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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27351. |
Alpha +bita/alpha-bita |
| Answer» Rationalise kr de bhai | |
| 27352. |
Show that one and only one of n, n+2,n+4 is divisible by 3 |
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Answer» We applied Euclid Division algorithm on n and 3.a = bq +r on putting a = n and b = 3n = 3q +r , 0 | |
| 27353. |
Please help i can\'t understand why we take 3 why not 9 to show that 9m,9m+3,9m+8 |
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Answer» I can\'t understand can you please tell me in easier way Okk ab kuchh smjh aaya ki nhi... Aree hum 9 isliye nhi lete kyoki 9 lene par hame r ki boht value rakhni padegi 8 tak .Likin agar hum 3 lengs toh r ki sirf teen value rakhni hogi |
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| 27354. |
Why we take 3 not 9 to prove 9m,,9m+1,9m+8 please help |
| Answer» Three . 9 ka factor hai isliye | |
| 27355. |
2×3×15+7 is composite or prime number.justify your answer |
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Answer» 2×3×15+7 = 6 ×15+7 = 90 + 7 = 9797 is a prime numberSo, 2×3×15+7 is prime number Because it has more than two factors ,therefore it is composite no. 90 is a composite no. as it has factors other than 1 |
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| 27356. |
Alpea and beta |
| Answer» kya btana h issme? | |
| 27357. |
Euclid division lemma explain |
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Answer» r 0<=r For a given positive integer a and b ,there exist q and r in such a way that a= bq + r, 0<=r a= bq+r |
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| 27358. |
Find the large number which divides 245 and 1037 remainder 5 in each case |
| Answer» 1 | |
| 27359. |
Why we are putting k in ex 8.1 sum no. 3 class 10 |
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| 27360. |
Kya kisi ke pas mere ques. Ka answer hai? |
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Answer» Ye question mein gadbad h... grouped data or ungrouped data ki jagah... Even no.of data And odd no. Of data Aana chaiye...? But.. question kya h..? Why we use n/2 for grouped data and n/2+1 for ungrouped data?Mujhe iska answer google pe bhi nhi mil rha . May be aapko aata ho Soory yrr ask plz... Question kya hai |
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| 27361. |
Why we use n/2 for grouped data and n/2+1 for ungrouped data? |
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| 27362. |
2x sqare-11x+14 |
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| 27363. |
Show that every positive integer is odd or even |
| Answer» According to the question, we have to show that every positive integer is either even or odd.Let us assume that there exists a smallest positive integer that is neither odd nor even, say n. Since n is the least positive integer which is neither even nor odd, n - 1 must be either odd or even.Case 1: If n - 1 is even, n - 1 = 2k for some k.But this implies n = 2k + 1This implies n is odd.Case 2: If n - 1 is odd, n - 1 = 2k + 1 for some k.But this implies n = 2k + 2 = 2(k + 1)This implies n is even.Therefore,In both cases , we arrive at a contradiction.Thus, every positive integer is either even or odd | |
| 27364. |
X/a+y/b=a+b,x/a^2+y/b^2=2 |
| Answer» What should have to find out | |
| 27365. |
Find the condition that zeros pf x^3-px^2+qx-r may be in A.P |
| Answer» Let a - d, a and a + d be the zeros of the polynomial F(x). Then,Sum of the zeroes =\xa0{tex}- \\frac { \\text { Coefficient of } x ^ { 2 } } { \\text { Coefficient of } x ^ { 3 } }{/tex}{tex}\\Rightarrow (a-d)+a+(a+d)=-\\frac { ( - p ) } { 1 }{/tex}{tex}\\Rightarrow 3a=p{/tex}{tex}\\Rightarrow a=\\frac { p } { 3 }{/tex}Since {tex}a{/tex}\xa0is a zero of the polynomial {tex}f(x){/tex}. Therefore,{tex}f(a)=0{/tex}{tex}\\Rightarrow a^3-pa^2+qa-r=0{/tex}{tex}\\Rightarrow \\left( \\frac { p } { 3 } \\right) ^ { 3 } - p \\left( \\frac { p } { 3 } \\right) ^ { 2 } + q \\left( \\frac { p } { 3 } \\right) - r = 0{/tex}{tex}\\Rightarrow p^3-3p^3+9pq-27r=0{/tex}\xa0{tex}\\Rightarrow 2p^3-9pq+27r=0{/tex}hence,\xa0{tex}2p^3-9pq+27r=0{/tex}\xa0is the required condition | |
| 27366. |
(a +b)2 |
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Answer» a2+2ab+b2 a^2+b^2+2ab |
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| 27367. |
Find the smallest number which leaves remainder 8&12 when divided by 28&32 respectivelt |
| Answer» 10 and 15 respectively | |
| 27368. |
Yeh question kaha gayb ho gaya |
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Answer» itne dino se hum bhi nhi smjh pa rhe???? I don\'t know Raunak?? |
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| 27369. |
Cosec square 55degree _ cot square 55degree |
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Answer» Cosec square ( 90° - 55°) - cot square (90 ° - 55°)=sec square 55°- tan 55°=1 Cosec square (90°- 55°) -cot square (90°- 55°) Sec square 55° - tan square 55°1 |
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| 27370. |
Cost of 2 nooks 4pens 2pencils are 240 and 1 book 3pens 8pemcils 220 find 1 book pen pencils cost |
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| 27371. |
Find zeroes of x3+6x2+11x+6 which have x+1 as a factor |
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| 27372. |
What is calcus |
| Answer» It is a branch of mathematics | |
| 27373. |
Solve by completing there square e |
| Answer» Incomplete question.. ? | |
| 27374. |
How much time we should give maths in aday |
| Answer» Depends on ur potential level.. | |
| 27375. |
Find all the zeros of the polynomial 2x^4 - 9x^3 + 5x^2 + 3x -1 if two zeros are 2+√3 and 2-√3 |
| Answer» Given:f(x) = (2x4\xa0– 9x3\xa0+ 5x2\xa0+ 3x – 1)Zeroes = (2 + √3) and (2 – √3)Given the zeroes, we can write the factors = (x – 2 + √3) and (x – 2 – √3){Since, If x = a is zero of a polynomial f(x), we can say that x - a is a factor of f(x)}Multiplying these two factors, we can get another factor which is:((x – 2) + √3)((x – 2) – √3) = (x – 2)2 –\xa0(√3)2⇒x2\xa0+ 4 – 4x – 3 = x2\xa0– 4x + 1So, dividing f(x) with (x2\xa0– 4x + 1)f(x) = (x2\xa0– 4x + 1) (2x2\xa0– x – 1)Solving (2x2\xa0– x – 1), we get the two remaining roots as{tex}x = {-b \\pm \\sqrt{b^2-4ac} \\over 2a}{/tex}where f(x) = ax2\xa0+ bx + c = 0(using Quadratic Formula){tex}\\mathrm{x}=\\frac{-(-1) \\pm \\sqrt{(-1)^{2}-4(2)(-1)}}{2(2)}{/tex}{tex}\\mathrm{x}=\\frac{-1 \\pm 3}{4}{/tex}{tex}\\Rightarrow \\mathrm{x}=1,-\\frac{1}{2}{/tex}Zeros of the polynomial =\xa0{tex}1,-\\frac{1}{2}, 2+\\sqrt{3}, 2-\\sqrt{3}{/tex} | |
| 27376. |
Mere bhaiyo tatha beheno mujhe koi important question bata sakta hai |
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Answer» Ch 4 Kiske |
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| 27377. |
39cm hight 40 length how breth |
| Answer» | |
| 27378. |
What is gamma and what are its uses? |
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Answer» Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions. Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells. Brother don\'t find this type of answer online..its time read the book very carefully....you will find it in S Chand.. edition book ,or many more... |
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| 27379. |
Bhut dar LG rha h is bar 10 hi |
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Answer» Bhai meko bhi It\'s Easy yrr.. Just relax.. Stay calm.. Don\'t worry just chill ?? |
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| 27380. |
Prove that any +ve odd integer is of the form 4q+1,4q+3 where q is some integer |
| Answer» Keep the value of q then u will find ur answer only positive integers are allowed | |
| 27381. |
Prove that square of any +ve integer is of the form 5m, 5m+ 1 , 5m+4 same integer m |
| Answer» (1) 6m prime no | |
| 27382. |
If alpha&bera are the zeroes of quadratic polynomial f(x)=ax squared+bx+c,then evaluate alpha-beta |
| Answer» Its beta | |
| 27383. |
Spliting methodX2-17x-200X2-21x-270 |
| Answer» | |
| 27384. |
Express the HCF of 468 and 222 as 468x + 222y where x,y are integers in two different ways |
| Answer» HCF of 468 and 222468 = (222 x 2) + 24222 = (24 x 9) + 624 = (6 x 4) + 0\xa0Therefore, HCF = 66 = 222 - (24 x 9) = 222 - {(468 – 222 x 2) x 9 [where 468 = 222 x 2 + 24] = 222 - {468 x 9 – 222 x 2 x 9} = 222 - (468 x 9) + (222 x 18) = 222 + (222 x 18) - (468 x 9) = 222[1 + 18] – 468 x 9 = 222 x 19 – 468 x 9 = 468 x -9 + 222 x 19Hence, HCF of 468 and 222 in the form of 468x + 222y is 468 x -9 + 222 x 19. | |
| 27385. |
Ues the division of algorithms to find hcf of 105 and 120 |
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Answer» 15 15 5 |
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| 27386. |
Solve under root 2,3,5 by decimal method to 8 places |
| Answer» a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent). | |
| 27387. |
What is the sum and product of the following polynomials 3x²-5x+6 |
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| 27388. |
If the 7th term of an AP is 1/9 and its 9th term is 1/7. Find its 63rd term |
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Answer» Ok koi baat nhi wese ban gya ye question Y chapter abhi kisi n nhi pda . |
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| 27389. |
Convert ₹50 in dollars$ |
| Answer» 0.72 dollars.. | |
| 27390. |
Use euclid division algorithm to find the HCF of 441,567,693 |
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Answer» By Euclid’s division algorithm,693 = 567 x 1 + 126567 = 126 x 4 + 63126 = 63 x 2 + 0So, HCF(441, 63) = 63So, HCF (693, 567) = 63441 = 63 x 7 + 0Hence, HCF (693, 567, 441) = 63
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| 27391. |
An quadratic polynomial can have at most how many zeroes |
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Answer» A quadratic polynomial have at most two\xa0zeros because the degree of x is\xa02. 2 zeroes.. |
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| 27392. |
Anybody give me the solution of this question now |
| Answer» | |
| 27393. |
Chapter 1,ques.no. 10 |
| Answer» Priti ch 1 ni hua ch 2 me se agar kuch problem h to bta do | |
| 27394. |
Represent the following numbers in the real line under root 17 |
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| 27395. |
In triangle ab=24cm bc=7cm find Sina; cosA |
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| 27396. |
Prove that 3-2√7 is irrational |
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| 27397. |
x/3 + y/4 =11 5x/6 - y/3=-7 |
| Answer» The given equations are{tex}\\frac { x } { 3 } + \\frac { y } { 4 } = 11{/tex}{tex}\\frac { 5 x } { 6 } - \\frac { y } { 3 } = - 7{/tex}\xa0Now {tex}\\frac { x } { 3 } + \\frac { y } { 4 } = 11{/tex}\xa0{tex}\\Rightarrow{/tex}{tex}\\frac { 4 x + 3 y } { 12 } = 11{/tex}\xa0(by taking LCM){tex}4x + 3y = 132{/tex} ......(i){tex}\\frac { 5 x } { 6 } - \\frac { y } { 3 } = - 7{/tex}{tex}\\frac { 5 x - 2 y } { 6 } = - 7{/tex}(by taking LCM){tex}5x - 2y = -42{/tex}.........(ii)Multiplying (i) by 2 and (ii) by 3, we get{tex}8x + 6y = 264{/tex} ........(iii){tex}15x - 6y = -126{/tex} ........(iv)Adding (iii) from (iv), we get{tex}23x = 138{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}x = 6{/tex}Substituting x = 6\xa0in (i),we get{tex}4 \\times 6 + 3 y = 132 \\Rightarrow 3 y = 132 - 24{/tex}{tex}3y = 108{/tex}{tex}y = 36{/tex}{tex}\\therefore{/tex}\xa0Solution is {tex}x = 6, y = 36{/tex} | |
| 27398. |
Suggest any activity of chapter real number for students |
| Answer» | |
| 27399. |
7×m + 7 = 77 |
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Answer» 10 7×m + 7 = 777m + 7 = 777m = 77 - 77m = 70m = 70/7m = 10 7m+7=777m=77-77m=70M=70/7=10so,answer is 10 |
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| 27400. |
What is the difference between fractions and a rational number?? |
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Answer» Hello my friend faraction are in the form of p/q but it is not confirmed that q is not equal to zero then in the case of rational no it is confirmed that q is not equal to zero i think that you should get your answer,Thankyou A fraction is written in the form of m/n , where n is not 0 and m & n are natural numbers. For example: 12/23, 10/32, 12/10, 4/21. A rational number can also be written in the form of m/n , where n is not 0 and m & n are integers. For example: 15/7, -18/13, 3/-7, -6/-12. All Fractions can be termed as Rational Numbers, however, all Rational Numbers cannot be termed as Fractions. Only those Rational Numbers in which ‘m’ and ‘n’ are positive integers are termed as Fractions. The numbers in the form p/q where p and q are natural numbers and q not equal to 0 are called rational number Please answer fast |
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