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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 30251. |
R u doing extra books other than ncert |
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Answer» I referee question bank rd rs, so on Nancy which books r u prefering Yes No Yes |
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| 30252. |
A school team won matches this year against 5matches won a last year. what is the percent increase? |
| Answer» ?????). | |
| 30253. |
Find tan 60 geometrically |
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Answer» √3 Root 3 |
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| 30254. |
I found trigonometry 8.4 exercise tuff is there anyone else who find it tuf |
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Answer» Practise more this exercise No it is very easy From ncert it is easy but from question bank it is tuff it has more than 90 questions No..it is not very hard...if u only think u can do Me Very very very very very very easy Yes i know Me? |
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| 30255. |
Find tha value of k for which that difference between tha root of that equation x²+kx+8=0 |
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Answer» 4 und. Root 2 Correct h K=4 under root 2 |
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| 30256. |
The perimeter of a triangle with vertices (0,4), (0,0), and (3,0) is |
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Answer» Bhai bs formula tel de 12 .... 12 units? |
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| 30257. |
Is there any of my friends who are not sleeping.? |
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Answer» Who r ur Friends ? Are you my friend Me |
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| 30258. |
Then ap is 2,3,4,5 what is its common difference |
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Answer» 1 Common difference is 1 It\'s 1 Sorry 1 2 1 |
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| 30259. |
Without using trigonometric tables evaluate the following cos |
| Answer» Cos = 1/ sec | |
| 30260. |
a³+b³= |
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| 30261. |
1/c=1/a+1/b |
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| 30262. |
Fgdfhtg |
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| 30263. |
What is the probability that a non leap year has 30 Tuesday |
| Answer» 0 | |
| 30264. |
Volume of frustum |
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Answer» Upr aa na Hmm bhai..hello..how is ur preparation going on..? Hlo,, shudhanshu 1/3 pie h (r1)sq + (r2)sq +r1+r2 Hmm? 1/3*π*h(R1²+R2²+R1*R2) |
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| 30265. |
Good morning wishes.....plzz pray for my maths pre baoerd exam schedulde for tday...???? |
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Answer» Thankssss Best of luck Its postponded All the best Yet u r pre boards r not over |
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| 30266. |
If cosθ - sinθ=Гsinθ, prove that cosθ+sinθ=Гsinθ |
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Answer» Square both sides You will find it in rd sharma |
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| 30267. |
Hey guys!!! |
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Answer» Hi Good morning Hii |
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| 30268. |
Harsh kapoor how are you??? |
| Answer» fine but uh?????name plz | |
| 30269. |
Any one from Karnataka |
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Answer» Were are \'you\' from No,sorry No |
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| 30270. |
Mr harsh kapoor how your studies going on??? |
| Answer» gud but aap kon???? | |
| 30271. |
Hello frnds gud morning |
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Answer» Gm.. Hi wassup Yaa Hu wassup |
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| 30272. |
Difference of two numbers is 5 and difference of their reciprocal is 1/ 10. Find the numbers |
| Answer» 10 and 5 | |
| 30273. |
Kunaljit kahan ho...... good morning |
| Answer» Khan h tu | |
| 30274. |
What is the probability that a non leap year has 53 monday |
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Answer» 1/7 Non leap year has 365 days that is 364 days +1 day extra so the extra day can be Monday, Tuesday, Wednesday... Sunday total outcome are 7 , favorable outcome that is Monday is 1 so probability that a non leap year has 53 Mondays is 1/7. 53/365 2 /7 |
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| 30275. |
7/50 find decimal expansion without long division |
| Answer» 7 / 2*5*5 = 7*2/2*2*5*5= 14/100=0.14 | |
| 30276. |
If Tan A = n tanB and sinA=m sinB prove that cosA =m-1/m+1 |
| Answer» Given,\xa0tan A = n tan B{tex} \\Rightarrow{/tex} tanB = {tex}\\frac{1}{n}{/tex}tan A{tex}\\Rightarrow{/tex}\xa0cotB =\xa0{tex}\\frac { n } { \\tan A }{/tex}..........(1)Also given,\xa0sin A = m sin B{tex}\\Rightarrow{/tex}\xa0sin B =\xa0{tex}\\frac{1}{m}{/tex}sin A{tex}\\Rightarrow{/tex}\xa0cosec B =\xa0{tex}\\frac { m } { \\sin A }{/tex}.....(2)We know that, cosec2B - cot2B = 1, hence from (1) & (2) :-{tex} \\quad \\frac { m ^ { 2 } } { \\sin ^ { 2 } A } - \\frac { n ^ { 2 } } { \\tan ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } } { \\sin ^ { 2 } A } - \\frac { n ^ { 2 } \\cos ^ { 2 } A } { \\sin ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } - n ^ { 2 } \\cos ^ { 2 } A } { \\sin ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow{/tex}\xa0m2 - n2cos2A = sin2A{tex}\\Rightarrow{/tex}\xa0m2 - n2cos2A = 1 - cos2A{tex}\\Rightarrow{/tex}\xa0m2 - 1 = n2cos2A - cos2A{tex}\\Rightarrow{/tex}\xa0m2 - 1 = (n2 - 1) cos2A{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } - 1 } { n ^ { 2 } - 1 } ={/tex}\xa0cos2A | |
| 30277. |
Hlo everyone ? ? gud mrng? ? |
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Answer» Fine Good morning how are you Hlo, gm Gud morning |
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| 30278. |
Express the hcf of 48 and 18 as linear combination |
| Answer» Let us find HCF of 48 and 18{tex}48 = 18 \\times 2 + 12{/tex}{tex}18 = 12 \\times 1 + 6{/tex}{tex}12 = 6 \\times 2 + 0{/tex}Hence HCF (48, 18) = 6Now, 6 = 18 - 12\xa0{tex}\\times{/tex}\xa016 = 18 - (48 - 18\xa0{tex}\\times{/tex}\xa02)6 = 18 - 48\xa0{tex}\\times{/tex}\xa01 + 18{tex}\\times{/tex}26 = 18\xa0{tex}\\times{/tex}\xa03 - 48\xa0{tex}\\times{/tex}\xa016 = 18\xa0{tex}\\times{/tex}\xa03 + 48\xa0{tex}\\times{/tex}(-1)i.e., 6 = 18x + 48y ........ (1)where x= 3, y = -1{tex}\\therefore{/tex}\xa06 = 18\xa0{tex}\\times{/tex}\xa03 + 48\xa0{tex}\\times{/tex}\xa0(-1)= 18\xa0{tex}\\times{/tex}\xa03 + 48\xa0{tex}\\times{/tex}\xa0(-1) + 18\xa0{tex}\\times{/tex}\xa048 - 18\xa0{tex}\\times{/tex}\xa048= 18(3 + 48) + 48(-1 - 18)= 18\xa0{tex}\\times{/tex}\xa051 + 48\xa0{tex}\\times{/tex}\xa0(-19)6 = 18x + 48y ...... (2)where x = 51, y = -19Hence, x\xa0and y are not unique. | |
| 30279. |
Chapter 13 surface area and volume all formulae |
| Answer» Check last page of chapter | |
| 30280. |
Hi guys are all prepated for exams |
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Answer» Yes i m not |
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| 30281. |
Kiska kiska maths prepare ho gya |
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Answer» Me Mera Mera bilkul nhi hua hai ..... |
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| 30282. |
If sec¶=x+1/4x then prove that sec¶+tan¶=2x or 1/2x |
| Answer» Tan2= sec2-1 =(x+1/4x)square-1 =x2+1/16x2-1/2(by a2+b2=(a+b)2-2ab)We get, (x-1/4x)=tanSec+tan=x+1/4x+x-14x =2x | |
| 30283. |
If A+B=90° and secA=5/3,then find value of CosecB |
| Answer» A+B=90°secA=5/3We can write A=90°-Bso; secA= 5/3cosec(90-A)=5/3cosec(90-(90-B))=5/3 ( Putting the value of A)cosec(90-90+B)=5/3CosecB=5/3 | |
| 30284. |
Floor of a room is dimensions 5m by 4m and it is covered with circular tiles |
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| 30285. |
2x-2=0 |
| Answer» 1 | |
| 30286. |
Hhajjs |
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| 30287. |
Solve the following quadratic equation for x: 4 √3x` + 5x 2√3=0 |
| Answer» (4x-√3) and ( √3x+2) =0 then x= √3/4and -2/√3. | |
| 30288. |
find the sum of 21 term of an ap whose middle term is 20 |
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Answer» 420. I dont Know |
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| 30289. |
Idhsksgek |
| Answer» ??????.). | |
| 30290. |
Byyeee frnds...raat me milte hai..take care |
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Answer» Hii Byee |
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| 30291. |
If cumulative frequency is given of more than type then how to find frequency |
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| 30292. |
Prove that x2 + y2 =1 if xsin3A + ycos 3A=sinAcosA. When xsinA = ycosA |
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Answer» Again sorry modi Sorry modified Rachna modified I can answer |
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| 30293. |
How to prepare the mensuration part of maths |
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Answer» Go to helll I hate maths And the maths student I hate you sona I like mesuration chapter... I can clear your doubt.. bt we all belongs to different state.. Mujhe to sabse difficult lagata h By learning formula But exam is near It is easiest part of mathematics By solving more and more questions |
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| 30294. |
In triangle ABC, DE||BC. AD=2x,DC=x+3,BE=2x-1andCE=x,then find the value of x. |
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Answer» Plzz u solve X=3 Gsssnsj |
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| 30295. |
What is formula of sphere? |
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Answer» 4/3 π R×R×R For volume =4/3 pi r^3.....and for surface area it is 4 pi.radius ^2 Surface area 4pie rsquare |
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| 30296. |
How find percentage of marks |
| Answer» | |
| 30297. |
Hllo... Frnds!!!!! |
| Answer» Hi | |
| 30298. |
What is perimeter ?? |
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Answer» Sum of all sides Sum of all sides |
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| 30299. |
Hey angel Sharma I are u there |
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Answer» Nischit u asked me for friendship not us gf Sorry kis baat ka nischit.. Look I am not ur gf I am ur friend only Bolo U have gf How are u Hi vaishnavi Sorry Nikhil come on Hi Mikhail come on |
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| 30300. |
Determine the set of values of p for which the quadratic equation px2+6x+1=0 has real roots |
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Answer» 9 Ans =9 ok P=9 B^2 -4ac vala formula lag jaega |
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