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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27751. |
2+2+2+2+2+2-2-2-2-2-2-2 |
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Answer» -4 It will be 0 0 0 |
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| 27752. |
Wish all of you all the best. Put your all effort and give your 120%???? |
| Answer» Wow , thanq and s2 u | |
| 27753. |
,what is copsotive number |
| Answer» A number which has 2 or more than 2 factor | |
| 27754. |
Given hemisphere volume |
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Answer» 2/3πr^3 2/3πr^3 2/3 pie r cube |
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| 27755. |
Formula area of minor segment if theta is equal to 60 degree |
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Answer» π×Φ/360 -sinΦ/2 ×cosΦ/2 Area of sector - area of triangle60/360 (pie r square)- area of triangle |
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| 27756. |
Which term of the arithmetic progression 3,,10,17...... will be 84 morr than its 13th term? |
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Answer» 13th term is = 3+12*713th term is 84 Ans. 84+84= 168 the answer lies between 1-infinity |
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| 27757. |
एक समदिबाहु त्रिभुज ABC मे AB=AC है और B से भुजा AC पर लम्ब BD है सिध्द कीजिएः BD^2- CD^2 =2CD.AD |
| Answer» Please English me likho bhai | |
| 27758. |
What is the meaning of composite number |
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Answer» Composite no. is the no. which have more than two factors i.e 1, itself and any other no. for example 9 it has factors 1, 3 and 9 itself More than 2factors composite no which has factor 1 , itself n one more factor like 4 =4×1 4=1×4 4=2×2 A composite no. Is a no. Which has factor 1 and itself |
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| 27759. |
State the theorem of triangles ,which is used for dividing a line segment in agiven ratio |
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| 27760. |
sin^6-cos^6 |
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| 27761. |
Pathyagores therom |
| Answer» AC²= AB² + BC² | |
| 27762. |
a quadrilateral ABCD is drawn to circumscribe a circle. prove that AB+CD=1/2(AB+BC+CD+AD) |
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| 27763. |
Find the hcf of 325670 |
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| 27764. |
Find the hcf of 3276052 and use the formula in it |
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| 27765. |
Through a two dice and find the probability of prime no. |
| Answer» Let A be the event of getting the sum as a prime number i.e. 2,3,5,7,11\xa0Elementary events favourable to event A are:(1, 1), (1, 2), (2, 1), (1, 4), (4, 1), (2, 3), (3, 2), (1, 6), (6, 1),(2, 5), (5, 2), (3, 4), (4,3) , (6,5) and (5, 6).Favourable number of elementary events = 15Hence, required probability{tex}= \\frac { 15 } { 36 } = \\frac { 5 } { 12 }{/tex} | |
| 27766. |
What is the relation between mean median and mode |
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Answer» 3Median =1Mode+2Mean 3 median= mode +2mean Mode =3median-2mean Mode = 3 median - 2 mean |
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| 27767. |
let x-1, x-4 and x-7 are in the ap find the value of x |
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Answer» 0 Wrong question |
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| 27768. |
Prove that {1-tanA ÷ 1-cotA } = tan^2A |
| Answer» {tex}\\begin{array}{l}\\left(\\frac{1-\\mathrm{tanA}}{1-\\mathrm{cotA}}\\right)^2=\\left(\\frac{1-\\mathrm{tanA}}{1-{\\displaystyle\\frac1{\\mathrm{tanA}}}}\\right)^2\\\\=\\left(\\mathrm{tanA}\\frac{(1-\\mathrm{tanA})}{\\mathrm{tanA}-1}\\right)^2\\\\=(-\\mathrm{tanA})^2=\\tan^2\\mathrm A\\end{array}{/tex} | |
| 27769. |
Show that number of the from 14n , where n is a natural number can never end with digit zero |
| Answer» If the number 14n ,for any n , were to end with zero , then it would be divisible by 5 . that is the prime factorization of 14 and would contain the prime 5 it is not possible because 14 n =[7]2n , show the only prime in the factorization of 14 and S7 so the uniqueness of the fundamental theorem of arithmetic guarantees that | |
| 27770. |
1/x+1/y=1/z |
| Answer» x,y,z=mishra | |
| 27771. |
If zeroes of polynomial x3-3x2+x+1 are a-b, a, a+b, find a & b. |
| Answer» Get me answer.. | |
| 27772. |
How we can calculate hours into fraction |
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| 27773. |
Find the sum of( 5+13+21+....+121) |
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Answer» a=5,d=8 l=121an=a+(n-1)d121=5+(n-1)x8116=8n-88n=124n=124/8=15.5So 121 cannot be term of this AP,So question is not correct(this is not an AP)pl check question again 1008 |
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| 27774. |
What is the unit place of 9n |
| Answer» 9 | |
| 27775. |
The ratio of the sum of n term of two Ap in (7 n+1):(4 n+27). Find the ratio of their m term |
| Answer» 7m+1:4m+27 | |
| 27776. |
DA and DB are the tangents drawn from D ro the circle with centre O.If angle ADO=40 .Find angle AOB |
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Answer» Answer is 100 Sorry this ans is incorrect 140 |
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| 27777. |
Nth term of formula |
| Answer» an = a + (n-1)d | |
| 27778. |
Formulao chapter5 |
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| 27779. |
Find quadratic polynomial whose sum and product of whose zerores are -3 and 2 respectively |
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Answer» Let the first zero be x And second be y A.T.Qx+y= -3 = -b upon axy=2=c upon aWe have a=1 , b=3 (because -b= -3 so b=3) and c =2 ax square +bx +c=0X square +3x+2=0 x^2 + 3x + 2 ... Its too easy |
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| 27780. |
Find the number of solution of linear equations 2x-y=3 and 4x-y = 3 |
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| 27781. |
How to draw a ogive of less or more than type of data is given on the graph |
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Answer» calculate cumulative frequency then write less than upper limit similarly write all from class interval n put the value of cf bcoz in less than value is same as cf in more than type write lower limit of class interval n their value in 1st u can write to last c.f in only 1st then from 2nd just subtract the frequency no. from 1st , from 2nd value subtract 2nd of frequency n so on then u can draw easily Commulative frequency ko adjust krke less than or more than mein f bnake graph draw ki a jaenga |
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| 27782. |
The annual profits |
| Answer» What | |
| 27783. |
Explain completing the square method with examples |
| Answer» {tex}x^2 +\xa06x - 16 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 + 6x = 16{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 + 6x + 9 = 16 + 9{/tex} [Adding on both sides square of coefficient of x, i.e. ({tex}\\frac{6}{2}{/tex})2]{tex}\\Rightarrow{/tex}\xa0{tex}(x + 3)^2 = 25{/tex}{tex}\\Rightarrow{/tex}\xa0x + 3 =\xa0{tex}\\pm{/tex}{tex}\\sqrt{25}{/tex}{tex}\\Rightarrow{/tex}\xa0x + 3 =5 or x + 3 = -5{tex}\\Rightarrow{/tex}\xa0x = 2 or x = -8 | |
| 27784. |
How to pass in maths? |
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| 27785. |
Math k paper me ncert Ka kitna percent ayega |
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Answer» Agr concept clear h to aap 90+ score kr sakte ho 65 to 70% Please ase mat bolo mene to preparation hi ise ki h 75% ncert mai se hi aata h 0.00005% ?? 75% |
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| 27786. |
How to find the middle most value in an ap |
| Answer» If first term (a) and last term (l) is given,the middle term is given by-(a+l)/2 | |
| 27787. |
A motor boat whose speed is 24 km/hr in still water takes |
| Answer» Complete the question.... please | |
| 27788. |
Lcm our hcf 125. 225 |
| Answer» Lcm=1125 , hcf=25 | |
| 27789. |
135 our 225 |
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| 27790. |
Solve for x:2x_3÷x_1_4(x_1)÷2x_3=3 |
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| 27791. |
Maths ka paper kaisa hoga? |
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Answer» 70 percent out side 80 percent ncert |
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| 27792. |
Prove that sec^2A + cosec^2A >2 |
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| 27793. |
how u calculated 1200x - 1800x |
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Answer» -600x -600x 700x |
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| 27794. |
Split 208 into three parts such that these are in Ap and the product of two smaller part is 4623 |
| Answer» 67 69 71 | |
| 27795. |
Find HCF of 96,240,and 336 |
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Answer» vaishika I think Answer is 48 96=25 x 3240=24x3x5336=24x3x7HCF=24x3=16x3=48 |
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| 27796. |
Find root of quadratic equation 6x2-x-2 |
| Answer» 2 and 2/3 | |
| 27797. |
Prove that= cosA-sinA+1/cosA+sinA-1=cosecA+cotA |
| Answer» LHS : = CotA-1+cosecA/CotA+1-CosecA. (Divide the both the value by "SinA") = CotA+CosecA-(Cosec^2A-Cot^2A) / CotA-CosecA+1. (1=cosec^2A-cot^2A) = (CotA+CosecA)-(cosec^2A+cot^2A)/CotA-CosecA+1 = (CotA+CosecA)-(CosecA+CotA)(CosecA-CotA) = CotA+CosecA-(CotA-CosecA+1)/CotA-CosecA+1 = CotA+CosecA PROVED!!!!Its a question NCERT EX-8.4 Q5 (v) part... | |
| 27798. |
Find the mean |
| Answer» Where is the question..?? | |
| 27799. |
Abc is an iscoscles triangle right angled at c prove ab2 = 2ac2 |
| Answer» Given: ABC is an isosceles triangle right angled at C.To prove: AB2 = 2AC2Proof : ABC is an isosceles triangle right angle at C.{tex}\\therefore {/tex} AC = BC........(1)and {tex}\\angle{/tex}C = 90o.......(2)In view of (2) in{tex}\\vartriangle {/tex} ABC,AB2 = AC2 + BC2........By Pythagoras theorem.AC2 + AC2 ........Frrom(1)= 2Ac2 | |
| 27800. |
Prove that cotA+cosecA-1 |
| Answer» | |