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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3001. |
Which book should I prefer to get 70 marks out of 80 in math |
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Answer» RD sharma Math exempler or ncert |
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| 3002. |
If 1 is the zero of the polynomial p(x)=ax sq -3(a-1)x-1, , then find the value of a |
| Answer» 1 | |
| 3003. |
If secA=x+1/4x , to prove that secA + tanA =2x or 1/2x |
| Answer» | |
| 3004. |
How to get 70 marks out of 80 in math in class 10 which book should I prefer and how to study |
| Answer» Buk doesn\'t matter the thing which matter is basic concept...N u will nt get 70/80 by asking to anyoneDo practise | |
| 3005. |
What are co prime no? |
| Answer» Having common factor 1 | |
| 3006. |
125 x square divided by 25 over 5 x square Axis care |
| Answer» | |
| 3007. |
The marks of 7 students are 70,73,72,76,74,80 and 84. Compute the appropriate central tendency |
| Answer» 75.57 | |
| 3008. |
Statement of Pythagoras theo |
| Answer» h²=p²+b² | |
| 3009. |
Perimeter and area |
| Answer» | |
| 3010. |
Anybody plz help me who have given ftre exam...in solving ques |
| Answer» | |
| 3011. |
Find the value of a ,b and c such that the number a,7,b,23 and c are in AP |
| Answer» {tex}a, 7, b, 23{/tex} and {tex}c{/tex} are in A.P.Let the common difference be d.{tex}a + d = 7{/tex} ....(i){tex}a + 3d = 23{/tex} ....(ii)From (i) and (ii), we get{tex}2d = 16{/tex}{tex}d = 8{/tex}Put d = 8 in (1) we get{tex}a + 8 = 7{/tex}{tex}a = -1{/tex}{tex}b = a + 2d{/tex}{tex}b = - 1{/tex} + 2 {tex}\\times{/tex}\xa08or,{tex} b = - 1 + 16{/tex}or, {tex}b = 15{/tex}{tex}c = a + 4d{/tex}= - 1 + 4 {tex}\\times{/tex}\xa08= - 1 + 32{tex}c = 31{/tex}{tex}\\therefore{/tex}\xa0{tex}a = - 1,b = 15, c =31{/tex} | |
| 3012. |
Find mean diameter of following circle 33-36=15,37-40=17,41-44=21,45-48=22,49-52=25. |
| Answer» \tDiametersClassesMid vales xifi{tex}u = \\frac{{x - 42.5}}{4}{/tex}fufu233-3632.5-36.534.515- 2- 306037-4036.5-40.538.517- 1- 171741-4440.5-44.542.52100045-4844.5-52.546.5221222249-5248.5-52.550.525250100\xa0\xa0\xa0100\xa025199\tMean\xa0{tex}(\\bar x) = A + \\frac{{\\Sigma fu}}{N} \\times h{/tex}{tex} = 42.5 + \\frac{{25}}{{100}} \\times 4{/tex}= 42.5 + 1 = 43.5 mmStandard deviation\xa0{tex}(\\sigma ) = \\frac{h}{N}\\sqrt {N\\Sigma f{u^2} - {{(\\Sigma fu)}^2}}{/tex}{tex} = \\frac{4}{{100}}\\sqrt {100 \\times 199 - {{(25)}^2}} = \\frac{1}{{25}}\\sqrt {19275}{/tex}{tex} = \\frac{1}{{25}} \\times 138.83{/tex} = 5.55 | |
| 3013. |
From which book all the question of mathematics asked |
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Answer» RD SHARIA AND ALSO NCERT And what about rs agarwall RD sharma is the best book |
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| 3014. |
Find 4/3tan^2 30degree + sin^2 60degree - 3cos^2 60degree + 3/4tan^2 20degree - 2tan^0 45degree |
| Answer» | |
| 3015. |
Two cones have their heights in the ratio 1:3 and radii 3:1 .what is the ratio of their volumes? |
| Answer» It is 3 : 1 | |
| 3016. |
7 tanA. +2/2tanA+7 evaluate ifsinA+cosA/sinA-cosA=5/3 |
| Answer» | |
| 3017. |
Find distance. Between point |
| Answer» | |
| 3018. |
Mode 47.5 and median 55.5 find mean |
| Answer» 3median= mode+2mean3(55.5)=47.5+2mean166.5=47.5+2mean166.5-47.5=2mean119/2=mean59.5=mean | |
| 3019. |
Solve for X: 6(√X/X+4) -2(√X+4/X) |
| Answer» | |
| 3020. |
Hiiiii bps r u online |
| Answer» | |
| 3021. |
Given a = 8, an = 62, sn = 210, find n and d. |
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Answer» n=6and d=10.8 Sn =n/2(a+An) 210 =n/2(8+62)210=n/2*70210*2/70=nn=6an=a+(n-1)d62=8+(6-1)d62-8/5=dd=54/5=10.8 n=6d=10.8 n=6 and d=10.8 n=6d=10.8 i think n will be 105/4 |
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| 3022. |
2sec square theta -sec4 theta -2cosec square theta +cosec4 theta= cot4 theta- tan4 theta |
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Answer» Isko solve kar lo 2(1+tan square thita)-(1+tan square thita)^2-2(1+cot square thita)+(1+cot square thita)^2 |
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| 3023. |
Show that 12n cannot end with digit 0 or 5 for any natural n |
| Answer» 12 = 22{tex}\\times{/tex} 3{tex}\\therefore 12^n=(2^2 \\times3)^n=(2^2)^n \\times3^n{/tex}\xa0So, only primes in the factorisation of 12n are 2 and 3 and, not 5.Hence, 12n cannot end with digit 0 or 5. | |
| 3024. |
Is -150 a term of AP 17,12,7,2 |
| Answer» \xa0The given term of arithmatic progression is17, 12, 7, 2, ......Here, a = 17, d = 12 - 17 = - 5 where a is first term and d is common differenceSuppose an = -150a + (n - 1)d = -150 {tex}\\Rightarrow{/tex}\xa017 + (n - 1)(-5) = -150{tex}\\Rightarrow{/tex}\xa0(n - 1)(-5) = -150 - 17 {tex}\\Rightarrow{/tex}\xa0(n - 1)(-5) = -167{tex}\\Rightarrow{/tex}\xa0n - 1 =\xa0{tex}\\frac { 167 } { 5 }{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0n =\xa0{tex}\\frac { 167 } { 5 }{/tex} + 1{tex}\\Rightarrow{/tex}\xa0n =\xa0{tex}\\frac { 167 + 5 } { 5 } = \\frac { 172 } { 5 } = 34 \\frac { 2 } { 5 }{/tex}wheren is not a whole number.{tex}\\therefore{/tex}\xa0-150 is not a term of the A.P. | |
| 3025. |
If A+B=90 Then prove that 1+cot square A=sec square B |
| Answer» A+B=90A=90-B1+cot square A=cosec squareAcosecA*cosecA=cosec(90-B)*cosec(90-B)secB*secB=sec squareB | |
| 3026. |
The product of two consecutive even natural numbers is 120. Find the numbers. |
| Answer» Let 1st no. be x and next no. be x+1.ATSX(x+1)=120Now solve this quadratic equation... | |
| 3027. |
Prove that √3 is irrational number |
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Answer» Let us assume that |
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| 3028. |
Can u think,19=8,17=9,9=4,27=11,30=6,what is 20=and16=? |
| Answer» | |
| 3029. |
(√3-1)(3-cot30°)=tan^30°-2sin^260° |
| Answer» We have to prove that:\xa0{tex}( \\sqrt { 3 } + 1 ){/tex}\xa0(3 – cot 30°) = tan3\xa060° – 2 tan 60°Here, LHS =\xa0{tex}( \\sqrt { 3 } + 1 ){/tex}\xa0(3 – cot 30°){tex}= ( \\sqrt { 3 } + 1 ) ( 3 - \\sqrt { 3 } ){/tex}{tex}= \\sqrt { 3 } ( 3 - \\sqrt { 3 } ) + 1 ( 3 - \\sqrt { 3 } ){/tex}{tex}= 3 \\sqrt { 3 } - 3 + 3 - \\sqrt { 3 }{/tex}{tex}= 2 \\sqrt { 3 }{/tex}RHS = tan3\xa060° – 2 sin 60°{tex}= ( \\sqrt { 3 } ) ^ { 3 } - 2 \\times \\frac { \\sqrt { 3 } } { 2 }{/tex}{tex}= 3 \\sqrt { 3 } - \\sqrt { 3 }{/tex}{tex}= 2 \\sqrt { 3 }{/tex}⇒ LHS = RHSHence, proved. | |
| 3030. |
Prime factor of 7429 |
| Answer» 7429=17 × 23× 19 | |
| 3031. |
2x+3y=? |
| Answer» | |
| 3032. |
which sample papers r better OSWAL or Arihant??? |
| Answer» | |
| 3033. |
Write a rational number between root2 and root3? |
| Answer» 1.416893 | |
| 3034. |
Write the exponent of 2 in the prime factorisation of 144 |
| Answer» Prime factorisation of 144 = 2×2 ×2\xa0×2\xa0×3\xa0×3{tex}144 = {2^4} \\times {3^2}{/tex}Therefore the exponents of 2 in prime factorisation of 144 is 4. | |
| 3035. |
Show that x=2, y=- is a solution of the linear equation 5x+3y=4 |
| Answer» 5*2+3*-2=410-6=44=4 | |
| 3036. |
I can type my question please check it |
| Answer» | |
| 3037. |
Excuseme please if you don\'t mind tell me the answer of my question |
| Answer» | |
| 3038. |
Find the sum of all even integers between 2 to 100 divisible by 2 |
| Answer» | |
| 3039. |
If the nth term of an AP is 2n+1, find sum of first m terms of an AP |
| Answer» n square + 2n | |
| 3040. |
How to evaluate trigonometry questionswithout using trigonometry tables |
| Answer» | |
| 3041. |
Square root of567 |
| Answer» 23.811..... | |
| 3042. |
The sum of 1st n terms of an AP is given by Sn=2n square+3n. Find the 16th term of AP. |
| Answer» 65 | |
| 3043. |
Find the 11 term from the last term ofthe AP:27,23,19,...,-65 |
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Answer» Sn = n%2[2a+(n-1)d = 11%2[2*27+(11-1)*-4] = 77 11 term from last is (-21) -25 |
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| 3044. |
BPS reply do yrr |
| Answer» | |
| 3045. |
How many students are coming here for chatting not for studies?? |
| Answer» So I can cancel all of ur permit | |
| 3046. |
BPS KYA HUA |
| Answer» | |
| 3047. |
exam date koi batayega |
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Answer» 8 march Release hogi january ke first week me |
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| 3048. |
ejevsjsvdkdbvddkdvskke |
| Answer» | |
| 3049. |
Find zeroes of xsquare-x+1and verify it also |
| Answer» | |
| 3050. |
sample question paper no. 4 |
| Answer» | |