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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27901. |
solve graphically 5x-y-5=0, 3x-y-3=0 |
| Answer» When you put the value of x=2 so you get5 into 2-y-5=0 10-y-5=0Y-5=10Y=10+5Y=15Put the value of y=2 so you get 5x-y-5=0 5x-2-5=03x-5=0X=5upon 3 | |
| 27902. |
(x+1/4x)square -1 =(x-1/4x)square.. Prove.. Please help me |
| Answer» solving LHSx²+1+2x/4x-1. ......... ........x²+1+ 2x-4x/4x.........x²+1-2x/4x..... ......,..... =(x-1)²/4x..........LHS=RHSHENCE PROVED | |
| 27903. |
1/(a+b+x)=1/a+1/b+1/x |
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Answer» 1/a+b+x - 1/x = 1/a + 1/bx-a-b-x/x(a+b+x) = a+b/ab-1/x(a+b+x) = 1/ab-ab = ax+bx+x2X2+ax+bx+ab= 0X (x+a) + b (x+a) = 0(x+a)(x+b) = 0X = -a, -bAm i right Question clear nhi ho paa rha h..... Help me to understand.... |
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| 27904. |
Construction chapter me denominator big hai to 2nd triangle inside or outside the 1st tiangle. |
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Answer» It will be inside The second ,smaller triangle will be constructed inside the first triangle Inside hota hai sorry sorry Agar denomi is greater triangle is constructed outside |
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| 27905. |
what is the hcf of smallest prime number and the smallest composite number.? |
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Answer» 2 2 2 |
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| 27906. |
Two opposite vertices of a square are A(-1,2) and C(3,2) .Find the other two vertices. |
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| 27907. |
If sec theta + tan theta then find value of cossec theta |
| Answer» Question is incomplete bro | |
| 27908. |
Page no. 283 in ncert maths . Questions no. 16 Plz ans .. |
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| 27909. |
If x+a is a factor of the polynomial x²+px+q and x²+mx+n prove that a=n-q/m-p |
| Answer» Since x + a is a factor of x2+ px + qthen (-a)2\xa0- pa + q = 0{tex}\\Rightarrow{/tex}a2 = pa -q ..........(i)also (x + a) is a factor of x2+ mx + n then we get(-a )2\xa0- am + n = 0{tex}\\Rightarrow{/tex} a2 - am + n= 0{tex}\\Rightarrow{/tex}a2\xa0=\xa0am - n........(ii)From eq(i) and (ii), we getam - n = ap - q{tex}\\Rightarrow{/tex}am - ap = n - qHence, a =\xa0{tex}\\left[ \\frac { n - q } { m - p } \\right]{/tex} | |
| 27910. |
a+b ka whole cube |
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Answer» a³+b³+3ab(a+b) a cube plus b cube plus 3ab (a+b) |
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| 27911. |
Prove that cos2theta =sin2tgeta |
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| 27912. |
Express sin 70°+85°in terms of trigonometric ratios of angles between 0°and 45° |
| Answer» sin(70+85)=sin 155=sin(180-25)=sin (2x90-25)=sin 25 | |
| 27913. |
Calculate the HCF of 3³×5 and 3²×5² |
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Answer» 45 45 is the HCF |
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| 27914. |
Sin theta _ cos theta + 1/sin theta + cos theta _1 =1/sec theta_ tan theta |
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Answer» I can\'t understand that See in ncert chapter trignometry example 15 |
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| 27915. |
how prove the ex 8.4 |
| Answer» q5 | |
| 27916. |
If Sec+Tan = pFind the value of Cosec. |
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Answer» Is this was helpful for you? Please tell me. 1/cosA + sinA/cosA=p1+sinA/cosA=pOn squaring on both sides.(1+sinA)^2/(cos^2)=p^2(1+sinA)^2/(1-sinA^2)=p^2(1+sinA)/(1-sinA)=p^2Now by changing sin into cosec and simplify the eq. and then take cosec common and you will get the answer. |
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| 27917. |
How can we select median class if there are 2 missing frequency and median is given |
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| 27918. |
Blue print of marhs 2019 |
| Answer» Q | |
| 27919. |
If the pth, qth & rth term of an AP is x, y and z respectively, show that x(q-r) +y(r-p) +z(p-q) =0 |
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Answer» Try this.Two two digit numbers are written one after another to give a four digit number such that the larger two digit number is written first. now if the difference of the four digit number and the sum of two two digit numbers is 5742 then find the two digit number. That\'s very good question. Okay |
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| 27920. |
What is the value of cos square 67 zero - sin square 23 zero. |
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Answer» Ya it will be zero As sin(90-thita)=cos thita So sin square 23 will be converted into cos then cos square 67 and the sin that is changed into cos will be cancelled and will give an answer equal to 0 Zero....????...??? |
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| 27921. |
If alpha plus beta =90° |
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Answer» So.. Complete the question |
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| 27922. |
How many theorem come in board exam |
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Answer» Bpt , pythagorus main h vse baki kuch idea nhi All most 1 or 2 but they come for only 3-4 mark only 1or 2 1or 2 |
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| 27923. |
If median of the distri bution |
| Answer» Complete kro question ko.. | |
| 27924. |
1by(x-1)(x-2) +1by(x-2)(x-3)=2by3Solve for x |
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Answer» No answer is 0,4 -1+√17/2 and -1-√17/2 |
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| 27925. |
Kya trigonometry ke questions ncert se aate h |
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Answer» Yes. Somewhat |
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| 27926. |
Find the value of \'k\' for which the quadratic equation (k-2)x^2+2(2k-3)x+(5k-6)=0 has equal roots. |
| Answer» Get the discriminant equal to zero and put the values of a,b,and c and solve it. You will surely get the answer. The value of k can be 1 and 3. | |
| 27927. |
If in an AP 16th term is zero then show that 33rd term if 3 times of its 15th term. |
| Answer» 6=0a+5d=0a=-5d----(i)now33rd term=a+32dputting the value of a from equation (i) we gett33=-5d+32d=27d----(ii)now,t15=a+14d=-5d+14d=9d-----(iii)from equation (ii) and (iii)3(t15)=(t33)proved. | |
| 27928. |
If the area of 2 similar triangles are equal, prove that they are congurent. |
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Answer» Let triangles ABC and PQR have equal areas.we have the formula for area of similar triangles.area of ABC/area of PQR=\xa0AB2/PQ2\xa0=\xa0BC2/QR2=\xa0AC2/PR2but given that ar(ABC)=ar(PQR)implies that AB=PQ, BC=QR, AC=PR.therefore triangle ABC≅ triangle PQR Iss app par dekhlo...ex 6.4 ka 5th ya 6th question h... |
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| 27929. |
Maths 2017 board question paper |
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| 27930. |
Drive Trigonometery ratios in questions? Plzz. .. |
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Answer» Thankss Isde vaaste diagram di zarurt h...but itthe pictures paste nahi kr skde....google kr le paii.. |
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| 27931. |
Cbse important question of maths |
| Answer» U tube mai ek channel hai Fastest Education name se...usmai hain videos aisi dheer saari...check them out! | |
| 27932. |
Find the middle term of the AP 213,205,197,.....37. |
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Answer» Given, T1 = 213 = a. T2 = 205. Then, d = T2 - T1. d = 205 - 213. d = - 8.Now, Tn = a + (n - 1) × d. 37 = 213 + (n - 1) × (-8). 37 = 213 - 8n + 8. 37 = 221 - 8n. 8n = 221 - 37. 8n = 264. n = 184/8. n = 23. Hence the total no. of terms in the A.P are 23.therefore the no. middle term will be 12.Then, T12 = a + (12 - 1) × d. = a + 11d. = 213 + 11(-8). = 213 - 88. T12 = 125. Take out first no of terms do it\'s half that tern 125 which is 12th term of ap |
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| 27933. |
Prove 9AD²=7AB² |
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Answer» 6.5 que 15 What\'s your question........? |
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| 27934. |
Quadratic equation .formula.based |
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| 27935. |
Solve for x and y 7sup x + 5sup y =74. 7sup (x+1)-5sup(y+1)=218 |
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| 27936. |
Find the 18th term of AP: √2,√18,√50,√98,... |
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Answer» Ap= √2,√18,√50, √98 it can also be writtenin the form Ap=√2,3√2,5√2,7√2...... A=√2. D=2√2. Now, a of 18= a+( n-1 )×d. √2+17×2√2. = √2+34√2. =35√2 answer.? Ap is in form /2, 3/2, 5/2 ........ where / means root and difference d = a2-a1 =3/2-/2 = 2/2 a=/2d=2/2a18= a+17d = /2 + 17×2/2 = /2 + 34/2 =35/2 = /2450 The AP can be written as:√2 ,3 √2 ,5 √2 ,7 √2 ...a= √2 and d=2 √2a18= √2 +17*2 √2=(1+34) √2=35 √2 ={tex}\\sqrt 2450{/tex}\xa0 35√2 A=root 2D=2 root2N=18Therefore applying a+(n-1)dANSWER IS= 35root2 35 root 2..... sqrt 2450 |
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| 27937. |
How to revise maths before 1 done of exam |
| Answer» U just see the register on which u have practiced maths | |
| 27938. |
Find HCF of 91 and 130 and express its in the form of 91x+130y. |
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Answer» Hcf=13 and x=3, y=-2 x=3, y= -2 |
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| 27939. |
How many three-digit numbers are division by 7. |
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Answer» 128 is the correct answer. Thanks an = a + (n-1)d a is 105D is 7 and an = 994994 = 105 + (n-1)7889÷ 7 = n-1127 =n-1128 = n Refer to ncert ch-5 A.P 128 Ans fast....... |
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| 27940. |
Find the zeros of the polynomial x^2-3x-m(m+3) |
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Answer» Ya X^2 - 3x - m(m+3) = 0=> x^2 + mx - (m+3)x- m(m+3) = 0=> x(x+m) - (m+3)(x+m) = 0=> (x+m) (x-m-3) = 0x = - m and m+3Roots are - m and m+3?? |
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| 27941. |
Find the zeros of the polynomial x^2+x-p(p+1) |
| Answer» x2+x-p(p+1)=0x2+(p+1)x-px-p(p+1)=0x(x+p+1) -p(x+p+1)=0(x+p+1)(x-p)=0x=-p-1, phope it will help u?? | |
| 27942. |
Prove that (1 + sinA-cosA) ÷(1+sinA+cosA) =(1-cosA)÷(1+cosA) |
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Answer» The answer of this question is too long.How I can send u Bhai its to long how i send u |
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| 27943. |
SINA-COSA+1/SINA+COS-1=1/SECA-TANA |
| Answer» LHS = (sinθ - cosθ + 1)/(sinθ + cosθ - 1) dividing by cosθ both Numerator and denominator = (sinθ/cosθ - cosθ/cosθ + 1/cosθ)/(sinθ/cosθ + cosθ/cosθ - 1/cosθ)= (tanθ + secθ - 1)/(tanθ - secθ + 1) Multiply (tanθ - secθ) with both Numerator and denominator = (tanθ + secθ - 1)(tanθ - secθ)/(tanθ - secθ + 1)(tanθ - secθ)= {(tan²θ - sec²θ) - (tanθ - secθ)}/(tanθ - secθ + 1)(tanθ - secθ)= (-1 - tanθ + secθ)/(tanθ - secθ + 1)(tanθ - secθ) [ ∵ sec²x - tan²x = 1 ]= -1/(tanθ - secθ) = 1/(secθ - tanθ) = RHSHope it helps archana ? | |
| 27944. |
SinA-1/CosA+SinA-1=CosecA-CosA |
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| 27945. |
What is probability???? |
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Answer» Probability: how likely something is to happenFormula to find probability = favourable outcomes /total outcomes...Probability is can\'t be negative..... Favorable outcomes/total putcomes Fav. outcomes/total outcomes |
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| 27946. |
Find the value of P such that quadratic equation ( P-12)x2-2(P-12)x+2=0 has equal root |
| Answer» (P -12)x² +2( P -12) x + 2 =0 have two real and equal roots so, D = b² -4ac =0here, b = 2( P -12) a = (P -12) c = 2 now, D = {2(P -12)}² -4.2(P -12) =04{ (P -12)² -2( P -12) } =0(P -12)² -2(P -12)=0(P -12){ P -12 -2} = 0(P -12)( P -14) =0P = 12, 14 hence value of P = 12,14 | |
| 27947. |
How many of u are perparing for maths to write on 7th march 10:30am |
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Answer» I\'m preparing for board exams on 7 March Me... |
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| 27948. |
Prove that in circle the angle in the alternate segment are equal |
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| 27949. |
Real numbers proving |
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| 27950. |
sir please tell the prove trigonometry identies |
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