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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 30051. |
Sina ( 1+tana)+cosa(1+cota) |
| Answer» Coseca + seca | |
| 30052. |
Sino=oProve this |
| Answer» | |
| 30053. |
GM apeksha |
| Answer» Nahi hai abhi | |
| 30054. |
1.32333423574 is a composite no why |
| Answer» Bcoz it has more than two factors | |
| 30055. |
100 marks paper and 20 marks send by School we want to how many marks get in bord exam |
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Answer» For pass it is 27 It\'s depend on you |
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| 30056. |
Find the coordinates of the point on y axis which is nearest to the point -2,5 |
| Answer» 0 5 | |
| 30057. |
Prove that root2 is rational |
| Answer» Let us find the square root of 2 by long division method as shown below:{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt{2}{/tex}\xa0= 1.4142135.Clearly, the decimal representation of{tex}\\sqrt{2}{/tex}\xa0is neither terminating nor repeating. Hence, it is not a rational number. | |
| 30058. |
4+8(-5)-(-5)+3(5)-3+5(1)2=? |
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Answer» -9 9 |
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| 30059. |
Find the 7th term from the end of the ap 7,10,13,.......184 |
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Answer» We have,a = 7, d = 3, an = 184,n = ?Formula an=a+(n-1)d 184=7+(n-1)3184-7=(n-1)3177/3=(n-1)59=(n-1)n=59+1n=60According to the question,We have= a=7, d=3, n=7th,Formula an=a+(n-1)dan=7+(7-1)3an=7+(6)3an=7+18an=25 166 |
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| 30060. |
If two eqilateral triangle are similar prove that they are congruent |
| Answer» Given :\xa0ar\xa0{tex}\\triangle \\mathrm{ABC}{/tex}\xa0= ar\xa0{tex}\\Delta \\mathrm{PQR}{/tex}{tex}{/tex}To prove:\xa0{tex}\\triangle \\mathrm{ABC} \\cong \\triangle \\mathrm{PQR}{/tex}Since,ar\xa0{tex}\\triangle A B C=\\text { ar } \\triangle P Q R{/tex}\xa0(given){tex}\\frac{{\\Delta ABC}}{{ar\\Delta PQR}} = 1{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{{A{B^2}}}{{P{Q^2}}} = \\frac{{B{C^2}}}{{Q{R^2}}} = \\frac{{C{A^2}}}{{P{R^2}}} = 1{/tex}[Using Theorem of area of similar Triangles]{tex}\\Rightarrow{/tex}\xa0AB = PQ, BC = QR & CA = PRThus,\xa0{tex}\\triangle \\mathrm{ABC} \\cong \\triangle \\mathrm{PQR}{/tex} | |
| 30061. |
If two equilateral triangle are similar prove that they are congruent |
| Answer» Hlo | |
| 30062. |
Sallybus |
| Answer» | |
| 30063. |
Find the coordinates of point on y-axis which is nearest to the point(-2,5) |
| Answer» X= 0Y = 5 | |
| 30064. |
If cotA=7/8, then find the value of (1+sinA)(1-sinA)÷(1+cosA)(1-cosA) |
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Answer» 49/64 =1-sin²A/1- cos²A=cos²A/sin²A=cot²A=49/64 |
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| 30065. |
what is componendo and dividendo? |
| Answer» If a/b=c/d then a+b/a-b=c+d/c-d. | |
| 30066. |
Will this question given by this will come in exam |
| Answer» | |
| 30067. |
1245 |
| Answer» | |
| 30068. |
D=? |
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Answer» b^2 - 4ac b²-4ac |
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| 30069. |
The side of a square is 10 cm . Find the area of circumscribed and inscribed circles |
| Answer» Coi CCTV hm techno l CNN hmm dunno centennial | |
| 30070. |
For papers only ncert and rd sharma for paper |
| Answer» Ncert | |
| 30071. |
Area of major sector |
| Answer» 360 - ∆/ 360 * πr² | |
| 30072. |
Easy way of doing cross multiplication method |
| Answer» No way.... | |
| 30073. |
Oswaaaal books |
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Answer» Then who you are We see the most beautiful girls Oooh I didn\'t told to impress you Oh... I didn\'t ask that Kerala I am a malayali Ha toh |
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| 30074. |
Formula of centroid |
| Answer» X=x1+x2+x3/3Y=y1+y2+y3/3 | |
| 30075. |
How many sets will be published by Cbse throughout india |
| Answer» 16 sets | |
| 30076. |
M times the mth term is equal to nth time the n term find (m +n)th term |
| Answer» M×(a + DM -d )=n×(a+dn-d)...=>am -DM=an-dn...=>m(a-d)=n(a-d)....=>m=n....=>A(m+n)=a + Md + nd -d...=> | |
| 30077. |
A water |
| Answer» Oh so what to do | |
| 30078. |
Find the probability that in a leap year there will be 53 Tuesdays. |
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Answer» Sorry it\'s 2/7 /72 2/7 |
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| 30079. |
Are yr ye riddhi khandelwal Kon h. Bilkul shrm nhi h kya isko |
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Answer» Lekin sb fake nhi h bhai Mne socha ki yha kuch help ho jayegi study main and new friends bhi bn jaynge but yha toh fake frnds ?? Sorry Ok fine Yes what the hell is she doing She doesn\'t have sense to chat Or bhi bahoot log yha pe fake id leke ghum rahe hai so please unke kisi bhi post pe koi comments Mt karna Riddhi ki ma ki CH...........t She is a good girl but someone is misusing her id frm yesterday Vo fake hai Hoti to yha hota |
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| 30080. |
Hlooooo??? |
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Answer» Hm bhi mst h Nice and you Bdiaa Goid n u Kaise ho sb??????? Hii Hello Hii Hlo |
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| 30081. |
Ae sab sun lo main fake hoon aur ladka hoon.koi kaira vaira nhi |
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Answer» Nhi main prince hoon Mujhe pata h tum ishan goswami h? |
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| 30082. |
Are paul yahaan na boul varna teri maa ka bowl |
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Answer» Tu apne pura khandaan ka bowl Aur apni ma ka khol |
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| 30083. |
Cos4A=Sin(A-20) |
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Answer» A=22 Cos4A=Cos 20, 4A=20,A=5 sin(90-4a)=sin(a-20)90+20=a+4a110=5a110/5=a22=a |
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| 30084. |
Ek week baad said pprs r starting.....ek khararnak samaya....afraid hu....pass honga ya nahi...?? |
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Answer» Okzzz Be calm dear..and alwys keep a positive thinking?? |
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| 30085. |
Irratonal |
| Answer» | |
| 30086. |
Cosu/1+sinu=1-sinu/cosu |
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Answer» Correct answer LHS=cosu/1+Sinu=cosu/1+sinu×1-sinu/1-sinu.....cosu(1-sinu)/1-sin^2u....=cosu(1-sinu)/cos^2u......=1-sinu/cosu |
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| 30087. |
In value based questions how can we find out that hcf or lcm |
| Answer» | |
| 30088. |
Who loves rajvee Gandhi famous mused???? |
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Answer» Yes that\'s what I was thinking about our name... Yes and name is also quite similar na?? We are having soo many qualities similar right?? I |
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| 30089. |
Ncert unit 10 exercise 10.2 12th question is where |
| Answer» | |
| 30090. |
How to study all syllabus in short period of time of science? |
| Answer» Repeat your notes which u had been make...during school time | |
| 30091. |
Solve for x and y m+n=m |
| Answer» | |
| 30092. |
If the ratio of the sums 1st terms of 2 A. P is(7n+1):(4n+27),find the :of mth term |
| Answer» Let a, and A be the first terms and d and D be the common difference of two A.PsThen, according to the question,{tex}\\frac { S _ { n } } { S _ { n } ^ { \\prime } } = \\frac { \\frac { n } { 2 } [ 2 a + ( n - 1 ) d ] } { \\frac { n } { 2 } [ 2 A + ( n - 1 ) D ] } = \\frac { 7 n + 1 } { 4 n + 27 }{/tex}or,\xa0{tex}\\frac { 2 a + ( n - 1 ) d } { 2 A + ( n - 1 ) D } = \\frac { 7 n + 1 } { 4 n + 27 }{/tex}or,{tex}\\frac { a + \\left( \\frac { n - 1 } { 2 } \\right) d } { A + \\left( \\frac { n - 1 } { 2 } \\right) D } = \\frac { 7 n + 1 } { 4 n + 27 }{/tex}Putting,\xa0{tex}\\frac { n - 1 } { 2 } = m - 1{/tex}{tex}n-1 = 2m - 2{/tex}{tex}n= 2m - 2 + 1{/tex}or, {tex}n = 2m - 1{/tex}{tex}\\frac { a + ( m - 1 ) d } { A + ( m - 1 ) D } = \\frac { 7 ( 2 m - 1 ) + 1 } { 4 ( 2 m - 1 ) + 27 }{/tex}{tex}\\frac { a + ( m - 1 ) d } { A + ( m - 1 ) D } = \\frac { 14 m - 7 + 1 } { 8 m - 4 + 27 }{/tex}{tex}\\frac { a + ( m - 1 ) d } { A + ( m - 1 ) D } = \\frac { 14 m - 6 } { 8 m + 23 }{/tex}Hence,\xa0{tex}\\frac { a _ { m } } { A _ { m } } = \\frac { 14 m - 6 } { 8 m + 23 }{/tex} | |
| 30093. |
5. In an AP, if d= −2, n= 5 and Tn = 0, then find the value of a |
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Answer» 8 8 Sorry it\'s 8 8 8 -12 |
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| 30094. |
How we find mean |
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Answer» Ok Fixi/fi |
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| 30095. |
5. In an AP, if ? = −2, ? = 5 and ?? = 0, then find the value of ?. |
| Answer» Given:d = -2, n = 5 and an = 0We know that , an = a + (n - 1) d{tex}0 = a + (n - 1) d{/tex}{tex}[ a_n = 0]{/tex}{tex}0 = a + ( 5 - 1 ) (-2){/tex}0 = a + 4 {tex}\\times{/tex}\xa0- 2{tex}0 = a - 8{/tex}0 + 8 = aa = 8Hence, the value of a is 8. | |
| 30096. |
If the 7th term of an AP is -7 and comman difference is 5 find 18th term and general term |
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Answer» 48..... 18th term=48Nth term=5n-42 |
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| 30097. |
Find the first term and common difference of 0,- 4, - 8, - 12, ............ |
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Answer» A= 0 & D= -4-0=4 First term, a= 4...... common difference, d=-4 a=0,d=-4-0=-4 |
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| 30098. |
Find root of the quadratic equation by factorisation 2 X square + X - 6 is equal to zero |
| Answer» X= -3/2 ; x=2 | |
| 30099. |
Riddhi jadldi bol |
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Answer» Riddhi is not here Tell me riddhi jhut pyarrr ka naam karti hoo tell me first I want answer from u telllll meeee Riddhi nhi aaigi chalie bhagie |
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| 30100. |
Find the least number that is divisible by all the numbers from 1 tof 10 |
| Answer» We have to find the least number that is divisible by all numbers between 1 and 10(both inclusive).The required number is LCM of 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10.{tex}\\therefore{/tex}LCM= 2{tex} \\times{/tex}2{tex}\\times{/tex} 3{tex} \\times{/tex} 2{tex} \\times{/tex} 2{tex} \\times{/tex} 5{tex} \\times{/tex}7 = 2520 | |