Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 23001. |
A÷b_ab_cd=0 |
| Answer» | |
| 23002. |
a+b=-b/a then a-b=? |
|
Answer» mistake, ab instead of 2a2 -b-2a2/a |
|
| 23003. |
26×6 |
| Answer» 156 | |
| 23004. |
Define...cohesion...and tension.... |
|
Answer» tension is the force when an object is held perpendicular n cohesive is with its contact I hate everyone koi baat mt krna mujhse ab ohh to mai acting krra hu thik hai sorry bye Byee ??.. mere pass inna dimak ni h jo... Apki inni sad sad story sunu..??har har Mahadev.. mera dimaag kharaab hora hai... sb mere saath aesa kyu krte hai mai hi sbse buri kismat wala insaan hu Bye!? Broken buddy ji kayko overacting kr rahe ho... Diku n toh kuch bola bhi ni ... Phir bhi boleja rahe ho? Hi suhu ??? nhi nhi haan mene dekh liya na? Ni yrr sb mere baare mai bura soxhne lage hai? Sis.. sorry n dikshu sb kyu krre hai mere saath aesa mujbe koi kyu ni samajta? Ya Sachi yaarr M ni naraj hu aseem ,yha ans ni show ho re Ni bhai...aap.itna kyo sad rhte ho M kyu bura manu... Aapki marji yrr plzzz n sb naraz hore hai mujhse ab aap sb to mt hoo n ? Ok..sis.. Ok..tumhre kl wale q me Bhai brainly p hi aa jao ye had se jyda slw h &% Hii aseem Hii sister agr aapko meri baat ka bura laga to sorry? Hlw bhai Hmm ... $ Hii mene ni kaha aapne disturb kiya ...isliye hi aaya tha kyuki aapne kaha tha sorry aaya ab ni aunga? ? Yo yo??? Jana h toh jao,I will not disturb u agr koi khaas baat hai to batao nhi to mai jau? mai kisi se naraz nhi Yo yo ?☝?☝??????????????diksha Why broken? Mera khne ka mtlb tha aap nraj ho kya mujhse jo aaj kal ache se baat ni krte... aap kehri thi aata ni aajkl batao aapko mujhse kuch kehna tha? ,,, Aaj kal inne sad kyu rhte ho ... Hlwww hi Tension is a situation in which our mind stops working and we get highly dependent upon god?✌ |
|
| 23005. |
CotA-casA/cotA+cosA=cosecA-1/cosecA+1 |
|
Answer» How to find distance from origin U understand or not Change it terms of sin and cos then if not coming i will solve ( vasu Yadav) |
|
| 23006. |
Plz answer me !! Solve for xa/x-b +b/x-a = 2Plz solve asap |
| Answer» X2-2x-k=0 | |
| 23007. |
Find value of cos 60 geometrically and find cosec 60 |
| Answer» This question is not given by the board pattern of cbse | |
| 23008. |
I mark questions |
| Answer» | |
| 23009. |
Of 4/5,a,2 are three consecutive terms of an A.p ,then find the value of a. |
|
Answer» Then solve it Take the 3 consecutive term as a-d , a, a+d Hi sir As they\'re said to be in ap the common difference is the same. So a-4/5=2-a solving this eqn, you will geta=7/5 A=7/5 |
|
| 23010. |
Hcf of 123 and 145 |
|
Answer» Q 1 1 1 Hcf=1 1 1 1 |
|
| 23011. |
Given that a right angle triangle ABC, D and ई trisect BCto prove - 8AEsquare =3ACsquare +5ADsquare |
| Answer» | |
| 23012. |
If One root of equation (k-1)x2 - 10x + 3 =0 is the reciprocal of the other, then the value of is |
|
Answer» Thanks ? Beta=1/alphaGeneral form x^2-(sum of zeroes)x+(product of zeroes)(K-1)x^2-(alpha+1/alpha)x+(alpha*1/alpha)Given the eqn,Alpha*1/alpha should be 3So, x=1/3 (k-1)(1/3)^2-10(1/3)+3On solving, you getk=4 K=4 |
|
| 23013. |
What changes occur in madame loisel after 10 years |
| Answer» | |
| 23014. |
How much difference between the basic and standard paper |
| Answer» Standard-Level and Basic-level Question papers shall be based on the same syllabus. However the Standard-Level Mathematics assesses higher Mathematical abilities compared to Basic-Level. Accordingly, the difficulty level of the Mathematics – \'Basic\' is less than that of Mathematics-\'Standard\'. | |
| 23015. |
Pls any body tell me that is for standard maths 6.6 is necessary optional |
|
Answer» Yes.. Do it come to exam ? Reply fast |
|
| 23016. |
Sir this year in maths optional questions will come.. Tell me please very much confusion is there |
|
Answer» How you know bro.. Yes sir...?..It\'ll come.. |
|
| 23017. |
Theorem 10.2 |
| Answer» | |
| 23018. |
Tan theta barabar0.75 tab sin theta Ka man nikale |
| Answer» | |
| 23019. |
A + b 90 degree and 10 a 3 upon me for then what is the court be |
| Answer» | |
| 23020. |
The distance of the points P{-3,-4} from the X - axis {in units} is |
|
Answer» If coordinates of points defined as P(a,b), then1. The distance of the point P(a,b) from the x-axis is |b| units.2. The distance of the point P(a,b) from the y-axis is |a| units.The given point is P(-3,-4).Here, the x-coordinate is -3 and y-coordinate is -4. It means a=-3 and b=-4. So,1. The distance of the point P(-3,-4) from the x-axis = |-4| = 4 units.2. The distance of the point P(-3,-4) from the y-axis is = |-3| = 3 units.Therefore, the required answer is 4 units. 4 units 4 ubits 4 unit |
|
| 23021. |
Basic maths ke student ko sirf ncert se hi question ayege na ??? Plzz plzz reply |
|
Answer» Also revise RS aggarwal book Yes! Yah Yupp Prepare ncert with examples, optional , and exercises completely. For 70 + Yes , but only 1or 2 questions are of outside |
|
| 23022. |
Determine the AP whose 3 ^rd term is 16 and 7^th term exceeds the 5 ^ th term by 12... |
| Answer» A3=16A | |
| 23023. |
Chapter 13 formule ouestoion |
| Answer» | |
| 23024. |
Sin²60+2tan²45-cos²30 |
|
Answer» 2 Answer is 2 Ans. 2 . |
|
| 23025. |
How to prepare for standard maths exam |
|
Answer» You solve only question bank Yes my special friend is pretty right.....nd i prefer...RS agarwal.....nd all questions of ncert.....must solve past yr papers. Solve ncert with exempler...sample papers as much as you can. Also solve R.D.Sharma or R.S.Aggarwal.. |
|
| 23026. |
The sum of n, 2n , 3n terms of an AP are S1,S2 ,S3 respectively. Prove that S3 = 3(S2 -S1). |
|
Answer» S1= n/2 [2a+(n-1) d]S2= 2n/2 [2a+(2n-1) d] S3= 3n/2 [2a+(3n-1) d] .......(i) S2-S1 = 2n/2 [2a +(2n-1) d] - n/2 [2a+(n-1) d ] = n/2[2a +(2n-1) 2d - 2a -(n-1) d ] = n/2 [2a + ( 4n-2-n+1) d ] = n/2 [ 2a + (3n-1) d ] (ie) 3 (S2-S1) = 3n/2 from (i) Hence proved . S1=a1S2 =a1+a2=n+2n=3nS3 =a1+a2+a3=n+2n+3n=6nLhs=S3=6nRhs=3(3n-n)Rhs=6nLhs=RhsHp It is not possible |
|
| 23027. |
Ab and CD are common tangents to two circles of equal radii prove that AB equal to CD |
| Answer» | |
| 23028. |
Cos45/sec30 +cosec30 |
| Answer» {tex} Value \\: of \\:\\frac{cos45}{(sec30+cosec30)}{/tex}{tex}=\\frac{\\frac{1}{\\sqrt{2}}}{\\frac{2}{\\sqrt{3}}+2}{/tex}{tex}=\\frac{\\frac{1}{\\sqrt{2}}}{\\frac{2+2\\sqrt{3}}{\\sqrt{3}}}{/tex}{tex}=\\frac{1}{\\sqrt{2}}\\times \\frac{\\sqrt{3}}{2(1+\\sqrt{3})}{/tex}{tex}=\\frac{\\sqrt{2}}{\\sqrt{2}\\times \\sqrt{2}} \\times \\frac{\\sqrt{3}\\times (\\sqrt{3}-1)}{2(\\sqrt{3}+1)(\\sqrt{3}-1)}{/tex}{tex}=\\frac{\\sqrt{6}(\\sqrt{3}-1)}{4\\left(\\big(\\sqrt{3}\\big)^{2}-1^{2}\\right)}{/tex}{tex}=\\frac{\\sqrt{6}(\\sqrt{3}-1)}{4(3-1)}{/tex}{tex}=\\frac{\\sqrt{6}(\\sqrt{3}-1)}{8}{/tex}Therefore,Value{tex} \\: of \\:\\frac{cos45}{(sec30+cosec30)}\\\\=\\frac{\\sqrt{6}(\\sqrt{3}-1)}{8}{/tex} | |
| 23029. |
Important chapter to secure 90 percentage |
|
Answer» All stats ,construction,theorems,and ncert exampler All chapters are very very important. But the most asked questions are from algebra (polynomials, linear eqn, quadratic eqn, arithmetic progressions) because they are asked for 20 marks All |
|
| 23030. |
Justification of line segments division |
|
Answer» Good Gggg |
|
| 23031. |
Hin |
| Answer» Tin? | |
| 23032. |
The distance of the point p (3 , -4) from its origin is |
| Answer» 5 units.. | |
| 23033. |
Prove that √1+sinA/1-sinA = secA + tanA |
| Answer» LHS = √(1 + sin∅)/√(1 - sin∅)= √(1 + sin∅) × √(1 + sin∅)/√(1 -sin∅)×√(1 +sin∅)= √(1 + sin∅)²/√(1 -sin²∅)= (1 + sin∅)/√cos²∅= (1 + sin∅)/cos∅= 1/cos∅ + sin∅/cos∅= sec∅ + tan∅ = RHS | |
| 23034. |
Find the area of the triangle whose vertices are :(2,3), (-1,0) (2 -4) |
|
Answer» 21/2 1/2 | 2{(0-(-4)} + (-1)(-4-3) + 2(3-0) | |
|
| 23035. |
If lines given by 3x+2y=9and 2x+5k=0 are parallel then find the value of k |
| Answer» | |
| 23036. |
Second term of an A.P. is 7and the common difference is 4.find the 10th term |
| Answer» second term=7common difference =4second term=a+da+4=7a=7-4a=3So, tenth term=a+9d= 3+9(4)= 3+36= 39Step-by-step explanation:second term=first term+common differencenth term =a+(n-1)dHeren=10n-1= 10-1=9so tenth term= a+9d | |
| 23037. |
Standerd paper ke liye ncert karenge to hoga |
|
Answer» Of course hoga No bro you have to do at least rs or rd Only maths ncert krenge to hoga na ?? Hn bro...... |
|
| 23038. |
Pre final paper |
| Answer» | |
| 23039. |
X2+23 |
| Answer» | |
| 23040. |
Solve the differential equation (x2+3xy2+y2)dx-x2dy |
| Answer» | |
| 23041. |
If 1+sin^2A=3sinAcosAThen prove that tanA=1or1/2 |
| Answer» | |
| 23042. |
9[52-{65+(53-98)65}78] |
| Answer» | |
| 23043. |
Q no 4and5 exercise no 13.4 |
| Answer» | |
| 23044. |
Explanation of the chapter coordinate geometry |
|
Answer» Ryt??? There are just 3 formulas rt lo |
|
| 23045. |
Sin^6alpha+cos^6alpha=1-3sin^2alpha+3sin^4alpha |
| Answer» | |
| 23046. |
Find the point on y axis which is equidistant from points (5,-2) and(-3,2) |
| Answer» Let suppose the point on Y axis is ASo the A(0,y)(5,-2) = P(-3,2)=QAP²= AQ²..(Equidistant point)By distance formula(0-5)² + [(y-(-2)]²=[(0-(-3)]² + (y-2)²25+y²+4y+4 = 9+ y²-4y+44y +4y=9-25 ......(like term)8y=-16y=-16/8y=-2A(0,-2) | |
| 23047. |
Sin^6alpha+cos^6 |
|
Answer» 1 Sin^6alpha + cos^6alpha =1 1 |
|
| 23048. |
Find the sum of all. The 11term of an ap whose middle most term.is 30 |
|
Answer» We can say that 30 is the Median of 11 terms.thereforewe knowM = (n + 1)/2 th observation for n = oddTherefore the 6th term of this AP is 30Therefore A6 = 30a + 5d = 30therefore we need to find S11Therefore S11 = n/2(2a + (n-1)d)=11/2(2a + 10d)=11/2(2(a + 5d)replacing value=11/2(2(30))=11 * 30=330therefore Answer is 330 330 |
|
| 23049. |
If cosA+cos2A=1 then the value of sin2A+sin4A is |
| Answer» 3CosA | |
| 23050. |
Give me some hint to make maths lab manual . |
| Answer» | |