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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 24001. |
The sum of first nth term of AP is 5(n×n)+3n is nth term is 168.Find n and 28th term of Ap |
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| 24002. |
Find the coordinates of point on the x axis which is nearest to point (-2,5) |
| Answer» (-2,0) | |
| 24003. |
Mid point theorm prove |
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| 24004. |
Mid point theorm proved |
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| 24005. |
The height of tower is root 3 times of it shadow.find the elevation of sun. |
| Answer» Let the shadow be x & height be x√3. Then tan theta = x√3/x = √3 = tan 60°Angle of elevation = 60°. | |
| 24006. |
give last exam paer |
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| 24007. |
Explain why 7×11×13×13 are composite number |
| Answer» Because it has more than. 2 factor | |
| 24008. |
Find the value of k for which the equation x²+k(2x+k-1)+2=0 has real and equal roots |
| Answer» Then the Value of x will be =0 | |
| 24009. |
a+b is root of equatio |
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| 24010. |
Board exam me questions konse book ya sample paper se aate h |
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Answer» Ideal and arihant Aree phele ncert hi properly karlo. Oswal karna X am ides ya phir oswal se |
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| 24011. |
Where is the date sheet of this session 2017-18 |
| Answer» In internet | |
| 24012. |
Area of triangle?? .. not using herons formula.. |
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Answer» The sum of three angles is 180 and its formula wil be \'half base into height \'. Half base*hight Root3(side)square Equilateral - root over 3 by 4 into side square Right triangle -1/2*base*height |
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| 24013. |
Realno |
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| 24014. |
A/ax-1 + b/bx-1 = a+b |
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| 24015. |
ABC is a triangle with DE parallel to BC . if AD =2 cm , BD = 4 cm then find the value of DE : BC. |
| Answer» DE||BC so ∆ABC~∆ADE. AD/AB= 2/6= 1/3 & AD/AB = DE/BC = 1/3. | |
| 24016. |
Cos A - sin A +1/ cosA + sinA = cosec A+ cot A |
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| 24017. |
Area of rhombus=?? |
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Answer» 1/2 product of diagonal Prity tm nhi batayege.. 1/2* product of its diagonals. |
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| 24018. |
Solve for x:root of 2x+9+x=13 |
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Answer» means 4 by 3 ans 4÷3 4/3 |
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| 24019. |
ABC is a triangle where angleB=135. Prove that AC sq=AB sq+BCsq+4arABC |
| Answer» Construction:- Draw\xa0{tex}A D \\perp B C{/tex}Proof:-In\xa0{tex}\\triangle ADB{/tex},\xa0By using\xa0Pythagoras theorem, we get\xa0AD2\xa0=\xa0AB2 - BD2\xa0....(i)In\xa0{tex}\\triangle ADC{/tex},\xa0By using\xa0Pythagoras theorem, we get\xa0AC2 = AD2 + DC2{tex}\\Rightarrow{/tex}\xa0AC2 = AB2 - BD2 +(BD + BC)2 [from (i)]{tex}\\Rightarrow{/tex}\xa0AC2 = AB2 - BD2 + BD2 + BC2 + 2BC\xa0{tex}\\times{/tex}\xa0BD{tex}\\Rightarrow{/tex}\xa0AC2 = AB2 + BC2 + 2BC\xa0{tex}\\times{/tex}\xa0BD ...(ii){tex}\\therefore{/tex}\xa0Area of\xa0{tex}\\triangle ABC{/tex}\xa0=\xa0{tex}\\frac { 1 } { 2 } B C \\times A D{/tex}{tex}\\Rightarrow \\quad 2 \\operatorname { ar } ( \\Delta A B C ) = B C \\times A D{/tex}\xa0...(iii){tex}\\because \\angle A B C = 135{/tex}Then,\xa0{tex}\\angle A B D = 180 ^ { \\circ } - 135 ^ { \\circ } = 45 ^ { \\circ }{/tex}In\xa0{tex}\\triangle ADB{/tex}{tex}\\tan 45 ^ { \\circ } = \\frac { A D } { D B }{/tex}{tex}\\Rightarrow \\quad 1 = \\frac { A D } { B D }{/tex}{tex}\\Rightarrow{/tex}{tex}\xa0BD = AD{/tex}\xa0...(iv)from (ii) and (iv){tex}2 a r ( \\triangle A B C ) = B C \\times B D{/tex}\xa0...(v)From (ii) and (v)AC2 = AB2 + BC2 +\xa0{tex}2 \\times 2 a r ( \\triangle A B C ){/tex}{tex}\\Rightarrow{/tex}\xa0{tex}AC^2 = AB^2 + BC^2 + 4ar{/tex}\xa0({tex}\\triangle ABC{/tex}) | |
| 24020. |
NSTSE ka exam kon kon deta h ?? |
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| 24021. |
What is centroid |
| Answer» The centroid or geometric center of a plane figure is the arithmetic mean position of all the points in the figure. | |
| 24022. |
Surface area and volume means |
| Answer» The surface area to volume ratio of an object is the relationship between two measurements. It is the ratio of Surface area to volume. It shows the comparison between the size of the outside of an object and the amount it can hold inside it. Small or thin objects have a large surface area compared to the volume. | |
| 24023. |
Prove that sum of square of two sides of triangle is equal to area of triangle |
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| 24024. |
Probablity of coin till one head and five tails is shown? |
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| 24025. |
Supporting material of class 10 pg 105 question no.24 |
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| 24026. |
If i want to get the height of a hemisphere the how i can find it |
| Answer» The height and radius of the hemisphere are always same | |
| 24027. |
Find a quadratic polynomial 1/4,-1 |
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| 24028. |
If Sum of pth term is q and sum of qth term is p then find sum of( p+q)th term |
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Answer» Don\'t do again these type of comments P +q ki shaadi ke baad )pq aayega |
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| 24029. |
Find the value of k of quadratic equations having two equalRoots k x (x-2)+6=0 |
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Answer» k=6 K = 1 |
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| 24030. |
(1+ CotA+ tan) ( sinA - cosA ) = sinA tanA - cot A cosA |
| Answer» RHS. SinA tanA - CotA CosA SinA *SinA/CosA - cosA * cosA/sinASin2 A /cosA - cos2 A/ sinA (Sin3A -cos3A)/sinA cosA (SinA - cosA) (sin2A. + cos2A + sinAcosA)/sinAcosA(SinA - cosA) ( 1 +sinA + cosA) /sinA cosA(SinA - cos A) ( sinA cosA/sinAcosA + sin2A/ sinA cosA + cos2A/sinA cosA)(SinA - cosA) ( 1 + sinA/cosA + cosA/sinA)(SinA-cosA ) ( 1 +tanA cotA ) = LHS | |
| 24031. |
What is organic compound |
| Answer» any compound that contains carbon | |
| 24032. |
what is the formula of a2+b2 |
| Answer» a^2 + b^2 + 2ab | |
| 24033. |
Any positive integer is of the form n n+1n+2 |
| Answer» On dividing n by 3, let q be the quotient and r be the remainder.Then, {tex}n = 3q + r{/tex}, where {tex}0 \\leq r < 3{/tex}{tex}\\Rightarrow\\;n = 3q + r{/tex} , where r = 0,1 or 2{tex}\\Rightarrow{/tex}{tex}n = 3q \\;or \\;n = (3q + 1) \\;or\\; n = (3q + 2){/tex}.Case I If n = 3q then n is clearly divisible by 3.Case II If\xa0{tex}\\;n = (3q + 1)\\; {/tex} then {tex} (n + 2)= (3q + 1 + 2) = (3q + 3) = 3(q + 1){/tex}, which is clearly divisible by 3.In this case, {tex}(n + 2){/tex} is divisible by 3.Case III If n = {tex}(3q + 2){/tex} then {tex}(n + 1) = (3q + 2 + 1) = (3q + 3) = 3(q + 1){/tex}, which is clearly divisible by 3.In this case,{tex} (n + 1){/tex} is divisible by 3.Hence, one and only one out of {tex}n, (n + 1){/tex} and {tex}(n + 2){/tex} is divisible by 3. | |
| 24034. |
What is the difference between segment and lenght |
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| 24035. |
thales theoram |
| Answer» If a straight line is drawn parallel to one side of a triangle intersecting the other two sides then it divides the two sides in the same ratio. | |
| 24036. |
Tan A/2+ tan B/2 = cot C/2 + cot D/2 |
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| 24037. |
Sin/cot+cosec- sin/cot-cossc |
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| 24038. |
Prove. That2+5_/3is an irrational |
| Answer» If possible let 2 + 5_√3 be rational number and it is in the form of a÷b , where a and b are co- prime number. 2+5√3= a÷b 5√3 = a÷b - 2. √3 = a÷5b - 2. Here , a and b are integer , and a÷5b -2 is rational number , so √3 is rational , but this contradict the fact that √3 is irrational , this contradiction has arisen because of our incorrect assumption that 2 +5√3 is rational , so 2+ 5√3 is irrational . HENCE PROVED | |
| 24039. |
2000000+ 2000 = ? |
| Answer» 2002000 | |
| 24040. |
Answers of pk garg latest |
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Answer» e On dividing x3-5x3+6x+4 by a polynomial gx quotient =x-3 and remainder=4 find gx Middle term split method |
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| 24041. |
cosA+sinA/sinA-cosA |
| Answer» CosA-cosA+sinA/sinA=0+1= 1 | |
| 24042. |
Prove that a centroid of a medium divides it into a ratio of 2:1 |
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| 24043. |
5u×u + 10u find zeros |
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Answer» 5u(u+2)=05u=0. and u+2=0 U=0. and u= -2 Given |
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| 24044. |
5u×u + 10u |
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Answer» ओठृछचःचृछृ Not clear Did u understand... 5u(u+2) so u=1/5 or u=-2 |
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| 24045. |
√13 is an irrational number |
| Answer» Yes, √13 is an irrational number because square root of every prime number is an irrational number. | |
| 24046. |
Prove that √3 irrational |
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Answer» Let us assume that |
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| 24047. |
how to solve trigonometry questions |
| Answer» In proving questions if u r not able to prove L.H.S to R.H.S try solving R.H.S | |
| 24048. |
One number is twice the other and square of other .find the number |
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Answer» Noo No. is 4 which is twice and square of 2 |
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| 24049. |
Sin Thitha - cos thitha=1/2 Find ( sinthitha + costhitha) |
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Answer» ✓3/✓2 √3/√2 |
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| 24050. |
A circle has how many parrellel tangents |
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Answer» Sorry only two 2 Parallel tangents only 2 parallel tangents Infinite |
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