InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2901. |
Prove that altitudes of a triangle are concurrent. |
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| 2902. |
Formulas of chapter AP |
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Answer» Sn=n/2 [2a+(n-1)d] An=a+(n-1)D |
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| 2903. |
write the general form of positive even integer |
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| 2904. |
Sir I want to know about surface area or volumes |
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| 2905. |
How can we multiple 3 root2 and root 3? |
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| 2906. |
X×X |
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| 2907. |
Express 3825 as product of prime factor |
| Answer» 5*5*3*3*17 | |
| 2908. |
Merry Christmas to all of u |
| Answer» Ambani..... | |
| 2909. |
Area of triangle A2,2 B 3,3 |
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| 2910. |
Solve for ×1|2a+b+2×==1|2a+1|b+1|2× |
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| 2911. |
Abc is a triangle in which D,e,f are the mid point of abc. A=0,-1 B 1,0 D=1,0 E=0,1 |
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| 2912. |
How to solve median of less than frequency |
| Answer» By adding all fiquencies | |
| 2913. |
The length of tangents drawn from an external point to a circle are equal |
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Answer» We are given a circle with centre O , a point P lying outside the circle and two tangents PQ , PR on the circle from P. We are required to prove that PQ = PROQ=OR (radii of circle)OP=OP (comman)Triangle OQP ~ORP (RHS)PQ = PR (CPCT) It\'s a theoram |
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| 2914. |
Merry christmas to all of you??????? |
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| 2915. |
Merry Christmas to all my frnds |
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| 2916. |
Happy christmas to everyone ? ?? |
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| 2917. |
CBSE marking scheme ki baare mein kuch kaho |
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| 2918. |
Anybody is here to be my friend. |
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Answer» I m here too Yaa I\'m here Yes I am here |
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| 2919. |
If p(e) =0.05 what is probability of \'not \'e ? |
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Answer» 1-0.05=19/20 0.95 0.95 0.95 0.95 |
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| 2920. |
Find x and y |
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| 2921. |
I need more sample papers in all subjects .Please agree with my request. |
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| 2922. |
What is the pattern of paper |
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| 2923. |
Kal maths ka paper hai Kya karun |
| Answer» R. D. Sharma solve kr lo | |
| 2924. |
What is Combsit number |
| Answer» it have more than 2 factors | |
| 2925. |
Easy trick to learn trigonometry table |
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| 2926. |
Composit number |
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Answer» A whole number that can divide by 1 and itself evenly by other no. Ex 9 it can be divided by 1 , 9 and 3 Number divisible by 2 |
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| 2927. |
A bicycle makes 10000 revolution in moving 22km. Find the circumference of the wheel? |
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| 2928. |
Prove that cos thita -sin thita+1/cos thita +-sin thita-1 =cosec thita+cot thita |
| Answer» Cos /sin - sin /sin +1/sin %cos /sin +sin /sin - 1/sin =cot - 1+cosec /cot +1-cosec =cot +cosec - (cosec 2-cot2)/cot - cosec +1=cot +cosec - (cosec +cot) (cosec - cot) /(cot - cosec) +1=cot +cosec-(-1)/1=cot +cosec | |
| 2929. |
Sahil sabse baat kar me ke lite net tha an khatam |
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| 2930. |
A vertical pole of length 6cm castsa shadow 4m long on the ground |
| Answer» Let AB denoted the vertical pole of length 6m.BC is the shadow of the pole on the ground BC = 4m.Let DE denote the tower.EF is shadow of the tower on the ground.EF = 28 m.Let the height of the tower be h m.In {tex}\\triangle {/tex}ABC and {tex}\\triangle {/tex}DEF,{tex}\\angle{/tex}B = {tex}\\angle{/tex}E ......[Each equal to 90o because pole and tower are standing vertical to the ground]{tex}\\angle{/tex} C = {tex}\\angle{/tex} F .....[Same elevation]{tex}\\angle{/tex}A = {tex}\\angle{/tex}D {tex}\\because {/tex} shadows\xa0are cast at the same time{tex}\\therefore {/tex}{tex}\\triangle {/tex}ABC and {tex}\\triangle {/tex}DEF,{tex}\\angle{/tex}B= {tex}\\angle{/tex} E ............[Each equal to 90o because pole and tower are standing vertical to the ground.]{tex}\\angle{/tex}A={tex}\\angle{/tex}D ({tex}\\because {/tex}shadows\xa0are cast at the same time){tex}\\therefore {/tex}{tex}\\vartriangle {/tex}ABC ~{tex}\\vartriangle {/tex}DEF ......(AA similarity criterion){tex}\\therefore {/tex}{tex}\\frac{{AB}}{{DE}} = \\frac{{BC}}{{EF}}{/tex} ...........[{tex}\\because {/tex} corresponding sides of two similar triangles are proportional]{tex}\\Rightarrow {/tex}{tex}\\frac{6}{h} = \\frac{4}{{28}}{/tex}{tex}\\Rightarrow {/tex}{tex}h = \\frac{{6 \\times 28}}{4} \\Rightarrow h = 42{/tex}Hence, the height of the tower is 42 m | |
| 2931. |
What is the HCF of the smallest composite number and the smallest prime number |
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Answer» 2 2 2 |
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| 2932. |
25-24 (100-120) 555+518=5510 |
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| 2933. |
The king of diamonds in playing cards |
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| 2934. |
Page no.167 of evergreen 100%success of maths question no. 2 |
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| 2935. |
1÷(x_1)(x_2)+1÷(x-2)(x_3)=2÷3 (find value of x) |
| Answer» -34/3 | |
| 2936. |
Check whether 6n can end with the digit 0 where n is any natural number |
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| 2937. |
Find the eleventh term from last by AP 27 23 19 ....-65 |
| Answer» Ans. Is - 25 | |
| 2938. |
All formula of CH 12&13 |
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| 2939. |
Find the co-ordinate in Y-axis which is nearest to the point (-2,5)? |
| Answer» (0,5) | |
| 2940. |
Show that any positive odd integer is of the form of 6q+1,or6q+3,or 6q+5,where q is some integer |
| Answer» Let a be any positive integer and b = 6∴ by Euclid’s division lemmaa = bq + r, 0≤ r and q be any integer q ≥ 0∴ a = 6q + r,where, r = 0, 1, 2, 3, 4, 5If a is even then then remainder by division of 6 is 0,2 or 4Hence r=0,2,or 4or A is of form 6q,6q+2,6q+4As, a = 6q = 2(3q), ora = 6q + 2 = 2(3q + 1), ora = 6q + 4 = 2(3q + 2).If these 3 cases a is an even integer.but if the remainder is 1,3 or 5 then r=1,3 or 5or A is of form 6q+1,,6q+3 or,6q+5Case 1:a = 6q + 1 = 2(3q) + 1 = 2n + 1,\xa0Case 2: a = 6q + 3 = 6q + 2 + 1,= 2(3q + 1) + 1 = 2n + 1,\xa0Case 3: a = 6q + 5 = 6q + 4 + 1= 2(3q + 2) + 1 = 2n + 1This shows that odd integer is of the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer. | |
| 2941. |
Find the 25 term of the ap -5 ,4 6 |
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Answer» Yes it\'s not an AP........ Yes it\'s not an AP It is not an AP |
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| 2942. |
RIMSHA aa jao yrr |
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| 2943. |
Maths mein 9 check.ki taiyaari kaise karoon Kal maths ka paper hai |
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Answer» Yes but technical also Trigonometry so simple |
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| 2944. |
Hellooo ??friendss |
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| 2945. |
If sec a=5/4.verfy that= tan a/1+tan=sin a/sec a |
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| 2946. |
The 19th term of a.p is equal to three times its 6th term is 19 find the a.p |
| Answer» Let the first term of the A.P. be \'a\'.and the common difference be \'d\'.19th term of the A.P., t19 = a + (19 - 1)d = a + 18d6th term of the A.P., t6 = a + (6 - 1)d = a + 5d9th term of the A.P., t9 = a + (9 - 1)d = a + 8dt19 = 3t6{tex}\\Rightarrow{/tex}a + 18d = 3(a + 5d){tex}\\Rightarrow{/tex}a + 18d = 3a\xa0+ 15d{tex}\\Rightarrow{/tex}18d - 15d = 3a - a{tex}\\Rightarrow{/tex}3d = 2a{tex}\\therefore \\mathrm { a } = \\frac { 3 \\mathrm { d } } { 2 }{/tex}t9 = 19{tex}\\Rightarrow \\frac { 3 \\mathrm { d } } { 2 } + 8 \\mathrm { d } = 19{/tex}{tex}\\Rightarrow \\frac { 3 d + 16 d } { 2 } = 19{/tex}{tex}\\Rightarrow \\frac { 19 \\mathrm { d } } { 2 } = 19{/tex}{tex}\\Rightarrow{/tex}\xa0d = 2{tex}\\Rightarrow{/tex}a = 3t2\xa0= 3 + (2 - 1)2 = 5t3\xa0= 3 + (3 - 1)2 = 7The series will be 3, 5, 7...... | |
| 2947. |
Please give me latest blue print class 10 2017 -18 Q paper |
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| 2948. |
What is formula of distance |
| Answer» √(x1-x2)² + (y1-y2)² | |
| 2949. |
Kya itni jldi pre board hona chahiye ??????? |
| Answer» Hyyy sonali tumhare school me kitni br pre board hote h | |
| 2950. |
√3 is a solution of a quadric equtaion |
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