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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 25951. |
Q4 of ex 7.2 |
| Answer» Prefer this app itself go for ncert exercises in maths section | |
| 25952. |
Chapter 7 all exercise question |
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Answer» Which subject What |
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| 25953. |
All furmula |
| Answer» Of? | |
| 25954. |
If cos A =2/5 then find the value of 4+4tan2 A |
| Answer» 25 | |
| 25955. |
Sin squared is equal to 2 sin a what will be the value of a |
| Answer» | |
| 25956. |
Two zeroes of a cubic polynomial ax3+3x2-bx-6are -1and-2.find the third zero and values of a and b. |
| Answer» Let {tex}p(x) =ax^3 + 3x^2\xa0- bx\xa0- 6{/tex}{tex}\\because{/tex}\xa0- 1 is a zero{tex}\\therefore{/tex}\xa0{tex}p(-1) =0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}a(-1)^3\xa0+ 3(-1)^2\xa0- b(-1) - 6 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}-a + 3 + b - 6 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}-a + b = 3.{/tex}.........(i)Also, -2 is another zero{tex}\\therefore{/tex}\xa0{tex}p(-2) =0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}a(-2)^3\xa0+ 3(-2)^2\xa0- b(-2) - 6 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}- 8a + 12 + 2b - 6 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}- 8a + 2b = -6{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}4a - b = 3{/tex}.........(ii)Solving equation (i) and (ii), we geta = 2 and b = 5{tex}\\therefore{/tex} p(x) = 2x3 + 3x2\xa0- 5x\xa0- 6Let third zero = kSum of zeroes =\xa0{tex}\\frac { - 3 } { 2 }{/tex}{tex}\\Rightarrow{/tex}\xa0-1 + (-2) + k =\xa0{tex}\\frac { - 3 } { 2 } \\Rightarrow k = \\frac { - 3 } { 2 } + 3 = \\frac { 3 } { 2 }{/tex}Therefore, third zero =\xa0{tex}\\frac { 3 } { 2 }{/tex} | |
| 25957. |
How can I pass in maths..?? |
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Answer» Do you knowWork hard in silence and let the success make noiseSo, you can pass in math by work hard Do first ncert and then rd sharma because it is the best book By practice Practice By practicing ?? Just practice |
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| 25958. |
Find the middle term of AP 6,13,20,........216. |
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Answer» May be 104 and 111??is it correct? 111 is the middle term |
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| 25959. |
Is there any formula to find the middle term of an arithmetic progression |
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Answer» Yes if no. Of terms are odd then middle term is n+1/2 the term. See in RD Sharma for more details No |
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| 25960. |
How to rationalize |
| Answer» You should see video on YouTube | |
| 25961. |
Discuss the roots of the quadratic equation 4/3x2_2x+3/4=0 |
| Answer» | |
| 25962. |
Is Ncert good for board exam |
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Answer» Ya ?? Yes but you should do it by heart Yes.... |
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| 25963. |
3x-5y=5 |
| Answer» X= 5+5y/3 | |
| 25964. |
What is geometric progression |
| Answer» Geometric Progression is a progression of numbers with a constant ratio between each number and the one before (e.g. 1, 3, 9, 27, 81). | |
| 25965. |
How to find length of altitude of the parallelogram on the base AB if A ,B,C,D points are given |
| Answer» | |
| 25966. |
Find the area of triangle with vertices a, b + c, b,c+a and c, a + b |
| Answer» 0 | |
| 25967. |
How many number not divisible by 2,3,5 between 1 to 900 |
| Answer» Prime no... | |
| 25968. |
Root of 2 |
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Answer» 1.414 1.41 1.414 |
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| 25969. |
If one zero of p(x)=4x2-(8k2-40k)x-9 is negetive of other find the value of k. |
| Answer» | |
| 25970. |
Find the 17th term from the end of the ap: 1,6,11,16...201,216 |
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Answer» 136 136 |
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| 25971. |
1वोल्ट की परिभाषा |
| Answer» 1 joule/ coulomb | |
| 25972. |
If cosa/cosB=m and cosa/sinB=n.show that (mm+nn)coscosB=nn. |
| Answer» | |
| 25973. |
Explain why 13233343563715 is a composite number??? |
| Answer» 13233343563715 , this number can divided evenly by 5 ( as well as 1 or itself) thats why its become composite number... | |
| 25974. |
1/sinQ =1-tanQ |
| Answer» 1 | |
| 25975. |
how to complete maths in one month |
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Answer» Confident yourself Never Just practice ncert only |
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| 25976. |
-x + 3y = 84x + 7y = 25 By eliminating method |
| Answer» x=1 and y=3 | |
| 25977. |
What is the meaning of nth term in arithmetic progression chapter? |
| Answer» The number of term uh are finding.or it\'s given find the nth term means unknown terms in simple terms x | |
| 25978. |
- 4 + 3 Y equal to 8 4x+ 7 y = 25 |
| Answer» | |
| 25979. |
Reproduction is essential for survival of organisms.comment |
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Answer» Continuity of our species Sorry ....wrong anybody else Sorry...wrong anybody else Reproduction causes variation... variation causes help in natural selection where one variant can survive even in exterme conditions.... |
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| 25980. |
Length of sides of triangle are 2x+y÷2\'5x3--× |
| Answer» | |
| 25981. |
For What value of n, n^th terms would be same of two APs 63 65 67 ........ and 3 10 17 ......... |
| Answer» 13th term | |
| 25982. |
ABC is an isosceles triangle right angled C. Prove that AB² = 2AC² |
| Answer» Using Pythagoras theorem | |
| 25983. |
what is terminating numbers and non terminating numbers ? |
| Answer» terminating numbers are repeating numbers...and non terminating are non repeating numbers . they are in fraction form.. | |
| 25984. |
How to concentrate while studying..... |
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Answer» don\'t drink water during study.. because chemistry says adding water decreases concentration ?? Don\'t use smartphone Think only about you class 10 results Chocolate khakhe pd... high sugar lvl... high attention |
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| 25985. |
What is TanA ×CosA |
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Answer» Just checking you guys SinA SinA |
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| 25986. |
Solve for x: 9x²-6ax+(a²-b²)=0 |
| Answer» Given equation, 9x2- 6ax + a2- b2 = 0{tex}\\therefore \\quad x = \\frac { 6 a \\pm \\sqrt { ( - 6 a ) ^ { 2 } - 4 \\times 9 \\times \\left( a ^ { 2 } - b ^ { 2 } \\right) } } { 2 \\times 9 }{/tex}or,\xa0{tex}x = \\frac { 6 a \\pm \\sqrt { 36 a ^ { 2 } - 36 a ^ { 2 } + 36 b ^ { 2 } } } { 18 }{/tex}or,{tex}x = \\frac { 6 a + 6 b } { 18 } , x = \\frac { 6 a - 6 b } { 18 }{/tex}or,\xa0{tex}x = \\frac { 6 ( a + b ) } { 18 } , x = \\frac { 6 ( a - b ) } { 18 }{/tex}or,\xa0{tex}x = \\frac { a + b } { 3 } , x = \\frac { a - b } { 3 }{/tex} | |
| 25987. |
ax+by=1 and bx+at=(a+b)®÷a®+b®-1 |
| Answer» Given equations are{tex}ax + by - 1 = 0{/tex}....(i) and {tex}bx + ay ={/tex}\xa0{tex}\\frac { ( a + b ) ^ { 2 } - \\left( a ^ { 2 } + b ^ { 2 } \\right) } { a ^ { 2 } + b ^ { 2 } }{/tex}{tex}\\Rightarrow{/tex}{tex}bx + ay ={/tex}\xa0{tex}\\frac { 2 a b } { a ^ { 2 } + b ^ { 2 } }{/tex}{tex}\\Rightarrow{/tex}{tex}(a^2 + b^2)bx + (a^2 + b^2)ay - 2ab = 0{/tex}...(ii)Here a1 = a, b1 = b, c1 = -1a2 = (a2 + b2)b,b2 = (a2 + b2)a,{tex}c_2 = -2ab{/tex}By cross multiplying method, we have{tex}\\Rightarrow{/tex}{tex}\\frac { x } { b _ { 1 } c _ { 2 } - b _ { 2 } c _ { 1 } }{/tex}\xa0=\xa0{tex}\\frac { y } { c _ { 1 } a _ { 2 } - c _ { 2 } a _ { 1 } }{/tex}\xa0=\xa0{tex}\\frac { 1 } { a _ { 1 } b _ { 2 } - a _ { 2 } b _ { 1 } }{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac { x } { b \\times ( - 2 a b ) - \\left( a ^ { 2 } + b ^ { 2 } \\right) a \\times ( - 1 ) }{/tex}\xa0=\xa0{tex}\\frac { y } { - 1 \\times \\left( a ^ { 2 } + b ^ { 2 } \\right) b - ( - 2 a b ) \\times a }{/tex}\xa0=\xa0{tex}\\frac { 1 } { a \\left( a ^ { 2 } + b ^ { 2 } \\right) a - \\left( a ^ { 2 } + b ^ { 2 } \\right) b \\times b }{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac { x } { - 2 a b ^ { 2 } + a ^ { 3 } + b ^ { 2 } a }{/tex}\xa0=\xa0{tex}\\frac { y } { - a ^ { 2 } b - b ^ { 3 } + 2 a ^ { 2 } b }{/tex}\xa0=\xa0{tex}\\frac { 1 } { \\left( a ^ { 2 } + b ^ { 2 } \\right) a ^ { 2 } - \\left( a ^ { 2 } + b ^ { 2 } \\right) b ^ { 2 } }{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac { x } { a ^ { 3 } - a b ^ { 2 } }{/tex}=\xa0{tex}\\frac { y } { a ^ { 2 } b - b ^ { 3 } }{/tex}\xa0=\xa0{tex}\\frac { 1 } { \\left( a ^ { 2 } + b ^ { 2 } \\right) \\left( a ^ { 2 } - b ^ { 2 } \\right) }{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac{x}{a}{/tex}\xa0=\xa0{tex}\\frac{y}{b}{/tex}\xa0=\xa0{tex}\\frac { 1 } { a ^ { 2 } + b ^ { 2 } }{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac{x}{a}{/tex}\xa0=\xa0{tex}\\frac { 1 } { a ^ { 2 } + b ^ { 2 } }{/tex}\xa0and y =\xa0{tex}\\frac { 1 } { a ^ { 2 } + b ^ { 2 } }{/tex}{tex}\\Rightarrow{/tex}x =\xa0{tex}\\frac { a } { a ^ { 2 } + b ^ { 2 } }{/tex}\xa0and y =\xa0{tex}\\frac { b } { a ^ { 2 } + b ^ { 2 } }{/tex} | |
| 25988. |
1+sinA/1+cosa |
| Answer» 1+tanA | |
| 25989. |
Define maths in 3 words |
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Answer» Yaa Depends on interest Seriously?? Very interesting subject |
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| 25990. |
Find probabilityof card drawn from52 cards (1) ace and king. (2) jack or Queen |
| Answer» 1)02)8/52=2/13 | |
| 25991. |
If the diameter of a semi circular protector is 14cm, then find its perimeter |
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Answer» Sorry its πr+d bcoz the perimeter of full circle is 2πr so the perimeter of semi circle is.....πr+d Yes varsha is right perimeter of semi circle is 2πr+d 36cm as perimeter of semicircle is 22/7r+2r 22/7*7 because perimeter of circle is 2πr 22cm |
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| 25992. |
If (1,2) , (4,y), (x,6) and (3,5) are the vertices of a parallelogram taken in order , find x and y |
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Answer» You can apply mid point area and distance formula to get the values X=6 Y=3 Mid point of AC=midpoint of BD /mid point is O We know that diagonals of ||gram bisect each other therefore the mid point of both diagonals will be equal....hence apply the mid point formula |
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| 25993. |
Plz prof it |
| Answer» See the proof in Ncert.its given | |
| 25994. |
Find a quadratic polynomial whose sum and products of its zeros are 1/4,-1 respectively |
| Answer» 1/4 (4x^2-x-4) | |
| 25995. |
Instructions |
| Answer» | |
| 25996. |
Sec2theta -tan2theta= |
| Answer» 1 | |
| 25997. |
Find side of equilateral triangle of area 196√3m` |
| Answer» √3/4.(side) ^2 = 196√3(side) ^2=196.4Side=√196.√4Side=14.2Side=28 | |
| 25998. |
if K + 1 K - 4 K + 3 hour constructive terms of AP then find the value of k |
| Answer» | |
| 25999. |
Is -1 a term of an AP 27,23,19,.......-65? Justify |
| Answer» | |
| 26000. |
Hcf of 33 |
| Answer» | |