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28301.

PQ is a tangent at a point C toa circle with center O. AB is a diameter and CAB=30° find PCA

Answer» PCA=60°
I think 60° answer hai?
PCA= 60°
28302.

Root 3 is irranional

Answer» Pooja r u mad
NCERT book ka examples me dekho yrr
In THE maths book answer is their
Book bhi khola kro...plzzz, answer bahut bada hai, kaise type krun.... hope yu can understand ?
28303.

Find the area of triangle ABC with A1,-4 and the mid point of side through A being 2,-1 and 0,-1

Answer» 12 sq. units
28304.

(7,2),(5,1),(3,k) points are Collinear. Find the value of k

Answer» A(7,-2), B(5,1), C(3,2K)Δ = 1/2[(x₁y₂+x₂y₃+x₃y₁)-(x₂y₁+x₃y₂+x₁y₃)Δ = 1/2[(7+10K-6)-(-10+3+14K)] = 1/2[1+10K+7-14K] = 1/2[8-4K] = 4-2KGIVEN THE POINTS ARE COLLINEARΔ = 04-2K = 02K = 4K = 2
Area of ∆ABC=01/2{x1(y2-y3)+x2(y3-y2)+x3(y1-y2)=01/2{7(1-k)+5(k-2)+3(2-1)=07-7k+5k-10+3=02k=0k=0
Put area of triangle as 0...then write the formula for area of triangle =0 put all the values of x1, x2, x3, y1, y2, y3.....then yu will get d answer
28305.

Derive frustum formula

Answer» Let V be the volume of the frustum of cone. Then,V = Volume of cone V AB– Volume of cone VA ‘B’Thus, the volume of the frustum of the cone is given by\xa0
Cbse never ask derivation only question of it
What?
28306.

Abcd is parallelogram find x OA = 2x-y OB= 16 OC= 6 OD= 3x-5y

Answer» x= 13/14
28307.

If secA+tanA=pFind the value of cosecA

Answer» Please saw me how you solved this question
Ohh...sry by mistake... square lagana rh gaya..sachin ji ap Eeya ji k answer ko refer kr lena mene to galat type kar dia...??
1+p/1-p
cosecA= p^2+1/p^2-1,-1
28308.

Pooja ji tum online ho abhi

Answer» Nhi hun.....
28309.

in ∆abc, ab=3, bc=4, ac=5, then the radius of the circle touching all the three sides is ?

Answer»
28310.

Tan 48 tan 23 tan 42 tan 67

Answer» Tan 48 tan 42 tan23 tan67. = Tan(90-42) tan42 tan23 tan(90-23) = Cot42 tan 42 tan23 cot 23 = 1
28311.

Total surface area of hemisphere

Answer» Hi sneha jii.
3πr²
3 pi r2
28312.

Hcf of 28

Answer» 28 itself
7
28313.

If sin tetha =x and sec theta=y tehn find the value of cot thetha

Answer» So Cot Q= sinQ/cosQSo cotQ=1/xy
SinQ=x and secQ=y
28314.

If d=4 and a7=4 find first term of an A.P

Answer» A= -20
A=-20
a= - 20...
a = -20
28315.

If a tangent drawn from external point are equal

Answer» Yes
28316.

Define lemna

Answer» A lemma is a proven statement used for proving another statement.
Lemma is a proven statement which is used to prove another statement
Not lemna,it\'s lemma
28317.

Theoram triangle 10 class cbse

Answer» Page number 124 of our NCERT textbook.?
NCERT dekho
28318.

In ΔABC, right angle triangle at A, tanC=√3Find the value of sin B. cosC + cosB. sinC

Answer» sinB.cosC+cosB.sinCAC/BC×AC/BC+AB/BC×AB/BC=1/2×1/2+√3/2×√3/2=1/4+3/4=4/4=1
1
1
1+ root3
28319.

Use Euclid\'s algorithm to find HCF of 1651 n 2032 express the HCF in the form 1651m+2030n

Answer» It\'s difficult to type here sorry..... U can refer Google
Pl show method
H. C. F=127....m=5 and n=-4
28320.

difference between tan p and tan r

Answer» Figure bhi hoga
28321.

What is the formula for area of sector and segment

Answer» Formula of segment.....??
Pie r^2theta/360-[1/2r^2sinTheta]
I think it will help you a lot
Area of Segment = θ − sin(θ)2 × r2 (when θ is in radians)Area of Segment = ( θ × π360 − sin(θ)2 ) × r2
Area of Sector = θ × π360 × r2 (when θ is in degrees)
28322.

Maths NCERT of class 7 of chapter perimeter and area

Answer» Jao
Class 7 mai jau
Class 7.... nhi ye class 10 hai???
28323.

If x=y^z , y=z^x , z=x^y then find xyz

Answer» {tex}\\begin{array}{l}\\mathrm x=\\mathrm y^{\\mathrm z},\\mathrm y=\\mathrm z^{\\mathrm x},\\mathrm z=\\mathrm x^{\\mathrm y}\\\\\\mathrm{xyz}=\\mathrm x^{\\mathrm y}\\mathrm y^{\\mathrm z}\\mathrm z^{\\mathrm x}\\\\\\mathrm{xyz}=\\mathrm{xyz}(\\mathrm x^{\\mathrm y-1}\\mathrm y^{\\mathrm z-1}\\mathrm z^{\\mathrm x-1})\\\\\\mathrm{or}\\;\\mathrm x^{\\mathrm y-1}\\mathrm y^{\\mathrm z-1}\\mathrm z^{\\mathrm x-1}=1\\\\\\frac{\\mathrm x^{\\mathrm y}\\mathrm y^{\\mathrm z}\\mathrm z^{\\mathrm x}}{\\mathrm{xyz}}=1\\\\\\mathrm{So}\\;\\;\\mathrm{xyz}=\\mathrm x^{\\mathrm y}\\mathrm y^{\\mathrm z}\\mathrm z^{\\mathrm x}\\end{array}{/tex}
Kya
Tujya i chi bhook
28324.

ptove that (sin4+cos4)/1-2sin2×cos2 = 1

Answer» Prove to ho gya, bt apko bataun kaise
28325.

In an AP,if the common difference=2 and sixth term a6 is 20,then find the first term

Answer» a=10
28326.

If the point P(x,y) is equidistant from the pointsA(5,1) and B(-1,5) .then prove that 3x=2y

Answer» Apply distance formula ,(AP)^2=(BP)^2ND get ur ans.....
28327.

Solve x2+4x-5=0 by completing the square method.

Answer» Are you Anushka Sharma from dichoan
x2+4x−5=0,x2+4x+4−9=0,(x+2)²=9,(X+2)=(3)²X+2=3X=3-2X=1
28328.

Hy iss bar ka maths ka paper mostly NCERT m si hoga kya...-?

Answer» Up board walo ka ncert se kam question aya the
Yes 70% chance
Hha sayad .!!
28329.

Prove that length of tangents from an external point are equal

Answer» Pg no. 211
Ncert m h yai
U can read from 10.2
28330.

(SinA-secA)^2+(cosA-cosecA)^2=(1-secA.cosecA)^2

Answer» I know yr........Isliye pucha
It is complicated
28331.

For what value of k, x=a is a solution of equation x²-(a+b)x+k=0 ?

Answer» The value of K is AB ...
How please tell me
K = ab
K=ab
28332.

How can we save iron from ruting write 5ways?

Answer» (¡) Oiling...(¡¡) Painting...(¡¡¡) Galvanisation...(¡v) Zinc coating...(v) Greasing...
Sry, apne 5 pucha tha.. maine glti se 6 bta diya, ap isme se 5 choose kr lijiyega....???
* oiling, *electroplating, *painting, *galvanisation, *greasing, *chrome plating.....
1. By painting.......2. by preventing it from moisture......3. by galvanisation.....4. Anodising......5. oil coating...
Give me ans pls...
28333.

If the first two terms of an ap is -3 and 4 find its 21 terns

Answer» an = a + ( n - 1)d = -3 +( 21 -1) 7 = -3 +140 = 137
28334.

Sec =13/5,show that 2sin-3cos/4sin+9cos

Answer»
28335.

10.1 theorm full

Answer» 10.2 exam m hamesha aata cbse board m
The tangent from any point of a circle is perpendicular to the radius through the point of contact.
28336.

alfa

Answer» ã
28337.

495÷7Plz urgent Explain it in detail plzzz

Answer» 71
Sorry ;;;. ....the answer is 70.7142857
71
28338.

Prove that the points (3,0), (6,4), (-1,3) are the vertices of a right angled isosceles triangle.

Answer» Apply distance formula and find the measure of all sides and then use pyth. theorem for proofing it.
28339.

Solve value of x :√(2x+9) +x-13=0

Answer» By quadratic formula solve it
Shift x-13 to rhs and square the rhs
28340.

ncert exercise 4.3 ka 6 question

Answer»
28341.

How we will devide 220/3.4

Answer» 2200÷34 it is very easy question ?
220/3.4=2200/34=64.70588
2200/34
2200/34
64.7
28342.

Prove that cos u\\1+sin u =1-sin u\\cos u

Answer» Hope it will help u???
By cross multiplication.....-------> cosU × cosU = (1-sinU)(1+sinU)....-------> cos^2U = 1-sin^2U....-----> cos^2U = cos^2U.......proved
28343.

If 1, 2, 4, 1, x, 6 and 3, 5 are the vertices of a parallelogram taken in order find X and Y

Answer» Same here question clearly likho bhn
Apply the formula (x1+x3)-x2=x4
Yur question is nt clear
Isme Y Kahan hai aur vertices kuch samajh me nhi aa rha??????
28344.

Prove that parallelogram circumscribing a circle is a rhombus

Answer» Given ABCD is a ||gm\xa0such that its sides touch a circle with centre O.∴ AB = CD and AB || CD,AD = BC and AD || BCNow, P, Q, R and S are the touching point of both the circle and the ||gmWe know that, tangents to a circle from an exterior point are equal in length.∴ AP = AS [Tangents from point A] ... (1)\xa0BP = BQ [Tangents from point B]\xa0... (2)\xa0CR = CQ [Tangents from point C]\xa0... (3)\xa0DR = DS [Tangents from point D]\xa0... (4)On adding (1), (2), (3) and (4), we getAP + BP + CR + DR = AS + BQ + CQ + DS⇒ (AP + BP) + (CR + DR) = (AS + DS) + (BQ + CQ)⇒ AB + CD = AD + BC⇒ AB + AB = BC + BC [∵ ABCD is a ||gm .\xa0∴ AB = CD and AD = BC]⇒ 2AB = 2BC⇒ AB = BCTherefore, AB = BC impliesAB = BC = CD = ADHence, ABCD is a rhombus.\xa0In rhombus, it is not necessary that diagonals are equal. If they are equal, then rhombus is considered as a square whose diagonals are always equal. So, there isn\'t any use of proving that the diagonals of a rhombus are equal.
28345.

Find the value of k if points A(2,3),B(4,k),C(6,-3) are collinear

Answer» When points are collinear area of triangle is 0 Then put values inX1(y2-y3) +x2(y3-y1) +x3(y1-y2),Aur solve kar lo
Bhai isme triangle ka formula = 0 rakh de
ar(ABC) = 0So, k = 0
28346.

what formulas can help me to clear algebra part??

Answer» (a+b)^2=a^2+2ab+b^2
28347.

Theorm from circle will definate come

Answer» Thm 8
Circle or from triangles definitely ?%
Ya bt only 1 and 2
28348.

In an equilateral triangle ABC ,AD perpendicular to BC .prove that 3BC2=4AD2

Answer» Thank you both
AB=BC=AC , BD=DC=BC/2,. AB ^2=BD^2+AD^2 bus issi mein AB ke jagah BC aur BD ke jagah BC/2 put kar do aur value nikal lo
Solution kaisr bhejun........
Please answer fast
28349.

Given that √2 is irrational, prove that (5+3√2) is an irrational

Answer» Let 5+3√2 is rational number say p/q where q is not equal to zero and p and q is coprime.5+3√2=p/q3√2=p/q-53√2=p-5q/q√2=p-5q/3q√2is irrational and p-5q/3q is rational.Therefore our supposition is wrong. 5+3√2 is irrational
Let assume √2 as a rational no. It can be wriien as a/b where a,b both r integers so a/b=5+3√2 .now a/b -5=3√2,now a-5b/b= 3√2and a-5b/3b =√2 bt it can\'t happen bcz a,b both r integers so r.h.s not equals to l.h.s so assumption is wrong and hence it is proved that 5+3√2 is an irrational no.
28350.

If Cos (q+r)=0, then find sin(q-r)

Answer»