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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27951. |
Preparation kaisi h |
| Answer» Bhaukali | |
| 27952. |
Write a fraction that is not in simplest form, then simplify it |
| Answer» | |
| 27953. |
If T^ n= sin^n + cos^n |
| Answer» Complete ur que. | |
| 27954. |
Math ka cbse paper easy hota hai |
| Answer» Yes... Pichle baar ka dekho 99%Ncert h | |
| 27955. |
What is the value of theta?? |
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Answer» {tex}\\theta{/tex} is a simple letter of greek language like a,b ..x ,y.So need get confusedYou can use {tex}\\theta{/tex} like x,y a,b,m or n.....{tex}\\theta{/tex} is commonly used to indicate angle in trigonometry,But it is not fixedwe are also using A,x ... in trigonometry,So no any fixed value of {tex}\\theta{/tex}, it is used as variable. Nobody know it..... |
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| 27956. |
Find the sum of n terms of the series (4-1/n)+(4-2/n)+(4-3/n)+............ |
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Answer» Sum=4n-1/n(1+2+3+........n)=4n-1/n*n(n+1)/2=4n-(n+1)/2=1/2(8n-n-1)=1/2(7n-1) Series becomes:4x n-1/n(1+2+3+.......n)=4n-1/n*n(n+1)/2=4n-(n+1)/2=1/2(8n-n-1)={tex}\\frac{7n-1}{2}{/tex} 3n |
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| 27957. |
What is the valve of sin 30 |
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Answer» 1/2 1÷2 1/2 1/2 1/2 |
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| 27958. |
Hcf of two numbers is 13 and LCM is 182 if one number is 26 then find the other number |
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Answer» 91 Other no. is 91 91 Etne simple que. To khud kr skte hn atleast ab to books kholo |
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| 27959. |
Solve it 2-2 ×3+3 |
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Answer» 7 According to BODMAS, 2-2×3+3 = 2-6+3= 5-6 = -1 -1 According to BODMAS the answer is -1 7 |
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| 27960. |
If sec theta=x+1/4xProve that sec theta + tan theta =2x or 1/2x |
| Answer» Find attached the solution | |
| 27961. |
In an equilateral triangle with side a,prove that area =√3/4a^2 |
| Answer» This is class 9th NCERT ques....ch name Herons Formula....check it ....you\'ll get it | |
| 27962. |
Using quadratic formula solve the following quadratic equation p×px×x+(p×p-q×q)x-q×q=0 |
| Answer» Given\xa0p2x2\xa0+ ( p2\xa0- q2)x - q2\xa0= 0.⇒\xa0p2x2\xa0+ xp2\xa0- xq2\xa0- q2\xa0= 0.⇒ xp2(x + 1) -\xa0q2\xa0(x + 1)\xa0= 0.⇒ (xp2-\xa0q2)(x + 1)\xa0= 0⇒ x = q2\xa0/ p2\xa0or -1. | |
| 27963. |
The first three terms of an A. P. respectively 3y-1,3y+5 and 5y+1. Find the value of y |
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Answer» Step-by-step explanation:3y+5-(3y-1) = 5y+1-(3y+5)6 = 2y-4Y= 5So the three terms are 14,20,26 y=5 |
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| 27964. |
What is the Value of Cot²θ. |
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Answer» Cosec2theta-1 1/tan^2theta 1/tan²theta Cosec2thitha-1 |
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| 27965. |
3/4 परिमेय सखंख है |
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Answer» Yess Yes |
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| 27966. |
If the zeroes of the polynomials x²_px+q are in the ratio 2:3. Prove that 6p²=25q |
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| 27967. |
Prove that n^2-n is divisble by 6 for any natural no. n |
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| 27968. |
X2-5x-7 |
| Answer» It will not vime because 7 and 5 are prime number ??? | |
| 27969. |
Find the value secA if sinA = 3/5. |
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Answer» 5/4 dear. Ans is 5/4 5/4 |
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| 27970. |
The perimeter of a sector of a circle of radius 5.2 is 16.4 . find the area of the sector |
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Answer» 15.6 cm2 is the answer 15.6 cm^2 |
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| 27971. |
Hcf of 385 |
| Answer» And where\'s the second number. | |
| 27972. |
Blue print of class 10 |
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| 27973. |
Write the value of cot^-1÷sin^ |
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| 27974. |
If a2,b2,c2 are ap, then prove that a/b+c,b/c+a,c/a+b are also in ap |
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| 27975. |
What is co prime numbers ?? |
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Answer» Ya vaibhav- diksha is right Eg-1, 5,7,11and so on Two natural numbers are called co prime numbers if there hcf is one not necessarily prime |
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| 27976. |
Exercise 6.4 question no. 7 |
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Answer» Yes Siddharth is saying right Actually es ques. M bs diagram banana thoda sa complicated h baaki simple h Its too easy aap previous year paper k solutions m jao vhaa apko mil jayega |
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| 27977. |
Prove that 12n is not end with digit0 and 5 |
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Answer» Thanks manisha Its correcy diksha Because 12 has not 2 and 5 its prime factor so 12n can\'t end with digit 0 and 5 |
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| 27978. |
In figure , AB||DE and BC||EF .prove that AC||EA |
| Answer» What is the figure??? | |
| 27979. |
(p,q),(m,n),and (p-m,q-n)are collinear, show that pn=qm |
| Answer» Given points are collinear. Therefore[p {tex}\\times{/tex}\xa0n + m(q - n) + (p - m) q] - [m {tex}\\times{/tex}\xa0q + (p - m) n + p (q - n)] = 0{tex}\\Rightarrow{/tex}\xa0(pn + qm - mn + pq - mq) - (mq + pn - mn + pq - pn) = 0{tex}\\Rightarrow{/tex}\xa0(pn + p q - mn) - (mq - mn + pq) = 0{tex}\\Rightarrow{/tex}\xa0pn - mq = 0{tex}\\Rightarrow{/tex}\xa0pn = qm | |
| 27980. |
board give same mark for question or it may veriy |
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| 27981. |
yes they follow this blue print blue print of maths send me |
| Answer» | |
| 27982. |
did board following blue print of maths ? |
| Answer» Yess | |
| 27983. |
How many multiples of 4 lie between 10& 250 |
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Answer» Put a=12 ,d=4 and an=248 A.p series 12,16,20.............248 60 |
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| 27984. |
Prove that a quadrilatera and a circumscribe |
| Answer» Ye to 12.2 ka hy ncert | |
| 27985. |
Question 5 of exercise 10.2 |
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Answer» Page number 208 aur 209 Ismai theorem 10.1 prove krna hai |
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| 27986. |
If (cosec o- sin0)=m^3 and( secO-cos0)=n^3,then show that m^4n^2+m^2n^4=1 |
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Answer» Then give the answer So please tell how to solve this question So easy |
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| 27987. |
What is the method of finding prime number? Is there any formula for this?? |
| Answer» there is no formula for this_Method is prime factorisation | |
| 27988. |
Find the probability that a non leap year selected at random will contain 53 Sunday. |
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Answer» The probability of Sunday is equal to 1/7 2/7... 2/7 |
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| 27989. |
A circle touches all the four sides of a quadrilateral abcd prove that AB+CD=BC+DA |
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Answer» Proof:we know that length of tangent drawn from ext. point are equal ..ye is se proof hoga..isse m detail me likh kr kaisr btau AQ+AS+PB+ps+cp+cs+qd+pd they have prove that AB+CD=BC+DA |
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| 27990. |
IS OPTIONAL EXERCISE OF MATHS CLASS 10 COMING? |
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Answer» Your welcome It may be come |
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| 27991. |
FIND k SO THAT x2 +2x+k IS A FACTOR OF 2x4+x3-14x2+5x+6 |
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Answer» K=-3 Please answer my question |
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| 27992. |
If sec theta =x+1÷4x then tan theta +sec theta=2x or 1÷2x |
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| 27993. |
All done for maths exam on 7 march |
| Answer» | |
| 27994. |
Find the centre of a circle passing through the points (6,-6) (3,-7) and(3,3) |
| Answer» Let the given points are\xa0A(6,-6), B(3,-7), C(3,3)And P(x,y)\xa0be the centre of the circle. So, AP = BP = CP (radii\xa0of the circle)Taking AP = BP and\xa0Squaring both sides, we get,{tex}\\Rightarrow A P ^ { 2 } = B P ^ { 2 }{/tex}{tex}\\Rightarrow ( x - 6 ) ^ { 2 } + ( y + 6 ) ^ { 2 } = ( x - 3 ) ^ { 2 } + ( y + 7 ) ^ { 2 }{/tex}(by using distance formula){tex}\\Rightarrow x ^ { 2 } - 12 x + 36 + y ^ { 2 } + 12 y + 36{/tex}\xa0={tex}x ^ { 2 } - 6 x + 9 + y ^ { 2 } + 14 y + 49{/tex}{tex}\\Rightarrow - 12 x + 6 x + 12 y - 14 y + 72 - 58 = 0{/tex}{tex}\\Rightarrow - 6 x - 2 y + 14 = 0{/tex}{tex}\\Rightarrow 3 x + y - 7 = 0{/tex}\xa0……….(i)Again, taking BP = CP and squaring both sides, we get,{tex}\\Rightarrow B P ^ { 2 } = C P ^ { 2 }{/tex}{tex}\\Rightarrow ( x - 3 ) ^ { 2 } + ( y + 7 ) ^ { 2 } = ( x - 3 ) ^ { 2 } + ( y - 3 ) ^ { 2 }{/tex}{tex}\\Rightarrow x ^ { 2 } - 6 x + 9 + y ^ { 2 } + 14 y + 49{/tex}\xa0={tex}x ^ { 2 } - 6 x + 9 + y ^ { 2 } - 6 y + 9{/tex}{tex}\\Rightarrow - 6 x + 6 x + 14 y + 6 y + 58 - 18 = 0{/tex}{tex}\\Rightarrow 20 y + 40 = 0{/tex}{tex}\\Rightarrow y = - 2{/tex}Putting the value of y\xa0in eq. (i),{tex}3x + y - 7 = 0{/tex}{tex}\\Rightarrow 3 x = 9{/tex}{tex}\\Rightarrow x = 3{/tex}Hence the coordinates of P i.e. centre of circle are (3,-2). | |
| 27995. |
Tik tok is the best app for us if agree then write yes and like |
| Answer» | |
| 27996. |
If the roots of the equation (b-c)x²+(c-a)x+(a-b)=0 are equal prove that 2b=a+c |
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Answer» Here; quadratic equation is in the form of ax sqaure +bx +c =0..then..a=(b-c),b=(c-a),c=(a-b) (b-c)+(a-b)b+b=a+c2b=a+c |
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| 27997. |
If the quadratic px2-2underroot5+15 =0 has two equal roots then find the value of p |
| Answer» Underroot 5x hai ki nahi | |
| 27998. |
Ex -9.1 Q.6 |
| Answer» | |
| 27999. |
Theorem 6.3 of class 10 chapter 6 |
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| 28000. |
Do we have to write the sample space of dice in probability or just favorable outcomes❓❓❓❓⁉⁉ |
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Answer» Both I think both... |
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