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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 28151. |
Prove that rooy 3 is a irrational |
| Answer» See ncert ex no.9 page 13 | |
| 28152. |
1/cos^2 thet( |
| Answer» Question to puta likho.....??? | |
| 28153. |
the probability the occuring tail whose a coin tose ties is |
| Answer» 1/2 | |
| 28154. |
Prove basiv proportionality theorem |
| Answer» Book bhi dekh liya kr bhai | |
| 28155. |
The length of the shadow of a man is equal to the height of man. What is the angle of elevation? |
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Answer» Angle of elevation will be 45 degree The angle of elevation is 45.Explanation:-Let height = base(shadow) = x Tan thita = P÷BTAN THITA = x ÷ xTan thita = 1 Tan thita = tan 45 (TAN 45 = 1)SO, thita = 45. 45° Angle of Elevation is 45° |
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| 28156. |
Write a quadratic polynomial where sum of zeroes and product of zeroes are respectively -4 and 6 |
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| 28157. |
If the roots of the equation (a-b)x²+(b-c)x+(c-a)=0 are equal,show the c,a and b are in AP |
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| 28158. |
Can a no. Can have 308 and 18 as its lcm nd hcf |
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Answer» Thanks✌ No because 308 is not divisible by 18 |
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| 28159. |
Find HCF of 726and 275 |
| Answer» 11 | |
| 28160. |
How to find 0s for a pol all 0s |
| Answer» Sry, yur question is nt clear ? | |
| 28161. |
Do the equation x+3y-1=3 and 2x+6y=6 represent a pair of coincident lines? Justify your answer |
| Answer» inconsistent | |
| 28162. |
What is the weightage of maths of 2019 |
| Answer» 80 marks? | |
| 28163. |
solve the equation 2(2×-1/×+3) -3(×+3/2×-1)=5 |
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Answer» kya mahnaat ki yrr likhne me????? 2(2x-1/x+3)-3(x+3/2x-1)=5or, {2(2x-1)²-3(x+3)²}/(x+3)(2x-1)=5or, {2(4x²-4x+1)-3(x²+6x+9)}/(2x²+6x-x-3)=5or, 8x²-8x+2-3x²-18x-27=5(2x²+5x-3)or, 5x²-26x-25=10x²+25x-15or, 5x²-10x²-26x-25x-25+15=0or, -5x²-51x-10=0or, 5x²+50x+x+10=0or, 5x(x+10)+1(x+10)=0or, (x+10)(5x+1)=0Either, x+10=0or, x=-10Or, 5x+1=0or, 5x=-1or, x=-1/5Therefore, x=10,-1/5 Ans. |
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| 28164. |
find the area of the quadrilateral abcd whose vertices are a(3 -1) b(9 -5) c(14 0) and d(9 19) |
| Answer» Join A and CNow, Area of quadrilateral ABCD = Area of\xa0{tex} \\Delta{/tex}ABC + Area of\xa0{tex}\\Delta{/tex}ACDArea of\xa0{tex} \\Delta A B C = \\frac { 1 } { 2 } | 3 ( - 5 - 0 ) + 9 ( 0 + 1 ) + 14 ( - 1 + 5 ) |{/tex}{tex}= \\frac { 1 } { 2 } | - 15 + 9 + 56 |{/tex}{tex}= \\frac { 1 } { 2 } \\times 50{/tex}= 25 sq. unitsArea of\xa0{tex}\\Delta ACD = \\frac{1}{2}|3(0 - 19) + 14(19 + 1) + 9( - 1 - 0)|{/tex}{tex}= \\frac { 1 } { 2 } | - 57 + 280 - 9 |{/tex}{tex}= \\frac { 1 } { 2 } \\times 214{/tex}= 107 sq. unitsArea of quad. ABCD = Area of\xa0{tex}\\Delta{/tex}ABC + Area of\xa0{tex}\\Delta{/tex}ACD= (25 + 107) sq. units=132 sq. units | |
| 28165. |
What is surface area of frustum of cone |
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Answer» Pie l (r1+r2)+pie( r1)square+pie (r2)square.....it\'s too difficult to write here...bt i hope u get it.... Pie*l(r1+r2) |
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| 28166. |
What is doon law |
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Answer» hmn? Bhai ye kaunse ch ka hai math mai toh khi ni hai |
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| 28167. |
Pls draw the figure and confirm.... |
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Answer» Which fig? Which fig |
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| 28168. |
What is value of cos30* |
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Answer» Root 3/2 Root 3/2 |
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| 28169. |
Solve the equation 2xsquare - root5x - 2 = 0 |
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Answer» Root5+root21 whole divided by 2? or root 5-root21 whole divided by 2 Put the quadratic formula |
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| 28170. |
I mean is it sufficient? |
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Answer» Preeti plz fotgive me but ye kux jyada hi krr ra hai Bak yaha se What |
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| 28171. |
Show that 5n can not end with the digit 2 for any natural number. |
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Answer» Agar, 3 marks ka aya hoga to or likhna hoga apko, piyush ji ne jo likha hai, ye main hai,baki ap likh dena Is ot sufficient?? To end with digit 2 ,5 should have 2 as it factor but factor of 5 are 5and1... So it will not end with 2..hence 5n cant end with 2 |
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| 28172. |
In ap 2,4,6. 7 find 15tem |
| Answer» An = a+(n-1)dAn =2+(15-1)2An=2+14×2=2+28=30 | |
| 28173. |
2xsquare -7x-3 solve this equation by completing Square method |
| Answer» We have 2x2 - 7x + 3 = 0{tex}\\implies2( x^2 - {7 \\over 2}x + {3\\over 2}) = 0{/tex}{tex}\\implies\u200b\u200b x^2 - {7 \\over 2}x + {49 \\over 16} = {-3 \\over 2} +{ 49 \\over 16}{/tex} (Adding 49/16 to both sides){tex}\\implies x^2 -2 \\times x \\times {7 \\over 4} + ({7 \\over 4})^2 = {-24 +49 \\over 16}{/tex}{tex}\\implies (x-{7\\over4})^2 = {25 \\over 16}{/tex}{tex}\\implies x-{7\\over 4}= \\pm \\sqrt({25 \\over 16}){/tex}{tex}\\implies x={7\\over 4} \\pm {5 \\over 4}{/tex}{tex}\\implies x={7\\over 4} + {5 \\over 4}\\, and \\,x={7\\over 4} - {5 \\over 4}{/tex}{tex}\\implies x=3\\, and \\,{1\\over 2}{/tex}{tex}\\therefore{/tex}the roots of the given equation are {tex}3{/tex} and {tex}1\\over 2{/tex}. | |
| 28174. |
Length of corresponding arc |
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| 28175. |
Can someone tell me angle bisector theorem?? ...........Plzzzz?? |
| Answer» Let ABC be a triangle where AD bisects angle A and is drwn to side BC(u must take a pen and paper along and make figure as written ,ull understand it better)Now,according to angle bisector theorm,AB/AC=BD/CD Here a proof holds by construction. Check it on net otherwise cannot give here. | |
| 28176. |
Prove that riot 2 is irrational |
| Answer» Firstly suppose √2 is rational Than √2=a\\ba ans b both are integers also hcf of a,b =1 Squarin both sides2=a2\\b22b2=a2a2is divisible by 2 Also, a is divisible by 2 Now a=2m Put it in firt eq.2b2=4m2b2=2m2b2is divisible by 2 Also, b is divisible by 2 So , hcf of a,b =2 So it is not rational It is irrational .. | |
| 28177. |
To verify the sum of n-natural numbers is n(n+1)/2 |
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Answer» |
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| 28178. |
Segment |
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Answer» Chord A segment is the portion of a cicle enclosed between a chorf |
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| 28179. |
Find the centre of a circle passing through the points (6,-6),(3,-7) & (3,3) |
| Answer» Ordinate =-2 aur uske baad dist. formula lagr ke abscissa find kar lena | |
| 28180. |
If the ratio of roots of equation lx²+nx+n=0 is p:q, prove that √p/q+ √q/p+ √n/l = 0 |
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| 28181. |
ABCD is a cyclic quadrilateral (Fig. 3.7 NCERT) . Find the angles of the cyclic quadrilateral. |
| Answer» In a cyclic quad we know that sum of opp angle=180So,3y-5+(-7x+5)=180,(eq..1)4y+20+(-4x)=180,(eq..2)Now from eq 1,3y-5-7x+5=180,3y-7x=180,From eq 2,4y-4x=160,X-y=40,Using any method we will get x=-15 and y=25, substitute the value and result will come | |
| 28182. |
2018-2019 Sample papers |
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| 28183. |
Peace out every one |
| Answer» | |
| 28184. |
CosA + cos2^A=1 then sin2^A +sin4^=1 proof |
Answer» \xa0Since cos A + cos2\xa0A=1\xa0Now,cosA= 1-cos2A=sin2AThen taking L.H.S. sin2A+sin4A=Sin2A(1+sin2A)=CosA(1+cosA)CosA+cos2A=1(given)L.H.S =1 Hence proved |
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| 28185. |
sec thetha + cosec thetha =nsin thetha + cos thetha=mthen prove that n(m square-1) = 2m |
| Answer» Question:\xa0Show that n (m2-1 ) = 2m , if sin theta + cos theta = m and sec theta + cosec theta = nAnswer: | |
| 28186. |
The product of the zeros of polynomail |
| Answer» | |
| 28187. |
How to find median in stastics in graf |
| Answer» In the stastics graf if it has only one slope than we fnd N/2 and mark the point on graf after that join the point to x-axis hence this will the median . In case of less than and more than ogive, the point of their intersection will be joind to x-axis that point on x-axis will be median | |
| 28188. |
Srry anushka jugran agli baar nhi.....pakka srry gakat family ho gyi |
| Answer» | |
| 28189. |
If 5th term of an AP is zero, show that it\'s 33rd term is four times its 12th term. |
| Answer» a5 =0 a + 4d =0a = -4da33 = 4(a12)a+ 32d = 4( a+11d)put the value of a-4d + 32d= 4(-4d+11d)28d= -16d + 44d28d = 28d H.P. | |
| 28190. |
What is the formula of The area of segment of a circle |
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Answer» Area of the corresponding sector-Area of the corresponding triangle For minor it is ar.of sector-ar.of triangleFor majorar.of circle-ar.of sector |
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| 28191. |
(a+b) 2 |
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Answer» (a+b) ka whole square nikalna hai toh ::(a+b)^2 = a^2+b^2+2ab hoga 2a+2b |
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| 28192. |
Where is blueprint of mathematics |
| Answer» Go for any refer book like U-like or u can take help of sample paper of cbse | |
| 28193. |
Is there anyway to logout from this app if it is there then plz tell |
| Answer» Ok | |
| 28194. |
1+secQ-TanQ/1+secQ+tanQ |
| Answer» | |
| 28195. |
Prove that : sinA- 2sin^A / 2cos ^ A - cos A = tan A |
| Answer» LHS =\xa0{tex}\\frac{\\sin A-2 \\sin ^{3} A}{2 \\cos ^{3} A-\\cos A}{/tex}=\xa0{tex}\\frac{\\sin A\\left(1-2 \\sin ^{2} A\\right)}{\\cos A\\left(2 \\cos ^{2} A-1\\right)}{/tex}=\xa0{tex}\\frac{\\sin A\\left(1-2\\left(1-\\cos ^{2} A\\right)\\right)}{\\cos A\\left(2 \\cos ^{2} A-1\\right)}{/tex}\xa0[{tex}\\because sin^2\\theta=1-cos^2\\theta{/tex}]=\xa0{tex}\\frac{\\sin A\\left(1-2+2cos ^{2} A\\right)}{\\cos A\\left(2 \\cos ^{2} A-1\\right)}{/tex}=\xa0{tex}\\tan A \\frac{\\left(2 \\cos ^{2} A-1\\right)}{\\left(2 \\cos ^{2} A-1\\right)}{/tex}= tan A = RHSHence proved. | |
| 28196. |
हमारे जवान सिर्फ 2km तक अंदर गए और दहशत 200 km तक अंदर गयी ….…..jai hind …. |
| Answer» Jai hind?????? | |
| 28197. |
0.68 (bar on 68)+0.73 (bar on 73) |
| Answer» | |
| 28198. |
CM and RN are respectively the median of ∆ABC and∆PQR . If ∆ABC~∆PQR ,prove that i) ∆AMC~∆PNR |
| Answer» As CM amd RN are medians ,so 2MA=AB AND 2PN=PQ. Now ,as ?️ABC〰️?️PQR then angleA = angleP and AB/PQ=AC/PR ,➡️2MA/2PN=AC/PR ➡️MA/PN= AC/PR , SO BY SAS Criteria of Similarity, ?️AMC〰️?️PNR....... HENCE PROVED ???? | |
| 28199. |
prove that (sinA/1-cosA - 1- cosA / sinA) × (cosA/1-sinA - 1- sinA/cosA) =4? |
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| 28200. |
(sinA/1-cosA - 1- cosA / sinA) × (cosA/1-sinA - 1- sinA/cosA) =4? |
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