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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 25001. |
2+5= |
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Answer» 7 7 |
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| 25002. |
What is the list |
| Answer» | |
| 25003. |
7x,7x+7,7x+14=777 |
| Answer» | |
| 25004. |
What is the minimum qualifications to teach in CBSE schools |
| Answer» Graduation is the minimum educational qualification required to apply for Teacher job in private CBSE Schools. | |
| 25005. |
Questions of mathematics in bored examination come from which book??? |
| Answer» | |
| 25006. |
X2_2x_8 |
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Answer» =x2-2x-8=x2-4x+2x-8=x(x-4)+2(x-4)=(x-4)(x+2)\xa0\xa0\xa0\xa0 Time nikal ke apni maths thik kro jitna zayda ho sake utni maths lgao aur ek baat aur acche tutor se coaching padho dekhna apne ap maths thik ho jayegi ?????? Ha ha ha bhaiera math bahut kmjor h bhai. Bahut jada hi kmjor h bhai kaise shi hoga yeh. |
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| 25007. |
Find the sum of first 30 natural nos. |
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Answer» Thank you all of you for your answers 1,2,3,4,5,6,...................... 30a=1d=1an =a+(n-1)d30=1+ n-1n=30S30 =15(2a+(29d)) = 30+29x15 = 30+435=465check ur answer s=n/2(a+L) = 15x31=465 ok =2a+(n-1)d=2×1+(n-1)1=2+n-1=-2=n-1=-2+1=n=-1=n Use formula 2a+(n-1)d |
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| 25008. |
Rd sharma solutions of chapter arithmetic progressions |
| Answer» RD Sharma Solutions are available in each chapter. | |
| 25009. |
How to understand the questions |
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| 25010. |
Is this system is new |
| Answer» | |
| 25011. |
Bzsgfshsjwjjw |
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| 25012. |
Write elevan thousand elivan handrad elevan it how write |
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Answer» 12111 11,111 |
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| 25013. |
The perimeter of garden is 108cm.find the diameter of the garden |
| Answer» 137.454545 | |
| 25014. |
Pattern for question paper class 10 maths CBSE 2017-18 |
| Answer» Check question paper pattern here :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 25015. |
Find the points on the X axis whic |
| Answer» | |
| 25016. |
What is the blue print of mathematics class 10 of year 2017 |
| Answer» Check paper pattern of mathematics here :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 25017. |
For 2017-18 blue print of maths |
| Answer» Check blue print of question paper here :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 25018. |
If x is equal to root 2 of solution K X square + root 2 x minus 4 is equal to zero |
| Answer» Kx2+root 2x-4=0 K(root 2)2+root 2×root 2-4=0 2k+2-4=0 2k-2=02k=2K=2/2K=1 | |
| 25019. |
Find the zero if 4usquare+8u |
| Answer» 4u(u+2)=04u=0u=0/4=0u+2=0u=0-2=-2Therefore,Zeroes of given polynomial are 0 and -2. | |
| 25020. |
(cosA/1-tanA) +(sinA/1-cotA) = cosA+sinA |
| Answer» {tex}\\eqalign{ & = {{\\cos \\,A} \\over {1 - {{\\sin \\,A} \\over {\\cos \\,A}}}} + {{\\sin \\,A} \\over {1 - {{\\cos \\,A} \\over {\\sin \\,A}}}} \\cr & = {{{{\\cos }^2}A} \\over {\\cos A - \\sin A}} + {{{{\\sin }^2}A} \\over {\\sin A - \\cos A}} \\cr & = {{{{\\cos }^2}A - {{\\sin }^2}A} \\over {\\cos A - \\sin A}} \\cr & = {{(\\cos A - \\sin A)(\\cos A + \\sin A)} \\over {\\cos A - \\sin A}} \\cr & = \\sin A + \\cos A \\cr} {/tex} | |
| 25021. |
12-13 |
| Answer» -1 | |
| 25022. |
3(sin∅-cos∅)⁴+ 6(sin∅+cos∅)²+4(sin6∅ + cos6∅) is independent ∅. |
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| 25023. |
How to give us 20% marks |
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| 25024. |
Prperties 115 element in perodic table |
| Answer» See on u tube | |
| 25025. |
Is it important to write given, so , therefore, according to question,etc in bird exam |
| Answer» | |
| 25026. |
TanA\\secA-1+tanA\\secA+1=2cosecA |
| Answer» LHS=TanA\\secA-1+tanA\\secA+1=tanA(secA+1)+tanA(secA-1)\\(secA-1)(secA+1)=tanA[secA+1+secA-1]\\sec^2 - 1=tanA(2secA)\\tan^2A (sec^2A - 1=tan^2 A) =2secA \\tanA=2cosecA | |
| 25027. |
3x+2y=0 find the value of x |
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Answer» -1/2 ok 2y=3x ; y=3x/2Then add 3x+3/2=0X ki value aa jayegi |
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| 25028. |
When will we get some more latest sample paper |
| Answer» Never???? | |
| 25029. |
When are our exams |
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Answer» It may be on 18 feb I read in news ??? It may be on March 5th but cbse has not announced yet... |
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| 25030. |
chapter 13 |
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Answer» 5 question 13.2 |
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| 25031. |
Value of sin 60 |
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Answer» Root 3/2 Root 3 / 2 |
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| 25032. |
Which is the best reference book for math according to ur convince |
| Answer» Rs aggarwal | |
| 25033. |
Find the ratio in which the line segment joining the point (-3,10)and(6,-8)is divided by(-1,6) |
| Answer» x= m1x2\xa0+m2\xa0x1/m1+m2-1=m1x6 +m2\xa0x-3/m1+m26m1\xa0-3m2\xa0= -1(m1+m2)6m1\xa0-3m2\xa0= -m1\xa0-m26m1+m1\xa0= -m2\xa0+3 m27m1\xa0= 2m2m1/m2\xa0= 2/7So,point (-1,6)divides the line segment joining the points (-3,10) and (6,-8) in 2:7. | |
| 25034. |
Draw the graph of less than type |
| Answer» | |
| 25035. |
what is euclids division lemma |
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Answer» a= bq + r Given positive integers a and b there exist unique integer q and r satisfying a=bq+r, The basis of Euclidean division algorithm is Euclid\'s division lemma. To calculate the Highest Common Factor (HCF) of two positive integers a and b we use Euclid\'s division algorithm. HCF is the largest number which exactly divides two or more positive integers. |
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| 25036. |
Masala |
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| 25037. |
Find the area of a sector of a circle with radius 6cm if angle of the sector is 60\' ? |
| Answer» 132/7 cm sq. | |
| 25038. |
If secA +secA=p then show p2 -1÷ p2+1=sinA |
| Answer» | |
| 25039. |
How to do distance formula sum |
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| 25040. |
Can you please send me all the formula for surface area and volume of class 10 |
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| 25041. |
All formula for chapter 4 |
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| 25042. |
Prove that : Cos u/1+sin u=1-sin u/cos u |
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Answer» LHS: cos u/1+sin u=Dividing numerator and denominator by 1-sin u=Cos u ( 1-sin u )/1- sin²u= Cos u (1-sin u)/cos u. {Sin²u + cos²u=1}= 1-sin u/cos u = RHS I have also got the answer just multiply 1-sinu/1-sinu to the L.H.S and simplify LHS = cos u / 1+sin u = Cos u / 1+ sin u × 1-sin u / 1- sin u=Cos u (1-sin u)/1- sin2 u= Cos u - cos u sin u / 1-sin2 u= Cos u ( 1-sin u) / cos2 u=1-sin u/ cos u |
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| 25043. |
A number when divided by 53 gives 34 as quotient and 21 remainder .find the number |
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Answer» 1823 1823 1823 |
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| 25044. |
What is length of tangent |
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| 25045. |
Let |
| Answer» Lashkar- e- thoiba? | |
| 25046. |
Express sec50°+Cot78°.In terms of t- ratio of angles between 0°and 45° |
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Answer» Oh..Sorry?? It would be cosec40 not cosec 30 correct it cosec30°+ tan12° |
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| 25047. |
Ek Khilona Balan ki Santa ka Arth Kya Hota Hai |
| Answer» | |
| 25048. |
1.8÷4.88 |
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Answer» Approx 0.37 0.36885245901 |
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| 25049. |
45+45 |
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Answer» 90 90 90 |
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| 25050. |
x\'=3 |
| Answer» | |