Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 24201. |
If sec a +tan a =x , write the value of sec a- tan a good in terms of x. |
| Answer» | |
| 24202. |
How we can solve question no.5 S.E |
| Answer» | |
| 24203. |
Find the value of x if x+a is a factor of eqn.2x square + 2ax + 5x + 10. |
| Answer» a=2x=-2 | |
| 24204. |
Sir tangent touches only one point of circle or two |
|
Answer» When a chord touch one point of circle is called tangent & touch two points of circle is called secant Only one point of circle |
|
| 24205. |
Hots in math diffuculty |
| Answer» | |
| 24206. |
Statistics board question |
| Answer» | |
| 24207. |
Cos60 value |
| Answer» 1/2 | |
| 24208. |
5*5*8*6*3 |
| Answer» | |
| 24209. |
2*4 |
| Answer» | |
| 24210. |
For 20 students the mess bill will be 7000.for how many days the bill of 8 students will be 4900 |
| Answer» | |
| 24211. |
How to prove bNPT theorem |
| Answer» | |
| 24212. |
What are all the trigonometric ratios |
| Answer» | |
| 24213. |
For what value of k will k+9, 2k-1 and 2k+7 are the consecutive terms of an A.P.? |
| Answer» We know that difference between any two consecutive terms of an AP\xa0is equal{tex}\\therefore{a_2} - {a_1} = {a_3} - {a_2}{/tex}let\xa0{tex}a_1=(k+9), a_2=(2k-1), a_3=(2k+7){/tex}{tex} \\Rightarrow (2k - 1) - (k + 9) = (2k + 7) - (2k - 1){/tex}{tex} \\Rightarrow k - 10 = 8{/tex}{tex} \\Rightarrow k = 18{/tex} | |
| 24214. |
X+1/2-y+4/11=2 and x+3/2+2y+3/17=5 |
| Answer» | |
| 24215. |
Is there any MSQs type ques in board paper |
| Answer» May be in section b of science | |
| 24216. |
Math me intelligent ho jau mai |
| Answer» ??? Nice joke?? | |
| 24217. |
The base of an isosceles triangle measures 80cm and Find the perimeter of triangle |
| Answer» Let each equal side be a cm and base = 80 cmArea =\xa0{tex}\\frac { 1 } { 4 } b \\times \\sqrt { 4 a ^ { 2 } - b ^ { 2 } }{/tex}\xa0sq. units=\xa0{tex}\\frac { 1 } { 4 } \\times 80 \\times \\sqrt { 4 a ^ { 2 } - 6400 }{/tex}\xa0cm2=\xa0{tex}20 \\times \\sqrt { 4 a ^ { 2 } - 6400 }{/tex}\xa0But area = 360 cm2{tex}\\therefore 20 \\sqrt { 4 a ^ { 2 } - 6400 }{/tex} = 360{tex}\\Rightarrow 20 \\times 2 \\sqrt { a ^ { 2 } - 1600 }{/tex}\xa0= 360{tex}\\Rightarrow \\sqrt { a ^ { 2 } - 1600 } = 9{/tex}{tex}\\Rightarrow a ^ { 2 } - 1600{/tex}\xa0= 81{tex}\\Rightarrow a ^ { 2 } = 1681{/tex}{tex}\\Rightarrow{/tex}\xa0a = 41 cm{tex}\\therefore{/tex}\xa0perimeter of triangle = (2a + b) cm= (2\xa0{tex}\\times{/tex}\xa041 + 80) cm= (82 + 80) cm = 162 cmHence, perimeter of the triangle = 162 cm | |
| 24218. |
what is mathamatics |
|
Answer» wastage of time .......cause of headache .. It isn\'t a problem... It\'s solution to every problem.... It is very big problem |
|
| 24219. |
X2+34x |
| Answer» | |
| 24220. |
New pattern Model Paper 2018 |
| Answer» | |
| 24221. |
Two coins are tossed what Is the probability of getting only one head |
|
Answer» 2/4 = 1/2 1/2 P(E) =2 2 |
|
| 24222. |
Tan A + secA -1 upon tan A - sec A+ 1 = 1 + sin A upon |
| Answer» Tan + sec - 1--------------------Tan - sec + 1Tan + sec - ( sec^2 - tan^2 )--------------------------------------------Tan - sec + 1(Tan + sec) - ( sec + tan ) (sec - tan )--------------------------------------------------------Tan - sec + 1(sec + tan )(1 - sec + tan )------------------------------------------tan - sec + 1Sec + tan1/cos + sin/cos 1 + sin----------- proved....cos | |
| 24223. |
The area of a rectangle is 192cm2 and it\'s perimeter is 56cm. Find the diameter of rectangle. |
| Answer» Area of rectangle = length x breadth192 = l xb\xa0perimeter = 2(length+ breadth)56= 2(l+b)(l+b)= 56/2 =28l = 28-bSubstituting the value of l in eq(1), we get(28-b) x b = 19228 b-{tex}b^2{/tex}\xa0= 192{tex}b^2-28b +192 = 0{/tex}{tex}b^2-16b-12b+192= 0{/tex}b(b-16)-12(b-16) = 0(b-12)(b-16)= 0b=12 or 16If b= 12 then l=16{tex}Diagonal = (l^2+b^2)^1/2{/tex}Diagonal = ({tex}16^2+12^2)^1/2{/tex}diagonal = (256+144){tex}^1/2{/tex}Diagonal = ({tex}400)^1/2{/tex}Diagonal = 20 cm\xa0 | |
| 24224. |
(Sin+cos)whole sqare |
|
Answer» 1+2sincos 2sincos 1 |
|
| 24225. |
3n(n=9) |
| Answer» | |
| 24226. |
How many three-digit numbers are divisible by 9 |
| Answer» First and last 3 digit no. divisible by 9 are 108 and 999Let a=108,l=999 , d=9 n=?l=a+(n-1)dl=108+(n-1)9999=108+9n-9999-108+9=9n900=9nn=100Therefore 100 three digit numbers are divisible by 9 | |
| 24227. |
Cos u/1+sin u =cos u/1-sin u |
| Answer» | |
| 24228. |
draw less than ogive or more than ogive from these two curve .find the median |
| Answer» | |
| 24229. |
Sir questions are from book or out from NCERT book because 2016 questions are from out of NCERT book |
| Answer» | |
| 24230. |
Find the no.of terms in the following AP, -65.....,19,23,27 |
| Answer» 24 | |
| 24231. |
What is meant by colinear |
|
Answer» Points that lie on the same straight line In same line... Points A, B and C are collinear if they lie on same line It means that all the points are on the same line.See example -. _____._________.________ (A). (B) Here A and B are colinear |
|
| 24232. |
Tangent property |
| Answer» When two tangents are drawn from external point to circle theyare equal in length | |
| 24233. |
Solve for x 1/x+1+2/x+2=4/x+4 |
| Answer» For this take lcm and the u will get your answer n that is 2 | |
| 24234. |
Formulla of median |
| Answer» | |
| 24235. |
What is real numder |
| Answer» | |
| 24236. |
When final exam will be conducted for class 10 |
|
Answer» I think in February May be 9th March.... |
|
| 24237. |
Which of the following is smallest composite number?A.1B.2C.3D.4 |
|
Answer» Because 1 is neither prime nor composite and 2 is a prime number C. 3 |
|
| 24238. |
Is there Tricks or method to do speed and distance problems in surface area and volume |
| Answer» Try to multiply and divide in the last step and if and if there is 10 in the denominator do not divide it | |
| 24239. |
26 and 91 LCM and hcf |
|
Answer» HCF = 13LCM = 182 26= 2x13. 91= 13x7 HCG= 13LCM= |
|
| 24240. |
2x+5=11 |
| Answer» X=3 | |
| 24241. |
What is paythagorus theorem |
|
Answer» In a right angle triangle the square of hypotenuse is equal to sum of square of base and square of perpendicular.Ac2=Ab2+Bc2. Square of hypotenuse is equal to the square of other two sides.AC2 = AB2 + BC2 |
|
| 24242. |
Flnd AP 2,4,8,16,..... |
| Answer» This is gpIn this every term is multiplied by 2So 16×2=3232×2=64 | |
| 24243. |
What is tsa of frustum of cone |
| Answer» | |
| 24244. |
What is the answer for 55+(-3) - (-8) |
|
Answer» 60 60 |
|
| 24245. |
CosA =2/3 |
| Answer» | |
| 24246. |
If secA=x+1/4x,then prove that secA+tanA=2x or 1/2x |
| Answer» {tex}\\begin{array}{l}If\\;secA=x+1/4x,then\\;prove\\;that\\;secA+\\tan A=2x\\;or\\;1/2x\\\\sec\\varnothing=x+\\frac1{4x}\\\\\\tan^2\\varnothing=sec^2\\varnothing-1=\\left(x+\\frac1{4x}\\right)^2-1=\\left(x+\\frac1{4x}\\right)^2-4x\\frac1{4x}=\\left(x-\\frac1{4x}\\right)^2\\\\\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\left[\\left(a+b\\right)^2-4ab=\\left(a-b\\right)^2\\right]\\\\\\tan\\varnothing=\\pm\\left(x-\\frac1{4x}\\right)\\\\when\\;\\;\\;\\;\\;\\tan\\varnothing=x-\\frac1{4x}\\;,\\;sec\\varnothing+\\tan\\varnothing=\\left(x+\\frac1{4x}\\right)+\\left(x-\\frac1{4x}\\right)=2x\\\\when\\;\\tan\\varnothing=-\\left(x-\\frac1{4x}\\right)\\\\so\\;sec\\varnothing+\\tan\\varnothing=\\left(x+\\frac1{4x}\\right)\\left(\\frac1{4x}-x\\right)=\\frac1{4x}+\\frac1{4x}=\\frac1{2x}\\\\hence,sec\\varnothing+\\tan\\varnothing\\;is\\;either\\;2x\\;or\\;\\frac1{2x}.\\end{array}{/tex} | |
| 24247. |
How can we prove that tangents of circle are equal |
|
Answer» Can we also prove it by pythagoras theorem By RHS criteria 1.Raddi of a circle is equal.2.angle between tangent and radius is 90°.3.one common side(Hypotenuse) |
|
| 24248. |
what is mathematics |
| Answer» | |
| 24249. |
After how many places will the decimal expension of 147%120 terminator |
| Answer» | |
| 24250. |
Sin(1+tan) +cos (1+cot) = sec +consec prove it |
| Answer» | |