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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27701. |
Is exame pad is allowed in examination hall |
| Answer» Yes....but it should be transparent Suman ......All the best for ur exams ?? | |
| 27702. |
Please send all formula of class 10 |
| Answer» | |
| 27703. |
Find the mode of following data120 110 130 110 120 140 130 120 140 120 |
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Answer» 120 Mode is 120 120 paji |
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| 27704. |
Maths mi graph kise banye |
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Answer» If cbseguide would allow pictures then surely i can answer you bt...still the feature isnt introduced yet. ...call your school buddies for help Answer me... |
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| 27705. |
If Cos theta -sin theta =root 2sin theta prove that cos theta + sin theta = root 2 sin theta |
| Answer» Galat question hProof mei √2Costheta hoga | |
| 27706. |
If the mth of an AP is 1/n & nth term is 1/m then show that its (mn)th term is 1. |
| Answer» Rd sharma me solutuon diya h | |
| 27707. |
The length of tangent drawn from an external point at a circle are equal |
| Answer» Refer Ncert | |
| 27708. |
Anyone here who is hoping excessively to prevent leaking of paper like yesteryear...? |
| Answer» | |
| 27709. |
Prove that thetangents drawn at the end of a diameter of a circle are parallel |
| Answer» Given: PQ is a diameter of a circle with centre O. The lines AB and CD are the tangents at P and Q respectively.\xa0To prove: AB\xa0{tex}\\parallel{/tex} CDProof: AB is a tangent to the circle at P and Op is the radius through the point of contact{tex}\\because{/tex}{tex}\\angle{/tex}OPA = 90o .......(1) [The tangent at any point of a circle is perpendicular to the radius through the point of contact]{tex}\\because{/tex}\xa0CD is a tangent to the circle at Q and OQ is the radius through the point of contact.{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}OQD = 90o ........(2) [The tangent at any point of a circle is perpendicular to the radius through the point of contact]From (1) and (2),{tex}\\angle{/tex}OPA = {tex}\\angle{/tex}OQDBut these form a pair of equal alternate angles.{tex}\\because{/tex}\xa0AB\xa0{tex}\\parallel{/tex} CD | |
| 27710. |
Root √5 is irrational |
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Answer» Let us assume that √5 is rational, then it will be =a/ba and be are coprime numbers. √5=a/bSquaring both sides5=a²/b²5b²=a²It means 5 will divide a² and also a. 5 will divide a for some integer c5c=a (squaring both sides) 25c² = a²So 25c²=5b²5c²=b²It contradicts that a and b are coprime, our assumption was wrong and √5 is irrational How i can solve it Yes bro |
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| 27711. |
That root 2 + root 2 is irrational |
| Answer» Let that be equal to p/q where p q r integers .....Sqaure on b.sAnd after that u know it | |
| 27712. |
All the best to all students who use this app for their maths exam |
| Answer» Thanq..n same to u | |
| 27713. |
Csa of conical top |
| Answer» | |
| 27714. |
Full mathematics fomulae |
| Answer» Plzz search on google | |
| 27715. |
Find lcm |
| Answer» Its not full question | |
| 27716. |
The ratio of area of 2 similar triangles is equal to the square of the corresponding |
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Answer» Sides Dont know |
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| 27717. |
area of major or minor sector |
| Answer» Area of sector theta /360 ×πr²Major sector area of circle - area of minor sector πr²-theta/360×πr² | |
| 27718. |
What is the value at unit place value 9° |
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| 27719. |
1+sinA+cosA/1+cosA-sinA=1+sinA/cosA |
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| 27720. |
If circumference of a circle is equal to perimeter Of Square then ratios of Their areas is? |
| Answer» 14:11 | |
| 27721. |
Two zeroes of polynomial x^4- 13x^3+52x^2-64x+24 are3+ root5 and 3- root 5 find the other zeroes |
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Answer» 3+-root5 equals to me x rkh kr..squring krdijiye...gx nikl jaega Rd sharma is a book Bese ye..question RD ka..hai kya Is question ko pd kr..lg raha hai..ki mera abhi..bohot bcha hai??? Error 305? |
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| 27722. |
Converse of bpt |
| Answer» Line bisecting the other two sides of traingle will be parallel to third side | |
| 27723. |
what are the possible values of remainder r, when a positive integer "a" is divisible by 3? |
| Answer» Values of r can be 0,1,2 by euclids division lemma | |
| 27724. |
Find the mode of the following data 120,130,140,150,160,170 |
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Answer» Haan ungrouped data mai... Mode highest no. Hota hai ? 170 |
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| 27725. |
Itnnaa sannataa kyu hai bhai!!!??? |
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| 27726. |
Slove for x and mx+y=m+n m(1\\m_n-1/m-n)x+n(1/n_m_content://media/external/file/1080221m+n |
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| 27727. |
A12 the term of ap is -3, -1/2, 2 |
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| 27728. |
Find the value of k so that 2x find the value of k so that 2 X square + kx + 3 is equal to zero |
| Answer» 2x2 + kx +3=0We know that quadratic equation has two equal roots only when the value of discriminant is equal to zero.Comparing equation 2x 2 +kx +3=0 with general quadratic equation ax2 + bx + c =0, we get a = 2, b = k and c = 3Discriminant = b2 − 4ac = k2 - 4(2)(3) = k2 -24Putting discriminant equal to zerok2 - 24 = 0 ⇒ k2 = 24{tex}\\Rightarrow k = \\pm \\sqrt { 24 } = \\pm 2 \\sqrt { 6 } \\Rightarrow k = 2 \\sqrt { 6 } , - 2 \\sqrt { 6 }{/tex} | |
| 27729. |
Formula of Area of minor segment |
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Answer» Area of sector - area of tirangle Theta/360×πr^2- r^2 × sin theta/2 |
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| 27730. |
1. 1. 1. 1A+b+x=. A+ b+. X |
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| 27731. |
√2 is irrational no. |
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| 27732. |
Find the distance between A(a,b)&(-a,-b) |
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| 27733. |
(a+b) whole squa re is identify me agar a= 2a diya hai too a whole square me kya lenge |
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| 27734. |
If \uf020\uf044ABC ~ \uf044QRP, ar(\uf044ABC)ar(\uf044QRP) = 94, and BC = 15 cm, then find PR. |
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| 27735. |
If sec theta + tan theta=p then,find the value of cosec theta |
| Answer» Secθ+tanθ=p ----------------------(1)∵, sec²θ-tan²θ=1or, (secθ+tanθ)(secθ-tanθ)=1or, secθ-tanθ=1/p ----------------(2)Adding (1) and (2) we get,2secθ=p+1/por, secθ=(p²+1)/2p∴, cosθ=1/secθ=2p/(p²+1)∴, sinθ=√(1-cos²θ)=√[1-{2p/(p²+1)}²]=√[1-4p²/(p²+1)²]=√[{(p²+1)²-4p²}/(p²+1)²]=√[(p⁴+2p²+1-4p²)/(p²+1)²]=√(p⁴-2p²+1)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1)∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1) I HOPE THIS HELPS! | |
| 27736. |
The height of a cone is 120cm.A small cone is cut off at the top |
| Answer» Complete the question please.... | |
| 27737. |
1+tan |
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| 27738. |
1/a+b+x =1/a +1/b + 1/c |
| Answer» Question clear nhi ho paa rha hai... | |
| 27739. |
Probability dice |
| Answer» Easy hai | |
| 27740. |
Pythagoras thearm |
| Answer» Pythagoras TheoremStatement: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.\xa0Given: A right triangle ABC right angled at B.To prove: AC2\xa0= AB2\xa0+ BC2Construction: Draw BDACProof :We know that: If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.ADBABCSo,(Sides are proportional)Or, AD.AC = AB2\xa0... (1)Also,BDCABCSo,Or, CD. AC = BC2\xa0... (2)Adding (1) and (2),AD. AC + CD. AC = AB2\xa0+ BC2AC (AD + CD) = AB2\xa0+ BC2AC.AC = AB2\xa0+ BC2AC2\xa0= AB2\xa0+ BC2Hence Proved. | |
| 27741. |
Proof pythagores thorem |
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| 27742. |
Write the value of (1-sin square theta) sec square theta |
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Answer» Cos theta Cos squre theta |
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| 27743. |
If we do multiply with negative numbers |
| Answer» Ans will be positive-5 * (-5)= 25 | |
| 27744. |
Sec Q + tan Q = p prove that |
| Answer» | |
| 27745. |
A dice thrown twice find the probability that 5 will not come up either time |
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Answer» U can search in ncert solutions in this app 25/36 |
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| 27746. |
Ex-3.5 -2 |
| Answer» . | |
| 27747. |
WHAT IS DIGIT AT UNIT PLACE OF NINE SQUARE AND |
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| 27748. |
Under root 5 |
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| 27749. |
Find the distance of x axis from point (3,-4)? |
| Answer» 4 units | |
| 27750. |
tan a+b=90 |
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