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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 26901. |
Derivation of the formula of frustum of the cone |
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| 26902. |
Please ans me |
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| 26903. |
Hello everyone how was your day |
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Answer» Kah Thik kab sakte hain |
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| 26904. |
Did all question will be from ncert |
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| 26905. |
For an AP, show that Tp+Tp+2q=2Tp+q |
| Answer» Let the first term be a and the common difference be d.we know,\xa0{tex}a_n= a+(n-1)d{/tex}{tex}a_p=a+(p-1)d{/tex}{tex}a_{p+2q}=a+(p+2q-1)d{/tex}\xa0{tex}\\therefore a_p+a_{p+2q}=a + (p - 1)d + a + (p + 2 q -1)d{/tex}{tex}= a + pd - d + a + pd + 2qd - d{/tex}{tex}= 2a + 2pd + 2qd - 2d{/tex}{tex}= 2[a + (p + q - 1) d]{/tex} ............(i){tex}2a_{p+q}=2[a + (p + q - 1 ) d ]{/tex}\xa0..........(ii)From (i) and (ii), we getap + ap + 2q\xa0= 2ap+q | |
| 26906. |
Which term of sequence 20,77/4,37/2,71/4,.........is first negative term? How to solve this ???? |
| Answer» The given sequence is an A.P. in which first term a = 20 and common difference d =\xa0{tex}-\\frac34{/tex}Let the nth term of the given A.P. be negative thenT\u200b\u200b\u200b\u200b\u200b\u200bn\u200b\u200b\u200b\u200b\u200b < 0a+(n-1)d<020+(n-1)({tex}-\\frac34{/tex})<0On multiplication by 4 we get80-3n+3<083-3n<083<3nOr 3n>83{tex}n > \\frac{83}{3}{/tex}n > 27.67Hence 28th term will be first negative term | |
| 26907. |
A equilateral triangle ABC inscribed in a circle of radius 4 cm.Find side of triangle |
| Answer» ans 4√3 | |
| 26908. |
In a given AP if pth term is q and the qth term is p then show that the nth term is ( p+q - n). |
| Answer» Let \'a\' be the first term and d be the common difference of the given A.P.Then,according to question we have\xa0Tp = a + ( p - 1 )d and Tq = a + ( q - 1 )d.(where Tp\xa0and Tq\xa0are pth\xa0and qth\xa0terms\xa0of given A.P)Now, Tp = q and Tq=\xa0p (given).a + (p -1)d = q ...(i)and a + (q - 1) d = p ...(ii)On subtracting (i) from (ii), we get{tex}\\implies{/tex}(q-1)d-(p-1)d=p-q{tex}\\implies{/tex}qd-d-pd+d =p-q{tex}\\implies{/tex}(q - p)d = ( p - q ){tex}\\implies d=\\frac{p-q}{q-p}{/tex}{tex}\\Rightarrow{/tex}d = -1.Putting d = -1 in (i), we get a = (p + q -1).Thus, a = (p + q - 1 ) and d = -1.Therefore, nth term = a+ (n- 1)d = (p + q -1) + (n -1) {tex}\\times{/tex}\xa0(-1)=p+q-1-n+1= p + q - n.Hence, nth term = (p + q - n). Which is required answer. | |
| 26909. |
LCM of 5728,6785,7766 |
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| 26910. |
If perimeter and area of a circle are numerically equal, then find the radius of circle. |
| Answer» The radius is either 0 or 2 . | |
| 26911. |
What is Auxin?? |
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Answer» Its a plant growth hormome that is present at its tip. Auxin is growth hormone of plant Plant hormone |
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| 26912. |
Two stations due south to a leaning tower |
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| 26913. |
If the point (x,y)be equidistant from the point { (a+b),(b-a)}and{(a-b),(a+b)} prove that bx=ay |
| Answer» So easy???? | |
| 26914. |
The decimal expansion of rational number 14587÷1250 will terminate after how many decimal places |
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Answer» Kya m hass lu Ye joke tha Answer... Ranjan ka anwer so easy |
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| 26915. |
sina/sec a+tan a - 1 +cos a /cosec a + cot a |
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| 26916. |
20x²-157x+78 |
| Answer» X=7,0 | |
| 26917. |
If sum of first 10 terms of ap is -150 and sum of its next ten terms is -550 . Find ap |
| Answer» According to the question,the sum of first 10 terms of an AP is -150 and the sum of its next 10 terms is -550Let a be the first term and d be the common difference of the given AP.Then, we haveS10=-150{tex}\\Rightarrow \\frac { 10 } { 2 } [ 2 a + 9 d ] = - 150{/tex}{tex}\\Rightarrow{/tex}5[2a+9d]=-150{tex}\\Rightarrow{/tex}2a+9d=-30...(i)Clearly, the sum of first 20 terms =-150+(-550)=-700{tex}\\therefore{/tex}S20=-700{tex}\\Rightarrow \\frac { 20 } { 2 } [ 2 a + 19 d ] = - 700{/tex}{tex}\\Rightarrow{/tex}10[2a+19d]=-700{tex}\\Rightarrow{/tex}2a+19d=-70...(iii)Subtracting (i) from (ii), we get10d=-40{tex}\\Rightarrow{/tex}d=-4{tex}\\Rightarrow{/tex}2a=-30-9(-4)=-30+36=6{tex}\\Rightarrow{/tex}a=3Thus, we have\xa0First term=a=3Second term= a+d=3+2(-4)=-1Third term=a+2d=3+2(-4)=3-8=-5Fourth term=a+3d=3+3(-4)=3-12=-9Thus, the given AP is 3,-1,-5,-9,.... | |
| 26918. |
If AB parallel CD ,EF perpendicular CD and angle GED=126°,find angle AGE,angle GED and angle FGE |
| Answer» {tex}\\angle{/tex}AGE = {tex}\\angle{/tex}GED = 126o . . . [Alternate interior angles]{tex}\\angle{/tex}GED = 126o{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}GEF + {tex}\\angle{/tex}FED = 126o{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}GEF + 90o = 126o . . . [As EF ⊥ CD {tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}FED = 90o]{tex}\\therefore{/tex}{tex}\\angle{/tex}GEF = 126o – 90o = 36o{tex}\\angle{/tex}GEC + {tex}\\angle{/tex}GEF + {tex}\\angle{/tex}FED = 180o{tex}\\angle{/tex}GEC + 36o + 90o = 180o{tex}\\angle{/tex}GEC + 126o = 180o{tex}\\angle{/tex}GEC = 180o – 126o = 54o{tex}\\angle{/tex}FGE = {tex}\\angle{/tex}GEC = 54o . . . . [Alternate interior angles] | |
| 26919. |
If area of sector of a circle is 7/20of the area of circle, then find sector angle |
| Answer» 126° | |
| 26920. |
What is the formula of gas of frustum |
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| 26921. |
Mera bhai online h kya???? |
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| 26922. |
What is the formula of AP |
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| 26923. |
Prove that 1/root2 is irrational |
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| 26924. |
Hey frnds pls solve my question |
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| 26925. |
The pPer will come from outside?? |
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| 26926. |
Find the length of altitude of an equilateral traingle of side 2 cm |
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Answer» √3 √3 cm. |
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| 26927. |
Sample papers of class 10 of year 2017_2018 |
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| 26928. |
Sum of first 10 terms of a |
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| 26929. |
From which chapter questions will come more. |
| Answer» Algebra and trigonometry. | |
| 26930. |
Find 25th term of the A.P -5,-5/2,0,5/2,.......... |
| Answer» The given Arithmetic progression is\xa0{tex} - 5 , \\frac { - 5 } { 2 } , 0 , \\frac { 5 } { 2 } ,{/tex}.....Its first term a = -5 and common difference d =\xa0{tex}\\left( \\frac { 5 } { 2 } - 0 \\right) = \\frac { 5 } { 2 }.{/tex}Therefore,\xa0a = -5 and\xa0{tex}d = \\frac { 5 } { 2 }.{/tex}{tex}\\Rightarrow{/tex}\xa0T25 = a + (25-1)d{tex}= a + 24 d \\\\= ( - 5 ) + \\left( 24 \\times \\frac { 5 } { 2 } \\right)\\\\ = - 5 + 60 = 55.{/tex}Hence, 25th term = 55. | |
| 26931. |
Write 0.32 in fraction form |
| Answer» In order to express the above question in fractional formLet {tex}x = 0 . \\overline { 32 }{/tex}. Then,x = 0.3232... ...(i){tex}\\therefore{/tex} 100x = 32.3232... ...(ii)Subtract (i) from (ii), we obtain99x = 32\xa0{tex}\\Rightarrow x = \\frac { 32 } { 99 }{/tex}. Hence, {tex}0 . \\overline { 32 } = \\frac { 32 } { 99 }{/tex}. | |
| 26932. |
0.32 in fraction form |
| Answer» 0.32 in to Fraction = ?= 32/100 = 16/50= 8/25 is The Answer | |
| 26933. |
Find the hcf of 180 and 240 using prime factorization method |
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| 26934. |
When the examination 2018 |
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Answer» U can check on official website of cbse www.cbse.nic.in It will be in march. |
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| 26935. |
If HCF (a,b)= 12 and a ×b=1800,then find Lcm |
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Answer» 150 Sorry 150 is correct 150 216 is it correct..?? |
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| 26936. |
find the coordinates of point on y-axis which is closest to point(-2,5). |
| Answer» The point on y-axis that is nearest to the point(-2,5) is (0,5). | |
| 26937. |
Find the zeros of the polynomial |
| Answer» Which polynomial | |
| 26938. |
Why are you all not asking questions???? |
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| 26939. |
√12√12√12....... |
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| 26940. |
Sahil kaha ho are you busy |
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| 26941. |
how to learnt trigonometry |
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| 26942. |
Please send math notes in Hindi |
| Answer» Are u mad or what maths notes Hindi me nhi hote | |
| 26943. |
13 ch ka Q3 |
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| 26944. |
Find the zeroes of the polynomial x2+x-p(p+1) |
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| 26945. |
1/x-3-1/x+5=1/6 |
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| 26946. |
RIMSHA plZ |
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| 26947. |
RIMSHA reply me yrr |
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| 26948. |
Show that exactly one number n,n+2or n+4 is divisible by 3 |
| Answer» Let n =3kthen n + 2 = 3k + 2and n + 4 = 3k + 4Case 1: When n=3k ,n is divisible by 3 ............(1)n + 2 = 3k + 2or, n + 2 is not divisible by 3n + 4 = 3k + 4= 3(k + 1) + 1or, n + 4 is not divisible by 3Case 2:When n=3k+1, n is not divisible by 3\xa0n + 2 = (3k + 1) + 2=3k + 3 = 3(k + 1){tex} \\Rightarrow{/tex}\xa0n+ 2 is clearly divisible by 3..........................(2)n + 4 = (3k + 1) + 4= 3k + 5= 3(k + 1) + 2{tex}\\Rightarrow{/tex}\xa0n + 4 is not divisible by 3Case 3:When n=3k+2,n is not divisible by 3\xa0n + 2 = (3k + 2) + 2= 3k + 4(n + 2) is not divisible by 3x + 4 = 3k + 6 = 3(k + 2){tex}\\Rightarrow{/tex}\xa0n + 4 is divisible by 3........................(3)Hence, from (1),(2) and (3) it is clear that\xa0exactly one of the numbers n, n + 2, n + 4, is divisible by 3. | |
| 26949. |
The sum of the first and third term of HP is 9.The second term is 4 find the 10th term of that HP |
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| 26950. |
How many tangents does a circle have |
| Answer» Number of tangents of a circle depends upon the size and number of points in a circle. Number of tangents in a circle = Number of points in a circle For example, 500000 points = 500000 tangents | |