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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 29301. |
Area of cylinder |
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Answer» Curved surface area is 2pai (r)(h) Apka followers ma h Kon h vo ? Sachin ?? Sachin kon h Yaa..Srishti.. LSA = 2πrh If its SA , then TSA = 2πr ^2 + 2πrh Oops sry... i thought of its volume... Devika πr ^2 h |
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| 29302. |
If A+B=90 and sec=5/3 then find the value of cosec B |
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Answer» Welcome ?? Thanx Oops...sry once again .???Cosec B =5/3 Cosec B = 3/4 Sry.. Then cosec B = 5/4 Sec a Hey...its sec A or B ? |
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| 29303. |
Solve the following pair of liner equation by the sumstitution method√3x+√5y=0√5x-√8y=0 |
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Answer» Answer will be - 1 Ans will be 0 becoz C term is already 0 |
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| 29304. |
3xx-6x-2 |
| Answer» Roots or zeroes are - 1/3 ,,, - 2 | |
| 29305. |
3x²—k√3x+4=0 |
| Answer» +_4 | |
| 29306. |
What is the name of the polynomial whose degree is 4? |
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Answer» Biquadratic Biquadratic polynomial biquadratic |
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| 29307. |
If Sn is denoted the first term of an AP.Prove that S12=3(S7-S4). |
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| 29308. |
How to download this app from app store |
| Answer» You can download the app from here :\xa0https://play.google.com/store/apps/details?id=in.techchefs.MyCBSEGuide&referrer=utm_source=mycbse_home&utm_medium=link_home&utm_campaign=downloadApp | |
| 29309. |
Anyone serious about board exam |
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Answer» Hlo fashion girl ? Seriousness is careness First paper of life which can decide our future to serious hona padega Main to sahi karta hoon Sahi kiya Main to ho gaya Serious to hona padega Yes Yes I am only serious about exams |
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| 29310. |
In the adjoining fig ABCD is a square of did 6 cm.find the area of the shaded region |
| Answer» shaded region ??? | |
| 29311. |
How can we get value of tan60 GEOMETRICALLY?? A question from boards, 2009 |
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Answer» Welcome Thanx Utkarsh got it Take a equilateral triangle,and then draw a perpendicular to it......then tan©=P/B....... I know..... Bt geometrically YHA...... Not possible |
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| 29312. |
how many natural numbers are there between 200 and 500 which are divisible by 7 |
| Answer» Given: A.P. 203, 210, 217, ………., 497Here a = 203, d = 210 - 203 = 7\xa0and an = 497Now, an = a + (n - 1)d {tex}\\Rightarrow 497= 203 + ( n - 1 ) \\times 7{/tex}{tex}\\Rightarrow 497- 203 = ( n - 1 ) \\times 7{/tex}{tex}\\Rightarrow 294= ( n - 1 ) \\times 7{/tex}{tex}\\Rightarrow n - 1 = \\frac { 294} { 7 } = 32{/tex}{tex}\\Rightarrow{/tex}\xa0n = 33\xa0\xa0 | |
| 29313. |
What is the value of x |
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Answer» ???ohh Lucifer... I never had any ex,?????? 5 |
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| 29314. |
Write co ordinates of (2,-3) |
| Answer» ????? | |
| 29315. |
Convert it into rational number 0.3796 |
| Answer» 0.3796We know that 0.3796 can be converted into {tex}\\frac{p}{q}{/tex}While, converting 0.3796 into {tex}\\frac{p}{q}{/tex} form, we get{tex}0.3796 = \\frac{{3796}}{{10000}}{/tex}The rational number {tex}\\frac{{3796}}{{10000}}{/tex}can be converted into lowest fractions, to get {tex}\\frac{{949}}{{2500}}{/tex}We can observe that 0.3796 can be converted into a rational number.Therefore, we conclude that 0.3796 is a rational number. | |
| 29316. |
Find the distance from x axis in (2,-3)? |
| Answer» 3 unit | |
| 29317. |
Root 23 is rational or irrational? Why or why not |
| Answer» Thus, {tex}\\sqrt { 23 }{/tex}\xa0= 4.795831523......{tex}\\because{/tex} The decimal expansion is non-terminating non-recurring.{tex}\\therefore{/tex}\xa0{tex}\\sqrt { 23 }{/tex}\xa0is an irrational number. | |
| 29318. |
If the side of the triangle is 4 root5 find the area of the triangle |
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Answer» No 40 It\'s 50 |
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| 29319. |
What happens to value of cos theta, when theta increase from 0 degree to 90 degree |
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Answer» Value kya hoga It decrease |
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| 29320. |
How to score 50 marks in maths |
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Answer» Haa.... Itne lane h padhne ki jarurt nhi h... Aise hi exam Dene jayo itna to aise hi aajayega Jo tumhe aata uski practice more karo What you only want to score 50 marks Just practice |
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| 29321. |
Express x in terms of a , b and c |
| Answer» \u200b\u200b{tex}\\triangle {/tex}\u200bABO \u200b{tex} \\bot {/tex}\u200b \u200b{tex}\\triangle {/tex}\u200bOCD\u200b{tex}\\Rightarrow {/tex}\u200b {tex}\\frac{x}{a} = \\frac{{x + b}}{c}{/tex}\u200b{tex}\\Rightarrow {/tex}\u200bx = ax + xb{tex}\\Rightarrow {/tex} x (c - a) = ab\u200b{tex}\\Rightarrow {/tex}\u200b {tex}x = \\frac{{ab}}{{c - a}}{/tex} | |
| 29322. |
Express x in terms of a, b and c. |
| Answer» \u200b\u200b{tex}\\triangle {/tex}\u200bABO \u200b{tex} \\bot {/tex}\u200b \u200b{tex}\\triangle {/tex}\u200bOCD\u200b{tex}\\Rightarrow {/tex}\u200b {tex}\\frac{x}{a} = \\frac{{x + b}}{c}{/tex}\u200b{tex}\\Rightarrow {/tex}\u200bx = ax + xb{tex}\\Rightarrow {/tex} x (c - a) = ab\u200b{tex}\\Rightarrow {/tex}\u200b {tex}x = \\frac{{ab}}{{c - a}}{/tex} | |
| 29323. |
Sin90°/cos45°+1/cosec30° |
| Answer» 5/2 | |
| 29324. |
Hii freinds |
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Answer» Hiii Hii Hlo |
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| 29325. |
F = |
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Answer» Frequency Frequency of middle class. |
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| 29326. |
If ?4/5,a,2 are three consecutive terms of an ap then find the value of a. |
| Answer» given 4/5 , a , 2 are in AP=> d = a - 4/5 = 2 - a=> 5a - 4 = 10 - 5a=> 10a = 14=> a = 7/5\xa0 | |
| 29327. |
Find the 11th term from the last term of the a.p 27, 23, 19, .....-65 |
| Answer» -25 | |
| 29328. |
Find the root of equation 2x^2 -7x+3=0 by the mathod of completing the square. |
| Answer» x = -3 , x = 1/2 | |
| 29329. |
(cosec - cot ) |
| Answer» 1-cos/sin | |
| 29330. |
In a triangle and,DE parallel BC.if AD:DB=3:5 then area of triangle DEC by area of triangle CFB |
| Answer» In \u200b\u200b{tex}\\triangle {/tex}\u200bADE and \u200b\u200b{tex}\\triangle {/tex}\u200bABC\u200b{tex}\\angle{/tex}\u200b 1 = \u200b{tex}\\angle{/tex}\u200b 1 [Common]\u200b{tex}\\angle{/tex}\u200b 2 = \u200b{tex}\\angle{/tex}\u200b ACB [Corresponding \u200b{tex}\\angle{/tex}\u200bs]\u200b\u200b{tex}\\therefore {/tex}\u200b\u200b\u200b{tex}\\triangle {/tex}\u200b\u200bADE \u200b\u200b{tex}\\sim{/tex}\u200b\u200b{tex}\\triangle {/tex}\u200b ABC [By A.A Rule]{tex}\\therefore {/tex}{tex}\\frac{{DE}}{{BC}} = \\frac{{AD}}{{AB}}{/tex}.....(i)Again in \u200b\u200b{tex}\\triangle {/tex}\u200bDEF and \u200b\u200b{tex}\\triangle {/tex}\u200bCFB\u200b{tex}\\angle{/tex}\u200b 3 = \u200b{tex}\\angle{/tex}\u200b 6 [Alternate \u200b{tex}\\angle{/tex}\u200b s]\u200b{tex}\\angle{/tex}\u200b 4 = \u200b{tex}\\angle{/tex}\u200b 5 [Vertically opposite \u200b{tex}\\angle{/tex}\u200b s]\u200b{tex}\\therefore {/tex}\u200b\u200b\u200b{tex}\\triangle {/tex}\u200b\u200b DFE \u200b{tex} \\sim {/tex}\u200b\u200b{tex}\\triangle {/tex}\u200b CFB [By A.A Rule]\u200b{tex}\\therefore {/tex}\u200b{tex}\\frac{{area\\left( {\\triangle DFE} \\right)}}{{area\\left( {\\triangle CFB} \\right)}} = \\frac{{D{E^2}}}{{B{C^2}}} = {\\left( {\\frac{{AD}}{{AB}}} \\right)^2}{/tex}[From (i)]{tex}= {\\left( {\\frac{5}{9}} \\right)^2}\\left[ {\\because \\frac{{AD}}{{DB}} = \\frac{5}{4} \\Rightarrow \\frac{{AD}}{{AD + DB}} = \\frac{5}{{5 + 4}} \\Rightarrow \\frac{{AD}}{{DB}} = \\frac{5}{9}} \\right]{/tex}\u200b{tex}\\therefore {/tex}\u200b{tex}\\frac{{area\\left( {\\triangle DFE} \\right)}}{{area\\left( {\\triangle CFB} \\right)}} = \\frac{{25}}{{81}}{/tex} | |
| 29331. |
Sec0 -tan0 =root under 2 tan0 then show that sec0 +tan0 =root under 2 sec0 |
| Answer» | |
| 29332. |
LOVE THEM |
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Answer» is baar ni hua bro one direction yrr ???? |
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| 29333. |
Find hcf of the numbers:.. K, 2k,3k,4k,5k..where k is any positive integer |
| Answer» Hcf = k | |
| 29334. |
Let d be the H.C.F of 24 and 36. Find two numbers a and b such that d=24a+36b |
| Answer» Let d be the HCF of 24 and 36.24 = 23{tex}\\times{/tex}336 = 22{tex}\\times{/tex}32HCF = 22{tex}\\times{/tex}3 = 12{tex}\\Rightarrow{/tex}{tex}d = 12{/tex}Now {tex}d = 24a + 36b{/tex}{tex}12 = 24a + 36b{/tex}When\xa0{tex} a = -1{/tex} and {tex}b = 1{/tex}, we get12 = 24{tex}\\times{/tex}(-1) + 36{tex}\\times{/tex}(1)= -24 + 3612 = 12So, a = -1 , b = 1 satisfy the equation d = 24a + 36b{tex}\\therefore{/tex} One possible value of a and b is -1 and 1. | |
| 29335. |
Proof of area of an equilateral triangle whose side is a. |
| Answer» \'a\' = a, \'b\' = a, \'c\' = a{tex}\\therefore{/tex}{tex}s=\\frac{^{\\prime} a^{\\prime}+b^{\\prime}+^{\\prime} c^{\\prime}}{2}{/tex}s =\xa0{tex}\\frac{a+a+a}{2}{/tex}\xa0=\xa0{tex}\\frac{3a}{2}{/tex}\xa0{tex}\\therefore{/tex}\xa0Area of the equilateral triangle=\xa0{tex}\\sqrt{s\\left(s-\' a^{\\prime}\\right)\\left(s-^{\\prime} b^{\\prime}\\right)\\left(s-^{\\prime} c^{\\prime}\\right)}{/tex}=\xa0{tex}\\sqrt{\\frac{3 a}{2}\\left(\\frac{3 a}{2}-a\\right)\\left(\\frac{3 a}{2}-a\\right)\\left(\\frac{3 a}{2}-a\\right)}{/tex}=\xa0{tex}\\sqrt{\\frac{3 a}{2}\\left(\\frac{a}{2}\\right)\\left(\\frac{a}{2}\\right)\\left(\\frac{a}{2}\\right)}{/tex}=\xa0{tex}\\frac{\\sqrt{3} a^{2}}{4}{/tex}\xa0square units. | |
| 29336. |
3sinα + 5cosα = 5, prove that ( 5sinα - 3cosα ) = ±3 . |
| Answer» | |
| 29337. |
Hey guys sb ki kaise preparation hai board ke liye |
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Answer» Hasti tho tho tum top karogi Full on All is well . |
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| 29338. |
13+ |
| Answer» ????? | |
| 29339. |
67,+123 |
| Answer» 190 | |
| 29340. |
What is similarity |
| Answer» Triangles said to be similar if they have same angles and ratio of sides are proportional lly same | |
| 29341. |
A piggy bank contains 50 |
| Answer» What ? | |
| 29342. |
dusri crush ye hai love her too |
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Answer» Isme kon sii bdi batt h??? hiba nawab hai ye yrr sab tv mai aati hai Ise mai janti hu. Bohot cute h ye Bta do Yaa par kaise kiya Harsh bta de please Kaise kar rahe ho bhai?? Kaisa kia |
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| 29343. |
Aap sb ki favourite |
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Answer» Are ye toh priya hai sorry AA but its a secret Ye kaise kiya bhai?? Alia h kya ye Bekar Ye kaise kiya ?????? |
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| 29344. |
Sm=sn to prove s(m+n)=0 |
| Answer» | |
| 29345. |
MY crush\xa0sooooo cuteeeee love her\xa0 |
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Answer» Accha to mycbseguide 0e jakr gmail se login kre... na gmail se sinthi ??? Harsh bta.... Naa yaar. Iske lye fb se connect krna hota h... Kya?? Hame bhi Batao n please..... model hai yrr. yee ???? SECRET TRICK Accha mujhe laga Sach mai tumhari crush h Are nahi Ye tumne kiya kaise yrr ye model hai yrr or mujhe se 10 years bdi hai lol batao n harsh please Alia ko gussa ayega na phir Ooo Are apne photo kaise dali Nice but ye hua kaise na asma shah hai ye i love her Who is she Alia hai kya |
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| 29346. |
Rangan 90 |
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Answer» Not defined What is this |
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| 29347. |
1- |
| Answer» ?? | |
| 29348. |
find the Valueofx |
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Answer» Equation kha h ?? |
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| 29349. |
Prove that the tangent drawn at end point of a chord of a circle make equal angle with the chord |
| Answer» Let AB be a chord of a circle whose centre is 0. Let PA and PB be tangents to the circle at A and B respectively. Then,PA = PB [{tex}\\because{/tex} Tangent segments from an external point to a circle are equal]In\xa0{tex}\\triangle{/tex} PAB,{tex}\\angle{/tex}PAB = {tex}\\angle{/tex}PBA [Angle opposite to equal sides of a triangle are equal] | |
| 29350. |
BAE GOALS\xa0YRR ITS KINDS DIFFERENT FEEL\xa0DOING THIS |
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Answer» Isme itna maza nhi jitna poori duniya ko apne neeche jhukaane me aata hai...????? How r u doing this?? Plz bata do Ab kya kbse pics hi upload krna h kya ? Abb bta bhi de |
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