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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 29451. |
Bye guyss ???? |
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Answer» Are app ke batya kr na accha lagta ranha Gn dear gn Areee Yrr plz Matt jyo Byee Yrrmuja batt kr ne ha Byee |
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| 29452. |
Hello frndz |
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Answer» I\'m fine Hello???? hiihow are you Hello Hii |
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| 29453. |
Ifucb |
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Answer» Hello Kaha sa ho Hi kundan Hi Linda |
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| 29454. |
Pankaj chanchal are u here |
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Answer» yrr wo sb doston ki wajah se naam change kr rkha hu Brainly ki I\'d banao ysss yrr kahan thi abtk |
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| 29455. |
Pankaj |
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Answer» Accha h... ???? Pankaj I\'d bolo brainy ki Mannu pankaj aagaya yss mene bana liya h id brainly ka ?? |
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| 29456. |
The length of an arc of a circle with radius 12cm is 10πcm. The central angle of this arc is |
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Answer» 150 degree angle 5 may be |
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| 29457. |
sin6a-cos6a |
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Answer» Ye kya h?pura que likho So easy ???? |
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| 29458. |
Haisjshsjs |
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Answer» I have some dought in this topic thats why i have asked Kamaal ka ques pucha aapne... wah |
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| 29459. |
How you can prove 1+ cot2a =cosec2 a |
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Answer» Change sin in cos/sin.. And solve? It\'s easy |
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| 29460. |
1+sin²thita=3sin thita×cos thitaThen prove that tan thita=1or½ |
| Answer» Given, 1 + sin2\xa0θ = 3 sin θ cos θ, then we have to prove that tan θ = 1, or\xa0{tex}\\frac { 1 } { 2 }{/tex}.Now, lets take given trigonometric equation1 + sin2θ = 3 sinθ cosθ\xa0[Dividing by sin2\xa0θ 0n both sides]⇒\xa0{tex}\\frac { 1 } { \\sin ^ { 2 } \\theta } + \\frac { \\sin ^ { 2 } \\theta } { \\sin ^ { 2 } \\theta } = \\frac { 3 \\sin \\theta \\cos \\theta } { \\sin ^ { 2 } \\theta }{/tex}⇒ cosec2θ + 1 = 3 cotθ⇒ 1 + cot2θ + 1 – 3 cotθ = 0⇒ cot2\xa0θ – 3 cot θ + 2 = 0⇒ cot2\xa0θ – 2 cot θ –cot θ + 2 = 0⇒ cot θ(cot θ – 2) –1(cot θ – 2) = 0⇒ (cotθ – 2) (cot θ – 1) = 0⇒ cotθ – 2 = 0 or (cot θ – 1) = 0⇒ cotθ = 2 or cot θ = 1⇒ tanθ =\xa0{tex}\\frac { 1 } { 2 }{/tex}\xa0or tan θ = 1Either tan θ =\xa0{tex}\\frac { 1 } { 2 }{/tex}, or 1which is a required answer. | |
| 29461. |
1+sin² |
| Answer» -cos² | |
| 29462. |
Pankaj plss yaar tumhari I\'d bolo na |
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Answer» bhai kohli plzz leave ha pkchtk h mera username Mil gyi na. Ab apni bolo Suno pankaj tumhari I\'d ka password bhi dalo Pawanjhahaz1 |
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| 29463. |
Please give me all the formulas chapter wise |
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Answer» Go to maths section and revision part Read revision notes on this app |
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| 29464. |
Today i completed rd sharma after 4 months |
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Answer» But how Only in 4 months Are wah aman... ?? Me too Really Gr8 achievment..M ab soch rha kharidne ki?? Superb...? Congrats ??? |
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| 29465. |
Prove that sin theta/ 1- 1/sin theta + 1/sin theta / 1 - sin theta = 1 + sin theta 1/sin theta |
| Answer» LHS = {tex}\\sqrt { \\frac { 1 + \\sin \\theta } { 1 - \\sin \\theta } } + \\sqrt { \\frac { 1 - \\sin \\theta } { 1 + \\sin \\theta } }{/tex}{tex}= \\sqrt { \\frac { ( 1 + \\sin \\theta ) } { ( 1 - \\sin \\theta ) } \\times \\frac { ( 1 + \\sin \\theta ) } { ( 1 + \\sin \\theta ) } }{/tex}+\xa0{tex}\\sqrt { \\frac { ( 1 - \\sin \\theta ) } { ( 1 + \\sin \\theta ) } \\times \\frac { ( 1 - \\sin \\theta ) } { ( 1 - \\sin \\theta ) } }{/tex}{tex}= \\sqrt { \\frac { ( 1 + \\sin \\theta ) ^ { 2 } } { 1 - \\sin ^ { 2 } \\theta } } + \\sqrt { \\frac { ( 1 - \\sin \\theta ) ^ { 2 } } { 1 - \\sin ^ { 2 } \\theta } }{/tex}{tex}= \\sqrt { \\frac { ( 1 + \\sin \\theta ) ^ { 2 } } { \\cos ^ { 2 } \\theta } } + \\sqrt { \\frac { ( 1 - \\sin \\theta ) ^ { 2 } } { \\cos ^ { 2 } \\theta } }{/tex}\xa0{tex}[\\because sin^2\\theta+cos^2\\theta=1]{/tex}{tex}= \\frac { 1 + \\sin \\theta } { \\cos \\theta } + \\frac { 1 - \\sin \\theta } { \\cos \\theta }{/tex}\xa0{tex}= \\frac { 1 + \\sin \\theta + 1 - \\sin \\theta } { \\cos \\theta }{/tex}{tex}= \\frac { 2 } { \\cos \\theta }{/tex}=\xa0{tex}2sec\\theta{/tex}= RHS | |
| 29466. |
(1+sinA)÷cosA=? |
| Answer» SecA + tanA | |
| 29467. |
If alpha and beta are roots of ax^2 - bx+C = 0 then caculate alpha + beta |
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Answer» Gana galo bhai "main hoon bas yaah ma mere jisa koi he kaha" b/a Mai hoon Koi online hai tho krapaya uttar de -b/a is correct b/a |
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| 29468. |
ncube-n divisible by 6 |
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Answer» Hello Ruhi |
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| 29469. |
I want cbse guess paper of maths |
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Answer» U can get cbse sample papers on net too.. Solve evergreen sample papers..... |
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| 29470. |
Guyzz suggest me some tips to complete maths xam paper in less time....? |
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Answer» Thnx every1 for ur advice??? Use short trick of calculation. Stop wasting time in one question.... New comer...? Try to complete 1 sample paper in 2 hr Practice well Who r u |
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| 29471. |
How many of u started practicing sample paper |
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Answer» Me i had cmpketed math sample 1 in just 1 hour 13 min and only one ans was wrong ✌??? From tomorrow I\'ll start maths ?? Completed except maths |
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| 29472. |
Is ncert is sufficient for get 70 % marks |
| Answer» Yes | |
| 29473. |
If area of 2similar triangles are equal then prove that these triangles are congruent |
| Answer» Given:{tex}∆ABC\\sim∆PQR{/tex}and\xa0{tex}ar∆ABC=ar∆PQR{/tex}To prove:\xa0{tex}∆ABC\\cong∆PQR{/tex}Proof:\xa0{tex}∆ABC\\sim∆PQR{/tex}\xa0Also\xa0{tex}\\operatorname { ar } ( \\Delta A B C ) = \\operatorname { ar } ( \\Delta P Q R ){/tex}\xa0(given)or,\xa0{tex}\\frac { \\operatorname { ar } ( \\Delta A B C ) } { \\operatorname { ar } ( \\Delta P Q R ) } = 1{/tex}Or\xa0{tex}\\frac{AB^2}{PQ^2}=\\frac{BC^2}{QR^2}=\\frac{CA^2}{RP^2}=1{/tex}Or\xa0{tex}\\frac{AB}{PQ}=\\frac{BC}{QR}=\\frac{CA}{RP}=1{/tex}Hence we get thatAB=PQ,BC=QR and\xa0CA=RPHence\xa0{tex}∆ABC\\cong ∆PQR{/tex} | |
| 29474. |
The identity (a-b)whole square when we open it .the minus present in it is cutted by other minus |
| Answer» Then | |
| 29475. |
If 3cot °=2 show that (4cos°-3cos°) (2sin°+6cos°)=1 3 |
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Answer» 3cot°= Cot =3/2 means b/p then make a triangle mark b nd p find h then put according in asked que |
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| 29476. |
4+(-64)-(-43)=? |
| Answer» -17 | |
| 29477. |
The sum of the two consecutive odd number is 394. Find the numbers. |
| Answer» According to the question,the sum of the squares of two consecutive odd numbers is 394.Let the odd no. be 2x + 1{tex}\\therefore {/tex}\xa0Consecutive odd number = 2x + 1 + 2=2x + 3Now, according to question{tex}( 2 x + 1 ) ^ { 2 } + ( 2 x + 3 ) ^ { 2 } = 394{/tex}{tex}\\Rightarrow 4 x ^ { 2 } + 4 x + 1 + 4 x ^ { 2 } + 12 x + 9 = 394{/tex}{tex}\\Rightarrow \\quad 8 x ^ { 2 } + 16 x - 384 = 0{/tex}{tex}\\Rightarrow \\quad x ^ { 2 } + 2 x - 48 = 0{/tex}{tex}\\Rightarrow \\quad x ^ { 2 } + 8 x - 6 x - 48 = 0{/tex}{tex}\\Rightarrow {/tex}\xa0x(x + 8) - 6(x + 8) = 0{tex}\\Rightarrow(x-6)(x+8){/tex}{tex}\\Rightarrow x=6, x=-8{/tex}-8 get rejected, hence{tex}\\therefore {/tex}\xa01st\xa0number =\xa0{tex}2 \\times 6 + 1{/tex}= 13\xa0and second odd number = 15 | |
| 29478. |
Find x(-4)+(-1)+2+.........+x=437 |
| Answer» (-4) + (-1) + 2 + 5 + ---- + x = 437.Now,-1 - (-4) = -1 + 4 = 32 - (-1) = 2 +\xa01 = 35 - 2 = 3Thus, this forms an A.P. with a = -4, d = 3,l = xLet their be n terms in this A.P.Then,Sn\xa0=\xa0{tex}\\frac { n } { 2 } [ 2 a + ( n - 1 ) d ] {/tex}{tex}\\Rightarrow 437 = \\frac { n } { 2 } [ 2 \\times ( - 4 ) + ( n - 1 ) \\times 3 ]{/tex}{tex}\\Rightarrow{/tex}\xa0874 = n[-8 + 3n - 3]{tex}\\Rightarrow{/tex}874 = n[3n - 11]{tex}\\Rightarrow{/tex}874 = 3n2\xa0- 11n{tex}\\Rightarrow{/tex}3n2\xa0- 11n - 874 = 0{tex}\\Rightarrow{/tex}3n2\xa0- 57n + 46n - 874 = 0{tex}\\Rightarrow{/tex}3n(n - 19) + 46(n - 19) = 0{tex}\\Rightarrow{/tex}3n + 46 = 0 or n = 19{tex}\\Rightarrow n = - \\frac { 46 } { 3 }{/tex}\xa0or n\xa0= 19Numbers of terms cannot be negative or fraction.{tex}\\Rightarrow{/tex}\xa0n = 19Now, Sn\xa0=\xa0{tex}\\frac { n } { 2 } [ a + l ]{/tex}{tex}\\Rightarrow 437 = \\frac { 19 } { 2 } [ - 4 + x ]{/tex}{tex}\\Rightarrow - 4 + x = \\frac { 437 \\times 2 } { 19 }{/tex}{tex}\\Rightarrow - 4 + x = 46{/tex}{tex}\\Rightarrow x = 50{/tex} | |
| 29479. |
The side of a square is 10cm. Find the area of circumscribed and inscribed circles. |
| Answer» Area of inscribed circle is 78.57 cm square (approx) | |
| 29480. |
Hello ppll!! |
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Answer» Hey Hii Hey.. Hlo new ?/ |
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| 29481. |
Show that an exactly no. N,n+2,n+3 is natural number |
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| 29482. |
Which book is best for eexams |
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Answer» Textbooks itself are best. But only for maths u can also refer together with question bank. Thanks to all I like rs agarwal And Ncert for clearing concept U - like And ncert NCERT IS THE BASIC ONE Oswaal sample papers |
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| 29483. |
anyone |
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Answer» ??? Koi bat nahi or doond le Bhai jis ldki ke maze le eha tha.. 12th ki nikli...???? KLPD??? bc hhawas ka pujari bc lol Khade l.nd par dokha bc..????? KLPD ye kya hai bhai?? Yes Bhai yaar mere saath KLPD ho gaya Present |
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| 29484. |
2x+32×55=0 |
| Answer» -880 | |
| 29485. |
cos45°÷sec30°+cosec30° |
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Answer» Using Cos45°=√2 Sec30°=2/√3 Cosec30°=2=2/2√3+2=2/2(√3+1)=1/(√3+1)Hope this helps...? Answer 2+ under root6/ 2 |
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| 29486. |
If sina1+sina2+sina3=3 then prove that the value of cosa1+cosa2+cosa3 |
| Answer» 3 root 3 | |
| 29487. |
ignorance\xa0 |
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Answer» Okk kkrh harsh kuch nahi yrr leave it I don\'t understand what you said What ignorance.... Harsh |
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| 29488. |
find the coordinate of point on y axis which is nearest to the point (-2,5) |
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Answer» how the solve plz show me in detail 0,5 |
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| 29489. |
Hello guys kaise ho |
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Answer» M bhi thik hu aap btao kaise ho aap log Sahi hai Hey aadhira me thikh hu or tum Mja ma |
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| 29490. |
riddhi sun uss stupid ko ignore kar |
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Answer» ☺☺ Are yrr whi baar baar paresaan kr rhi h MAI TOH IGNORE KAR RHA HU ;) Just leave it and chill Are choro na use.. Are yrr yek ladki h pagal aree ek pagal hai yha voh kuch bhi bolti rehti hai sabko Ok harsh just chill Kya hua Harsh bro? Hmmm woo wyse v pagal khane se avi just aayi h sayad tumhe nahi dear ek hai koi or Kon stupid kya mujhe bol rahe ho |
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| 29491. |
Hii friends this is shreyash |
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Answer» Hello Hii shreyash kaise ho Hi this is mehak how u shreyash |
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| 29492. |
Exam ki practice made chal rahi ha |
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Answer» Yes I m I am going to take science Kon sci Lana Wala ha |
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| 29493. |
Hi friends and raya |
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Answer» Hi fine Fine what about you How are you Hello adi |
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| 29494. |
How many subjects will come in 2018 class 10 board exams? |
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Answer» Agar aap computer loge toh it is compulsory In my not Is computer compulsory or not? Hindi A OR B. SST .ENGLISH. SCIENCE. MATHS.AND EXCEPTIONAL WHAT YOU CHOOSE Hindi, English, Science, S. st, Maths I have five Please tell the names of those compulsory subjects.. 5 6 subjects.in which one is exceptional See ur syllabus |
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| 29495. |
Tonight let’s get some and live while we’re youngone direction fever |
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Answer» Sunlenge Ok Heart attack song sune ho #1d love 1D❤? |
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| 29496. |
All u r ready for board exams |
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Answer» No preparing No ?? Yrs |
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| 29497. |
Hiiii frnds....study kaisi chllk rhi hai .....tum sbki?? |
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Answer» Meri v Achi or tumhari ? Me tooo ....iss tym ky study krr rhe ho....? Mst n u r |
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| 29498. |
Rational numbers between √2 and√3 |
| Answer» | |
| 29499. |
Find length of diagonal in rectangle BCDF if AC=6cm and CE=12 cm |
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| 29500. |
Jarun kumar |
| Answer» | |