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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 25301. |
Can I get chapterwise weightage of maths? |
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Answer» U can check out in this app also Hahahahaha mobile me koi browser nhi h kyaa?????????? Search on Google...?? |
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| 25302. |
Please give me the equations for that question |
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Answer» I have given that eqn see above please scrolll up screen It is the greatest common factor or diviser between or among the the algebric expressions Oooo Uska ans 4.8 hrs h Is my ans...right? Find hcf Find H.C.F....? |
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| 25303. |
A two digit number is 4 time the sum and 3time the product of it\'s digit .find the number |
| Answer» two digits, x & y10x + y = the number:>> A two digit number is 4 times the sum of its digits10x + y = 4(x+y)10x + y = 4x + 4y10x - 4x = 4y - y6x = 3y>> divide both sides by 32x = y >> " and twice the product of its digit."10x + y = 2xy>> Replace y with 2x10x + 2x = 2*x*2x12x = 4x^2>> Divide both sides by 4x3 = xtheny = 2(3)y = 6:>> the number = 36 | |
| 25304. |
Do any1 have maths question paper of sahodaya compex?? |
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| 25305. |
aj konsa pre board hai mera sci |
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Answer» Kaal hamara Mathematics exam fantastico raha. Maths Bhai mera bhi hai 2nd language bengali ka. |
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| 25306. |
Determine the AP whose 3rd term is 16 and 7th term exceed the 5th term by 12 |
| Answer» Let the first term and the common difference of the AP be a and d respectively.Then,Third term = 16{tex} \\Rightarrow {/tex}\xa0a + (3 - 1)d = 16\xa0{tex}\\because {a_n} = a + (n - 1)d{/tex}{tex} \\Rightarrow {/tex}\xa0a + 2d = 16 ...... (1)and, 7th term = 5th term + 12{tex} \\Rightarrow {/tex}\xa0a + (7 - 1)d = a + (5 - 1)d + 12\xa0{tex}\\because {a_n} = a + (n - 1)d{/tex}{tex} \\Rightarrow {/tex}\xa0a + 6d = a + 4d + 12{tex} \\Rightarrow {/tex}\xa06d - 4d = 12{tex} \\Rightarrow {/tex}\xa02d = 12{tex} \\Rightarrow d = \\frac{{12}}{2} = 6{/tex}Put d = 6 in (1), we geta + 2(6) = 16{tex} \\Rightarrow {/tex}\xa0a + 12 = 16{tex} \\Rightarrow {/tex}\xa0a = 16 - 12{tex} \\Rightarrow {/tex}\xa0a = 4Hence, the required APs also4, 4 + 6, 4 + 6 + 6, 4 + 6 + 6 + 6, .......i.e. 4, 10, 16, 22, ....... | |
| 25307. |
find the value of k fir which the roots of quadratic equation (k+1)^2x^2-2(k-1)x+1=0 are equal |
| Answer» {tex}( k + 1 ) x ^ { 2 } + 2 ( k + 1 ) x + 1 = 0{/tex}\xa0has equal roots if\xa0D = 0i.e\xa0{tex}b ^ { 2 } = 4 a c{/tex}Here, a = (k+1), b = 2 (k+1), c = 1or,\xa0{tex}4 ( k + 1 ) ^ { 2 } = 4 ( k + 1 ){/tex}{tex}k ^ { 2 } + 2 k + 1 = k + 1{/tex}{tex}k^2+2k+1-k-1=0{/tex}{tex}k ^ { 2 } + k = 0{/tex}k(k + 1) = 0k = 0, - 1Since k = - 1 does not satisfy the equation{tex}\\Rightarrow{/tex}k=0 | |
| 25308. |
Find the value of K for which the quadratic equation 2x2 kx 3 |
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Answer» ? Han bhaii shi bola Incomplete que... |
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| 25309. |
Tan 60 value |
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Answer» Root3 √3 |
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| 25310. |
Find one rational and one irrational no. Between √3 and √5 |
| Answer» Rs agrawal me hai | |
| 25311. |
x⁴-(a+b)x³-a(a-b)x²+a²(a+b)x-a³b=0 |
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| 25312. |
Xy/x+y=1/2,xy/x-y=1/6,x+y≠0,x≠y solve |
| Answer» X :- -1/2 and y :- 1/4. | |
| 25313. |
Cost + sin theta is equal to root 2 cos theta cos |
| Answer» So wat? | |
| 25314. |
( a square + b square + c square) |
| Answer» a^2+b^2+c^2+2ab+2bc+2ca | |
| 25315. |
Hay friends |
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Answer» Why not Usha How are you all Hi can I join you Hi Hiii Hey |
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| 25316. |
I want to know some important mathematics questions |
| Answer» Ohoo | |
| 25317. |
In acute angle triangle sin(A+B-C)=1÷2,cos(B+C-A)=1÷√2.Find A,B,C. |
| Answer» Sin(A+B+C)= 1/2Thus, A+B+C=30°....(i)Cos(B+C-A)= 45°.... (ii)A+B+C=180° [sum of all angles of a triangle]...(iii)Now solve it | |
| 25318. |
If a |
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| 25319. |
A is a point on side AD in a parollagram ABCD and BE intersect CD at D prove ABE=CFB |
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| 25320. |
sabnay yo yo honey singh ka naya gana suna i am king |
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Answer» Nhi Naa Na ji |
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| 25321. |
abhi hm sabko mobile ko chodna honga aj saiy hm kasam khate hai ki 1 mhena no moblie |
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Answer» Aisa ho nhi sakta ??? Chhodna likho bhai ???? |
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| 25322. |
Find the hcf of the number given below k 2k 3k 4k and 5k where k is any positive integer |
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Answer» Do you know bengali? K. ??? Sathick konta K 2 K |
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| 25323. |
If sinK1+sinK2+sinK3=3; then what is value of cosK1+cosK2+cosK3=? |
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| 25324. |
2+:2 |
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Answer» 4 2+2=4 Ye kya likja b bhai |
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| 25325. |
Show that the square of an odd positive integer is of the form 8m+1, where m is some whole number. |
| Answer» Since, any odd positive integer n is of the form 4m\xa0+ 1 or 4m + 3.if n = 4m + 1n2 = (4m + 1)2= 16m2 + 8m + 1= 8(2m2 + m) + 1So n2 = 8q + 1 ........... (i)) (where q = 2m2 + m is a positive integer)If n = (4m + 3)n2 = (4m + 3)2= 16m2 + 24m + 9= 8(2m2 + 3m + 1) + 1So n2 = 8q + 1 ...... (ii) (where q = 2m2 + 3m + 1 is a positive integer)From (i) and (ii) we conclude that the square of an odd positive integer is of the form 8q + 1, for some integer q. | |
| 25326. |
If tan+sin =m and tan-sin=n then prove that m+n=√4mn |
| Answer» Given, {tex}\\tan \\theta + \\sin \\theta = m{/tex} and {tex}\\tan \\theta - \\sin \\theta = n{/tex}L.H.S =\xa0{tex}m^{2}-n^{2}{/tex}{tex}=(tan\\theta+sin\\theta)^{2}-(tan\\theta-sin\\theta)^{2}{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-[tan^{2}\\theta+sin^{2}\\theta-2tan\\theta sin\\theta]{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-tan^{2}\\theta-sin^{2}\\theta+2tan\\theta sin\\theta{/tex}{tex}=4tan\\theta sin\\theta{/tex}R.H.S = 4{tex}\\sqrt{mn}{/tex}{tex}=4\\sqrt{(tan\\theta+sin\\theta)(tan\\theta-sin\\theta)}{/tex}{tex}=4\\sqrt{tan^{2}\\theta-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta}{cos^{2}\\theta}-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{cos^{2}\\theta}}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta (1-cos^{2}\\theta)}{/tex}{tex}=\\frac{4}{cos\\theta} \\times sin\\theta \\times \\sqrt{sin^{2}\\theta}{/tex}{tex}=4tan\\theta sin\\theta{/tex}Hence, L.H.S = R.H.S | |
| 25327. |
(sinA+secA)^2+(cosA+cosecA)^2=(1+secA×cosecA)^2 |
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| 25328. |
How I do preparation for board exam |
| Answer» Mast rhe | |
| 25329. |
7+6 |
| Answer» 13 | |
| 25330. |
1×2 |
| Answer» 2 | |
| 25331. |
Find cosec 30°and cos60° geometrically |
| Answer» 2,1/2 | |
| 25332. |
Hi..... |
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Answer» Hlo Hlo Namaskar Namaskar |
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| 25333. |
How triangle |
| Answer» | |
| 25334. |
Which term of the progression 4,9,14,19,...is 109 |
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Answer» 20 22 22 22 21 22 |
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| 25335. |
If the product of the zeroes of the polynomial ax²-5x+6 is 5, then find the value of a. |
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Answer» Nice Product of zeroes=c/a = 6/a5= 6/aa=6/5 6/5 6/5 |
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| 25336. |
What is underroot |
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Answer» Underroot squareroot nhi hota h Square root |
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| 25337. |
Are yaar batao cbse ke mah ke paper me choice aayigi kya |
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Answer» Sample paper me 7choice hai Yes maximum 4 marks ke questions me aayenge Haa |
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| 25338. |
where all of u live |
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Answer» CG Who |
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| 25339. |
Ac²=Ab²+Bc²-2Bc•Bd prove that |
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| 25340. |
Sir how to prepare ss to get 90 above |
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| 25341. |
Weight 4 6 8 10 12 14No.of 36 32 22 10 5 2Children |
| Answer» What to find? Mean, median or mode? | |
| 25342. |
Find them coordinates of them point equidistant from three given points A (5,1),B(-3,-7)and (7,-1) |
| Answer» We haveA {tex}\\rightarrow{/tex} (5, 1)B {tex}\\rightarrow{/tex} (-3, -7)C {tex}\\rightarrow{/tex} (7, -1)Let the point P(x, y) be equidistant from the three given points A, B, and C.Then PA = PB = PC{tex}\\Rightarrow{/tex} PA2 = PB2 = PC2First two givePA2 = PB2{tex}\\Rightarrow{/tex} (x - 5)2 + (y - 1)2 = (x + 3)2 + (y + 7)2{tex}\\Rightarrow{/tex} x2 - 10x + 25 + y2 - 2y + 1 = x2 + 6x + 9 + y2 + 14y + 49{tex}\\Rightarrow{/tex} 16x + 16y + 32 = 0{tex}\\Rightarrow{/tex} x + y + 2 = 0 ....Dividing throughout by 16 ....(1)Last two givePB2 = PC2{tex}\\Rightarrow{/tex} (x + 3)2 + (y + 7)2 = (x - 7)2 + (y + 1)2{tex}\\Rightarrow{/tex} x2 + 6x + 9 + y2 + 14y + 49 = x2 - 14x + 49 + y2 + 2y + 1{tex}\\Rightarrow{/tex} 20x + 12y + 8 = 0{tex}\\Rightarrow{/tex} 5x + 3y + 2 = 0 ....Dividing throughout by 4 ....(2)Multiplying equation (1) by 3, we get3x + 3y + 6 = 0 ....(3)Subtracting equation (3) from equation (2), we get2x - 4 = 0{tex}\\Rightarrow{/tex} 2x = 4{tex}\\Rightarrow x = \\frac{4}{2} = 2{/tex}Subtracting x = 2 in equation (1), we get2 + y + 2 = 0{tex}\\Rightarrow{/tex} y + 4 = 0{tex}\\Rightarrow{/tex} y = -4Hence, the required points is (2, -4). | |
| 25343. |
(-1)n+(-1)2n+1+)-1)4n+2, where n is any odd positive integer |
| Answer» Done | |
| 25344. |
Why are bags of chips flushed with nitrogen gas |
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Answer» To prevent from rusting this ans.. given in NCERT To avoid rancidity To prevent from rancidity ? So that it would not come in contact with o2 and thus to protect from rancidity To prevent it from rancidity |
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| 25345. |
What is Major segment |
| Answer» Segment covering area more than half of circle | |
| 25346. |
What is theodolite ??? Kisi ko nhi pata kya ??????? |
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Answer» Use in trigonometric measurement Sahii hai ?????? ??? Maine Google kiya hai: instruments which measure horizontal and vertical angles Mai he batao kya |
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| 25347. |
What is theodolite ??? |
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Answer» U r mathematician and u don\'t know about this anyone here...who can answer Don\'t know This is from maths broo Kitti der lagayega bhai Weak in bio.....ask from his.. |
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| 25348. |
Area of segment |
| Answer» Ø/360 ×pi r² - area of ⛛ | |
| 25349. |
How many sample papers are there in ulike |
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Answer» 300 print rate U like z a very nice book Laraib approx nhi exact value de. Approx 275 And price 20 unsolved and 20 solved |
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| 25350. |
How we can do cosA-sinA+1/cosA+sinA-1 |
| Answer» 1 | |