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26201.

How many terms of the series 54,51,48...be taken so that their sum is513?explain the double answer

Answer» Given series is 54, 51, 48,...Here, a = 54, d = 51 - 54 = - 3Let number of terms be n, then their sumSn\xa0= 513{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { n } { 2 }{/tex}\xa0[2a + (n - 1) d] = 513{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { n } { 2 }{/tex}\xa0[2\xa0{tex}\\times{/tex}\xa054 + (n - 1) (- 3)] = 513{tex}\\Rightarrow{/tex}\xa0n (108 - 3n + 3) = 513\xa0{tex}\\times{/tex}\xa02{tex}\\Rightarrow{/tex}\xa0- 3n2\xa0+ 111n = 1026{tex}\\Rightarrow{/tex}\xa0- (3n2\xa0- 111n + 1026) = 0{tex}\\Rightarrow{/tex}\xa0n2\xa0- 37n + 342 = 0{tex}\\Rightarrow{/tex}\xa0(n - 18) (n - 18) = 0\xa0{tex}\\Rightarrow{/tex}\xa0n = 18 or 19Here, the common difference is negative and 19th\xa0term= 54 + (19 - 1)\xa0{tex}\\times{/tex}\xa0(- 3) = 0So, the sum of 18 terms as well as that of 19 terms is 513.
26202.

Find the value of k,in which system of equation x 3y=2 and 2x ky=8 has no solution.

Answer»
26203.

In a family of 3 children find the probability of having atleast one boy

Answer» 2/3 or 1?
1.
?
How
2/3
26204.

Derivation of section formula in coordinet geometry

Answer» It is in Ncert
Yha kese kre ??
26205.

Which identity is used in(x-3)(x+3)

Answer» (a+b)(a-b)=a²-b²
X²-y²
X^2 - y^2
26206.

How can we find middle terms of AP

Answer» (a+b)(a-b)... correct?
26207.

Root 5 is irrational proved

Answer» In chapter it is given in example
Yha proof kese kre??
26208.

Sin3=3sin - 4sin-4

Answer» Given that x = 30o\xa0we have to verify that sin 3x = 3sin x - 4sin3x.{tex}\\Rightarrow 3 x = 90 ^ { \\circ }{/tex}{tex}\\therefore\\sin 3 x{/tex}{tex}= \\sin 90 ^ { \\circ } = 1{/tex}and, 3sin x - 4sin3x{tex}= 3 \\sin 30 ^ { \\circ } - 4 \\sin ^ { 3 } 30 ^ { \\circ }{/tex}{tex}= 3 \\times \\frac { 1 } { 2 } - 4 \\left( \\frac { 1 } { 2 } \\right) ^ { 3 }{/tex}{tex}= \\frac { 3 } { 2 } - \\frac { 1 } { 2 } = 1{/tex}.
26209.

Formula of area of rhombus

Answer» 4×area of∆AOB
Multiply length of digonals ÷2
26210.

In circle of triangle abc touches the side bc,ca,ab, at d,e,f .if ab=ac .Prove that bd=cd

Answer» So easy
26211.

3xxxx-6xx-8x+2

Answer»
26212.

Ex:13.3 *6

Answer» Please type the question
26213.

Boards ki preparation kse chl ri h

Answer» Hi
Hello friends I m Aakash from delhi
Ishan ap ka k ho
Okk..
No ishan it\'s apna uttarakhand...
United Kingdom ????
Okkk
I m from UK
????Board ki preparation bus???????????????????
And u ashia
I am from delhi
badiya
Archita ap ka se ho
jasi chalti h vase hi
??
?????
Sahi kaha ishan
Badiya
Bs chalye chalye bahut door chli gyi??
26214.

Pls send preboard papers.

Answer» How How How How......???????????????????
How??????
How ...
how???
26215.

What is a tangent on a circle

Answer» The line which passes through only one point of a circle is known as a tangent to a circle. ORThe line which is perpendicular to the radius at the point of contact of a circle is known as a tangent to the circle.
Any point of circle from which line can be drawn
26216.

In the given figure an and CD are 2 diameter

Answer»
26217.

Smallest composite number?

Answer» 4
4
26218.

47359445754754-373583367

Answer» I mean shivam
What is this shivaji
26219.

Which types of question come in exam

Answer» Its depend upon you that how you are studying nothing is hard if you will study hard then questions paper will be easy
easy bt depends on u...
26220.

Whole no

Answer» 0,1,2,3,4...n
26221.

√3044

Answer» 55.1724
26222.

What is progeny?

Answer» Next generation
26223.

18=18+2(k-8÷40-k)

Answer»
26224.

An equilateral triangle is inscribed in a circle of radius 6 cm . Find its side

Answer» Let {tex}\\Delta ABC{/tex} is an equilateral triangle of each side \' 2a\' inscribed in a circle of radius 6 cm and centre O.Draw {tex}AD \\bot BC{/tex} .Then ,BD = DC [In a equilateral triangle, perpendicular bisects the base]Also , O lies on AD [ In a equilateral triangle circumcentre and centroid coincides]Thus , OA : OD = 2 : 1{tex}\\Rightarrow \\frac{6}{OD}=\\frac{2}{1}{/tex}{tex}\\Rightarrow OD=3 cm {/tex}, then AD = 9 cmNow , using pythagoras theorem in {tex}\\triangle ABD{/tex}BA2 = BD 2 + AD2(2a)2 = (a)2 + (9)24a2 = a2 + 813a2 = 81a2 = 27we get {tex}a=3\\sqrt3{/tex}Side of triangle = 2a = {tex}2(3\\sqrt3){/tex} = {tex}6\\sqrt3{/tex}cm
26225.

If sinA-cosA=1/2Find 1/sinA+cosA

Answer» 4(sinA-cosA)
26226.

30a+44b=10 40a+55b=13

Answer» What we have to find
26227.

If cosA+sinA =√2cosA then show that (cosA -sinA)=√2 sin A.

Answer»
26228.

If sins=Cosa then find the value of 2tana+cos2a

Answer»
26229.

show that cube of the positive integer cab be of the form 4q+3 where q is some integee

Answer»
26230.

X=√5+√5+√5+√5+.......

Answer»
26231.

Linear equation graph is tough

Answer» I don\'t think soo
Ya right said
No it\'s easy u have to just practice more in that
No
26232.

What is an AP?

Answer» Vasa pta to h but i just try that is this app works correctly ??
arithmetic progression
Arethametic chapter in maths?
you đón t know
26233.

2y= x

Answer» Find
Fund kya krna hai
?????
26234.

Find the 24th term of the AP -5,-5/2,0,-5/2...

Answer» 105/2
26235.

What is the probability of an 3,4,5and6coins tosed in stimulation

Answer»
26236.

If 3sinA+5cosA=5 , prove that 5sinA-3cosA=+-3

Answer» i want answer of this question
26237.

Find the value of P for which one root of the quadratic equation px2-14x+8=0;is 6 times the other

Answer» Let\xa0{tex}\\alpha{/tex}\xa0and\xa0{tex}6\\alpha{/tex}\xa0be the roots of equation.We have, {tex}px^2-14x+8=0{/tex} where a= p, b = -14, c = 8Sum of zeroes{tex} = -\\frac ba = -\\frac{-14}{p}{/tex}{tex}\\alpha +6\\alpha=\\frac{14}{p}{/tex}{tex}7\\alpha = \\frac{14}{p}{/tex}{tex}\\alpha = \\frac2p{/tex}............(i)Also, Product of the zeroes\xa0{tex} = \\frac 8p=\\frac ca{/tex}{tex}\\alpha \\times 6\\alpha = \\frac 8p{/tex}{tex}6\\alpha^2=\\frac 8p{/tex}From (i){tex}6(\\frac{2}{p})^2=\\frac 8p{/tex}{tex}6\\times \\frac {4}{p^2}=\\frac 8p{/tex}{tex}\\frac{6}{p^2}=\\frac2p{/tex}{tex}\\frac 62=\\frac{p^2}{p}{/tex}{tex}Hence, \\ p=3{/tex}
26238.

spuare completing methad class 10

Answer»
26239.

if a tower 30 m high casts a shadow 10√3 then what is the angle of elevation of the sun

Answer» Here not possible
60°
Explain how 60 with diagram
60
Its 60
26240.

if a tower 30 m high casts a shadow 10√3

Answer» What to find
26241.

Find k,.if the quadratic equation 3x×x-k√3x+4,has equal roots?

Answer» +4 or-4
26242.

1+2+3+4+5+6+7+8+.....+................... infinite=

Answer» Infinity
26243.

if the ratio of sum of first n term of two AP is (7n+1);(4n+27) find the ratio of m term

Answer» See the answer of this question in the R.D Sharma book. Example 21 page (9.35)
26244.

determine the greatest no divided 9,11,13 leave remainder 1,2,3

Answer» u need subtract remainder from given no. and find their h.c.f u get answer ,ok may be it helps
26245.

Find the greatest number by which 2053 and 967 are divided, remainders 5 and 7 respectively

Answer» The required number divides (2053 - 5) ,I.e., 2048 and (967-7),I.e.,960 exactly. Now , 2048 =( power of 2 is 11) and 960 = ( power of 2 is 6 * 3 * 5) therefore HCF (2048,960)=( power of 2 is 6)=64
26246.

Solve the following quadratic equation for x: x square - 4 ax - b square + 4 a square=0

Answer» Answer. (2a+b)or (2a-b)
26247.

How to prove √5 is irrational ..

Answer» Thanks Disha
Suppose it to be a rational no. =a/b (a & b are co-prime no. and b is not=0 .then solve it.
Thanks for helping me
Hi
Neha is correct
Neha you give incomplete answer
At first,take it as rational then prove it irrational by contradiction.
26248.

Sec =

Answer» Hypotanus upon base
26249.

Thales theorum

Answer» BPT states if a line divides two sides of a triangle then corresponding lengths of side are equal.
Jaspreet ek question h
26250.

Prove Tangent are 90 degree angle

Answer» The shortest distance between two points is perpendicular distance therefore tangent of a circle is 90degree tocentre of a circle
It is theorem that the tangent drawn on a circle makes a perpendicular angle at centre .so it is prove that tangent are 90°angle