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23901.

X^=2^x+1

Answer»
23902.

Sn denote the sum of the first n terms of an a.p prove that S12=3(S8-S4)

Answer» So easy......S12 = n/2 ( 2a + (n - 1)d )S12 = 12/2 ( 2a + (12 - 1)d )S12 = 6 (2a + 11d)S12 = 12a + 66dSimilarly , we find value of S8 and S4S8 = 8a + 28dS4 = 4a + 6d3(S8 - S4)3( 8a + 28d - 4a - 6d)3( 4a + 22d)12a + 66d12a + 66d = S12S12 = 3(S8 - S4)Hence , proved.???
23903.

25 + 40 / 3

Answer» 38.3 or 115/3
23904.

25

Answer» Bauki
23905.

Explain why 7*11*13+13 is a composite number?

Answer» 7 × 11 × 13 + 13Take 13 common there we get\xa0= 13(7 x 11 +1 )= 13(77 + 1 )= 13(78)It is the product of two numbers and both numbers are more than 1. So, it is a composite number.
23906.

Find the discriminent of the quadratic equation 2x square _4x+3

Answer»
23907.

Formula of a4 +a4

Answer»
23908.

Koi trick h Jo trego ki identity achey se aa jae

Answer» Try kiya par clear nahi h
23909.

lateral surface area of cone

Answer» πrl
23910.

Difference between infinity,not defined and undefined

Answer» Infinity is the term we apply to a value which is greater than any finite value we can specify.Undefined means that the value can not be derived using standard rules and that it has not be defined as a special case with a special value; typically this occurs because a standard operation can not be meaningfully applied.
23911.

To proove angle bisector theoram

Answer»
23912.

How to prove Pythagoras theorem

Answer»
23913.

8root3 Cosec square30degree sin60degree cos60degree cos square30 degree solution

Answer»
23914.

3xy+5yz-7zxfrom5xy-2yz-2zx+10xyz

Answer»
23915.

All ncert formula class 10th

Answer» Check formulae in notes :\xa0https://mycbseguide.com/cbse-revision-notes.html
23916.

If A,B,&C are interioer angles of triangle ABC theN show that since [B+C÷2]=cos A

Answer» \xa0A, B, C, are interior angles of a\xa0{tex}\\Delta {/tex}{tex}\\because A + B + C = 180 ^ { 0 }{/tex}{tex}\\Rightarrow B + C = 180 ^ { 0 } - A \\Rightarrow \\frac { B + C } { 2 } = 90 ^ { 0 } - \\frac { A } { 2 }{/tex}{tex}\\Rightarrow \\sin \\frac { \\mathrm { B } + \\mathrm { C } } { 2 } = \\sin \\left( 90 ^ { \\circ } - \\frac { \\mathrm { A } } { 2 } \\right) \\left[ \\because \\sin \\left( 90 ^ { 0 } - \\theta \\right) = \\cos \\theta \\right]{/tex}{tex}\\Rightarrow \\sin \\frac { \\mathrm { B } + \\mathrm { C } } { 2 } = \\cos \\frac { \\mathrm { A } } { 2 } \\text { proved }{/tex}LHS = RHS
23917.

Write the empirical relationship between the three measures of central tendency

Answer»
23918.

X² -X+3

Answer» Try eq. b×b - 4ac
23919.

Derive csa,tsa and volume of frustum of cone.

Answer»
23920.

(x)²+[x²÷(x+1)²]=3Solve for the value of x

Answer»
23921.

Cos70/sin20+cos55 cosec35/tan5tan25tan45tan65tan85

Answer» Answer is 2.
23922.

0.65×15

Answer» 9.75 may be
23923.

What is integers

Answer» An integer is a whole number (not a fractional number) that can be positive, negative or zero. Examples of integers are: -5, 1, 5, 8, 97etc.
Integers are the group of positive and negative numbers
23924.

Any idea when our cbse exam would start?

Answer» 8 march
May be 1st week of march..
23925.

The sum of 4th and 8th term of is 24 and the sum of 6 th and 10 th term of is 44 .Find AP

Answer» -13,-8,-3,2,7
23926.

From which book other than ncert do you study mathematics.?

Answer» R d shrma sbse hard boooook h kase bna lete ho???
Rd sharma
23927.

Ek suggestion chahiye sb ??

Answer» Ky
23928.

CSA OF hollow HEMISPHERE

Answer» Curved surface area of hemisphere =\xa0{tex}2\\pi {r^2}{/tex}As the Hemisphere is the half part of a sphere, therefore, the curved surface area is also half that of the sphere.
23929.

If one zero of polynomial 3xsquare-8x+2k+1is seven time find the value of k

Answer» Let\xa0{tex}\\alpha{/tex}\xa0and\xa0{tex}\\beta{/tex}\xa0be the zeroes of the polynomial,\xa0{tex}3x^2-8x+2k+1{/tex}Given,\xa0{tex}\\beta = 7 \\alpha{/tex}{tex}\\therefore \\quad \\alpha + 7 \\alpha = 8 \\alpha = - \\left( - \\frac { 8 } { 3 } \\right)=\\frac{8}{3}{/tex}So,\xa0{tex}\\alpha = \\frac { 1 } { 3 }{/tex}and\xa0{tex}\\alpha \\times 7 \\alpha = \\frac { 2 k + 1 } { 3 }{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}7 \\alpha ^ { 2 } = \\frac { 2 k + 1 } { 3 }{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}7 \\left( \\frac { 1 } { 3 } \\right) ^ { 2 } = \\frac { 2 k + 1 } { 3 }{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}7 \\times \\frac { 1 } { 9 } = \\frac { 2 k + 1 } { 3 }{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { 7 } { 3 } - 1 = 2 k \\quad \\Rightarrow 2 k = \\frac { 4 } { 3 }{/tex}{tex}\\therefore k=\\frac{2}{3}{/tex}
23930.

Circle chapter ka important theorwm

Answer»
23931.

Find the area of a circle whose circumference is 22 cm.

Answer» Let r be the radius of the circle. It is given that the circumference of the circle is 22 cm.Now, Circumference = 22 cm{tex}\\Rightarrow2 \\pi r = 22{/tex}{tex}\\Rightarrow 2 \\times \\frac { 22 } { 7 } \\times r = 22{/tex}{tex}\\Rightarrow r = \\frac { 7 } { 2 } \\mathrm { cm }{/tex}Area of the circle =\xa0{tex}\\pi r ^ { 2 } = \\frac { 22 } { 7 } \\times \\frac { 7 } { 2 } \\times \\frac { 7 } { 2 }{/tex}cm2\xa0= 38.5 cm2
23932.

Which book did I read for board exam ncert,r.s agarwal or r.d sharma

Answer» Ncert and rs agrawall is good for board..
23933.

Can two numbers have 18 as their hcf and 380 as their lcm give reason

Answer» We know that HCF of two numbers is a divisor of their LCM. Here, 18 is not a divisor of 380.But 380 = 18×21+2Here 2 is remainder so 380 is not divisible by 18.So, 18 and 380 cannot be respectively HCF and LCM of two numbers.
23934.

Find the value of k so that 8k+,6k-2and 2k+7 will form AP

Answer» if 8k=a 6k-2 =b 2k+7=c . wkt in an ap 2b=a+c2(6k-2)=2k+7+8k12k-4= 10k+72k=11k=5.5
23935.

If a,b,c,d,e and f are in AP,then e-c is equal to

Answer» According to the question, we have\xa01st term = a and common difference = 3{tex}\\therefore{/tex}\xa0b = a + 3, c = a + 2(3) = a + 6d = a + 3(3) = a + 9,e = a + 4(3) = a + 12Now, e - c = (a + 12) - (a + 6) = 6
23936.

Solve for x :=:2(2x+3/x-3) -25(x-3/2x+3) = 0Answer fast plese

Answer»
23937.

in each of the following find value of k 1- (7,-2),(5,1),(3,k)

Answer» (7, –2), (5, 1), (3, k)Area of the triangle{tex}= \\frac{1}{2}{/tex}[7(1 – k) + 5(k – (–2)) + 3(–2 – 1)]{tex}= \\frac{1}{2}{/tex}[7 – 7k + 5k + 10\xa0– 9]{tex}= \\frac{1}{2}{/tex}[8 – 2k] = 4– kIf the points are collinear, then area of the triangle = 0{tex}\\Rightarrow{/tex} 4 – k = 0{tex}\\Rightarrow{/tex} k = 4
23938.

Is NCERT BOOKOR R S AGGARWAL BEST FOR MATHS CBSE BOARD EXAM

Answer» Both are best for solving maximum questions in exam
Both
Both
Please study rd sharma, it is best supportive book with challenging questions...
23939.

Which book is best for cbse board maths exam ...?

Answer» Rd or rs but first refer ncert
Rs aggarwal
23940.

The value of is

Answer»
23941.

For some integer m, every even integer is of the form.

Answer» 3m or 3m+1
23942.

For some integer m every

Answer»
23943.

How to find the area of segment?

Answer» Pie^2A/360 - 1/2 sin^2A
By using formula
23944.

If sum of zeroes of polynomial is 100 then find quadratic polynomial

Answer»
23945.

Prove that 5 is a irrational number.

Answer» Let us assume √5 as rational number √5 =a/b where a and b are Co primesSquaring both sides5 =a2/b25b2 =a2 5 divides a2 5 divides a Let a = 5c 5= 25c2/b25 divides b2 5divides b Therefore a nb have common factor as 5But this this lead to to contradiction because a nb have no common factor other than 1 Therefore our assumption is wrong √5 is irrational
See u any 10 th class book its a simple yrr...
23946.

Write factors of 172

Answer» 172=2x2x43x1
23947.

Find the value of p for which the equation px²-5x+p=0 has equal root

Answer» 25-4p root 2
23948.

Find A if sin(A+36°)=cosA, where (A+36°) is an acute angle

Answer» A is acute angle therefore A must beA+36° = 90°→ A = 90 - 36→ A = 54°
A= 27°
23949.

How many straight line of two point

Answer» Only one
Infinitely many
23950.

If we do divide zero by zero So what is the answer

Answer» In ordinary arithmetic, the expression has no meaning, as there is no number which, multiplied by 0, gives a (assuming a≠0), and so division by zero is undefined. Since any number multiplied by zero is zero, the expression 0/0 also has no defined value, when it is the form of a limit, it is an indeterminate form.