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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27251. |
How to do 6x-3-7x |
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Answer» First make it in standard form I.e.a*2+bx+c.then solve it. I think after 6x there is square.Then u can convert this equation inquadratic form then after use spilliting middle term or quadratic formula. |
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| 27252. |
Use euclid division lemma to find HCF of 885 and1990 |
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Answer» Delhi Capital of India |
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| 27253. |
Prove 3ander root 2 |
| Answer» Anser | |
| 27254. |
Solve 3x-5y=4 |
| Answer» Here given equations are2x - y = 5 ..........(i)3x - 5y = 4 ..............(ii)Multiplying equation (i) by 3, we get3 {tex}\\times{/tex}\xa0(2x - y = 5){tex}\\Rightarrow{/tex}\xa06x - 3y = 15 ...........(iii)Multiplying equation (ii) by 2 , we get2 {tex}\\times{/tex}\xa0(3x\xa0- 5y = 4){tex}\\Rightarrow{/tex}\xa06x - 10y = 8 ............(iv)Subtracting equation (iv) from (iii), we get{tex}\\Rightarrow{/tex}\xa0y = 1Put y = 1, equation (i) becomes2x - 1 = 5{tex}\\Rightarrow{/tex}\xa02x = 6{tex}\\Rightarrow{/tex}\xa0x = 3{tex}\\therefore{/tex}\xa0x = 3, y = 1 is the solution of given system of equations. | |
| 27255. |
Represent 1+root 9.5 on number line |
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| 27256. |
What is the formula |
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Answer» Kiska formula?? Not abhi abhi 1 month ago....? |
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| 27257. |
Solve these by quadratic formula.a²b²x²+b²x-a²x-1=0x-1/x-2+x-3/x-4=10/3 |
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Answer» Sorry for posting this I understand Hey kanika is there = only between the 2 equation |
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| 27258. |
x-a/x-b +x-b/x-a = a/b + b/a. |
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| 27259. |
(18x)³ |
| Answer» (18x)^3=(18)^3×x^3=5832x^3 | |
| 27260. |
Factorise x^6+18x^3+1 |
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| 27261. |
5x/3+2/5=1 |
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| 27262. |
If the HCF of 210 and 55 is expressible in the form 210 multiply 5 add 55 y , find y |
| Answer» Let us first find the HCF of 210 and 55.Applying Euclid division lemna on 210 and 55, we get210 = 55 × 3 + 4555 = 45 × 1 + 10\xa045 = 4 × 10 + 5\xa010 = 5 × 2 + 0\xa0We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.∴ 5 = 210 × 5 + 55y⇒ 55y = 5 - 1050 = -1045∴\xa0y = -19 | |
| 27263. |
Is Anyone have Coupon, promo Code ??? |
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Answer» Nooo? Sorry...me* Mr No?? |
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| 27264. |
Write the degree of polynomial x+ 3/x =x² |
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Answer» Take the LCM of x and3/x and cross multiply the equation we will get tge cubic polynomial with degree 3. Hiii Indu .....The degree of this polynomial is 2 and it\'s called quadratic polynomial...? Answer is 3 2 Ryt Honey remember me? First you tell me , Is it a polynomial? |
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| 27265. |
What is euclids divisiom lemma? |
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Answer» For a pair of given positive integers ‘a’ and ‘b’, there exist unique integers ‘q’ and ‘r’ such that`a=bq+r`, where `0≤r | |
| 27266. |
Find the HCF of 1965 and 2096 by Euclids division algoritham\xa0 |
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Answer» Ryt aditi The Hcf of 1965 &2096 is 131. 131 |
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| 27267. |
How to solve y+4=0 by graphical methods and how to find value of x?? |
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| 27268. |
Solve by elimination method 10/x+y=4 ; 15/x+y-5/x-y=n |
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| 27269. |
X ki power 3 + 2 x ki power 2- 11 x - 12 divide by -1 |
| Answer» Hiii manisha .........If p(x)=x³+2x²-11x-12....& g(x)=-1 ........on solving by division method .....we got .... q(x)=-x³-2x²+11x+12.......& r(x)=0 | |
| 27270. |
Find hcf of (x3-3x+2) and (x3-4x+3) |
| Answer» x3-3x+2 | |
| 27271. |
How much time we should give to studies for good results |
| Answer» 1 hr or more each subject | |
| 27272. |
Find the value of \'a\' so that the point (3,9)lies on the line represent by 2x-3y=5 |
| Answer» Since the point (3, a) lies on the line 2x - 3y = 5, we have2\xa0{tex}\\times{/tex}\xa03 - 3\xa0{tex}\\times{/tex}\xa0a = 5{tex}\\Rightarrow{/tex}\xa06 - 3a = 5{tex}\\Rightarrow{/tex}\xa03a = 1{tex}\\Rightarrow{/tex}\xa0{tex}a = \\frac { 1 } { 3 }{/tex} | |
| 27273. |
Happy world creativity and innovation day |
| Answer» Look good, Feel good,Do good?? | |
| 27274. |
In class 10 ch 3 how to choose a number in x and y that may the line in graph right |
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| 27275. |
X square + 6 x minus 9 |
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Answer» How to solve this by using spillting middle term - 3 + 3 root 2 and - 3 - 3 root 2 |
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| 27276. |
After how many places will the decimal expansion of 189\\125 terminate . Koi ans do |
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| 27277. |
Math subject was divided into two parts right or wrong |
| Answer» Yes, standard and basic.......But teaching is same for the whole year ........ Only the test paper will come in two patterns | |
| 27278. |
Math question paper divided into two parts basic and standard it is right or wrong? |
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Answer» Ryt...from year 2019- 20 Write |
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| 27279. |
Prove that√2 is irrational and hence prove that 5 by√2 is irrational |
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Answer» Let root 2 be rational number How |
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| 27280. |
I don\'t have Paytm So Can i Purchase Book |
| Answer» Yes u can perchase a book through Amazon, flipkart or many sopping apps. | |
| 27281. |
Irrational no problems |
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| 27282. |
Real number all questions |
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| 27283. |
If a possible integer p divide with 3 what are the possible remainder |
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| 27284. |
find HCF and LCM X2yz,X3y,and xyz |
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| 27285. |
Find a quadratic polynomial the sunand product whosrzeroesvarev-3 and 2 respectively? |
| Answer» Sum=S=-3Product=P=2Polynomial will bexsquare-Sx+P=xsquare-(-3)x+2=xsquare+3x+2 | |
| 27286. |
Parctical questions of mathematics |
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| 27287. |
Exercise 4.3 question no. 2 explain it |
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| 27288. |
Two natural numbers whose sum is 85 and the least common multiple is 102 are: |
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Answer» The prime factorisation of 102 is 2*3*17The prime factorisation of 85 is 5*1785 = 5*7 =(2+3)17The two numbers are 2*17=343*17=51 34 & 51 |
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| 27289. |
Under root 5 irrational number kaise proof Karen |
| Answer» Let us assume that root 5 is rationalroot 5=a/b ( where a, b are coprimes )root5b=asquaring on both sides,5b2=a2so, 5 divides both a and ba coprime doesn\'t divide two integersthis has been arisen due to our wrong assumption that root 5 is rationalso, root5 is irrational. | |
| 27290. |
Bhai yo 28 ka under root kya ho ga pura solution karna |
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| 27291. |
Define reduction |
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Answer» Reduction-Reduction is a chemical process in which a substance gains hydrogen and looses oxygen.-For exampleCuO(s)+H2(g)…Cu(s)+H2O(l)-If a substance gains hydrogen or looses oxygen during a reaction ,it is said to be reduced.-A substance that looses hydrogen or gain oxygen is known as reducing agent.-Reduction is defined as gain of electrons. It is loss of oxygen or gain of hydrogen |
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| 27292. |
How 3 is smallest composite number |
| Answer» 4 is the smallest composite number | |
| 27293. |
Using euclid division algorithm find hcf of 405and2520 |
| Answer» 2520=405*6+90 405=90*4+4590=45*2+0HCF OF 405 AND 2520 IS 45 | |
| 27294. |
What is a no |
| Answer» What?? What a silly questions | |
| 27295. |
Find the least no.which when divided by 35,56 and 91 leaves the remainder 7 in each case |
| Answer» 35 = 5 {tex}\\times{/tex}\xa0756 = 23{tex}\\times{/tex}\xa0791 = 13 {tex}\\times{/tex}\xa07L.C.M of 35, 56 and 91 = 23{tex}\\times{/tex}\xa07\xa0{tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa013 = 3640The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.Hence 3647 is the smallest number that, when divided by 35, 56 and 91 leaves a remainder of 7 in each case. | |
| 27296. |
Find HCF of 184,230 and 276 by euclid\'s division algorithm |
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Answer» Given numbers are 184, 230, and 276.Applying Euclid\'s division lemma to 184 and 230, we get230 = 184\xa0{tex}\\times{/tex}\xa01 + 46184 = 46\xa0{tex}\\times{/tex}\xa04 + 0The remainder at this stage is zero.So, the divisor at this or the remainder at the previous stage i.e., 46 is the HCF of 184 and 230.Also,276 = 46\xa0{tex}\\times{/tex}\xa06 + 0∴ HCF of 276 and 46 is 46HCF (184, 230, 276) = 46Hence, the required HCF of 184, 230 and 276 is 46. 46 |
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| 27297. |
Find the H C F of 90 and 144 |
| Answer» 90 = 2 x 3 x 3 x 5 = 2 x 32 x 5144 = 2 x 2 x 2 x 2 x 3 x 3 = 24 x 32HCF (90, 144) = 2 x 32 = 18 | |
| 27298. |
pxq=p+q+p/q find the value of x |
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| 27299. |
Zeros of quadratic polynomial f(x)=6x-3,verify relationship between zeros and coefficients |
| Answer» f(x)=6x2-3To find zeros6x2-3=06x2=3{tex}x=\\pm \\frac {1}{\\sqrt 2}{/tex}Henc the zeros f(x) are:{tex} \\alpha = \\frac { 1 } { \\sqrt { 2 } } \\text { and } \\beta = - \\frac { 1 } { \\sqrt { 2 } }{/tex}Sum of the zeroes =\xa0{tex} \\alpha + \\beta = \\frac { 1 } { \\sqrt { 2 } } + \\left( - \\frac { 1 } { \\sqrt { 2 } } \\right) = 0{/tex}\xa0and,\xa0{tex} - \\frac { \\text { Coefficient of } x } { \\text { Coefficient of } x ^ { 2 } } = - \\frac { 0 } { 6 } = 0{/tex}{tex}\\therefore{/tex}\xa0Sum of the zeros\xa0{tex} = - \\frac { \\text { Coefficient of } x } { \\text { coefficient of } x ^ { 2 } }{/tex}Also, Product of the zeroes =\xa0{tex} \\alpha \\beta = \\frac { 1 } { \\sqrt { 2 } } \\times \\frac { - 1 } { \\sqrt { 2 } } = \\frac { - 1 } { 2 } {/tex}, and\xa0{tex} \\frac { \\text { Constant term } } { \\text { Coefficient of } x ^ { 2 } }= \\frac { - 3 } { 6 } = \\frac { - 1 } { 2 }{/tex}{tex}\\therefore{/tex}\xa0Product of the zeros\xa0{tex}= \\frac { \\text { Constant term } } { \\text { Coefficient of } x ^ { 2 } }{/tex} | |
| 27300. |
Show graphically that the pair of equations 2x-3y+7=0,6x-9y+21=0 has infinitely many solutions |
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