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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 28251. |
Important theorem class9 for exam |
| Answer» Y 10th h mr.harpreetsingh....?? | |
| 28252. |
a/p(q-r)+b/q(r-p)+c/r(p-q) |
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| 28253. |
If sinA+2cosA=√3Then find the value of 4tan^2A+cot^2A |
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| 28254. |
How can we do mid term splitting of 5xsquare+7x+1 |
| Answer» We have to use in this formula method . Their is no use of mid term splitting in this equation | |
| 28255. |
Is the answer of sec a+tan a=p ; the value of cosec a can be 1+p Square /1-p Square |
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Answer» How you send image How to send image ???? |
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| 28256. |
3by2 of right angle |
| Answer» 135 | |
| 28257. |
a³+ab²÷a²+b² |
| Answer» a(a^2+b^2)/(a^2+b^2)=a | |
| 28258. |
Find the volume of largest right circular cone that can be cut out from a cube edge 4.2 cm. |
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Answer» 19.40 cm^3 Radius of cone =2.1 cm Height of cone = 4.2 cm Volume of cone = πr²h =π*2.1*2.1*4.2 = 58.188 cm³ |
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| 28259. |
If BC=1/3 BC,prove 9 (AD×AD)=7 (AB×AB) |
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Answer» Yaa it is ncert que u should see in book Ncert ka question h toh dekh lo? |
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| 28260. |
Draw a tangent to a circle of radius 6 cm from a point P at a distance of 10 cm from its centre |
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Answer» Answer is 6 8cm |
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| 28261. |
I should prefer ncrt or other reference book for examination.. |
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Answer» NCERT ko ekdum bdiya tarike se kar loo ?kafi hai☺️ Firstly ncert then some other sample papers |
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| 28262. |
Ch.9 related question |
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Answer» Please give me a answer Example 6 Konsa questions chahiye No |
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| 28263. |
041 questions paper |
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| 28264. |
Find the value of k for which one root of the quadritic equation kx2-14x+8=0 is 2 |
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Answer» Sorry it\'s k = 5 as ........28 - 8 = 20 nd.....,,,, 4k - 20=0 ......so,,,,,, k= 20/4=5 hence the value of k =5 x =2 so ,,,,_______ k(2^2) - 14^2 + 8 = 4k - 36=0 ,,,,,,,, 4k =36 = k =36/4 = 9 ...........so the value of k = 9 K=5 |
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| 28265. |
If nth term of A.P. is (2n+1), what is the sum of its first three terms ? |
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Answer» Lakin mera ta 15 aya hai Nth term =2n+1Now put n=1 2*1+1=3 ..............1Now put n=2 2*2+1=5 ..............2From 1 and 2 we have a=3D=5-3=2Using formula Sn=n/2(2a+(n-1)d) Sn=3/2(2×2+(3-1)*2) Sn=3/2(4+4) Sn=3/2*8 Sn=3*4 Sn =12 The required Sn is 12 15 |
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| 28266. |
Plz send me.imp. question for board point of view |
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Answer» Important question are:-Prove irrational..HCF is given and find LCM.. Relationship between zeroes..Solve word equestion...Find nth term and all ...Find variable in coordinate geometry.. Trignometrys small questions..Triangle construction...Prbability..Convert to less and more than ogive.. You tube me h Aap video download karo bhaskar sir ka. May be wo aa jaye Kyuki Jo bhi btaye question h wo sab important hai 7 ko to board h to abhi oswal le kar kya karega Bhai oswal le le |
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| 28267. |
If 4x=secA and 4/x =tanA find the value of 8(x2 _1/x2 |
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| 28268. |
Find the area of circle inscribed in a square of side a cm |
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| 28269. |
2235 |
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| 28270. |
If sin theta = cos theta , find the value of theta |
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Answer» 45 coz both are 1/root 2.. 45 degree Ans=45 degree |
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| 28271. |
show that the square of Any positive integers cannot be of form 5q +2 or 5q +3 |
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Answer» No it is the correct question 5q+2 is even and 5q+3 is odd your question is wrong |
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| 28272. |
Solved theoram 10.8 |
| Answer» there are only 2 theorems in the chapter 10 | |
| 28273. |
Theoram 10.8. Solved |
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| 28274. |
tanA+tanB+tanC= tanA tanB tanC |
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Answer» Prove that tanA+tanB+tanC= tanAtanBtanC Pura question likho...... |
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| 28275. |
how many ratrional number lie between root 2 and root 3 |
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Answer» root2 = 1.414 and root3 = 1.732 no. lie between them is 1.432 ,1.576 , 1.657 , 1.711, etc........ Infinite 1.5 |
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| 28276. |
The length of the shadow of a man is equal to the height of man . The angle of elevation is |
| Answer» Tan 45 is equal to 1 | |
| 28277. |
The sum of the first n term of an AP is 3n^2+6n. Find the n^th term of this AP |
| Answer» 6n+3 | |
| 28278. |
state whether 7×11×13+7is a composite no or a prime no |
| Answer» 7(1*11*13+1)=7*144 therefore clearly it has more than two factor so it is composite number | |
| 28279. |
Guys centroid kya hota hai |
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Answer» Refer Google... I don\'t know how to post pic here its something related to triangles Give me diagram Point at which all three medians of triangle intersect. |
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| 28280. |
When there is 2/3 triangle draw inside or outside |
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Answer» Inside..... Inside |
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| 28281. |
Write down the factorisation of 720 |
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Answer» Sry... its 2×2×2×2×3×3×5 2*2*2*2*3*3*3*5...... |
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| 28282. |
Give an example for the polynomials degree of p(x) =degree of q(x) |
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| 28283. |
1÷(a+b+x)=1÷a+1÷b+1÷x find the value of x |
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Answer» X=-a or -b x = - a and x= -b |
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| 28284. |
Prove that root 7 is an irrational number by contradiction method |
| Answer» What is contradiction method?? | |
| 28285. |
If sinΦ+cosΦ=p and secΦ+cosecΦ=q,then prove that q(p×p -1)=2p |
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Answer» (sin¢ + cos¢ )^2 = p^2SinA ^2+ cos A^2+2. sinA.cosA=p^21+2.sinA.cosA=p^22.sinAcosA= p2-1sinAcosA=p^2-1/2We write secA+ cosecA = q1/cosA+1/sinA=qsinA+cosA/sinA.cosA= qp/p2-1/2=q2p=q(p^2-1) Haa sahi h Question shi hna kuch mistake to nhi h na |
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| 28286. |
What is the next term of the A.P. √8,√18,√32..... ..? |
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Answer» 5√2 or √50 5√2 5✓2 5√2 |
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| 28287. |
Koi meko oswaal sample paper maths ka sample paper 1 ka Q27 dikhao mera misprint g |
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Answer» Agr tm meko de skte ho question to de Nhii mil ra bhai Nawab google se dekh le |
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| 28288. |
Express 2717 as a product of its prime factors |
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Answer» 11*13*19 11*13*19 Prime factors of 2717 is 11 × 13 × 19 . |
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| 28289. |
Screenshot from https://www.google.com/search?q=best+group+of+friends+board+exam+quotes&tbm=isch |
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Answer» Pagal tune naam change kr liya or mai paagL ki tarah tere ko dhund rhi itni der se Yaha Aaja jasleen Mahatma Gandhi OK ji....????????? ??????? |
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| 28290. |
In triangle ABC, angleC=3 ,angle B=2 (angle A+ angle B).find the three angles |
| Answer» Your question is wrong | |
| 28291. |
If sec 5A =cosec (A+36), where 5 A is an acute angle find the value of a??? ???? Solve fast |
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Answer» Tnxxx Ans is 9 Ans. 9 9 Sec 5A= cosec(A+36)Cosec(90-5A)=cosec(A+36) (secA=cosec(90-A)) 90-5A=A+3690-36=6A54=6AA=9 ans |
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| 28292. |
Bromopentane ka structure |
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Answer» CH3-CH2-CH2-CH2-CH2-Br Don\'t know how to post a pic here....... I don\'t know how to post pic here How can I draw here.... |
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| 28293. |
Which is important chapter |
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Answer» For passing marks...Ch- 1,2,3,4,5,7,11,15 Sbhi chapters imp hain All g |
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| 28294. |
Guys anyone is online??? |
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Answer» Ha,explain alkyle group. Any doubt?? Ya, hii shyam |
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| 28295. |
Is there anyone fromASSUMPTION PUBLIC SCHOOL, SIDHUAPAR, BARAHALGANJ ,GORAKHPUR |
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Answer» Rohit Tum kisi ko jante ho jo ASSUMPTION me pdta ho No but i m in gorakhpur No idea |
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| 28296. |
44p0 |
| Answer» ????? | |
| 28297. |
What is the sum of zeros |
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Answer» α+β=-b/a Sum of zeroes = -b/a Alpha + beta = -b/a |
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| 28298. |
α and 1/α are zeroes of 4x square-2x+k+7 find the value of k |
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Answer» Pura solution bta do K= -3 -3 k = -3 |
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| 28299. |
Sin thita value |
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Answer» For which angle For any angle The value of sin thita has between 1 and 0 Sin0°=0Sin30°=1/2Sin45°=1/√2Sin60=√3/2Sin90=1 but for which angle |
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| 28300. |
Without using trigonometric tables,prove that tan48°tan23°tan42°tan67°=1 |
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Answer» Are, dekho... tan(90-thita) = cot thita.... so agar tan 48 hai use tan(90-42) likha.... or use, cot 42° samjhe..... ab cot 42 × tan 42 = 1/tan42×tan42=1..... samjhe Puja ni smj aaya yar tan 48° tan 23° tan 42° tan 67° = tan (90° - 42°) tan (90° - 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°) = 1×1 = 1...............proved Tan48° Tan23° Tan(90-48) Tan(90-23).Tan48 Tan23 Cot48 Cot23. 1 |
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