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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 28451. |
Find perimeter of triangle with vertices (0,4), (0,0)and (3,0) |
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Answer» First find length of each sides of ∆Let A( 4 , 0) B(0, 0) and C (0 , 3)use distance formula,AB =√(4²+0) =4BC= √(0+3²) = 3CA =√(4²+3²) =5now ,perimeter of ∆ = 3 + 4 + 5= 12 unit Answer hai 30 pehle A(0,4) B(0,0) C(3,0) fir AB BC CA ki distance nikalkar jod Dena answer aa jayega |
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| 28452. |
2 sin square 60 degree plus |
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Answer» Right S N .... Plz complete your question 3 divided by 2 Pura questions toh likh do plz....Tabhi toh answer dege .... |
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| 28453. |
Ex 3.6 question no 1 part 8 |
| Answer» Get NCERT solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 28454. |
Ex 3.6 |
| Answer» Q8 | |
| 28455. |
Prove that the mid point of hypotenus of a right angled triangle is equidistance from its vertics |
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| 28456. |
Prove that the mid point of hypotnus |
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| 28457. |
What is the HCF of smallest composite number and smallest prime number |
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Answer» 2...... As we know that ,Smallest prime no.= 2Smallest composite no.=4HCF:-2 = 1×24 = 2×2SO COMMON FACTOR IS 2HENCE, HCF = 2. Smallest prime number=2, smallest composite number=4.so hcf=2 Smallest prime number is 2 and smallest composite number is 4 ...............Hcf of 2 & 4 is 2 |
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| 28458. |
Prove that:cosA/1-tanA +sinA/1-cotA=sinA+cosA |
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| 28459. |
Class 10th all important questio. Guess question |
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Answer» Complete yur ncert.......... Solve oswaal books Proving of theorem from lesson 6th |
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| 28460. |
Find the value of k, if the point P(2,3)is equidistant from the point A(K,1)and B(7,K) |
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Answer» Use distance formula. K= 13 Here, AP= BP so, apply distance formula and u will get the solution.... |
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| 28461. |
Find the value of k if the point A(2,3),B(4,K)and C(6,-3) are collinear |
| Answer» In the case of collinear area of ∆ becomes 0 so put these values in the formula of area of triangle and hence find the solution ....... | |
| 28462. |
Prove that ( 1+ cotA+ tanA ) ( sinA - cosA )= sinA.tanA - cotA.cosA |
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| 28463. |
If p , q and r are in AP , then prove that (p+2q-r)(2q+r-p)(r+p-q)=4pqr |
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Answer» Alkesh ye kaise kiya Pqr (1+2×1-1)(2×1+1-1)(1+1-1) = pqr (2)(2)(1) = 4pqr Pqr (1+2×1-1)(2×1+1-1)(1+1-1) pqr (2)(2)(1) 4pqr Yar koi solve kar do |
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| 28464. |
Write the definition of basic proportional theorem |
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Answer» If a line drawn parallel to one side of a ∆ then the to intersect the other two sides in distinct points , divides the two sides in the same ratio If a line drawn parallel to one side and intersect other two sides,then it will divide other two sides in the same ratio |
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| 28465. |
6.4 Q-3 |
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Answer» Please check in previous question See it in this app |
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| 28466. |
Class xCh 5Exe-5.3Q-9, 10,11,12,13,14 |
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Answer» |
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| 28467. |
The 7th term of an AP is _4 and its 13th term is_ 16 find AP |
| Answer» a7=4a+6d=4.........[1]a13=16a+12d=16......[2][2]-[1]6d=12d=12/6d=2Substituting d=2 in [1]a+6d=4a+12=4a=-8Therefore,AP= -8,-6,-4,-2,0,2,4,6,8,10,12,14,16,..... | |
| 28468. |
Is (a-b) the whole square and (b-a) the whole square same |
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Answer» Yes they are same(a - b)2 = a2+ b2 -2abAnd, (b - a)2 =b2 + a2 - 2ab Thereforethey are the same . I hope that you have understood this.Ok Absolutely sameAs (a-b)²=a²+b²-2abAnd(b-a)²=b²+a²-2ba |
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| 28469. |
Find the ratio in which X-axis divides the line segment joining the points (6,4)and (1,-7). |
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| 28470. |
Explain how to prove trignometry ratios |
| Answer» Given in ncert | |
| 28471. |
explain BPT ( basic proportionality theorm) |
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Answer» In a triangle if the points on two sides are parallel to third side than the ratio of the corresponding sides are equal Check it in yur book......... The ratio of proportional side of the similar triangle are equal. |
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| 28472. |
How l should study the trigonometry chapter . I just don\'t know any thing in trigonometry chapter |
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Answer» Your most welcome... ?? Any other suggestions from other friends Just learn every formula then you can solve everything. Mostly in prove questions change other terms such as CosecA to sinA or cosA Learn all the formula of that chapter........... And do practice 3to4 times.... |
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| 28473. |
Is 0.101100101010 an irrational number? Justify your answer |
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Answer» How?? Geetanand No it\'s rational number because it\'s terminating Do this as you do in proving√2 a irrational number |
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| 28474. |
Find the 11th tern of an AP -5, -5/2, 0, 5/2,...... |
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Answer» 11th term = 20 Find difference by subtracting first term from second term .then d=5/2,a=-5 and n=11.so An=a+(n-1)d.put the value=An=-5+(11-1)*5/2,then An=-5+(10*5/2), then An=-5+25=20ans.... 20 Can u explain?? 20is the answer |
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| 28475. |
Find the mean of the following data mark: 0 or above 80, 10 or above 77 |
| Answer» It mean nothing | |
| 28476. |
6n+1 |
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Answer» Thn what is the ans?? Same as que ans is 6n+1 ???????...... I think it is not complete que 7n |
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| 28477. |
5 add 2 |
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Answer» 7 7 answer so easy ........ |
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| 28478. |
What is the probability of a car, start or not??? |
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Answer» Probability is 1 1/2 1 |
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| 28479. |
Exe 14.1 1sum by step deviation |
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| 28480. |
If m^3 is equal to cosec - sin and n^3 is equal to sec - cos then prove that m^4n^2 +m^2n^4 = 1 |
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| 28481. |
Which term of the AP is first Negative term 121, 117..... |
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Answer» -3 is the first negative no.Substite -3 as An in the equation a+(n-1)d Take n=0 u will get the ans |
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| 28482. |
How can we make our calculations faster during exams? |
| Answer» By giving full concentration to the question | |
| 28483. |
(x-200)(x-400)(x-600)=2800 |
| Answer» X^3 + 1200x^2- 440000x- 4802800 | |
| 28484. |
Find the value of x and yPx+qy=p-qQx-py=p+q |
| Answer» X=1 ,y=-1 | |
| 28485. |
What is Euclid division Lemma explain |
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Answer» Consider a positive integer a and b. Then a=bq+r where a is divident b is divisor q is quotient and r is remainder. This is called euclid division lemma. It means :Dividend = ( divisor * quotient) +remainder |
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| 28486. |
What is the formula of area of sector other than given in ncert? |
| Answer» 1/2 *length of arc* radius | |
| 28487. |
Optional questions of chapter 2 |
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Answer» Check in this app....... Refer My cbse guide ncert solutions of polynomials |
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| 28488. |
What are consistent. No. |
| Answer» That have a solution to the equation(either unique or equal zeroes) | |
| 28489. |
Vertices mean?? |
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Answer» Friend,Vertex means "KONNA" or shearsh in hindi AND VERTICES IS PLURAL OF VERTEXIN {tex}\\triangle {/tex} ABC ,A ,B and C ARE VERTICESIn a square ABCD A,B,C,D are VERTICESIn geometry "Vertex is a point where two sides of any polygon meet or intersect.In physic Vertex is having some different meanings Vertex (physics), a point where particles collide and interact.Vertex (optics), a point where the optical axis crosses a lens surface.Vertex operator algebra in conformal field theory.Vertex function, describing the interaction between a photon and an electron. Topr is ryt.........? Plural of vertex s vertices. Point of intersection of 2 lines for forming an angle Where twosides of a quad. intersect |
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| 28490. |
The sum of first three terms of A.P. is 21 and their products is 231. Find the numbers |
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Answer» Let the No. a-d,a and a+dSum: a-d+a+a+d=213a=21, a=7product: a(a-d)(a+d)=231a(a2-d2)=2317(49-d2)=23149-d2=33d2=16, d={tex}\\pm{/tex}4So numbers are:3,7,11 or 11,7,3\xa0 Let the AP is (a-d), a, (a+d)(a-d)+a+(a+d) =213a=21a=7(a-d)×a×(a+d)=231(a×a-d×d) ×a=231(7×7-d×d)×7=231(7×7-d×d)=231÷7(7×7-d×d)=33d×d=49-33d×d=16d=4Hence, the A. P. is 3, 7, 11. the A. P. is 3, 7, 11. A=3 and d=4...therfore AP is 3,7,11.......And three numbers are 3,7 and 11 |
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| 28491. |
Use euclid algorthim to find the hvf of 12576and 4052 |
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Answer» 12576=4052*3+4204052=420*9+272420=272*1+148272=148*1+124148=124*1+24124=24*5+424=4*6+0Hcf=6 What do u mean by (hvf) |
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| 28492. |
find the value of x and y:5x+7y=507x+5y=46 |
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Answer» Mr Mishra don\'t worry here is the solution:5x+7y=50...(1)7x+5y=46....(2)Multiply (1) by 7 and (2) by 5 we get35x+49y=350.....(3)35x+25y=230.......(4)subtract (4) from (3)24y=120 , y=5Now from(1)5x+7*5=505x=15x=3, y=5\xa0\xa0\xa0 Sorry x=3 5x × 7y=50 ---(×7) =35x ×49y=350 --(1)7x ×5y=46 ---(×5) = 35x ×25y=230 ---(2)Solving (1)&(2)Y=5X=15 plz can u give me the full explanation and not just values..Like can u give its complete solution by any of the three methods..plz X is equal to 3Y is equal to 5 |
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| 28493. |
Sin A( 1+tan A)+cos A( 1+cos A)=sec A |
| Answer» B | |
| 28494. |
If 1+Sin²A = 3SinACosAProve that tanA=1 or 1/2 |
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| 28495. |
Sin tetha (1+tan tetha ) + cos tetha (1+ cos tetha ) = sec tetha |
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| 28496. |
6q+1 6q+3 6q+5 show that any postive integer |
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| 28497. |
How can i get a position to top vidharbha or maharashtra |
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| 28498. |
Formula to find area of tarpezium |
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Answer» 1/2(sum of two parallel line) x hight A = a+b/2 × h 1/2 ×(base1 + base2)×height |
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| 28499. |
hcf of 26 and 91 in form 26m+91n . find value of m and n |
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| 28500. |
Sin^2theta + cos^2theta=1 prove |
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Answer» Ha kabih kabih aate hai board me Is there a question like that Take (base)ka whole square+(perpendicular)ka whole square=(hypotenuse)ka whole square. Then divide whole equation by(hypotenuse)ka whole square you will get the answer.hope it helps you....... |
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