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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27101. |
Corss |
| Answer» ?? | |
| 27102. |
What is the diffrence between tan and cot |
| Answer» tani) Tanθ = opposite side/adjacent sideii) Tan θ = sinθ/cos θcoti) Cot θ = adjacent side/opposite sidrii) Cot θ = cosθ/ sin θ | |
| 27103. |
Hii..sbhi gye |
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Answer» Ok Ha bhi...??? |
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| 27104. |
Ldki bdi anjani h .....???? |
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Answer» Hm hitman ki ..❤️ Kiski Hitman ki na ???Bdalna bhi nhi....??? Dekho Ye Pagli bilkul na Badli...Ye Tu wahi Deewani Hai..?????? Kaun ??? |
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| 27105. |
Hola...hi hlo... |
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Answer» Hi bestir Hlow Hiiiiii bestie |
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| 27106. |
Write three greatest three digit number and express it in terms of its prime factors |
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| 27107. |
Huii...anybody is there ... |
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Answer» Baby doll aapka naam?? Hii Ya... Hlo |
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| 27108. |
In. a square + 9/ a = 6, what is the value of a |
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Answer» Hii The value of a is 2/3 1.5 ans |
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| 27109. |
(X+1)\\2 + (y-1)\\3= 8(X-1)/3 + (y+1)/2 =9Find the value of x and y |
| Answer» {tex}\\frac { x + 1 } { 2 } + \\frac { y - 1 } { 3 } = 9{/tex}\xa0or, 3(x + 1) + 2(y -1) = 54or, 3x + 3 + 2 y - 2 = 54or, 3x + 2y +1 = 54or, 3x + 2y = 53..........(i)and\xa0{tex}\\frac { x - 1 } { 3 } + \\frac { y + 1 } { 2 } = 8{/tex}\xa0or, 2(x -1 ) + 3 (y + 1) = 48or, 2x - 2 + 3y + 3 = 48or, 2x + 3y +1 = 48or, 2x +3y = 47........(ii)Multiply eqn.(i) by 3, multiply eqn.(ii) by 2 and subtracting both eqn{tex}\\therefore {/tex}\xa0{tex}x = \\frac { 65 } { 5 } = 13{/tex}\xa0Substitute the value of x in eqn. (ii),2(13) + 3y = 47or, 26 + 3y = 473y = 47-26 = 21{tex}\\therefore {/tex}\xa0{tex}y = \\frac { 21 } { 3 } = 7{/tex}\xa0Hence x = 13, y = 7. | |
| 27110. |
Factorise : t sq.+ 15 |
| Answer» T ka whole square and root 15 ka whole square se solve hoga | |
| 27111. |
Hiii ...koi h... |
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Answer» Hii Hlo plk Hlo.. |
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| 27112. |
Cube root of (10+6√2) Anyone plz tell |
| Answer» Plzz telll anyone | |
| 27113. |
P(x)=5x+6Value x is -2/3 |
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Answer» 8/3 is the answer 8/3 |
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| 27114. |
2x/x-4 +2x-5/x-3 =25/3 |
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| 27115. |
Kaisa gaya sab ka result.... ? |
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Answer» Bohat bdia ...???? Ohh to phir Kab h Aaj ni aaya |
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| 27116. |
If tan(A+B) =√3 and Tan(A-B) = 1/√3, where A and B are acute angle. Find them |
| Answer» Tan (A+B) = √3Since tan 60 = √3 Therefore A+B = 60°Tan A- B= 1/√3 A -B = 30 Therefore by elimination method2A = 90=> A = 45 B = 15 | |
| 27117. |
Aaj result aaraha hai ki nahi?? |
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Answer» Nhi Ni |
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| 27118. |
Prove that√3 is irrational |
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Answer» Let us assume that √3 is a rational number.That is, we can find integers\xa0a\xa0and\xa0b\xa0(≠ 0) such that √3 = (a/b)Suppose a and b have a common factor other than 1, then we can divide by the common factor, and assume that a and b are coprime.√3b = a⇒\xa03b2=a2\xa0(Squaring on both sides) → (1)Therefore, a2\xa0is divisible by 3Hence ‘a’ is also divisible by 3.So, we can write a = 3c for some integer c.Equation (1) becomes,3b2\xa0=(3c)2⇒\xa03b2\xa0= 9c2∴ b2\xa0= 3c2This means that b2\xa0is divisible by 3, and so b is also divisible by 3.Therefore, a and b have at least 3 as a common factor.But this contradicts the fact that a and b are coprime.This contradiction has arisen because of our incorrect assumption that √3 is rational.So, we conclude that √3 is irrational.Now√2 = 1.4142...√3 = 1.7321...1.45, 1.5, 1.55, 1.6, 1.65, 1.7 lies between √2 and √3.Hence the rational numbers between √2 and √3 are:145/100, 15/10, 155/100, 16/10, 165/100 and 17/10 Let root3 is a rational no and let its simplest form a/b ,but b is not equal to 0Root 3 =a/b => 3=a^2/b^2 (sq.both sides) => 3b=a^2 (3 divides 3 b^2) 3 divides aLet a=3c for c is some integer 3b^2 =9c^2 => b^2 = 3c^2 => 3 divides b^2So,root 3 is an irrational. PROVED |
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| 27119. |
How to construct 70 without protector |
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| 27120. |
Hlw gud mrng |
| Answer» Gm | |
| 27121. |
Chlo by guys ab mai nahi karunga chat kabhi ohk bbye |
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Answer» Haan bhai ye shi bola ...??? Inne gungun ko number diya or gungun ne call krne se mnaa jrdiya...isiliye n Dikhai na padna ab warna ghar aa kar marunga.... Kyu kya hua bhai aapko |
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| 27122. |
Yrr yaha bat karne me achha nahi lag raha miss chocolover WhatsApp me karte hai no.. duu???? |
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Answer» Sale tapori na bolna warna gali dena shuru krunga na to tumhe apni aukat pta chalegi.... Nhi ...mujhe nhi krni whatsapp pr baat yahi krlo Bhai bat karne ki tameej nahi hai aapko aur ha rahi bat chat ki to waha sirf ek se hi hoti hai yaha tum tapori bich me aajatehoo Sale usme bhi chat hi hota hai yhan bhi wahi hota hai.... |
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| 27123. |
I really getting boured now, here i am flirting with girl so plz.. pat mat jana ohk |
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Answer» Accha ... Yahi kam nahi hai miss , aaj kisi ke yaha aaye hue hai toh bour ho rahe hai actually yaha par mai jyada kisi ko janta nahi na ....? Haha yahi kaam h Bore ho rahe ho to flirt karoge...yeh kya baat hui.... |
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| 27124. |
All the best besties nd friends.... ..aap sbki % 90+ hi aayengi... |
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Answer» Hope so for me next year. Thnx a lot Tq |
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| 27125. |
Find the hcf and lcm of 25,90? |
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Answer» Okay...lcm is 450 and hcf is 5 Surely 5 450 9140352879 Aap call karo mai solution send karta huu |
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| 27126. |
3+3=5 kaise??? Anybody |
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Answer» Galti se..?? By mistake 3+3=5 |
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| 27127. |
Hiii...koi h ..m saalo bAad aa gyi. .. |
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Answer» Bhais wale yum..ya koi or.. Yum yum h hum Okay... Net nhi tha mobile m pappa aaye to hotspot chaalu krke aai Wlcm..wlcm..kaha the ap |
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| 27128. |
Cos2A=2coscosA-1=1-2sinsinA |
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Answer» Answer nhi dena aata hai to mat diya karo Tera sar |
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| 27129. |
Find two consecutive positive integers, sum of whose square is 365 |
| Answer» 13 and 14 | |
| 27130. |
Find the hcf of the samllest composite prime number |
| Answer» The smallest prime number is 2 and the smallest\xa0composite number is\xa0{tex}4=2^2{/tex}Hence the\xa0required HCF (4\xa0, 2) = 2 | |
| 27131. |
Hii....koi h. ... |
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Answer» Riya Aapka name??... Khushi* Hii khishi Hii |
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| 27132. |
In right tri. ABC right angled at C if tan A =1 then verify that 2 sin A cos A=1 |
| Answer» In {tex} \\triangle A B C{/tex},{tex}\\tan A = 1{/tex}{tex}\\Rightarrow \\quad \\frac { B C } { A C } = 1{/tex}{tex}\\Rightarrow {/tex}\xa0BC = x and\xa0AC = xUsing Pythagoras theorem,\xa0{tex}\\Rightarrow A B ^ { 2 } = A C ^ { 2 } + B C ^ { 2 }{/tex}{tex}\\Rightarrow \\quad A B ^ { 2 } = x ^ { 2 } + x ^ { 2 }{/tex}{tex}\\Rightarrow \\quad A B = \\sqrt { 2 } x{/tex}{tex}\\therefore \\quad \\sin A = \\frac { B C } { A B } = \\frac { x } { \\sqrt { 2 } x } = \\frac { 1 } { \\sqrt { 2 } } \\text { and } \\cos A = \\frac { A C } { \\sqrt { 2 } x } = \\frac { x } { \\sqrt { 2 } x } = \\frac { 1 } { \\sqrt { 2 } } {/tex}2 sin A cos A\xa0{tex}= 2 \\times \\frac { 1 } { \\sqrt { 2 } } \\times \\frac { 1 } { \\sqrt { 2 } } = 1{/tex} | |
| 27133. |
1253^1469-1258^1471 |
| Answer» ,Trjdkdidnssmdjkdjskjdjdjjd | |
| 27134. |
(a+b)^3 +(b+c)^3 +(c+a)^3 -3(a+b) (b+c) (c+a)=2(a^3+b^3+c^3-3abc) |
| Answer» Let a + b =x, b + c =y and c + a = z. Then,(a + b)3 + (b + c)3 + (c + a)3 - 3(a + b)(b + c) (c + a)= x3 + y3 + z3 - 3xyz = (x + y + z) (x2 + y2 + z2 - xy - yz - zx)= {(a + b) + (b + c) + (c + a)} {(a + b)2 + (b + c)2 + (c + a)2- (a + b)(b + c) - (b + c)(c + a) - (c + a) (a + b)}= 2(a + b + c) {a2 + b2 + 2ab + b2 + c2 + 2bc + c2 + 2ca + a2\xa0- (ab + ac + b2 + bc) - (bc + ba + c2 + ca) - (ca + cb + a2 + ab)}= 2(a + b + c) (a2 + b2 + c2 - ab - bc - ca) = 2(a3 + b3 + c3 - 3abc) | |
| 27135. |
5\\3÷2= |
| Answer» | |
| 27136. |
Hlo guys plz help me in this question what is electrolysis |
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Answer» ?? Electrolysis is the process of chemical decomposition produced by passing an electric current through a liquid or solution containing ions.The process is carried out in an electrolytic cell, an apparatus consisting of positive and negative electrodes held apart and dipped into a solution containing positively and negatively charged ions. |
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| 27137. |
Lgta h koi nhi h ....????? |
| Answer» Mai hu | |
| 27138. |
Hiii...koi h ..ya sb so gye ... |
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Answer» hai hqi |
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| 27139. |
Koi hai ?? |
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Answer» Hlo... Kaise ho.......... Yashu ji Hlo astha ! Hlo ..hmm aur baki sab kaha hai ??? Sab late hai ya mai jaldi ?? Ha m hu ... |
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| 27140. |
Prove that sum of square of two odd positive integers is even but not divisible by 4 |
| Answer» A= -1.25,d=- 0.25 | |
| 27141. |
If value of \'x\' and \'y\' is 1 then solve that LHS=RHS ax(1/a-b -1/a+b) +by(1/b-a-1/b+a) =2 |
| Answer» | |
| 27142. |
Find the polynomial whose zeros are 1/2,1,-2 and verify the relationship |
| Answer» | |
| 27143. |
Chaptet 4 answer |
| Answer» | |
| 27144. |
1st |
| Answer» Kya 1st ... | |
| 27145. |
find a quadratic polynomial whose zeros are 2+^3 and2-^3 |
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Answer» thank you gaurav seth ^ means root |
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| 27146. |
The 4th term of an AP is OK. Prove that the 25th term of the AP is 3 times its 11th term. |
| Answer» We have given that4th\xa0term of an A.P.= a4\xa0= 0∴ a + (4 – 1)d = 0∴ a + 3d = 0∴ a = –3d ….(1)25th\xa0term of an A.P. = a25= a + (25 – 1)d= –3d + 24d ….[From the equation (1)]= 21d3 times 11th\xa0term of an A.P. = 3a11= 3[a + (11 – 1)d]= 3[a + 10d]= 3[–3d + 10d]= 3 × 7d= 21d∴ a25\xa0= 3a11i.e., the 25th\xa0term of the A.P. is three times its 11th\xa0term. | |
| 27147. |
Which is best RD sharma ir RS aggarwal for class 10??And why?? |
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Answer» Both are best for class 10th Both the guides are best because both are Ph.d in maths |
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| 27148. |
If the sum of the square of the zeros of polynomial x^2-8x+k is 40 , find the value of k |
| Answer» Let {tex}\\alpha,\\beta{/tex}\xa0be the zeros of the polynomial {tex}f(x)=x^2-8x+k{/tex}.Sum of zeroes =\xa0{tex} \\alpha + \\beta = - \\left( \\frac { - 8 } { 1 } \\right) = 8{/tex}\xa0and, Product of zeroes =\xa0{tex} \\alpha \\beta = \\frac { k } { 1 } = k{/tex}Now,\xa0{tex} \\alpha ^ { 2 } + \\beta ^ { 2 } = 40{/tex}{tex} \\Rightarrow \\alpha ^ { 2 } + \\beta ^ { 2 }+2 \\alpha\\beta-2 \\alpha\\beta= 40{/tex}{tex} \\Rightarrow \\quad ( \\alpha + \\beta ) ^ { 2 } - 2 \\alpha \\beta = 40{/tex}{tex} \\Rightarrow \\quad 8 ^ { 2 } - 2 k = 40{/tex}{tex} \\Rightarrow \\quad 2 k = 64 - 40 {/tex}{tex}\\Rightarrow 2 k = 24 {/tex}{tex}\\Rightarrow k = 12{/tex} | |
| 27149. |
Find K so that x2+2x+k is the factor of 2x4+x3-4x2+5x+6 |
| Answer» If g(x)=x2 + 2x + k is a factor of f(x) = 2x4 + x3 - 14x2 + 5x + 6Then remainder is zero when f(x) is divided by g(x)Let quotient =Q and remainder =RLet us now divide f(x) by gx)R = x(7k + 21) + (2k2 + 8k + 6) -------(1)and Q = 2x2 - 3x - 2(k + 4).------------(2){tex}\\Rightarrow{/tex}x (7k + 21) + 2 (k2 + 4k + 3) = 0\xa0{tex}\\Rightarrow{/tex}7k + 21 = 0 and k2 + 4k + 3 = 0{tex}\\Rightarrow{/tex}\xa07(k + 3) = 0 and (k + 1) (k + 3) = 0{tex}\\Rightarrow{/tex}\xa0k + 3 = 0{tex}\\Rightarrow{/tex}k = -3Substituting the value of k in the divider x2 + 2x + k, we obtain: x2 + 2x - 3 = (x + 3) (x - 1) as the divisor.Hence two zeros of g(x) are -3 and 1.------(3)Putting k=-3 in (2) we getQ = 2x2 - 3x - 2= 2x2 - 4x + x - 2= 2x(x - 2) + 1 (x - 2)= (x - 2)(2x + 1)Q=0 if x-2=0 or 2x+1=0So other two zeros of f(x) are 2 and -{tex}\\frac12{/tex}-------(4)As g(x) is a factor of f(x) so zeros of G(x) are zeros of f(x) alsoHence from (3) and (4) we getThe zeros of f(x) are: -3 ,1,, 2 and {tex}\\frac12{/tex} | |
| 27150. |
what is euclids division algorithm |
| Answer» A division algorithm is an algorithm which, given two integers N and D, computes their quotient and/or remainder, the result of division. ... Examples of slow division include restoring, non-performing restoring, non-restoring, and SRT division. | |