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28201.

sec theta +tan theta =p

Answer»
28202.

Which sample paper is best for 10 only 11th student please

Answer» Haa funny
Geeta or bible any one will be best
28203.

Cot\'4A-1=COSEC\'4A-2cosec2A

Answer» cosec^4A - 2cosec^2A =cosec^2A( cosec^2A - 2 ) =cosec^2A( cosec^2A - 1 - 1 ). =cosec^2A( cot^2A - 1 ) =( cot^2A + 1 )( cot^2A - 1)=cot^4A - 1
28204.

How to find the roots of the quadratic equation bby factorisation

Answer» By splitting their mid term!!
28205.

A student prepares a poster on "save water" on a circular sheet

Answer» Ha fir
28206.

What is linear equations mean

Answer» Equation having a straight line graph is called linear equation.
28207.

If perimeter of circle and area of circle are equal then find the radius.

Answer» Perimeter of circle= area of circle2πr=πr×r2=r
2. Units
28208.

Pak ka aek f 16 tod dia hamare desh nae .. PROUD TO BE INDIAN

Answer» Jai hind.....
Jai hind..... ????????
Jai hind
Ji hind ...????
28209.

Find the 10th term of the AP :2,7,12....

Answer» 47
47
28210.

Explain me ex 13.3 question no 8

Answer»
Take the canal as a cuboid of dimensions:6,1.5 and convert 10km/hr into meter/minute we will get=1500.. NOW ACCORDING TO QUESTION 8cm STANDING WATER IS REQ. SO=1500*30*100/8(WATER FLOW FOR 30 MINUTE SO *30 AND 1M=100CM) SO WE WILL GET REWURE ANSWER THAT IS 525000m^2
28211.

What is zero?

Answer» Zero of any polynomial f(x) is the value of x for which f(x)=0e.g. for f(x)=x2-3x+2x=1 and 2 are zerothen f(1)=0 and f(2)=0
Zero is the only no. which has no sign ,neither +ve nor -ve
Zero is the middle most no. of all integers.
Friend zero ke chakkar mein na pado apni study karo
Zero is 0
28212.

Exam pad is allow to carry in examination hall??????

Answer» Yes but transparent one.
Nope
Yes
Na
28213.

NCERT 6.1 question number 5

Answer» There is only up to Q no 3. ....
28214.

In the adjoining figure angle B equal to 90 theta, angle BAC equal to theta

Answer»
28215.

X-y=3

Answer» What is the que
28216.

1/x+4- 1/x-5= 1/30 find the root

Answer» x=-10,1....
28217.

(CosΦ+secΦ)²+(sinΦ+cosecΦ)²=7+tan²Φ+cot²Φ

Answer» It is in ncert so easy
Dono ko pahle a+b ke square par thod do answer aa jayega
28218.

Ex. 13.1 que. 5

Answer» 1/4l^2(π-24) it can be found by adding TSA of cube and hemisphere
28219.

If sec + tan = p then find the value of cosec

Answer» Cosec (1+p^2) (1-p^2)
28220.

Consttruct a more than comulative frequency distribution table ci 50-60 60-70

Answer» Aur hoga ti sirf ye banega, more than 50 ,more than 60 and so on..
How to construct here......???
28221.

Important topics as per latest cbse syllabus

Answer»
28222.

Prove that the length of two tangents drawn from an external point to a circle are equal

Answer» Given = QP and PR are the external tangentProve = QP = PRConstruction = joint OP , OR &OQproof = ?POQ & ?OPR OQ =OR (radii) OP =OP (common) angle Q = angle R (90) ?POQ congruant ?OPR (R.H.S) PQ = OR (C.P.C.T ) THEOREM 10.2 (very IMP)
It\'s theorem 10.2 in ncert
28223.

how many terms of Ap 9,17,25 must be taken to give a sum of 636?

Answer» n=12
4n square +5n-636Split this
28224.

(A+b+c) ×2

Answer» 2a + 2b + 2c
28225.

Solv for x :1/x+1 +2/x+2=4/x+4

Answer» 2(1-√3) and 2(1+√3)
First take Lcm then cross multiply them u will get the answer
Put X=-1,-2,-4
28226.

For what value of p are 2p+1, 13 and 5p-3 three consecutive term of an Ap

Answer» to find consecutive term of an Ap we have a formula (A+C)=2Bhere we have a=(2p+1) b=13 c=(5p-3)by applying this in the formula.a+c=2b2p+1+5p-3=2×137p-2=267p=28p=28/7 p=4 .. thetefore value of p is 4
Terms-2p+1,13,5p-313-2p-1=5p-3-1312-2p=5p-1612+16=5p+2p28=7pp=4 Ans
28227.

Which term of an Ap 21,18,15..........…..............is 0

Answer» 21,18,15,............,na=21d=18-21 =-3an=0an=a+(n-1)d0=21+(n-1)-3-21=(n-1)-37=n-1n=88th term of an Appointment is 0 .Ans
An=0 apply the formula of an. a+(n-1)d =0. 21+(n-1) (--3) = 0. 21-3n +3 =0 . 24-3n =0 -3n =-24 . n= 8. So the 8th term of the ap will be 0.
28228.

What are the possible values of remainder r when a positive integer a is divided by 3

Answer» Possible values r will be 0, 1,2
Possible values of r is 0,1,2. Ans
28229.

(1+ Cos A + tan A)(sin A-cos A )=

Answer»
28230.

The factorisation of 3x²-15x+28

Answer» L.C.M. of 3×28=74;3 742 282 14 7Therefore, 3x^2-15x+28 =>3x^2-12x-7x+28 =>3x(x-4)-7(x-4) =>(x-4)(3x-7)Then, (x-4)=0 and (3x-7)=0Theefore, x=4 and x=7/3Now,4 and 7/3 are the roots of the given equation 3x^2-15x+28
If we find discriminant it will be( -111) which means that it does not have real roots
No real roots
28231.

Saloni ji Oswal me dekho mil jayega nai to teachers se puchna

Answer» And Oswal nahi h mere pas...
28232.

sorry 1 ki jagah PE 10 lika Gaya mind mat karna Anushka ji

Answer»
28233.

Anushka ek question hai batao cosA=2/5 find 4plustanA value only for Anushka

Answer» Question sahi to hai na... Khair iska answer to 11/5 aa rha hai shayad
28234.

If mtth term of a.p. is 1/n and nth therm finf sm of mn ted

Answer»
28235.

padlo 7 Ko paper hai

Answer» Marathi ka paper
5 ko hai bhai
28236.

CotA+cosecA -1/cotA -cosecA +1=1+cosA / sinA

Answer» First convert cotA + cosecA -1/cotA-cosecA+1 in sinA, cosA and 1 Then rationalise it u will get the answer
28237.

If the (1,5),(p,1),and (4,11)and power. Find the value of P

Answer»
28238.

cos A — sinA + 1 ÷ cosA + sinA — 1 = cosecA + cotA. Prove using cosec square A = 1+cot square A

Answer» =[CosA—SinA +1/CosA+Sin—1]×[CosA +SinA +1/CosA +SinA +1]=[Cos²A+CosA.SinA+CosA—CosA.SinA—Sin²A—SinA+CosA+SinA+1]/(CosA+SinA)²—(1)²=[Cos²A+2CosA+1—Sin²A]/[Cos²A+Sin²A+2SinACosA—1]----[:CosA.SinA—CosA.SinA=0, SinA—SinA=0]----=[2Cos²A+2CosA]/[1—1+2SinA.CosA]----[:1—Sin²A=Cos²A and Cos²A+Sin²A=1]=[2CosA(CosA+1)/[2SinA.CosA]=CosA+1/SinA--------[2CosA/2CosA=1]=CosA/SinA+1/SinA=CotA+CosecA, Hence Prooved
It\'s N.C.E.R.T ques
28239.

1+sin^2A = 3sinAcosA then prove that tanA=1 or 1/2

Answer»
28240.

Which term of A.P. 92, 88, 84, 80 ................. is 0 ?

Answer»
28241.

Triangle ex 6.5 15 and 16 question

Answer»
28242.

Find the quadaratic poly. whose zerros are (5+2√3)&(5-2√3)

Answer» How
X^2_ 10x+13
28243.

Find the distances of a point P(x,y) from the origin

Answer» Thanks
√x*2+y*2.. Think so
28244.

The mean of 6,6+2x,5 and 8+3x is 20.find the value of x

Answer» Bhai formula nhi pata kya Mean = Sum of all obs / Total No of obs.
Puja ji pura solve karo
x=11
28245.

1/(cosec x+cot x)-1/sin x=1/sin x-1/(cosec x-cot x)

Answer»
28246.

1+Cos a°+sin a° \\ 1 + cos a° -sin a°

Answer» Answer is 1. We can do this using identity
28247.

Find the zeroes of the following polynomial 5√5x*x+30x+8√5

Answer» -2root5÷5......n....-4÷root5........actually i cn use the proper sym for root so i \'d spell it....hope it will help uhhhhh....
28248.

Find the root of 4x^2+3x+5 =0 by the method of completing the square.

Answer» Bro competing square is easy but my way of doing is little bit diff.
Is answr=3+-√11/4
28249.

The 4 th term of an AP is 0.prove that the 25th term of an AP is 3 times its 11th term.

Answer» a+3d=0 (eq..1) given, a=-3d.(eq 2)Now ,A+24d=3(a+10d) to prove.. Substitute value of a, -3d+24d=-9d+30 , 21d=21d .. Therefore proved.. NOT SURE SO PLEASE ANY TEACHER CHECK MY WAY.
Anusree r u a malayali
it has been given that a4=0 => a+3d=0 => a= -3d ------- (1)a11= a+10d = -3d+10d = 7d [ from (1)]a25 = a+24d = -3d+24d = 21d [ from (1)]therefore, comparing 7d and 21d we get, 21d = 3 ( 7d ) i.e. a25 = 3(a11) Hence, proved.Hope it helps.
28250.

X^ 2 +2x + k is a factor of 2x^4+ x- 14x^2 5x 6

Answer» Your question is not clear ....Please write it clearly....??