Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27501. |
How to construct 135 degree angle |
| Answer» Bisector of 90° and 180 ° is 135° | |
| 27502. |
Relationship between the zeroes of 4u*2 |
| Answer» | |
| 27503. |
f (x) = 6x×5-X×4+4X×3-5X×2-x-15,g (x)=2x×2-x+3 |
| Answer» | |
| 27504. |
f(x) 6x |
| Answer» | |
| 27505. |
64*3/4 |
| Answer» | |
| 27506. |
If the zeroes of the polynomial 2x3-15x2+37x-30 are a-b,a.a+b.find all the zeroes |
| Answer» | |
| 27507. |
Yashraj you want to say something say it directly |
| Answer» | |
| 27508. |
Find all zeroes of f(x)= x^3+13x^2+32x+20,if one of it\'s zeroes is -2. |
| Answer» The given polynomial is f(x) = x3+ 13x2 + 32x + 20One of the zeroes = - 2{tex}\\therefore{/tex}\xa0x + 2 is a factor of p(x)For other factor divide p(x) by (x + 2){tex}\\therefore{/tex}Other factor of p(x) is x2 + 11x + 10For other zeroesx2 + 11x + 10 =\xa00(x\xa0+ 10)(x + 1) = 0x = -10, x = -1Hence the factors of x3+ 13x2 + 32x + 20 are -2, -10 and -1. | |
| 27509. |
If sinp= 1/2, show that 3cosp_4cos3p=0 |
|
Answer» Ya may be...par itni jaldi...sin cos.... I think he is just passout to 9th Are maths exam is over... |
|
| 27510. |
Why the sunshines . |
| Answer» Sunshines ke bad kya..... | |
| 27511. |
Hey guys which set according to you was the toughest in 10th board??? |
| Answer» Mere to 2nd set hota h | |
| 27512. |
Please give me idea for understanding real numbers of class 10 |
| Answer» Its the easiest chapter... bs basics clear krne ka try kro..... | |
| 27513. |
Guys tell me your scl name and district |
|
Answer» South point international school sonipat South point International school (sonipat) |
|
| 27514. |
Can two number have 15 as their hcf and 175 as their lcm,,?give reason?? |
| Answer» Yess | |
| 27515. |
Data handing |
| Answer» | |
| 27516. |
Traiangle |
| Answer» ∆ | |
| 27517. |
Write 98 as product of its prime factors |
| Answer» 98=2x49=2 x 72 | |
| 27518. |
tan theta + sec theta -1 divided by tan theta - sec theta + 1 equals to 1+ sin theta by cos theta |
| Answer» We have to prove that\xa0{tex} \\frac { 1 + \\sec \\theta - \\tan \\theta } { 1 + \\sec \\theta + \\tan \\theta } = \\frac { 1 - \\sin \\theta } { \\cos \\theta }{/tex}Recall identity sec2\xa0θ – tan2θ = 1Here, LHS\xa0{tex}= \\frac { 1 + \\sec \\theta - \\tan \\theta } { 1 + \\sec \\theta + \\tan \\theta }{/tex}{tex}= \\frac { \\sec ^ { 2 } \\theta - \\tan ^ { 2 } \\theta + \\sec \\theta - \\tan \\theta } { 1 + \\sec \\theta + \\tan \\theta }{/tex}{tex}= \\frac { ( \\sec \\theta - \\tan \\theta ) ( \\sec \\theta + \\tan \\theta ) + ( \\sec \\theta - \\tan \\theta ) } { 1 + \\sec \\theta + \\tan \\theta }{/tex}\xa0[ because, a2\xa0– b2\xa0= (a – b)(a + b)]{tex}= \\frac { ( \\sec \\theta - \\tan \\theta ) [ \\sec \\theta + \\tan \\theta + 1 ] } { ( \\sec \\theta + \\tan \\theta + 1 ) }{/tex}= sec θ – tan θ{tex}= \\frac { 1 } { \\cos \\theta } - \\frac { \\sin \\theta } { \\cos \\theta }{/tex}{tex}= \\frac { 1 - \\sin \\theta } { \\cos \\theta }{/tex}\xa0= RHSHence, proved. | |
| 27519. |
हर कामयाब स्टूडेंट?के पीछे, माँ ? की चप्पल का हाथ ?होता है !! |
| Answer» | |
| 27520. |
हर किसी को एक बार तो प्यार करना ही चाहिए… ताकि उसको पता चल सके कि प्यार क्यों नहीं करना चाहिए…? |
| Answer» | |
| 27521. |
(1÷x2+x2)-4(1÷x+x)+6 |
| Answer» | |
| 27522. |
SinA÷cosA+cosA÷sinA |
|
Answer» Nhi Tan+ cot |
|
| 27523. |
Prove that 1upon root 2 is irrational |
| Answer» We assume that 1/{tex}\\sqrt2{/tex} is a rational noSo\xa0{tex}\\frac ab=\\frac{1}{\\sqrt2}{/tex}( Where and\xa0b are co-primes)b=a{tex}\\sqrt 2{/tex}b2=2a2--------(1)b2 is divisible by 2 ,so b is divisible by 2-----(2)Let b=2c( c is any integer)b2=4c22a2=4c2a2=2c2So a2 is divisible by 2,So a is divisible by 2-----(3)From (2) and (3)\xa0a and b are divisible by 2But this contradict the assumption\xa0that a and b are co-prime ,So no common factor in and b except 1Hence our assumption that 1/\xa0{tex}\\sqrt2{/tex}\xa0is wrong ,Hence 1/{tex}\\sqrt2{/tex} is a non prime number- | |
| 27524. |
Sec A -1/secA+1 + secA+1 / secA-1 |
| Answer» Bhai, kal to Angreji ka Paper hai na, then why\'re you asking a Question of Trigonometry in the Early Morning, Huh......... | |
| 27525. |
Why we take more than two equatios in qudratic polynomial graph |
| Answer» | |
| 27526. |
What do you mean by euclid\'s division lemma ? |
| Answer» Maths now??? | |
| 27527. |
What do you mean by eculid division lemma? |
| Answer» For any two given positive integers a and b there exist unique whole numbers {tex}q\\ and\\ r {/tex}\xa0such that{tex}a = bq + r,{/tex} where\xa0{tex}0 \\leq r < b{/tex}We call \'a\' as dividend, b as divisor, q as quotient and r as remainder.{tex}Dividend = (divisor \\times quotient) + remainder{/tex} | |
| 27528. |
Find the polynomial who\'s zeros are 2+√3,2-√3 |
|
Answer» Check this question in this app for more information. In mathematics column exercise 2.4 question no. 4 ya 5 hoga Ncert book bhi khol lo X ^2 -(sum of 0s)x +(product of 0s) |
|
| 27529. |
State and prove Thales theorem |
| Answer» | |
| 27530. |
In angle ABC,DE||BC,AD=x+1,DB=x-1 AE=x+3 and EC=x,find x |
| Answer» | |
| 27531. |
56+67 |
|
Answer» 123 123.... 123 |
|
| 27532. |
If a boy is five times old as his fater find the oge of boy |
| Answer» 5x | |
| 27533. |
on comparing with a1÷a2,b1÷b2,c1÷c2 find out wheather the lines representing 5x-4x+8=0,7x+6x-9=0 |
| Answer» | |
| 27534. |
If 2 and 3 are the zeroes of the polynomial3x²-2kx+2m,then find the value of k and m |
| Answer» K=7.5 and m=9Since we know that sum of zeros is equal to -(co- efficient of x)/ co- efficient of x sq.And product of zeros is equal to constant term(c)/co efficient of x sq. | |
| 27535. |
If the polynomial p(x)=x^2-x+1 is divided by (x-2) than the remainder is |
|
Answer» Aree newcomer hoga Mathematics exam is over |
|
| 27536. |
What is trigonametri |
| Answer» | |
| 27537. |
The L.C.M of 2 nos. is 51 times the H.C.F and if 1 no. is 27,find the other no. |
| Answer» | |
| 27538. |
Toughest question of trignometry |
| Answer» Google it | |
| 27539. |
Express thetrigometric ratio sin A, sec A and tan A in terms of cot A. |
| Answer» cosec2A=Cot2A+1sin2A=1/(Cot2A+1)----------(1)sec2A=1+tan2A=1+1/cot2AtanA=1/cotA | |
| 27540. |
Thanks and good night and HAPPY WALI Holi too??????to alll??????? |
|
Answer» Ya happy holi and may god bless us with flying colors in our upcoming boards Same 2 u Same to you sanjana ji Same 2 u |
|
| 27541. |
You kabir come here |
|
Answer» What You also ask a question..... ?? |
|
| 27542. |
Hello everyone anyone online |
|
Answer» Yep.... Hlo..Isha ji Hello Hello isha Yah! |
|
| 27543. |
Express the HCF of 72 and 124 as a linear combination of 72 and 124 |
| Answer» | |
| 27544. |
2-2=? |
|
Answer» Itna bhi nhi aata kyaaNursery nhi padhi Bura mt manna meri baato ka agar bura lga ho toh sorry?? 0 |
|
| 27545. |
Value of tan15 |
|
Answer» Exam ho gaya????????? 12 std ki maths me dekho Not in syllabus |
|
| 27546. |
Prove that (7,-2), (5,1), (3,4) are collinear through section formula . |
| Answer» Take the ratio k:1 and find k in both x and y if the values of k is same that means they are collinear | |
| 27547. |
Secent thita - tan thita = cos thita by 1+sin thita |
| Answer» | |
| 27548. |
On the death of his mother, 5 years old boy was confused: Why everybody is calling mommy a body? |
|
Answer» I know? Nahi samaj aya yrr? का है यू Thik se samaj nahi aaya ..... Yeh samaj nahi aaya .... |
|
| 27549. |
It\'s fun time so don\'t take seriously |
| Answer» | |
| 27550. |
if alpha and beta are zero\'s s of x^2+5x+8 then alpha+beta=? |
| Answer» Ans-2/5 | |