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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 25101. |
If the area of an equilateral triangle is 36under root 3 cm find the perimeter |
| Answer» ar( equi. tri ) = root 3 ÷4 × a square =36 root 3 = root 3× a square =4× 36 root 3 = root 3× a square = 144 root 3 = a square = 144 root 3÷ root 3 so, a= 12 now perimeter = 12+12+12=36 | |
| 25102. |
10+2+40+10 |
| Answer» 62 | |
| 25103. |
Prove sinx has highest and lowest values 1 and -1 respectively |
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| 25104. |
If secA + tanA =x then find the value of secA |
| Answer» secA-tanA=1/xSo 2secA=(x^2+1)/xSo secA=(x^2+1)/2x | |
| 25105. |
Area of circle is a radius is r circumference is c to proof rc=2a |
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| 25106. |
Why 1/0 is not define |
| Answer» Kyuki zero ka devide kitne hi time ban me do ban nhi aaiga isiliye not define | |
| 25107. |
SinA+cosecA=3 find sin4A+1÷sin2A 2 n 4 are degrees |
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| 25108. |
7-5√3 |
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| 25109. |
16x²-27x-10=0 |
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| 25110. |
Date of board exam |
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| 25111. |
All formulae of ch 1 for class 10th |
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| 25112. |
What are all formula of ch 5 AP ?? |
| Answer» 1 an =a+(n-1)×d2 sn=n÷2(a+(n-1)×d) | |
| 25113. |
Formula of pythagoras theoram |
| Answer» H(square)=B(square)+P(square) | |
| 25114. |
Formula of (a+b)2 |
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Answer» a2+ b2 +2ab a2+b2+2ab a2+b2+2ab A2+b2 |
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| 25115. |
Find the ratio in which the line segment joining A(1,-5) and B(-4,5) is divided by the x-axis |
| Answer» 1:1 | |
| 25116. |
If the equation x square -bx+1=0 then find the number in which b lies |
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| 25117. |
Table of tan 0,30,90,60,45 |
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| 25118. |
What is direct method |
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| 25119. |
circle 22Cm |
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| 25120. |
Find the area of the triangle formed by the points 1. 0,0 , 3,0, 0,2 |
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| 25121. |
How to prove questions of trigonometry |
| Answer» By doing more practise | |
| 25122. |
In the circle perimeter of semicircle is protector 36 cm find its length |
| Answer» Perimeter of semicircle= πr+2rperimeter is 36cm 36=22/7r+2r36=22r+14r/736=36r/7r=36×7/36r=7Diameter=2×7=14 | |
| 25123. |
What is the meaning of unbiased die ? |
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Answer» A dice which is not bias , i . e. , a dice which is perfect and has no defect. It\'s rong Jis dice ka koi base na ho. .........lol. |
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| 25124. |
Prove that √7 is irrational no. |
| Answer» Let us assume that {tex}7^1/2{/tex}\xa0is a rational number. So it can be written in the form of a/b.{tex}a/b = 7 ^1/2{/tex}Squaring both sides, we get\xa0{tex}a^2/ b^2 = 7{/tex}{tex}a^2 = 7 b^2{/tex}\xa0......(1)This means that\xa0{tex}a^2{/tex}\xa0is divisible by 7. This implies that a is also divisible by 7.let a = 7c\xa0squaring both sides , we get\xa0{tex}a^2 = (7c)^2{/tex}\xa0or\xa0{tex}7b^2 = 49 c ^2{/tex}or\xa0{tex}b^2 = 7c^2{/tex}......(2)From eq(1) and eq(2), it is clear that both a and b are divisible by 7. . An irrational number can not common factor.This shows that our assumption is wrong.\xa0So\xa0{tex}7^1/2 {/tex}\xa0is an irrational number.\xa0 | |
| 25125. |
How to find mode |
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| 25126. |
The surface area of cube is equal to surface area of a sphere ,then find the ratio of their volume. |
| Answer» a:2r | |
| 25127. |
Find the area of segment AYB ,if radius of circle AOB is 21cm and angle AOB=120 |
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| 25128. |
If cosecA + cotA = p then prove that cosA = p2-1/p2+1 |
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Answer» Wah ??? cosec A + cot A = p\xa0Squaring both Sides, we get\xa0{tex}(Cosec A+ cot A)^2 = p ^2{/tex}{tex}Cosec^2 A+ Cot^2A + 2 cosec A Cot A = p^2{/tex}{tex}1+ cot^2A + Cot^2A+2 CosecACotA = p^2{/tex}\xa0(using identity\xa0{tex}Cosec^2A = 1+ Cot^2A{/tex}){tex}1+2 Cot^2A+2CosecA CotA = p^2{/tex}{tex}2 Cot^2A+2 CosecACotA = p^2-1{/tex}2 Cot A(CotA+ Cosec A) =\xa0{tex}p^2-1{/tex}2p cot A=\xa0{tex}p^2-1{/tex}\xa0as cot A+ cosec A= p givenAgain\xa0{tex}p^2 = Cosec^2A+Cot^2A+2 CosecA CotA{/tex}Adding 1 to both sides , we get\xa0{tex}p^2+1 = Cosec^2A+ Cot^2A+2CosecA CotA +1{/tex}{tex}p^2+1 = Cosec^2A+Cosec^2A+2CosecACotA{/tex}(using identity\xa0{tex}1+ Cot^2A = Cosec^2A{/tex}){tex}p^2+1= 2 Cosec^2A+2 CosecACotA{/tex}{tex}p^2+1 = 2 CosecA(CosecA+ Cot A){/tex}{tex}p^2+1= 2p Cosec A{/tex}\xa0as CosecA+ Cot A= p given{tex}p^2-1/p^2+1= 2pCotA/2pCosecA{/tex}{tex}p^2-1/p^2+1 = CotA/ CosecA{/tex}{tex}p^2-1/p^2+1= CosA/ Sin A . 1/Sin A{/tex}{tex}p^2-1/p^2+1 = Cos A{/tex}\xa0 |
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| 25129. |
Value of sim 180° |
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Answer» 0 value of sin 180 = 0 |
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| 25130. |
Trikon miti |
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| 25131. |
If 2 cos theta minus sin theta equal to 1 by root 2 then 2 sin theta + cos theta is equal to what |
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| 25132. |
If the sum of first term. 2m²+3m, what is the second term |
| Answer» When n=1, First term=(2*1*1)+(3*1)2+3=5Similarly when n= 2Second term =(2*2*2)+(3*2)=8+6=14 | |
| 25133. |
In a triangle ABC in which DE drawn parallel to BC and AD =1/2BD. BC=4.5cm , find DE |
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| 25134. |
(a+b)=? |
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| 25135. |
2+8 |
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Answer» 10 Lame question ?? 10 |
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| 25136. |
Hlooooo everyone |
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| 25137. |
Find how many integers between 200 and 500 are divisible by 8 |
| Answer» Numbers between 200 & 500 which are divisible by 8 are :-200, 208, 216........... 496Clearly, above is an A.P.a = 200d = 8L = 496{tex}\\Rightarrow{/tex}\xa0a + (n - 1)d = 496{tex}\\Rightarrow{/tex}\xa0200 + (n - 1)8 = 496{tex}\\Rightarrow{/tex}\xa0(n - 1)8 = 296{tex}\\Rightarrow{/tex}\xa0n - 1 = 37{tex}\\Rightarrow{/tex}\xa0n = 38No. of integers between 200 and 500 that is divisible by 8 are 38. | |
| 25138. |
Distance of the point (-3,4)from x axis is |
| Answer» Distance of point from x-axis\xa0{tex}= | a |{/tex}Distance of point from y-axis\xa0= 4A.T.Q.{tex}| a | = \\frac { 1 } { 2 } \\times 4{/tex}{tex}\\Rightarrow | a |{/tex}\xa0= 2{tex}\\Rightarrow{/tex}\xa0{tex}a = \\pm 2{/tex} | |
| 25139. |
Hmara mock test h can u tell which r important questions plzzz |
| Answer» | |
| 25140. |
Cos Q |
| Answer» opp side divided by hypotenuse | |
| 25141. |
find the centre of circle passing through the points (3,0) (2,√5) (-2√2,-1) |
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| 25142. |
Sin1°×sin2°×sin3°×sin4°------------sin90°= |
| Answer» 0 (zero) | |
| 25143. |
I want question papers of 2018 |
| Answer» Check question papers here :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 25144. |
(1-sin+cos)^2=1 |
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| 25145. |
SinA(1+tanA)+cosA(1+cotA)=(secA+cosecA) |
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| 25146. |
can hydrogen react with platinum? |
| Answer» Yes hydrogen (h2) absorb on the surface of platinum and then dissociates into hydrogen (h) atoms. | |
| 25147. |
what is condom?how twins take place in human birth? |
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Answer» Thanks Sahil u r right |
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| 25148. |
if all sides of a triangle are respectively 12,12,12.what would be the angletheta? |
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Answer» 60° 60Ram RAM ram ☺?????????????????? 60degree |
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| 25149. |
(a+b) (a-b) |
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Answer» a^2 - b^2 a²-b² A square minus b square a^2 -b^2 a2-b2 |
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| 25150. |
Find value of x for which (5x+2),(4x-1) and (x+2) are in AP. |
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Answer» x=-3 it is right answer I think it is -3 X=3 |
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