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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 29201. |
Is guide ka sample question paper 12 maths ka que no 9 ka answer wrong hai. |
| Answer» Which guide | |
| 29202. |
If sin theta +cos theta =x then prove sin^8 theta + cos^8 theta =4 - 3[x^2 - 1]^2 / 4 |
| Answer» LHS{tex} = {\\sin ^6}\\theta + {\\cos ^6}\\theta {/tex}{tex} = {\\left( {{{\\sin }^2}\\theta } \\right)^3} + {\\left( {{{\\cos }^2}\\theta } \\right)^3}{/tex}{tex} = {\\left( {{{\\sin }^2}\\theta + {{\\cos }^2}\\theta } \\right)^3} - 3{\\sin ^2}\\theta {\\cos ^2}\\theta \\left( {{{\\sin }^2}\\theta + {{\\cos }^2}\\theta } \\right){/tex}{tex}\\left[ {\\because {a^3} + {b^3} = {{(a + b)}^3} - 3ab(a + b)} \\right]{/tex}{tex} = {(1)^3} - 3{\\sin ^2}\\theta {\\cos ^2}\\theta \\times 1{/tex}\xa0{tex}\\left[ {\\because {{\\sin }^2}\\theta + {{\\cos }^2}\\theta = 1} \\right]{/tex}{tex} = 1 - 3{\\sin ^2}\\theta {\\cos ^2}\\theta {/tex}RHS\xa0{tex} = \\frac{{4 - 3{{({x^2} - 1)}^2}}}{4}{/tex}{tex} = \\frac{{4 - 3{{\\left\\{ {{{\\left( {\\sin \\theta + \\cos \\theta } \\right)}^2} - 1} \\right\\}}^2}}}{4}{/tex}\xa0{tex}\\left[ {given\\;x = \\sin \\theta + \\cos \\theta } \\right]{/tex}{tex} = \\frac{{4 - 3{{\\left\\{ {{{\\sin }^2}\\theta + {{\\cos }^2}\\theta + 2\\sin \\theta \\cos \\theta - 1} \\right\\}}^2}}}{4}{/tex}{tex} = \\frac{{4 - 3{{\\left\\{ {1 + 2\\sin \\theta \\cos \\theta - 1} \\right\\}}^2}}}{4}{/tex}\xa0{tex}\\left[ {\\because {{\\sin }^2}\\theta + {{\\cos }^2}\\theta = 1} \\right]{/tex}{tex} = \\frac{{4 - 3{{\\left( {2\\sin \\theta \\cos \\theta } \\right)}^2}}}{4}{/tex}{tex} = \\frac{{4 - 3 \\times 4{{\\sin }^2}\\theta {{\\cos }^2}\\theta }}{4}{/tex}{tex} = \\frac{{4\\left( {1 - 3{{\\sin }^2}\\theta {{\\cos }^2}\\theta } \\right)}}{4}{/tex}LHS = RHSHence proved. | |
| 29203. |
If the points A(k+1),B(3k,2k+3),C(5k-1,5k)are collinear, then find the value of k |
| Answer» If points are collinear then ar. triangle =0Put all points in formula | |
| 29204. |
2x+y=5 and 3x+2y=8 find the solution |
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Answer» 2 aur 1 x=2 & y=1 x=-2,y=1 X=2 Y=| |
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| 29205. |
Give a pen portrait of Helen Keller? |
| Answer» Sorry Eng... Question | |
| 29206. |
Name three laws of dominance...... |
| Answer» Law of dominanceLaw of segregation Law of independent assortment | |
| 29207. |
Prove 2+2 = 5 |
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Answer» ? Lete take 1St,, 2=3 and solve it??? Aese questions ma t purchase kar |
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| 29208. |
Prove that : sin thita/cot thita=2+sin thita/ cot thita-cosec thita |
| Answer» We have,{tex} \\frac { \\sin \\theta } { \\cot \\theta + \\cos ec \\theta } = 2 + \\frac { \\sin \\theta } { \\cot \\theta - \\cos ec \\theta } \\text { or, } \\frac { \\sin \\theta } { \\cot \\theta + \\cos ec \\theta } - \\frac { \\sin \\theta } { \\cot \\theta - \\cos ec \\theta } = 2{/tex}Now,{tex}\\mathrm { LHS } = \\frac { \\sin \\theta } { \\cot \\theta + \\cos ec \\theta } - \\frac { \\sin \\theta } { \\cot \\theta - \\cos ec \\theta }{/tex}{tex}\\Rightarrow \\quad \\mathrm { LHS } = \\frac { \\sin \\theta } { \\cos ec \\theta + \\cot \\theta } + \\frac { \\sin \\theta } { \\cos ec \\theta - \\cot \\theta }{/tex}{tex}\\Rightarrow \\quad \\mathrm { LHS } = \\sin \\theta \\left\\{ \\frac { 1 } { \\cos ec \\theta + \\cot \\theta } + \\frac { 1 } { \\cos ec \\theta - \\cot \\theta } \\right\\}{/tex}{tex}\\Rightarrow \\quad \\mathrm { LHS } = \\sin \\theta \\left\\{ \\frac { \\cos ec \\theta - \\cot \\theta + \\cos ec \\theta + \\cot \\theta } { \\cos ec ^ { 2 } \\theta - \\cot ^ { 2 } \\theta } \\right\\} = \\sin \\theta \\left( \\frac { 2 \\cos ec \\theta } { 1 } \\right){/tex}{tex} \\Rightarrow \\quad \\mathrm { LHS } = \\sin \\theta ( 2 \\cos ec \\theta ) = 2 \\sin \\theta \\times \\frac { 1 } { \\sin \\theta } = 2 = \\mathrm { RHS }{/tex} | |
| 29209. |
If 6x=secA and 6/x=tanA then find value of 9(x^2-1/x^2) |
| Answer» We have,6x = sec\xa0{tex}\\theta{/tex}........(i)and\xa0{tex}\\frac { 6 } { x } = \\tan \\theta{/tex} ........(ii)Adding (i) and (ii), we get{tex}6 \\left( x + \\frac { 1 } { x } \\right) = ( \\sec \\theta + \\tan \\theta ){/tex}.......(iii)Subtracting (ii) from (i), we get{tex}6 \\left( x - \\frac { 1 } { x } \\right) = ( \\sec \\theta - \\tan \\theta ){/tex}........(iv)Multiplying the corresponding sides of (iii) and (iv), we get{tex}36 \\left( x ^ { 2 } - \\frac { 1 } { x ^ { 2 } } \\right) = \\left( \\sec ^ { 2 } \\theta - \\tan ^ { 2 } \\theta \\right) = 1{/tex}{tex}\\Rightarrow 9 \\left( x ^ { 2 } - \\frac { 1 } { x ^ { 2 } } \\right) = \\frac { 1 } { 4 }{/tex} | |
| 29210. |
Kon Kon 10th me top karega |
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Answer» MATLAB? Soch to m bhi rha hu Top kerlena hi jindagi nahi hai... ????? Akira only topper |
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| 29211. |
A passenger whileboarding The Plane |
| Answer» | |
| 29212. |
What should i do to improve mine trignometry.. |
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Answer» Get yourself cleared all the concepts first, then practice it! Practise? The matter is that How to practice..it i could not solve the question to be proved Practice |
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| 29213. |
If m times of an mth terms of an AP is equal to n times of its nth term, find (m+n)th term. |
| Answer» 0 | |
| 29214. |
Determine two consecutive multiples of 3 whose product is 270 |
| Answer» Let the required number be 3x and 3x+3 . Then , (3x) (3x+3) =270Solved by the factorisation method | |
| 29215. |
If x=r sinA cosC ,y= r sinA sinC and z=r cosA,prove that r^2=x^2+y^2+z^2 |
| Answer» X 2 + y 2 +Z 2 = R2 ( cos 2C * sin 2 C) + R2 ( sin 2A * sin 2C) + R2 cos 2A = R2 * sin 2A ( cos 2 C + sin 2 C) + R2 cos 2 A = R2 sin2A * 1 + R2 * cos 2A = R2 (sin2A + cos 2 A) =R2 * 1 X 2 + y 2 + Z 2 = R2 Hence proved Hope this may help uh!! | |
| 29216. |
CosA = p^2 - 1 - - - - - - - - p^2 + 1 |
| Answer» | |
| 29217. |
Solve for a and b a /x-b + b/x-a =2 |
| Answer» The given equation can be rewritten as{tex}\\frac { a ( x - a ) + b ( x - b ) } { ( x - b ) ( x - a ) } = 2{/tex}a(x -a) + b(x- b) = 2[x2 - (a + b)x + ab]ax- a2\xa0+ bx - b2 = 2x2- 2(a + b)x + 2ab2x2- 3(a + b)x + (a + b)2 = 02x2 - 2(a + b) x - (a + b)x + (a + b)2 = 0{tex}2x[x-(a+b)]-(a+b)[x-(a+b)]{/tex}[2x - (a + b)] [x - (a + b)] = 0{tex}x = a + b , \\frac { a + b } { 2 }{/tex} | |
| 29218. |
Solve for a and b a/x-b +b/x-a =2 |
| Answer» The given equation can be rewritten as{tex}\\frac { a ( x - a ) + b ( x - b ) } { ( x - b ) ( x - a ) } = 2{/tex}a(x -a) + b(x- b) = 2[x2 - (a + b)x + ab]ax- a2\xa0+ bx - b2 = 2x2- 2(a + b)x + 2ab2x2- 3(a + b)x + (a + b)2 = 02x2 - 2(a + b) x - (a + b)x + (a + b)2 = 0{tex}2x[x-(a+b)]-(a+b)[x-(a+b)]{/tex}[2x - (a + b)] [x - (a + b)] = 0{tex}x = a + b , \\frac { a + b } { 2 }{/tex} | |
| 29219. |
Sina+sinb+sinc=3then cosa+ cosb+cosc=_____________ |
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| 29220. |
In an Ap the sum of n terms is 1/2(5n square+3n) find its 40 th term |
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| 29221. |
In the given figure . Find the perimeter of triangle ABC if AP=10cm |
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Answer» ???? Where is figure????? |
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| 29222. |
What is the probability that a leap year selected at random will be 53 Thursdays ? |
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Answer» 2/7 is the correct answer What is correct answer 12/91 Ur welcome anny Thanks Hasti ..Got it ?? There are 52 weeks (365 days) in a year....The last 366 th day can be one of this :1.monday2.tuesday3.wednesday4.thursday5.friday6.saturday7.sundaySo probability of last day being Thursday can be 2/7.....I hope u understood.... ? No prblm Thanks...? 2/7 Easy.. if u divude 366 by 7 than tha remainder is 2.. so there will be 2 prob of each day.. so 2/7 Okay Wait 2\\7 Hasti how to solve it? Probability is 2/7 |
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| 29223. |
If sec A = 2/root3 find the value of tanA/cosA +1+sinA/TanA |
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Answer» Friend one way is there.Here sec A =2/√3 is given so according to this u can find all tanA ,sinA,cosA etc.and then u put these values in the given equation. 8 answer I don\'t know how to solve....can any one help me |
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| 29224. |
Chapter 9 mai sin ki or tan ki value kab lagate hai koi samja do mujhe |
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Answer» See example no. 1 on pg.198 Example bhi de do koi Ek ecle bhi de do please If we have to find the value of perpendicular upon hypo then apply sin and if we have to find the value of perpendicular upon base than apply tan. It depends on values given to you of the figure...... If sides opposite to given angle or angle to be found and hypotenuse are given than use sin..... If sides opposite to and adjacent to given angle are given than use tan... |
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| 29225. |
Find the zeros of the polynomial x^3-7x +6 |
| Answer» 1 or 6 | |
| 29226. |
Are you all doing ncert only for maths?These exams are frustrating! |
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Answer» From RD sharma Noo!! |
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| 29227. |
If cos(a+b)=0 then sin(a-b)=? |
| Answer» cos 2b | |
| 29228. |
Experment |
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Answer» Ask properly ur ques!!! ?? |
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| 29229. |
How to write practil note book |
| Answer» With hand???? | |
| 29230. |
1 upon 8 minus 1 upon 20 |
| Answer» 3upon 40 | |
| 29231. |
Ozymandias was very cruel, arrogant, ruthless king |
| Answer» Yes. Ozymandias was a cruel, arrogant and a ruthless king as he was very proud of his dominant power and he considered himself as the greatest and the mightiest king among all the other kings. | |
| 29232. |
Hii frnds....Tum logo ka science and maths me kitna prepare hua |
| Answer» Main fail is baat bhai. | |
| 29233. |
Koi mera friend banega |
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Answer» Khan bna ga bhai Thanks app mrrfreind bani Yes offcourse |
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| 29234. |
Hello freind |
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Answer» Hello gies Kya kar rahe ho app log Hiii Hlo |
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| 29235. |
If one zero ofa polynomial 3x²-8x+2k+1 is seven times the other, find the value of k |
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Answer» Note- a=3 , b= -8 and c= 2k+1 2/3 but not sure. Thanks alpha =x and beta = 7x .then use formula alpha + beta to get the value of x . Then use formula alpha.bta to find k Phele ek ko x man ll uske bad dusre ko 7x man.ll fir ho gajga |
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| 29236. |
ब्रैकेट ओपन वनप्लस कौस स्क्वायर थीटा ब्रैकेट बंद ब्रैकेट ओपन 1 - 10 स्क्वायर थीटा |
| Answer» I Think -tan square theta but I haven\'t understand the question yet | |
| 29237. |
In a triangle ABC,it is given that DE |
| Answer» Plss complete the question | |
| 29238. |
Ax^3 +3x^2-13 and 2x^3-5x+2 have x-a as common factor ,find a |
| Answer» Let\xa0p(x) = ax3 + 3x2 - 13 and q(x) = 2x3 - 5x + a be the given polynomials.\xa0The remainders when p(x) and q(x) are divided by (x + 2) are p(- 2) and q(- 2) respectively.By the given condition, we havep(-\xa02) = q(-2){tex}\\Rightarrow{/tex}\xa0a(-2)3 + 3\xa0{tex}\\times{/tex} (-2 )2 - 13 = 2 {tex}\\times{/tex} (-2)3 - 5\xa0{tex}\\times{/tex} (-2) + a{tex}\\Rightarrow{/tex}\xa0-8a + 12 - 13 = - 16 + 10 + a\xa0{tex}\\Rightarrow{/tex}\xa0-8a - 1 = a - 6{tex}\\Rightarrow{/tex} -9a = - 5\xa0{tex}\\Rightarrow a=\\frac{5}{9}{/tex} | |
| 29239. |
Full form of SSS |
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Answer» Side side side criteria Side side side similarity |
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| 29240. |
kya iss bar ke board me maths ka paper easy hoga |
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Answer» Yes, absolutely .If you work hard..... It\'s said that this time it will be lengthy and hard.... Bt nt sure about it |
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| 29241. |
(SinA - 2Sin^2A)/(2Cos^3A-CosA)=tanA |
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Answer» Yes LHS=SinA (1-2sin2A)/cosA(2cos2A-1)=SinA (sin2A+cos2A-2sin2A)/ Cos A (2 cos2A- sin2A- cos2 A)=sinA ( cos2 A- sin2A)/ cos A ( cos2A- sin2A)= sinA/ cos A= tan ALHS=RHS In place of 2 sin^2A We have to take common..... The question us incorrect, i guess. It should be 2 sin^3A It\'s a 2 sin3A |
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| 29242. |
Hey everyone having tension of something? |
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Answer» ??????? yes bhut jada Ya |
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| 29243. |
Is the CBSE going to change syllabus for class 10 from 2018-19?? |
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Answer» ?? ????? Heyy,,dont use my second Name its is not for all??? Amrit ek failure dewana???? Ha shi...kaha bura lga...bechare ko...amrit.....chup hoja babu...rote nhi...haann. .jb..fail..karoge na tb..Ro.lena......olooelleele?? Jise fail hona wo yee sb puchta Hai... Example me shudhanshu??? Amrit ek pagal diwana??? Aur hamko tumpar doubt bhi hai...?? Ya Nhi...bhai...agar tu khi fail.ho gya to pakka lega...?? Sri hamare batch ka intzaar kar rahe the change karne ke liye Muje kya lena mai to chl gya abb??? Can be possible Ooo. Think not Yes but a little bit |
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| 29244. |
Your all subjects are ready... you are ll are not having any tensions about boards |
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Answer» Okk,bhai pdho sbb.??? Bahut tension ho rahi ha ...Exams ki Woh new pattern ke sath we r the 1st batch Bhai...mujhe bhi...ati hai...thori thori?? Glad ho gya exam ke tension mein isliye hindi bhojpuri dikh rahi ha I can ?? But I don\'t have any tension. ...mai sirf apne dosto ko tensions deta hu??? Mujese accha kon Bhojpuri bolega yha??? Why tension kuyn nahi ha Tension... Tension and only tension. I have Na bhojpuri ???? Okk,to Hindi hogi naa It\'s optional with it Hamko to ek dam tension nhi hai....?? Sanskrit bhi hota ha hamara toh nahi ha Noo...bhaut tension h!! Soo,much tension specispecially in sst and Sanskrit |
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| 29245. |
What is the melting point of diamond |
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Answer» 4726.85°C Answer de rha Hai bda scientists gysa??? Around 3550° C Tumko kya lena dena ....hai...Hai..bs...less hai...main kya...koi...scientist hu....... But dimond is hardeat substance.. How it melting point less than iron???#shudhanshu?? But friends I had heard somewhere that it\'s melting point is 3500 C ??? 700 degree Celsius 700 degree calcius |
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| 29246. |
Find the zeros of the quadratic polynomial X square + 7 x +12 |
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Answer» So easy yrr???,-4 &-3 -4, and -3 x=-3, - 4 |
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| 29247. |
Anne found a peter in Her Diary "Comment" |
| Answer» Anne was a very shy and introvert girl. She had friends but none with whom she could share her secrets. She never confided in any of them. On her thirteenth birthday, she was presented a red and white checkered diary by her parents. The first sight of the diary had made Anne grow a liking to it and she started making entry of her deep thoughts and feelings into it. She gave it a name "Kitty" and in all her entries, she had referred to it as "Dear Kitty". There was no aspect of her life which she had not mentioned in the diary. Whenever she found the\xa0time, she "spent" it with the diary. She confided about the teenage- desires, her friends, her fears, her loneliness. -in fact everything in the diary. She always felt a need of a\xa0true friend, which she could confide everything. She found that true friend in her Kitty. | |
| 29248. |
how to revise trignometry effectively |
| Answer» Formula ke ratte lgao | |
| 29249. |
How assumed mean find |
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Answer» By the formula : A+sigma fidi÷fi Where di = xi - A A = assumed mean Middle no of class interval |
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| 29250. |
Formula for finding zero of cubic polynomial |
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Answer» The outer covering of plant is epidermis What is epidermis Epiglottis locted in voice box Ok..amrit Tell me about epiglottis Eppoglotis is a lid which covers the larynx Can u tell what is epoglottis in science May come it is a optional exercise in ncrt....Anushka? Yes Use factor theorm method Sorry....but is it cubic polynomial is coming in boards |
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