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27551.

Prove that the following number are irrational first one by under root 2

Answer» Assume that 1/root 2 is a rational no.1/root 2 =a/b (a & b are co - prime no. and b is not equal to 0)Root 2a=bRoot 2 =b/aOur assumption is wrong 1/root 2 is an irrational no.
27552.

X²-5 factorize

Answer» Hii
(x+root 5)(x-root 5)x=-root5, x=root5
27553.

Prove that 4-3 under root 2 is irrational

Answer»
27554.

Using Euclid\'s division algorithm,find the HCF of 345 and 76

Answer» Abhi yad aana tha
27555.

Prove that 5× root 3 os an irrational number

Answer»
27556.

Find zeroes of (x) square-5/3 and verify the relationbetween its zeros and cofficient

Answer»
27557.

Find one rational number and one irrational number between root 3 and root 5

Answer» Sry the irrational number was wrong but to find irrational number , here √3 =1.73.... So we can take 1.740400400 ....or 1.750500500...... And infinites numners are there.
Can u explain it better
Root 4 is rational number and i don\'t know irrational no between them
Rational no. is 2 and irrational is 1.730300300030000..............
Pls answer fast ....
27558.

Can we have the complete solution of board paper all set.

Answer» Yes of course
27559.

Will class 10 is easy then class 9

Answer» Yup
Yes
27560.

Sin square theta +cos square theta =1

Answer» Ya
Yes
27561.

1/~=? Here ~stands for infinity

Answer» 0
So what?
27562.

Find the quadratic polynomial whose zeroes are 3 and -4 respectively.

Answer» x^2 + x - 12=0
Find the sum and product of zeroes and then put the answer in the formula- x^2 - (sum of zeroes)x + product of zeroes
27563.

I want marking scheme of class 10boards paper of CBSE

Answer» Search in cbse website
27564.

We can extend side from any point in right angled triangle in construction chapter

Answer» Yes it depends on how we have draw figure
27565.

If the 10th term of an AP is 52 and the 17th term is 20 more than the 13th term, find AP

Answer» 7,12,17,22...
7,12,17
27566.

Rationalise denominator 1/1-root2+root3

Answer» Ryt
Bhai jo niche denominator diya hai usme do pair bana le aur solve kar le Pehlu do term ka alag aur last term alag
then rationalise no
Paii hindi ka paper. Hai abhi bhi maths.uska to paper ho gaya
27567.

n^2 + n

Answer» n(n+1)
27568.

67(23)

Answer»
27569.

secA+tanA=xFind tanA

Answer»
27570.

If A+B =90 then prove that √tanA+tanB. cotB/sinA. secB -sin squareB/cos cubeA=tanA

Answer» Given,LHS=√tanAtanB+tanAcotB/sinAsecB-sin²B/cos²B=√tanAtan(90-A)+tanAcot(90-A)/sinAsec(90-A)-sin²(90-A)/cos²A=√tanAcotA+tanAtanA/sinAcosecA-cos²A/cos²A=√1+tan²A/1-1=√tan²A=tanA\xa0
U r new tenthian maths he.........u
Paper ho gya ab dimag kharab mat kar
27571.

When will be the marking scheme of class 10 2019 will come.?

Answer»
27572.

If alpha and beta are the zeroes of 2*x^2+5*x_10, then the value of alpha and beta is

Answer» roots will be -5+ 105^2 / 4 and -5 - 105^2 / 4
Oh...Thanks sanjana good answer...
P
27573.

If sin A--3/4 calculate sec A

Answer» Maths exam is over bro
27574.

find the zeros of the polynomial x2+1/6x-2

Answer»
27575.

What is mean by pythagorean

Answer»
27576.

find the largest no which divides 615 and 963 leaving the remainder 6 in each case

Answer» To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.Consider HCF be x.In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6\xa0from both the cases.609 = 3 x 3 x 29957= 3 x 11 x 29⇒ x = 3 x 29 = 87∴\xa0largest number which divides 615 and 963 leaving remainder 6 in each case is 87.
Maths exam is over bro now next is hindi see the date sheet
87...
27577.

Surface area volumes.... exercise 15.4 last sum ... can anybody solve it and send

Answer» yr it is given in this app only
27578.

Use Euclids division algorithm to find HCF 135and225

Answer» 135 and 225 Since 225 > 135,we apply the division lemma to 225 and 135 to obtain225 = 135 × 1 + 90Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain135 = 90 × 1 + 45We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain90 = 2 × 45 + 0Since the remainder is zero, the process stops.Since the divisor at this stage is 45,Therefore, the HCF of 135 and 225 is 45.
45
45
27579.

X²-15x+6 how to middle term spilliting

Answer» .
Mtlb kuch bhi krke discriminant mein 1 laa hi dena hain , iss ques. kya glti hain
i think this question is wrongit can be x^2-15x+56
I think solve this question by discriminant formula
yeh middle term se nhi ho ga
27580.

Sin/cos=4/3,write all t ratio

Answer»
27581.

If 30=3q+r ,find the value of q and r using euclid\'s division lemma

Answer» q=10, r=0
27582.

Prove that x square minus x is divisible by 2 for all positive integers x

Answer»
27583.

X2+12x+6

Answer»
27584.

find the value of x=10x+11=20

Answer» Given= x =10x+11=20Then, x-10x=20-11-9x=9, then x=-1
27585.

Mathematics Set-2 Solution...

Answer»
27586.

Solution of maths board paper 2019

Answer» Main SSt padh raha hoon
Abhi kyu.....
Ku????????
27587.

Find the largest number which divids 229,250,302 is reminder 3 in each

Answer» Kuch nhi upper chat box me pd lo,....
Kya hua
???
Koi hai etana andera ku hai bhai
???
Kya aap Jupiter se ho
27588.

If an odd number p divides q2 then will it divide q3 also?? Explain.

Answer» Smallest odd prime number = 3Smallest odd composite number = 9H.C.F. of (3, 9) = 3L.C.M. of (3, 9) = 9As odd number p divides q².⇒ p is a factor of q² or q²/p gives 0 as a remainder.Now,\xa0q²\xa0× q = q³, and p is a factor of q², hence it will also be a factor of q²\xa0× q.⇒ p is a factor of q³Therefore, p will divide\xa0q³ also.In general, we can say that if p divides q² then it will also divide qⁿ, where n is a natural number (n ≥ 2).
27589.

What is the formula of perimeter of parallrlogram

Answer» 2(l+b) where l,b are the sides of parallelogram
27590.

The radius of 2cylinders are in the ratio2:1 find the ratio of their heights

Answer» Answer required
27591.

-2/3×3/5+5/2-3/5×1/6

Answer»
27592.

The taxi fare after each km when the fare is Rs15 for the first km and Rs 8 for each additional km

Answer» No, because the total fare (in Rs.) after each km is 15,(15+ 8), (15 + 2 x 8), (15+ 3 x 8),…= 15,23, 31, 39,…Let t1\xa0= 15,t2\xa0= 23,t3\xa0= 31 and t4\xa0= 39Now, t2\xa0- t1\xa0= 23 - 15 = 8t3\xa0- t2\xa0= 31 - 23 = 8t4\xa0- t3\xa0= 39 - 31 = 8Since, all the successive terms of the given list have same difference i.e., common difference = 8Hence, the total fare after each km form an AP.
27593.

If p is a prime number, then what is the HCF of p, p^2 and pq?????

Answer» p
27594.

Find the HCF of 3^4 × 5^2 and 3^3 × 5^4?????

Answer»
27595.

∆abc measure angle a =90 and ab =ac then bc:ab =

Answer» bc:ab=bc:ac
27596.

Draw acircle of radius 4.9

Answer» You are mad,what a question
Yes, how can i keep copass on my phone
27597.

Consider a positive integer a and b =4 then, a=4q+r where o is greater than r and ris greater than4

Answer»
27598.

Find the largest number which own dividing 1251,9377,15628leaves remainder 1,2and 3respectively

Answer» 625,3115, 3125 respectively
27599.

Ex. 1.2 ques 6

Answer» see the answer at the last pages
Ab kya hoga
Which subject
27600.

Find the sum of all natural numbers from 1 to 1000 which are nither divisible by 2 nor 5

Answer»