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29801.

Hiii frnds r u here

Answer»
29802.

Find the value of p for which one root of the quadratic equation px^2-14x+8=0 is 6 times the other

Answer» Hay yaha per answer 3 diya ha par uska solution nahi diya
C/a = 8/ p =6P = 8/6=4/3
Here only given not solution
Here is given 3
No it\'s wrong answer
Kkkokk
Pls give solution
Ans to kr diya p=4/3
Hyy pls answer this
4/3
29803.

Explain why13233343563715 is a composite number

Answer» Yes it\'s right darshana
13233343563715 this number can divided evenly by 5 as well as 1 or itself thats why its become composite number
29804.

The sum of two number is 35 and difference is 9 find number

Answer» Let the number is x and y then sum =35 as x+y and there deference is 9as x-y so the ans. is x=22 and y=13
Sorry
23 abd 12
22 and 13
???????
29805.

Dekho tum school ki baatein school mein hi rehne do to achha hai

Answer» Main tumhe chhodungi nahi.
Us root ke saath ranraliya manaati hai.are sab sun lo ye ek no.ki kutti hai
Ok ok ok
Are ruk .kamini.kahan chali.us root ke paas kya.
Guys .bye.ye jo bhi bol raha hai jhootj jhooth hai.
Hey 2kaira r hers
Main kaun hoon tera order maanne waala
29806.

Are kaira kahan hai.baahar nikal.

Answer»
29807.

Hoe i remember that this formula is to be used in this sum ???

Answer» Wright all the things given in the ques. And then think that in which formula those all things come..
But which one
29808.

find the smallest 5 digit no. which is divisble by 12 or16 or 20

Answer»
29809.

Find the value of p for which one root of the quadratic equation px×x-14x+8=0 is 6 times the other

Answer» Let\xa0{tex}\\alpha{/tex}\xa0and\xa0{tex}6\\alpha{/tex}\xa0be the roots of equation.We have, {tex}px^2-14x+8=0{/tex} where a= p, b = -14, c = 8Sum of zeroes{tex} = -\\frac ba = -\\frac{-14}{p}{/tex}{tex}\\alpha +6\\alpha=\\frac{14}{p}{/tex}{tex}7\\alpha = \\frac{14}{p}{/tex}{tex}\\alpha = \\frac2p{/tex}............(i)Also, Product of the zeroes\xa0{tex} = \\frac 8p=\\frac ca{/tex}{tex}\\alpha \\times 6\\alpha = \\frac 8p{/tex}{tex}6\\alpha^2=\\frac 8p{/tex}From (i){tex}6(\\frac{2}{p})^2=\\frac 8p{/tex}{tex}6\\times \\frac {4}{p^2}=\\frac 8p{/tex}{tex}\\frac{6}{p^2}=\\frac2p{/tex}{tex}\\frac 62=\\frac{p^2}{p}{/tex}{tex}Hence, \\ p=3{/tex}
29810.

Find the value of p for which one root of the quadratic equation px

Answer» Let\xa0{tex}\\alpha{/tex}\xa0and\xa0{tex}6\\alpha{/tex}\xa0be the roots of equation.We have, {tex}px^2-14x+8=0{/tex} where a= p, b = -14, c = 8Sum of zeroes{tex} = -\\frac ba = -\\frac{-14}{p}{/tex}{tex}\\alpha +6\\alpha=\\frac{14}{p}{/tex}{tex}7\\alpha = \\frac{14}{p}{/tex}{tex}\\alpha = \\frac2p{/tex}............(i)Also, Product of the zeroes\xa0{tex} = \\frac 8p=\\frac ca{/tex}{tex}\\alpha \\times 6\\alpha = \\frac 8p{/tex}{tex}6\\alpha^2=\\frac 8p{/tex}From (i){tex}6(\\frac{2}{p})^2=\\frac 8p{/tex}{tex}6\\times \\frac {4}{p^2}=\\frac 8p{/tex}{tex}\\frac{6}{p^2}=\\frac2p{/tex}{tex}\\frac 62=\\frac{p^2}{p}{/tex}{tex}Hence, \\ p=3{/tex}
29811.

Find the values of k ,if the quadratic equation is 3x-k root 3+4 =0 has equal roots

Answer»
29812.

Factor of 1517

Answer»
29813.

marks below 10

Answer»
29814.

Hii koi h... shubham ritu??

Answer»
29815.

Solve ax+box=a-b bx-ay=a+bFor x and y

Answer» ax + by = a - b multiply by abx - ay = a + b multiply by b{tex}\\Rightarrow{/tex} x = 1{tex}\\therefore{/tex} a + by = a - bby = -by = -1{tex}\\therefore{/tex} x = 1y = -1
29816.

Prove that root 2+3 is a irrational.

Answer» If possible let {tex}3 + \\sqrt { 2 }{/tex} is rational number, and we take another rational number 2 for our calculation.{tex}\\Rightarrow ( 3 + \\sqrt { 2 } ) - 3 = \\sqrt { 2 }{/tex}\xa0( difference of two rational number is a rational number){tex}\\therefore \\sqrt { 2 }{/tex} is rationalThis contradicts the fact that {tex}\\sqrt { 2 }{/tex} is irrationalSince the contradiction arises by assuming that {tex}3 + \\sqrt { 2 }{/tex} is rational.Hence, {tex}3 + \\sqrt { 2 }{/tex} is irrational.
29817.

Simple method for learning formulae

Answer» ???
Yad to Karne he hai
29818.

Kon Kon last years ke papers kr rha h?

Answer» Ooo
Topper
OMG
3har sub
15
Kitne kr liye
Me
29819.

The sum of first n term of an ap is 3n2+4n find 25th term of this ap

Answer» 151
Shayad 80
29820.

Hey guys r u online

Answer» Hey sam
Hanji
Nahi we are without online
no
Hi kaha se ho
29821.

By any one online

Answer» I am from....delhi
Up And u Guy\'s
????
??
Hmm yar from where are you? ??
Byyy
29822.

Plzz explain section formulae?

Answer» √(X2-X1)^2+(Y2-Y1)^2
mx2+nx1/m+n my2+ny1/m+n
Book m h na ?
29823.

Modal paper for class 10 pree board

Answer» Net se nikal lo
29824.

Hhjjjn

Answer» Hey
29825.

What is the formula mean

Answer» O sorry that\'s o ly fixi
X=sigma fixing/sigma fi
29826.

Good bye frnd takecare

Answer» Tc
Gdbye..bt where are u going
29827.

Hiiii mainee

Answer» Kaha gye
29828.

Is it possible that two numbers can have LCM equals to 185 and HCF equal to 15

Answer» no the lcm must be divisible by hcf
No since lcm doesn\'t contain 3
29829.

important questions of math 10 class

Answer»
29830.

2tan 30°÷1_ tan^2 30°

Answer» Tan60°
29831.

Board me kis book me se ata hai

Answer» Ncert
BEST se
Ncert
Ncert se
Ncert book
Ncert
NCERT
29832.

Gf

Answer» Kya tum mei friend banogi
New friend
What means gf girlfriend ya ghost friend o sorry abb bura mat manna
Tu mari
29833.

Find all the zeros o f the polynomial x^3 + 3x^2 -4x - 12 ,if one of its zeros is -3

Answer» Other zeros are -2&2
29834.

san^4A-san^2A=tan^4+tan^2

Answer»
29835.

Trick of finding cube

Answer» Download maths trick app.
29836.

Benzenaldehyde plz ans the Q

Answer» Benzenaldehyde is an organic compound consisting of a benzene ring with a formal substituent it is the simplest aromatic aldehyde and one of the most industrially useful it is a cloudless liquid with a characteristics like doorFormula=C6H6O
C7H6O
C6H5CHO
Kitni baar puch chuka hu
Hi nishant
Kaunsa ques
29837.

Which book is best for practice rd sharma or rs agrawaal? ☺️

Answer» Agar one rahenge to n to book solve hogi or n hi rd ya agrawal
pk garg
Rd
Rs aggarwal is the best
Exam me to ncert se aa raha h to I think usse tum pad saktey ho
Thanks
Both are best. Practice kerne wale ke opper hota hai.
RD
29838.

Hello friends finally exams are coming

Answer» 6 march
When will ur exam starting from???
Accha hua bta Diya ?????Varna hm buul gaye the
We know that
29839.

Is tan A=n tanB and sin A=m sin B then prove cos2A= m2 - 1/n2-1

Answer» Rd sharma or rs ma dak la ha usma ya
29840.

How i get good marks in maths

Answer» Don\'t ask such kind of questions... stupid
Get yourself busy in mobile throughout the day
Practice
Practice. There is only one way.
29841.

Hello priyanka kumari wher

Answer» Ok but when she come again
She is doing study plz don\'t disturb her
29842.

Priyanka kumari here?

Answer» Which subject
Yes
Pdai me busy h vo abhi
29843.

Today match

Answer»
29844.

What is transpirational pull?

Answer» Kunaljit . Roy
Transpiration pull or the suction force is the force which aids in drawing the water upward from roots to leaves
It is a process by which water gets evaporated from the plants through stomata
I know
I don\'t know
Kunaljit kahan ho!!!!!!?????
29845.

If the Mth term of an AP is 1/n and Nth term is 1/m ,then show that the sum of MN terms is 1/2(MN+1)

Answer» A+(m-1)d=1/n. And. A + ( n-1)d =1/m...................An+mnd-dn=1. And. Am + mnd - dm = 1.......equating both these equations.........An+mnd-dn=am+mnd-dn.....N(a-d)=m(a-d).....M=n.......Smn=mn/2×(2a+(mn-1)d)......Smn=mn/2×(2a+mnd-d).......Smn=
Haa
Sirf ncert chalega
Rd se mt bnao..time waste hoga
also in Rs aggarwal
Rd ka question hai
29846.

Any one here of name riya kumari original one

Answer» Kya hua arpit..?
,????
Yaaa...
29847.

Hello?????????

Answer» Hlo ji hlo
29848.

prove that 4 minus root 5 root 3 is an irrational number

Answer»
29849.

Sin Q=

Answer» Opposite side to angle Q upon hypotenuse
29850.

In the given figure D is a point on AC such that AD=2CD rFkk DE || AB?

Answer» Given AD = 2CDSo AC = AD + DC = 2CD + CD = 3CDIn {tex}\\triangle{/tex}CDE and {tex}\\triangle{/tex}CAB,{tex}\\angle{/tex}C = {tex}\\angle{/tex}C (Common)and {tex}DE\\|AB{/tex}So {tex}\\angle{/tex}CDE = {tex}\\angle{/tex}CAB(Corresponding angles){tex}\\therefore{/tex}\xa0{tex}\\triangle{/tex}CDE\xa0{tex}\\sim{/tex}\xa0{tex}\\triangle{/tex}CAB (By AA similarity rule)Now,\xa0{tex}\\frac { \\operatorname { ar } ( \\triangle D C E ) } { ar( \\triangle A C B ) }{/tex},\xa0{tex}{/tex}={tex}\\frac{CD^2}{AC^2}=\\frac{CD^2}{(3CD)^2}=\\frac{1}{9}{/tex}