InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2801. |
M afisha u r boy |
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| 2802. |
8826277849 yeh lo aditi sharma my whatspp no. |
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| 2803. |
Real aditi sharma message me on whatspp |
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| 2804. |
RIMSHA plzz come yrr.... |
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| 2805. |
Aditi sharma whatspp pe aao |
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| 2806. |
RIMSHA plzz yrr |
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| 2807. |
If SinΦ+cosΦ=√2Find value of tanΦ+cotΦ |
| Answer» Any one have solution | |
| 2808. |
Find the value of the expression [Cot(20-A)+Tan(70+A)÷Sin(70-A)]×Sin(20-A) |
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| 2809. |
Okk I\'m going gyzz gud ni8 RIMSHA |
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| 2810. |
Find the value of K for which 1 root of the quadratic equation |
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| 2811. |
Gud night all of you |
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| 2812. |
Who want to talk with me |
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| 2813. |
Ye sin cos tan etc.... samajhne ka koi easy way h kyaa.....??? |
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| 2814. |
Root 2 |
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| 2815. |
Aditi sharma unblock kar dena |
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| 2816. |
What is Baudhyan theorem?( Spelling of Baudhyan might be in correct.)????? |
| Answer» Baudhayan was an ancient mathematician who discovered the Pythagoras Theorem before Pythagoras. H²= P² + B². | |
| 2817. |
Tan30+cos 35 |
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| 2818. |
SecX - tanX = 4 prove cosX = 8/7 |
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| 2819. |
What is timetable of 10 cbse board exams |
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| 2820. |
How it will help me |
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| 2821. |
H.c.f. of20123 and 1256 |
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| 2822. |
Prove that :(1/secA-tanA) - 1/cos=(1/cos)-1/sec+tan |
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| 2823. |
What does the Mandela thanks the international leaders for |
| Answer» Mandela thanks the international leaders because he help to the Mandela they give support and fight white people and when Mandela make a 1st black President of South Africa he go the assembly and take oath many international leader will be came than they say thanks for some international leader | |
| 2824. |
What is A.p? |
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Answer» AP is arithmetic progressions....in which the common diffrence of the digits are equal....??✌️✌️ Whose common difference is always equal Who terms different between same for example:3,6,9,12,15. |
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| 2825. |
The 7term of an ap is 32 and its 3 term 16 and 7 term exceeds its 5 term by 12 |
| Answer» Find kya Kerna hai | |
| 2826. |
SinA/sinb=m and cosA/cosB=n prove that TanA=m/n √(1-n^2)/(√m^2-1) |
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| 2827. |
120-50 |
| Answer» 70 | |
| 2828. |
+3_5 |
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| 2829. |
If the mean of the following data is 21.5 find the value of K. Xi=5,15,25,35,45 and fi=6,4,3,k,2 |
| Answer» Answer =5 | |
| 2830. |
cosA-sinA+1÷cosA+sinA-1=cosecA+cotA |
| Answer» It\'s a NCERT book questions you can find the answer in mathematics solutions | |
| 2831. |
Find centre of circle passing through points A(6,-6) B(3,-7) C(3,3). |
| Answer» Let\xa0A → (6, –6), B\xa0→ (3, –7) and C\xa0→ (3, 3).Let the centre of the circle be I(x, y)Then, IA = IB = IC [By definition of a circle]{tex}\\Rightarrow{/tex} IA2 = IB2 = IC2{tex}\\Rightarrow{/tex} (x - 6)2 + (y + 6)2 = (x - 3)2 + (y + 7)2 = (x - 3)2 + (y - 3)2Taking first two, we get(x - 6)2 + (y + 6)2 = (x - 3)2 + (y + 7)2{tex}\\Rightarrow{/tex} x2 - 12x + 36 + y2 + 12y + 36 = x2 - 6x + 9 + y2 + 14y + 49{tex}\\Rightarrow{/tex} 6x + 2y = 14{tex}\\Rightarrow{/tex} 3x + y = 7 ......(1) ....[Dividing throughout by 2]Taking last two, we get(x - 3)2 + (y + 7)2 = (x - 3)2 + (y - 3)2{tex}\\Rightarrow{/tex} (y + 7)2 = (y - 3)2{tex}\\Rightarrow{/tex} (y + 7) = {tex}\\pm{/tex}(y-3)taking +e sign, we gety + 7 = y - 3{tex}\\Rightarrow{/tex} 7 = -3which is impossibleTaking -ve sign, we gety + 7 = -(y - 3){tex}\\Rightarrow{/tex} y + 7 = -y + 3{tex}\\Rightarrow{/tex} 2y = -4{tex}\\Rightarrow y = \\frac{{ - 4}}{2} = - 2{/tex}Putting y = -2 in equation (1), we get{tex}\\Rightarrow{/tex} 3x - 2 = 7{tex}\\Rightarrow{/tex} 3x = 9{tex}\\Rightarrow{/tex} x = 3Thus, I {tex}\\rightarrow{/tex} (3, -2)Hence, the centre of the circle is (3, -2). | |
| 2832. |
Tangt cicles |
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| 2833. |
Aditi call kab karu |
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| 2834. |
Kaise ho aap sab ??? |
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| 2835. |
The roots of the equation x^2-3x-m (m+3)=0 where m is a constant |
| Answer» {tex}x^2 - 3x -m(m + 3) = 0\xa0{/tex}{tex}\\Rightarrow{/tex}{tex}\xa0x^2 + mx - (m + 3)x - m(m + 3) = 0{/tex}{tex}\\Rightarrow{/tex}{tex}x(x+m)-(m+3)(x+m){/tex}{tex}\\Rightarrow{/tex}\xa0(x+m) (x\xa0- m - 3) = 0x = -m and m + 3 | |
| 2836. |
Please solve ques 2 of ex 13.5 ncert in easy way |
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| 2837. |
Who is aryabath |
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| 2838. |
When will CBSE class10 exam start |
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Answer» Today in news said that from last week of February but me too not sure about that. The time table will be given in the month of jan,most probably in March . |
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| 2839. |
Say answer the question |
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| 2840. |
If the points (x,y),(1,2),(7,0) are collinear prove that a+b-7=0 |
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| 2841. |
When CBSE class 10 board paper held |
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| 2842. |
Trigonometry based |
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| 2843. |
What u want to talk with me |
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| 2844. |
Di |
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| 2845. |
RIMSHA do u hear me |
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| 2846. |
Who are u |
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| 2847. |
Hey koi h mera frnd |
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| 2848. |
Ratio of 81 and 108 |
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| 2849. |
No one talk with me |
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| 2850. |
Cos15.- |
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