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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 28651. |
2x+5y=8 and 4x+ 5 y =8 |
| Answer» Subtracting 2nd eq from 1st we get x = 0 putting x=0 in first we get y = 8/5 | |
| 28652. |
If a n is equal to 5 minus 11 and find the common difference |
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Answer» an = 5 - 11nIf n = 1 ;a1 = 5-(11×1)a1 = -6If n = 2 ;a2 = 5-(11×2)a2 = -17Now , a1=-6 & a2=-17Hence, common difference = d = a2-a1= -17-(-6)= -11 Complete question |
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| 28653. |
Converse of pythagoras |
| Answer» Given in ncert book | |
| 28654. |
Show that d=Sn-2Sn-1+Sn-2 |
| Answer» Complete question | |
| 28655. |
If sec theta + tan theta is equals to p then find the value of cosec theta |
| Answer» Secθ+tanθ=p ----------------------(1)∵, sec²θ-tan²θ=1or, (secθ+tanθ)(secθ-tanθ)=1or, secθ-tanθ=1/p ----------------(2)Adding (1) and (2) we get,2secθ=p+1/por, secθ=(p²+1)/2p∴, cosθ=1/secθ=2p/(p²+1)∴, sinθ=√(1-cos²θ)=√[1-{2p/(p²+1)}²]=√[1-4p²/(p²+1)²]=√[{(p²+1)²-4p²}/(p²+1)²]=√[(p⁴+2p²+1-4p²)/(p²+1)²]=√(p⁴-2p²+1)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1)∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1)\xa0 | |
| 28656. |
Sin-cos= 0 then sin4 +cos4is |
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Answer» sinθ-cosθ = 0,sinθ= cosθ,sinθ/cosθ = 1,tanθ = 1,Bu tan45 = 1,So,tanθ=tan45,θ = 45°,sin45 = 1/√2 cos45 = 1/√2,sin⁴θ+cos⁴θ = (1/√2)⁴+(1/√2)⁴, = 1/4+1/4 = 2/4 = 1/2 = 0.5 sinθ-cosθ = 0sinθ= cosθsinθ/cosθ = 1tanθ = 1Bu tan45 = 1So,tanθ=tan45θ = 45°sin45 = 1/√2 cos45 = 1/√2sin⁴θ+cos⁴θ = (1/√2)⁴+(1/√2)⁴ = 1/4+1/4 = 2/4 = 1/2 = 0.5 |
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| 28657. |
What is the root of 36 |
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Answer» √36= √2x2x3x3 = 2x3= 6 √36=6 6 6 |
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| 28658. |
Prove that root3 is a irrational |
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Answer» Let root 3 is a rational number Let a and b are positive integer and a and b have no common factor other than 1Root 3 =a/b3=a square/b square b square =a square/3a square is divided by 3 than a is also divided by 3Let a=3c3 b square = 9 c square b square = 3 c square b square/3 = c square b square is divided by 3 than b is also divided by 3Therefore a and b have at least 3 as a common factorThis contradiction has arisen because of our incorrect assumption that root 3 is rationalSo we conclude that root 3 is irrational number Yu can refer ncert.... |
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| 28659. |
Given that 2x, 5,6-x are the first three terms of an AP, what will be it\'s 10th term? |
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Answer» -19 a=2x and a2=5 So, d=a2-a=5-2x-(i) d=a3-a2= 6x-5 (ii) Comparing i and iiWe get, x=5/4So, d=5/2an=a+(n-1)da10=5+(10-1)(5/2)a10=5+45/2a10=55/2I thing you understood. common difference (d) = commonSo, 5 - 2x = 6 - x - 54 = xValue of x = 4.So, a = first term = 2x = 8d = - 3.a10 = a + 9d = 8 - 27 = -19Tenth term is - 17. |
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| 28660. |
Find the coordinate of the point on y-axis which is nearst to the point(-2,5). |
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Answer» (O, y) and (-2,5)Use Distance formula (0,5) |
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| 28661. |
If the pllynomial |
| Answer» ???? | |
| 28662. |
If root3tan*=3 then find the value of *t |
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Answer» let x is the angle then{tex}\\begin{array}{l}\\sqrt3\\mathrm{tanx}=3\\\\\\mathrm{tanx}=\\frac3{\\sqrt3}=\\sqrt3=\\tan60^\\circ\\\\\\mathrm{so}\\;\\mathrm x=60^\\circ\\end{array}{/tex} Sorry,find the value of * |
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| 28663. |
X square - 4 x minus 8 completing the square method |
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Answer» How did you do Ram Kushwaha ??? |
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| 28664. |
Any bodey is from leelewati school muradnagar |
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| 28665. |
Express the hcf of number 72 and 124 as a linear combination |
| Answer» Consider the following numbers72 and 124First find the HCF of above numbers.72 = 2\xa0× 2\xa0× 2\xa0× 3\xa0× 3\xa0⇒ 2³\xa0× 3²124 = 2\xa0× 2\xa0× 31⇒ 2²\xa0× 31To find the HCF of these numbers, take the least power of each common factor and find the product.Here 2 is the only common factor and least power of which is 2.So, we haveHCF(72 and 124) = 4Now we need to express HCF = 4 as a linear combination of 72 and 124.That is,4 = 72a + 124b, where a and b are integers.Use hit and trial method.Take a = -10 and b = 672(-10) + 124(6)\xa0⇒ -720 + 744 = 24, which is not equal to 4.So, take a = -12 and b =772(-12) + 124(7)⇒ - 864 + 868 = 4So, the required linear combination isHCF(72 and 124) = 4 = 72(-12) + 124(7) | |
| 28666. |
Show that square of any odd integer is of the form 4m+1 for some integer m. |
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Answer» Let a be any positive integer and b = 4\xa0Then, by Euclid\'\'s algorithm a = 4q + r for some integer q\xa00 and 0\xa0\xa0r < 4\xa0Since, r = 0, 1, 2, 3\xa0Therefore, a = 4q or 4q + 1 or 4q + 2 or 4q + 3\xa0Since, a is an odd integer, o a = 4q + 1 or 4q + 3\xa0Case I:\xa0When a = 4q + 1\xa0Squaring both sides, we have,\xa0a2\xa0= (4q + 1)2\xa0\xa0a2\xa0= 16q2\xa0+ 1 + 8q\xa0 = 4(4q2\xa0+ 2q) + 1\xa0 = 4m + 1 where m = 4q2\xa0+ 2q Case II:\xa0When a = 4q + 3Squaring both sides, we have,a2\xa0= (4q +3)2 = 16q2\xa0+ 9 + 24q = 16 q2\xa0+ 24q + 8 + 1 = 4(4q2\xa0+ 6q + 2) +1 = 4m +1 where m = 4q2\xa0+7q + 2Hence, a is of the form 4m + 1 for some integer m.\xa0 Refer ncert |
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| 28667. |
Find the value of a so the point (3, a) lies on the line represent by 2x -3y=5 |
| Answer» a=1/3 | |
| 28668. |
4 theroms |
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| 28669. |
If 3sin + 5cos=5. Prove that 5sin - 3cos=±3 |
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| 28670. |
Cosec square b+c/2 -tan square a/2=1 if ABC are interior angel of triangle abc |
| Answer» | |
| 28671. |
Q.Prove that BPT THEROM. |
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Answer» BPT we can prove by Similarity between Triangles also...My dear students This prove may be important in Board exam once think and prove bpt by Similar triangles concept. BPT(Thales Theorem) -\xa0Given - In triangle ABC, DE is parallel to BC. DE bisects AB at D and AC at E.To Prove - AD/BD= AE/CEConstruction - Join BE and CD and draw EF is perpendicular to AB and DG is perpendicular to AC.Proof -\xa0As, EF is perpendicular to AB, EF is the height of tr\'s ADE and DBE. |
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| 28672. |
Please give me chapter wise marks chat of math |
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Answer» Number system = 6 marks..........Algebra = 20 marks...........Coordinate geometry = 06 marks.............Geometry = 15 marks.......Trigonometry = 12 marks........Mensuration = 10 marks ........Statistics and probability = 11 marks...... Ch. 1=6marksCh.2=3mrk3=5mrk4=5mrk5=7mrk6=8mrk7=4mrk8=8mrk9=4mrk10=3mrk11=4mrk12=3mrk13=7mrk14=7mrk15=4mrk Every time marking scheme differs .... Even the no. Of questions differ.... |
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| 28673. |
(Sin*+sec*)square + (cos*+ cosec*)square= (1+sec*×cosec*)square |
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Answer» Yes Do u wanna prove this?? |
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| 28674. |
Find simple zeroes of x square minus three x minus m bracket m plus 3 |
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| 28675. |
What is root |
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| 28676. |
Difficult sub...... |
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Answer» It depends on yu....which sub is difficult fr yu...........??? What do u mean ? ? |
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| 28677. |
Find the area of right triangle whose hypotenus is 25 cm and perimeter is 60 m |
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Answer» If both are same then 20 and 15 Are you sure about the units??????? |
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| 28678. |
Normal find the zeros of the polynomial x square - 3 x minus M bracket M + 3 |
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Answer» (m+3) and _m |
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| 28679. |
Areas of similar triangles theorem |
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Answer» Refer ncert See in book |
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| 28680. |
Give one example of two irrational numbers whose sum is a rational number. |
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Answer» Root 2 and root minus 2 √2and -√2 |
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| 28681. |
Differentiate between non probable and probable numbers |
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| 28682. |
Find a quadratic polynomial ,the sum and product of whose zeroes are -7 and - 18 respectively |
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Answer» Sum of zeroes and products of zeroes For writing the form of quadratic poly. when sum and product of zeroes is given is {x sq. -(sum of 0s)+(prod. of 0s)} X square + 7 x- 18 X sq. +7x-18 |
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| 28683. |
What is the value of k, if 3×2-kx+6=2 |
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Answer» 4√3=k. The question is not complete i think Give answer completely Value of k is 12 |
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| 28684. |
A line segment is 8 cm in length. AB is produced to P such that BP*BP=AB*AP. Then length of BP is |
| Answer» | |
| 28685. |
how we understand chapter 13 of math for class 10th ncert |
| Answer» Go to the youtube page and see tha videos of vidyarthi mam | |
| 28686. |
The sum of a rational and irrational number is |
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Answer» Always irrational number Always irrational number Always irrational Irrational |
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| 28687. |
In word problems,how to understand hcf is the answer or lcm |
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Answer» When d Q asks about MAXIMIUM den u have to find Hcfwhen its asks About MINIMUM den Lcm is required...For ex. an army contigent of 616 members is to march behind d army band of 32 members . the two groups are to march in same no. of columns . den wt is maximum no of column dey can march.Here d Q cleary tells us we have to find its HCF bec its asking d max people required..Hope its Clear..... If the largest" or maximum" word is mention in question then you have to find HCF and LCM is oppsite to this word smallest or largest |
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| 28688. |
Please let me know the selected chapter to study |
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Answer» Staitistics, Probability, coordinate geometry, construction, real numbers and polynomials. If you done them then you may get passing marks in maths. U\'ll have to study them all for boards |
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| 28689. |
Please give me paper of 2015 solved plz because solutions i did not have |
| Answer» Download from:https://www.vedantu.com/previous-year-question-paper/cbse-maths-class-10-year-2015 | |
| 28690. |
A coin is tossed three times. Find the probability of getting at most two head |
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Answer» 4/8 =1/2 1/2 7/8 When 3 unbaised coins are tossed, the total number of events = 8They are {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}At most two headsThat is no head or one head or 2 headsProbability of getting at most two heads = 7/8 |
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| 28691. |
find the zeroes of x^2+1/6x-2 |
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| 28692. |
cos a- sin a=1 prove that cos a+sin a=+-1 |
| Answer» I got the answer | |
| 28693. |
Write the number which is three fight and divisible by 7 |
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Answer» Three digit..? GREAT!!!!!!!!!!!!!!!! Write the numbers |
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| 28694. |
(X+a) is a factor of the 2x2+2ax+5x+10Find out the value of a |
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Answer» How X+a is a factor of 2x²+2ax+5x+10therefore f(-a)=0;substituting values,2(-a)²+2(a)(-a)+5(-a)+10=02a²-2a²-5a+10=0-5a+10=0therefore a=2 |
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| 28695. |
3 |
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Answer» ya! This is not class 10 Question Yes Yes |
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| 28696. |
If sina+sinb+sinc=3 Find value of cosa +cosb+ cosc |
| Answer» Maximum value of sin Ф is 1.So sinA+sinB+sinC=3 means sin A = 1sin B = 1sin C = 1Thus, A = B = C = 90 degreecos A = cos 90 = 0cos B = cos 90 = 0cos C = cos 90 = 0cos A + cos B +cos C = 0 | |
| 28697. |
If the point P (x,y)is equidistant from the points A (a+b,a-b )and B (a-b, a +b) prove that bx =ay |
| Answer» |PQ| = |PR{tex}\\begin{aligned} \\sqrt { [ x - ( a + b ) ] ^ { 2 } + [ y - ( b - a ) ] ^ { 2 } } = \\sqrt { [ x - ( a - b ) ] ^ { 2 } + [ y - ( b + a ) ] ^ { 2 } } \\end{aligned}{/tex}Squaring, we get[x - (a + b)]2 + [y - (b\xa0- a)]2\xa0= [x - (a - b)]2 + [y - (a + b)]2or, [x - (a + b)]2 - [x - a + b]2\xa0= (y - a - b)2 - (y - b + a)2or, (x - a - b + x - a + b) ( x - a - b - x + a - b)= (y - a - b + y - b + a)(y - a - b - y + b - a)or, (2x - 2a) (- 2b) = (2y - 2b) (- 2a)or, (x - a)b = (y - b)aor, bx = ay.Hence Proved. | |
| 28698. |
If area of the two similar triangle in the ratio 25:64 write the ratio of their corresponding sides |
| Answer» 5:8 | |
| 28699. |
In triangle abc ,ab=5,ac=13 ,find the value of tan A+cotC. |
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Answer» {tex}\\style{font-size:12px}{\\begin{array}{l}AB=5,AC=13\\\\\\mathrm{So}\\;\\mathrm{BC}^2=\\mathrm{AC}^2-\\mathrm{AB}^2\\\\=169-25=144\\\\\\mathrm{BC}=12\\\\\\mathrm{Now}\\;\\mathrm{tanA}+\\mathrm{cotC}\\\\=\\frac{\\mathrm{BC}}{\\mathrm{AB}}+\\frac{\\mathrm{AB}}{\\mathrm{BC}}\\\\=\\frac{12}5+\\frac5{12}=\\frac{144+25}{60}=\\frac{169}{60}\\end{array}}{/tex} Tan12\\5 COT12\\5 |
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| 28700. |
Given that root 2 is irrational prove that 5 + 3 root 2 is an irrational number |
| Answer» Let 5\xa0+ 3{tex}\\sqrt{2}{/tex}\xa0be a rational number.{tex}\\Rightarrow{/tex}\xa05\xa0+ 3{tex}\\sqrt{2}{/tex}\xa0=\xa0{tex}\\frac{p}{q}{/tex}, p, q\xa0{tex}\\in{/tex}\xa0I, q\xa0{tex}\\ne{/tex}\xa00{tex}\\Rightarrow{/tex}\xa03{tex}\\sqrt{2}{/tex}\xa0=\xa0{tex}\\frac{p}{q}{/tex}\xa0- 5{tex}\\Rightarrow \\sqrt{2}{/tex}\xa0=\xa0{tex}\\frac{p - 5q}{3q}{/tex}{tex}\\frac{p - 5q}{3q}{/tex}\xa0is rational\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt{2}{/tex}\xa0is rational number which is a contradiction.5 + 3{tex}\\sqrt{2}{/tex} is irrational number. | |