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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2401. |
Composite numbers |
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| 2402. |
Find mean of first 12 prime numbers |
| Answer» what | |
| 2403. |
2x +x -6 |
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Answer» -3x x=2 x=2 |
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| 2404. |
Mean of 20 numbers is 18, if 2 is added every number find new mean |
| Answer» Now ans is 20 OK... | |
| 2405. |
name the organ man have not control |
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Answer» Heart and may be spinal cord Internal Body Organs |
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| 2406. |
Composite numbers? |
| Answer» The no. Which have more than one factor are known as composite no. | |
| 2407. |
If mean of 20 numbers is 18,if 20 is added in each number so find new mean |
| Answer» observations be x1, x2, x3,.......,x8, x9, x10, x11, x12,..........,x20.We know that,Sum of n observations = Mean × Number of observation, n∴ Sum of 20 observation = 18 × 20 ⇒ x1+ x2 + x3 +.......x8 + x9 + x10 + x11 + x12 +..........+x20 = 360 ...(1)when 20 is added to 20 observation, thenSum of new observations= (x1 + 20) + (x2 + 20) + (x3 + 20) +......+ (x8 + 20) + (x9 + 20) + (x10 + 20) +( x11 + 20) + (x12 + 20) +..........+ (x20 + 20).= (x1 + x2 + ...... + x20) + 20 × 20= 360 + 400 (Using (1))= 760. | |
| 2408. |
Find the mean of first 12 composite numbers |
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| 2409. |
If hcf of two number is 2and their product is 120, find their lcm |
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| 2410. |
2014 sample papers |
| Answer» Download it from google | |
| 2411. |
2 +2 |
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Answer» 2+2=question of lower classes??? 2+2=rahul 2+2=4 |
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| 2412. |
Can you give me formula of ch area related to circle |
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Answer» 1..Area of circle = πr2 ..2☺.. area of semi- circle = 1/2πr2 .3.☺. area of quadrant of circle= 1/4πr2 ..4..☺. Circumference of circle= 2πr. 5☺.. circumference of semi-circle= r(π+2)..6☺area of sector= πr2theta /360 or 1/2×L×R,?..7☺ length of arc= 2πrtheta/360... .. I hope it is helpful for you..☺☺ See in ncert book of 10th class |
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| 2413. |
Find the model |
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| 2414. |
Find the maximum volume of cube that can be carved out from a solid hemisphere of radius Rcm |
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| 2415. |
Find five terms of an ap whose sum 25\\2 and last terms ratio is 2:3 |
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| 2416. |
When is date sheet coming nd how many holidays will be this year in exams |
| Answer» You can check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 2417. |
Prove that root 6 is irrational |
| Answer» If possible, let {tex}\\sqrt { 6 }{/tex} be rational and let its simplest form be {tex}\\frac { a } { b }{/tex} then, a and b are integers having no common factor other than 1, and {tex}b \\neq 0{/tex}.Now, {tex}\\sqrt { 6 } = \\frac { a } { b } {/tex}{tex}\\Rightarrow 6 = \\frac { a ^ { 2 } } { b ^ { 2 } }{/tex} [on squaring both sides]{tex}\\Rightarrow 6b^2 = a^2{/tex} .................(i){tex}\\Rightarrow{/tex} 6 divides {tex}a^2{/tex} [{tex}\\because{/tex} 6 divides {tex}6b^2{/tex}]{tex}\\Rightarrow{/tex} 6 divides {tex}a{/tex}Let {tex}a = 6c{/tex} for some integer {tex}c{/tex}putting {tex} a = 6c{/tex} in (i), we get{tex}a^2 = 36c^2{/tex}{tex}6b^2 = 36c^2 \\;\\;\\;[6b^2 = a^2] {/tex}{tex}\\Rightarrow b^2 = 6c^2{/tex}{tex}\\Rightarrow{/tex} 6 divides {tex}b^2{/tex} [{tex}\\because{/tex} 6 divides {tex}6c^2{/tex}]{tex}\\Rightarrow{/tex} 6 divides {tex}b{/tex} [{tex}\\because{/tex} 6 divides {tex}b^2 = 6{/tex} divides {tex}b{/tex}]Thus, 6 is a common factors of {tex}a{/tex} and {tex}b{/tex}But, this contradicts the fact that {tex}a{/tex} and {tex}b{/tex} have no common factor other than 1The contradiction arises by assuming that {tex}\\sqrt { 6 }{/tex} is rational.Hence {tex}\\sqrt { 6 }{/tex} is irrational. | |
| 2418. |
4u2 + 8u |
| Answer» 4×2u +8u=16u | |
| 2419. |
Find the probably of 2 dice thrown 1.A prime number |
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| 2420. |
what is gizzard |
| Answer» The gizzard is an organ found in the digestive tract of some animals, including archosaurs, earthworms, some gastropods, some fish, and some crustaceans. | |
| 2421. |
If cylinder have 10 cm height and 10 cm diameter what it\'s volume |
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Answer» 785.71 62.8 cm°3 Answer is 785.71 |
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| 2422. |
De parallel bc and cd parallel ef prove that ad square=ab multiply af |
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| 2423. |
In the given figure if DE parallel BC then calculate x |
| Answer» In the given figure,DE \u200b{tex}\\parallel {/tex}\u200b BC\u200b{tex}\\therefore {/tex}\u200b {tex}\\frac{{AD}}{{DB}} = \\frac{{AE}}{{EC}}{/tex}\u200b{tex}\\Rightarrow {/tex}\u200b {tex}\\frac{x}{{x - 2}} = \\frac{{x + 2}}{{x - 1}}{/tex}\u200b{tex}\\Rightarrow {/tex}\u200b x = 4\xa0 | |
| 2424. |
Solve-3+3×34÷5×7+68904÷45= |
| Answer» Answer- 1677 | |
| 2425. |
What are the formulas of trigonometry? |
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| 2426. |
Sin60 ?? |
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| 2427. |
7=8-90/78-54 |
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| 2428. |
Find the area of a quadrant of a circular where the circumstances of the circle is 44 cm. |
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Answer» 38.5 38.5 38•5 cm². 35.5 38.5 |
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| 2429. |
A bridge across a river angle of 45 degree with the river bank |
| Answer» Given that a bridge across a river makes an angle of 45o with the river bank as shown in Fig. If the length of the bridge across the river is 150 m, we have to find the width of the river.In right triangle ABC, we have {tex} \\sin 45 ^ { \\circ } = \\frac { B C } { A C }{/tex}{tex}\\Rightarrow \\quad \\frac { 1 } { \\sqrt { 2 } } = \\frac { B C } { 150 }{/tex}{tex}\\Rightarrow \\quad B C = \\frac { 150 } { \\sqrt { 2 } }{/tex}( rationalization by √2){tex}\\Rightarrow \\quad B C = 75 \\sqrt { 2 } \\mathrm { m }{/tex}Hence, the width of the river is\xa0{tex}75 \\sqrt { 2 }{/tex} metres. | |
| 2430. |
Support material ch-4 all question solved |
| Answer» You can get NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 2431. |
Find 5th term of a.p whose nth term is 3n-5 |
| Answer» Tn=3n-5T5=3x5-5T5=15-5T5=10 | |
| 2432. |
1/2x+1/3y=2 |
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| 2433. |
Y+2y= |
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Answer» what nonsense kaira Y+2y=3y 3y 3y |
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| 2434. |
If 9th term of A.P. is zero, prove that its 29th term is double of its 19th term. |
| Answer» a+(9-1)d=0 ; a+8d=0 ; a= -8d a19=a+(19-1)d ; a+18d. -8d+18d= 10d. Similarly, a29=a+(29-1)d ; a+28d. -8d+28d= 20d. So, 20d is double of 10d.........Is it correct??????? | |
| 2435. |
Find the coordinate of the points on y axis which is nearest to point -2,5 |
| Answer» The point on y-axis that is nearest to the point(-2,5) is (0,5). | |
| 2436. |
1. In ΔLMN, ∟L = 50°and ∟N= 60°. If ΔLMN is similar to ΔPQR, then find ∟Q. |
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Answer» Here angle Q is 70° Angle Q is 70° |
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| 2437. |
what are the properties of cyclic quadrilateral |
| Answer» A cyclic quadrilateral is a quadrilateral that can be inscribed in a circle, meaning that there exists a circle that passes through all four vertices of the quadrilateral.\tIf one side of the cyclic quadrilateral is produced, then the exterior angle so formed is equal to the interior opposite angle.\tThe sum of the opposite angles of a cyclic quadrilateral is supplementary.\tIn a cyclic quadrilateral, the ratio of the diagonals equals the ratio of the sum of products of the sides that share the diagonal\'s end points.\tPerpendicular Bisectors of a quadrilateral are concurrent only if it is a cyclic quadrialateral. | |
| 2438. |
What is the properties of cyclic quadrilateral |
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Answer» A cyclic quadrilateral is a quadrilateral that can be inscribed in a circle, meaning that there exists a circle that passes through all four vertices of the quadrilateral.\tIf one side of the cyclic quadrilateral is produced, then the exterior angle so formed is equal to the interior opposite angle.\tThe sum of the opposite angles of a cyclic quadrilateral is supplementary.\tIn a cyclic quadrilateral, the ratio of the diagonals equals the ratio of the sum of products of the sides that share the diagonal\'s end points.\tPerpendicular Bisectors of a quadrilateral are concurrent only if it is a cyclic quadrialateral. Sum of opposite angles is 180 |
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| 2439. |
Mean of 5 numbers is 18. If one number minus then mean is 16 find the minus number |
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Answer» Mean =X = 18No of observations = 5 Sum of observations = = 18 x 5 = 90Let the excluded number be xNew Mean X\' = 16New number of observations = 4New sum of observations = 16 x 4 = 64 which is equal to 90 - x Thus x= 90 - 64 = 26 The minus no. Is 26 |
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| 2440. |
Prove that root 5 + root 3 is an irrational number |
| Answer» If possible, let\xa0{tex}\\sqrt{3}{/tex}\xa0+\xa0{tex}\\sqrt{5}{/tex}\xa0be a rational number equal to x. Then,x =\xa0{tex}\\sqrt{3}{/tex}\xa0+\xa0{tex}\\sqrt{5}{/tex}{tex}\\Rightarrow{/tex}\xa0x2 = ({tex}\\sqrt{3}{/tex}\xa0+\xa0{tex}\\sqrt{5}{/tex})2\xa0{tex}\\Rightarrow{/tex}\xa0x2 = ({tex}\\sqrt{3}{/tex})2 + ({tex}\\sqrt{5}{/tex})2 + 2\xa0{tex}\\times{/tex}\xa0{tex}\\sqrt{3}{/tex}\xa0{tex}\\times{/tex}\xa0{tex}\\sqrt{5}{/tex}= 3 + 5 + 2{tex}\\sqrt{15}{/tex}= 8 + 2{tex}\\sqrt{15}{/tex}{tex}\\Rightarrow{/tex}\xa0x2 - 8 = 2{tex}\\sqrt{15}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{x^2 -8}{2}{/tex}\xa0=\xa0{tex}\\sqrt{15}{/tex}Now, x is rational{tex}\\Rightarrow{/tex}\xa0x2 is rational{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{x^2 - 8}{2}{/tex}\xa0is rational{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt{15}{/tex}\xa0is rationalBut,\xa0{tex}\\sqrt{15}{/tex}\xa0is irrational.Thus, we arrive at a contradiction. So, our supposition that\xa0{tex}\\sqrt{3}{/tex}\xa0+\xa0{tex}\\sqrt{5}{/tex}\xa0is rational is wrong.Hence,\xa0{tex}\\sqrt{3}{/tex}\xa0+\xa0{tex}\\sqrt{5}{/tex}\xa0is an irrational number. | |
| 2441. |
Find the value of cos theta + sec theta , when it is given that cos theta =1/2 |
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| 2442. |
Maths paper will come only from ncert or rd sharma . Shall i do rd or not |
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| 2443. |
Find the sum of 2 middle most term AP-4/3,-1,-2/3,......13/3 . |
| Answer» Here in the given A.P the first term a , = -4/3an = 11/3 and d = 1/3an = a + ( n - 1 ) d11/3 = -4/3 + ( n - 1 ) 1/35 = n/3 - 1/35 + 1/3 = n/316/3 = n/316 = nNow the middle term = n/2 , n/2 + 1= 8th term and 9th term.a + 7d + a + 8d 2a + 15d 2(-4/3) + 15(1/3)-8/3 + 5(-8 + 15)/3 = 7/3 | |
| 2444. |
2i*5 |
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| 2445. |
Root 6 |
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| 2446. |
Determine the nth term of the AP whose 7th term is -1 and 16th term is 17. |
| Answer» 7term equal to (a plus 6d) nd 16term equals to (a plus 15d) By elimination method we get-9d equals to -18Means d equals to 2 a equals to -13 an equals to a plus(n-1)dbut there is no value of n pkease check your ques. | |
| 2447. |
Find the missing term of so7_,_,29/2 |
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| 2448. |
If the quadratic equation px^2 - 2 root5 px +15=0 then find the value of p |
| Answer» We have, px2\xa0-\xa0{tex}2\\sqrt{5}{/tex}px + 15 = 0\xa0Since the roots of equation are equal. Then,Discriminant, D = 0{tex}\\Rightarrow{/tex}\xa0({tex}2\\sqrt{5}{/tex}p)2\xa0- 4(p)(15) = 0{tex}\\Rightarrow{/tex}\xa020p2\xa0- 60p = 0{tex}\\Rightarrow{/tex}\xa020p(p -3) = 0{tex}\\Rightarrow{/tex}\xa020p = 0 or p - 3 = 0{tex}\\Rightarrow{/tex}\xa0p = 3 [since p\xa0{tex}\\neq{/tex}\xa00] | |
| 2449. |
Explain me pair of linear equation in two variable |
| Answer» | |
| 2450. |
No. Of honourable cards |
| Answer» 16 cards in a deck | |