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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 24651. |
37,511,713...???? |
| Answer» Answer:- 985 | |
| 24652. |
Rd sharma ex10.2 que 29 |
| Answer» | |
| 24653. |
How many irrational no. lie between √2 & √3 ? |
| Answer» Infinity irrational no.between _/2&_/3 | |
| 24654. |
1+1+1+1×0×1+1 |
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Answer» 5 by BODMAS 4BODMAS rule 4 0 4 |
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| 24655. |
What is the root of 6859565556554555556xh |
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| 24656. |
what is polynomiyal |
| Answer» | |
| 24657. |
10:26::50:x find the value of x and its option are 142 ; 122 ; 132 ; 112 ? |
| Answer» 10/26 =50/xx=50x26/10 = 130 | |
| 24658. |
How many question arises of 1 number or mcq |
| Answer» There are no McQ in exam pattern | |
| 24659. |
Ntse |
| Answer» Ntse means national talent search examination | |
| 24660. |
What is whole number |
| Answer» The numbers which starts from 0 to infinity | |
| 24661. |
name the types of quadrilateral is any by the following points and give reason for your answer |
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| 24662. |
2÷x |
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| 24663. |
Difference between a quadrant and a minor sector |
| Answer» A sector of is called a minor sector if the minor arc of the circle is apart of its boundary while quadrant of a circle is one fourth part of the circle. | |
| 24664. |
Sin120 |
| Answer» | |
| 24665. |
Triangle ABC similar Triangle PQR & AB:BC: AC =3:5:6 then Triangle PQR perimeter is 19.6 then QR= |
| Answer» QR=7 | |
| 24666. |
Sin 90 |
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Answer» 1 1. 1 |
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| 24667. |
If the zeros of a polynomial x square-7x+k are such that alpha - beta=1 then find the value of k |
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Answer» X sq. 7x+kAlpha=-b/a=7Beta=c/a=kIt is given that alpha-beta=1So,7-k=1-K=-6K=6 I need the answers with steps K=7 |
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| 24668. |
Section formula |
| Answer» The section formula tells us the coordinates of the point which divides a given line segment into two parts such that their lengths are in the ratio m:n. ... The section formula is helpful in coordinate geometry; for instance, it can be used to find out the centroid, incenter and excenters of a triangle. | |
| 24669. |
What is alternate swgment theorem |
| Answer» Alternate segment theorem. The angle between the tangent and chord at the point of contact is equal to the angle in the alternate segment. This is the circle property that is the most difficult to spot. | |
| 24670. |
Friends.. had you fill the form of ntse? |
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Answer» Yes I had filled. Yes I have filled |
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| 24671. |
Which term of AP :12,18,15,...is zero? |
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Answer» That to i also confused... Hmm Plz do check ur question... Bcz if it is saying the following no. Are in a. P then they should have common difference.. Which is not coming... |
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| 24672. |
What kind of questions are given in board exam |
| Answer» Cool. All que comes from our book ,almost | |
| 24673. |
If A,B,C are interior angles of triangle.prove that B+C½=cos A½ |
| Answer» \xa0A, B, C, are interior angles of a\xa0{tex}\\Delta {/tex}{tex}\\because A + B + C = 180 ^ { 0 }{/tex}{tex}\\Rightarrow B + C = 180 ^ { 0 } - A \\Rightarrow \\frac { B + C } { 2 } = 90 ^ { 0 } - \\frac { A } { 2 }{/tex}{tex}\\Rightarrow \\sin \\frac { \\mathrm { B } + \\mathrm { C } } { 2 } = \\sin \\left( 90 ^ { \\circ } - \\frac { \\mathrm { A } } { 2 } \\right) \\left[ \\because \\sin \\left( 90 ^ { 0 } - \\theta \\right) = \\cos \\theta \\right]{/tex}{tex}\\Rightarrow \\sin \\frac { \\mathrm { B } + \\mathrm { C } } { 2 } = \\cos \\frac { \\mathrm { A } } { 2 } \\text { proved }{/tex}LHS = RHS | |
| 24674. |
12-45 |
| Answer» -33 | |
| 24675. |
If (X)(X)(X)+(X)(X)-ax+b is divisible by (X)(X)-x find the value of a+b |
| Answer» Since f(x) =\xa0x3\xa0+ x2\xa0- ax + b is divisible by (x2\xa0- x), we havex2\xa0- x = 0{tex}\\Rightarrow{/tex}\xa0x(x - 1) = 0{tex}\\Rightarrow{/tex}\xa0x = 0 or x = 1Hence,f(0) = 0{tex}\\Rightarrow{/tex} x3\xa0+ x2\xa0- ax + b = 0{tex}\\Rightarrow{/tex}\xa003\xa0+ 02\xa0- a(0) + b = 0{tex}\\Rightarrow{/tex}\xa0b = 0Also,f(1) = 0{tex}\\Rightarrow{/tex} x3\xa0+ x2\xa0- ax + b = 0{tex}\\Rightarrow{/tex}\xa013\xa0+ 12\xa0- a(1) + 0 = 0{tex}\\Rightarrow{/tex}\xa01 + 1 - a = 0{tex}\\Rightarrow{/tex} 2 - a = 0{tex}\\Rightarrow{/tex}\xa0a = 2Hence , the value of a and b in given polynomial are a = 2 and b = 0. | |
| 24676. |
Completion of square method |
| Answer» The given equation is: 7x2\xa0+ 3x - 4 = 0 Multiply each term by 7, we obtain: 49x2\xa0+ 21x - 28 = 0{tex}\\Rightarrow{/tex}\xa049x2\xa0+ 21x = -28On adding\xa0{tex}\\left( \\frac { 3 } { 2 } \\right) ^ { 2 }{/tex} on both sides, we get (7x)2\xa0+ 2\xa0{tex}\\times{/tex}\xa07x\xa0{tex}\\times \\frac { 3 } { 2 } + \\left( \\frac { 3 } { 2 } \\right) ^ { 2 } = 28 + \\left( \\frac { 3 } { 2 } \\right) ^ { 2 }{/tex}\xa0{tex}\\Rightarrow \\left( 7 x + \\frac { 3 } { 2 } \\right) ^ { 2 } = 28 + \\frac { 9 } { 4 }{/tex}{tex}\\Rightarrow \\left( 7 x + \\frac { 3 } { 2 } \\right) ^ { 2 } = \\frac { 121 } { 4 }{/tex}{tex}\\Rightarrow 7 x + \\frac { 3 } { 2 } = \\pm \\frac { 11 } { 2 }{/tex}Therefore, either 7x =\xa0{tex}- \\frac { 3 } { 2 } - \\frac { 11 } { 2 }{/tex}\xa0or 7x =\xa0{tex}- \\frac { 3 } { 2 } + \\frac { 11 } { 2 }{/tex}{tex}\\Rightarrow{/tex}\xa07x = -7 or 7x = 4{tex}\\Rightarrow{/tex}\xa0x = -1 or x =\xa0{tex}\\frac { 4 } { 7 }{/tex}Hence, the roots of given equation are {tex}\\frac { 4 } { 7 }{/tex} and\xa0-1. | |
| 24677. |
Find the value of cot 10 cot 30 cot 30? |
| Answer» = cot 10° cot 30° cot 80°= cot (90° - 80°) cot 30° cot 80°{tex}[\\because cot(90^o-\\theta)=tan\\theta]{/tex}{tex}=tan80^o. cot30^o{/tex}.{tex}\\frac { 1 } { \\tan 80 ^ { \\circ } }{/tex}{tex}[\\because cot\\theta=\\frac{1}{tan\\theta}]{/tex}{tex}=cot30^o{/tex}\xa0{tex}=\\sqrt{3}{/tex}Therefore,\xa0{tex}cot10^o cot30^o cot80^o=\\sqrt{3}{/tex}{tex}{/tex} | |
| 24678. |
What is the debat |
| Answer» Debate is contention in argument; strife, dissension, quarrelling, controversy; especially a formal discussion of subjects before a public assembly or legislature, in Parliament or in any deliberative assembly. | |
| 24679. |
How to prove pythagoras theorm |
| Answer» | |
| 24680. |
Form a quadratic equation whos roots are 7+√5 and 7-√5 |
| Answer» x²-14x+44 | |
| 24681. |
Maths ko kese padi jaye easy way me |
| Answer» | |
| 24682. |
Maths ko jaldi kese samje |
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Answer» Revised the math Learning?? Maths learn kon krta hai by improving your learning and thinking skill...... |
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| 24683. |
Derivation of formulae (a^2 +b^2) |
| Answer» | |
| 24684. |
What is composite number |
| Answer» Number having more than two factor. | |
| 24685. |
Which book I should do or sample paper only |
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Answer» Sorry I mean exams are in March. I think you should go for previous year questions papers first.... then opt for sample paper only before one month of exam.. I hope exams are in November.. So study till January. Ncert only.. Then in February u can go for sample paper I think sample papers |
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| 24686. |
Hi can you send three square formula of trigonometry ratio |
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| 24687. |
Solve :-3x+9y= 0 |
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| 24688. |
90+60 |
| Answer» 150 | |
| 24689. |
solve (x-3)(x-4)=34/√1089 by factorisation method |
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| 24690. |
Co ordinate |
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| 24691. |
Cordinate |
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| 24692. |
How find is n in AParis chapter |
| Answer» {tex}s=\\;\\frac n2\\;\\left[2a\\left(n-1\\right)d\\right]{/tex} | |
| 24693. |
Solve:bx+ay=a+bax (1/a-b-1/a+b) +by (1/b-a -1/b+a)=2a/a+b |
| Answer» The system of equation is given by :bx + cy = a + b ......(i){tex}ax\\left( {\\frac{1}{{a - b}} - \\frac{1}{{a + b}}} \\right) + cy\\left( {\\frac{1}{{b - a}} + \\frac{1}{{b + a}}} \\right){/tex}{tex}= \\frac{{2a}}{{a + b}}{/tex}\xa0...(ii)From equation (i)bx + cy - (a + b) = 0 ............ (iii)From equation (ii){tex} ax\\left( {\\frac{1}{{a - b}} - \\frac{1}{{a + b}}} \\right) + cy\\left( {\\frac{1}{{b - a}} + \\frac{1}{{b + a}}} \\right){/tex}\xa0{tex} - \\frac{{2a}}{{a + b}} = 0{/tex}{tex}⇒ x\\left( {\\frac{{2ab}}{{(a - b)(a + b)}}} \\right) + y\\left( {\\frac{{2ac}}{{(b - a)(b + a)}}} \\right){/tex}\xa0{tex}- \\frac{{2a}}{{a + b}} = 0{/tex}{tex} ⇒ \\frac{1}{{a + b}}\\left( {\\frac{{2abx}}{{a - b}} - \\frac{{2acy}}{{a - b}} - 2a} \\right) = 0{/tex}\xa0{tex}⇒ \\frac{{2abx}}{{a - b}} - \\frac{{2acy}}{{a - b}} - 2a = 0{/tex} 2abx - 2acy - 2a(a - b) = 0 ....(iv)From equation (iii) and (iv), we geta1 = b, b1 = c and c1 = - (a + b)and a2 = 2ab , b2 = -2ac and c3 = -2a(a - b)by cross-multiplication, we get{tex}\\frac{x}{{ - 4{a^2}c}} = \\frac{{ - y}}{{4a{b^2}}} = \\frac{{ - 1}}{{4abc}}{/tex}Now, {tex}\\frac{x}{{ - 4{a^2}c}} = \\frac{{ - 1}}{{4abc}} {/tex}{tex}⇒ x = \\frac{a}{b}{/tex}And, {tex}\\frac{{ - y}}{{4a{b^2}}} = \\frac{{ - 1}}{{4abc}} {/tex}{tex}⇒ y = \\frac{b}{c}{/tex}The solution of the system of equation are {tex}\\frac{a}{b}{/tex}\xa0and {tex}\\frac{b}{c}{/tex}. | |
| 24694. |
If pth term of ap is q and qth term of ap is p then prove that R is equal to p+q-r |
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| 24695. |
What is the distance between the points (a,b)and(-a,b). |
| Answer» 2a units | |
| 24696. |
Decimal expansion of the rational number 47/2×2×25×2 |
| Answer» 2350 | |
| 24697. |
Cube volume |
| Answer» Side cube | |
| 24698. |
Volume of cube |
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Answer» Side cube a3 |
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| 24699. |
π×27×27 |
| Answer» 2290.2 if pie is taken as 22\\7 2289.6 if pie is taken as 3.14 | |
| 24700. |
Ripu singh |
| Answer» | |