure |
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| 22974. |
Prove that:sinA-cosA+1/sinA-cosA-1=1/secA-tanA |
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| 22975. |
Bpt theroum |
| Answer» If a line is drawn parallel to one side of a triangle interesting the other two sides, than it divided the two sides in the same ratio. | |
| 22976. |
State and prove basic proportionally theoram |
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Answer» Hi If a line is drawn parallel to one side of triangle interesting the other two sides, then it divides the side in the same ratio State and prove basic proportionally theoram |
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| 22977. |
State and prove basic proportionally theoram. |
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| 22978. |
Math humko samj ma nhi aata ha jaldi bato |
| Answer» Dont worry about it. Math seems tough but try to solve the chapters one by one calmly. For boards, go through your textbook thouroughly and you\'re good to go! Textbook is more than enough for boards. | |
| 22979. |
How to find the cf for median |
| Answer» Frequency1 ko freq 2 main plus krna hai and visa versa | |
| 22980. |
What is the value of sin 0 |
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Answer» 0 0 0 0 0 O 0 |
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| 22981. |
C f 135 and 225 nuclear division |
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Answer» I think CF=HCF AND NUCLEAR =Euclids i suppose its euclids division lemma??? |
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| 22982. |
In a isoceles traingl abc,ab=ac and bd perpendicular to ac.prove that (b²-cd²)=2cd×ad |
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| 22983. |
If nth term of an AP is an+b then its common difference is |
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Answer» You have to find it. a |
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| 22984. |
How many tangents can a circle have ? |
| Answer» Infinite.. | |
| 22985. |
All previous cbse board question paper with solution |
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| 22986. |
Plzz give me link 2018-19 official sample paper cbse last year |
| Answer» check cbse.nic.in and you can also get from this app..? | |
| 22987. |
If HCF of (26,169)=13,them LCM (26,169)is |
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Answer» H.C.F× L.C.M=product of two numbers 13×L.C.M=26×169. L.C.M=4394/13. L.C.M= 338 is a answer. Hello..? Oh ..hello and sorry? Vand ? who?? 338 (26×169)/13 =338 |
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| 22988. |
Formulas of sphere and hemisphere Please |
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Answer» Thanks TSA of sphere=4 ×22/7 r^2 CSA of hemisphere=2×22/7r^2 and. Volume of sphere = 4/3×22/7 r^3 Sphere:Surface area = 4πr^2Volume = 4\\3πr^3Hemisphere:TSA = 3πr^2CSA = 2πr^2Volume = 2\\3πr^3 |
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| 22989. |
Water tap |
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| 22990. |
Prove Thales therom |
| Answer» It is already proved? | |
| 22991. |
Without using trigonometric tables prove that : tan 1, tan 11, tan 21, tan 69, tan 79,tan 89 =1 |
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| 22992. |
tan 49/cot41+2cot50/tan 40+4+sin2-(2-cos2)/tan3tan17tan 73tan87 |
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| 22993. |
Sin30°+tan45°-cosec60°/sec30°+cos60°+cot45° |
| Answer» 43 - 24√3/11 | |
| 22994. |
2cos^2θ-1÷sinθcosθ=cotθ-tanθ |
| Answer» LHS - 2cos^2theta - (cos^2 theta + sin^2 theta) / sintheta × cos theta => cos^2 theta - sin^2 theta / sin theta × cos theta => [cos^2 theta/sin theta × cos theta ] - [sin^2 theta/ sin theta × cos theta ] => (cos theta / sin theta) - (sin theta / cos theta) => cot theta - tan theta... | |
| 22995. |
Find the distance of point (3,-8) from x axis |
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Answer» 8 units 8 units.. |
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| 22996. |
Ax/b-by/a=a+b :ax-by=2ab |
| Answer» x=a and y=-b | |
| 22997. |
Which chapter will be suitable for maths project?Chapters 1-15...ncert textbook.. |
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| 22998. |
A______ is a polynomial of degree zero |
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Answer» 1 2 Constant polynomial ? |
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| 22999. |
If one zero of the polynomial f(x) = (k^+9)x^ +13x +6k is reciprocal of other the k = |
| Answer» Given ÷ Alpha=1/beetaProof ÷Alpha=1/beeta=1=aplha×beeta=1=c/a ( alpha × beeta = c/a )Therefore , a = c ....eq1Here , a =( k+9)c = 6k Therefore, from equation 1...K+9=6k9=5kK=9/5 | |
| 23000. |
How many formulas are there in trigonometry |
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Answer» Bahut sare ???? So many So much ❤️???????????? Soooooo many ???? |
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