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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3101. |
5÷0=? |
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Answer» Not define Infinity. 0 |
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| 3102. |
Plz give solutions of rd sharma also like other apps |
| Answer» Refer google. | |
| 3103. |
100*99 |
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Answer» 9900 9900 |
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| 3104. |
2+8888878 |
| Answer» 8888880 | |
| 3105. |
What are important questions in maths |
| Answer» All ? | |
| 3106. |
If p th term of an AP is q and q th term is p, then show that its n th term is (p+q-n) |
| Answer» Let \'a\' be the first term and d be the common difference of the given A.P.Then,according to question we have\xa0Tp = a + ( p - 1 )d and Tq = a + ( q - 1 )d.(where Tp\xa0and Tq\xa0are pth\xa0and qth\xa0terms\xa0of given A.P)Now, Tp = q and Tq=\xa0p (given).a + (p -1)d = q ...(i)and a + (q - 1) d = p ...(ii)On subtracting (i) from (ii), we get{tex}\\implies{/tex}(q-1)d-(p-1)d=p-q{tex}\\implies{/tex}qd-d-pd+d =p-q{tex}\\implies{/tex}(q - p)d = ( p - q ){tex}\\implies d=\\frac{p-q}{q-p}{/tex}{tex}\\Rightarrow{/tex}d = -1.Putting d = -1 in (i), we get a = (p + q -1).Thus, a = (p + q - 1 ) and d = -1.Therefore, nth term = a+ (n- 1)d = (p + q -1) + (n -1) {tex}\\times{/tex}\xa0(-1)=p+q-1-n+1\xa0= p + q - n.Hence, nth term = (p + q - n). Which is required answer. | |
| 3107. |
???????? HOPE ...!!!! ??????? |
| Answer» | |
| 3108. |
Latest syllabus syllabus of 2017-18 class 10 |
| Answer» Check Syllabus here :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 3109. |
2+7-72 |
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Answer» -63 -63 |
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| 3110. |
A square + C square + 4 B square + 2AC - 4AB - 4BC = 0 |
| Answer» | |
| 3111. |
Formula for finding area of sector in circle? |
| Answer» Theta/360*π(r) r | |
| 3112. |
Find sec^2 42-cosec^2 48 |
| Answer» | |
| 3113. |
Solve each of the following systems of equations by method of cross -multiplication NB |
| Answer» The given system of equations arex + ay = bSo, x + ay - b = 0 ........ (i)And ax - by = cSo, ax - by - c = 0 .......... (ii)The given equations are in form ofa1x + b1y + c1 = 0and a2x + b2y + c2 = 0Compare (i) and (ii),we geta1 = 1, b1 = a, c1 = -ba2 = a, b2 = -b, and c2 = -cBy cross-multiplication, we get{tex}\\Rightarrow \\frac{x}{{a \\times ( - c) - ( - b) \\times ( - b)}}{/tex}\xa0{tex}= \\frac{{ - y}}{{1 \\times ( - c) - ( - b) \\times a}}{/tex}\xa0{tex}= \\frac{1}{{1 \\times ( - b) - a \\times a}}{/tex}{tex}\\Rightarrow \\frac{x}{{ - ac - {b^2}}} = \\frac{{ - y}}{{ - c + ab}} = \\frac{1}{{ - b - {a^2}}}{/tex}Now,{tex}\\frac{x}{{ - ac - {b^2}}} = \\frac{1}{{ - b - {a^2}}}{/tex}{tex}\\Rightarrow x = \\frac{{ - ac - {b^2}}}{{ - b - {a^2}}}{/tex}{tex}\\Rightarrow x = \\frac{{ - \\left( {{b^2} + ac} \\right)}}{{ - \\left( {{a^2} + b} \\right)}}{/tex}{tex} = \\frac{{{b^2} + ac}}{{{a^2} + b}}{/tex}and,{tex}\\frac{{ - y}}{{ - c + ab}} = \\frac{1}{{ - b - {a^2}}}{/tex}{tex} \\Rightarrow - y = \\frac{{ab - c}}{{ - \\left( {{a^2} + b} \\right)}}{/tex}{tex} \\Rightarrow y = \\frac{{ab - c}}{{{a^2} + b}}{/tex}Hence, {tex}x = \\frac{{ac + {b^2}}}{{{a^2} + b}},y = \\frac{{ab - c}}{{{a^2} + b}}{/tex}\xa0is the solution of the given system of the equations. | |
| 3114. |
If [email\xa0protected]@=l ,[email\xa0protected]@=m.....Then prove that......(lsquare+msquare+3)=1 |
| Answer» | |
| 3115. |
What should we write to prove that a parallelogram is a rectangle |
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Answer» Each angle should be 90° A parellogram is said to be rectangle, when its opposite sides are equal and diagonals are also equal |
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| 3116. |
RIMSHA kb aaogi yrr |
| Answer» | |
| 3117. |
Trigonometrical |
| Answer» | |
| 3118. |
Date sheet of class 10 |
| Answer» Jan ke fst week me release hogi | |
| 3119. |
Formula of Tenomentri |
| Answer» | |
| 3120. |
What is formula for segment of circle? |
| Answer» \xa0Area of a\xa0Segment\xa0in Radians. A = (1⁄2) × r2\xa0(θ – Sin θ)Area of a Segment\xa0in Degrees. A = (½) × r\xa02\xa0× [(π/180) θ – sin θ] | |
| 3121. |
The ratio of the sum of n term of two AP is 7n+1:4n+24 find the ratio of their mth term |
| Answer» Let a, and A be the first terms and d and D be the common difference of two A.PsThen, according to the question,{tex}\\frac { S _ { n } } { S _ { n } ^ { \\prime } } = \\frac { \\frac { n } { 2 } [ 2 a + ( n - 1 ) d ] } { \\frac { n } { 2 } [ 2 A + ( n - 1 ) D ] } = \\frac { 7 n + 1 } { 4 n + 27 }{/tex}or,\xa0{tex}\\frac { 2 a + ( n - 1 ) d } { 2 A + ( n - 1 ) D } = \\frac { 7 n + 1 } { 4 n + 27 }{/tex}or,{tex}\\frac { a + \\left( \\frac { n - 1 } { 2 } \\right) d } { A + \\left( \\frac { n - 1 } { 2 } \\right) D } = \\frac { 7 n + 1 } { 4 n + 27 }{/tex}Putting,\xa0{tex}\\frac { n - 1 } { 2 } = m - 1{/tex}{tex}n-1 = 2m - 2{/tex}{tex}n= 2m - 2 + 1{/tex}or, {tex}n = 2m - 1{/tex}{tex}\\frac { a + ( m - 1 ) d } { A + ( m - 1 ) D } = \\frac { 7 ( 2 m - 1 ) + 1 } { 4 ( 2 m - 1 ) + 27 }{/tex}{tex}\\frac { a + ( m - 1 ) d } { A + ( m - 1 ) D } = \\frac { 14 m - 7 + 1 } { 8 m - 4 + 27 }{/tex}{tex}\\frac { a + ( m - 1 ) d } { A + ( m - 1 ) D } = \\frac { 14 m - 6 } { 8 m + 23 }{/tex}Hence,\xa0{tex}\\frac { a _ { m } } { A _ { m } } = \\frac { 14 m - 6 } { 8 m + 23 }{/tex} | |
| 3122. |
In triangle abc right angled at B and BC + AC=14 cm and AB 6 cm find value of tanA÷1-sin^2A. |
| Answer» | |
| 3123. |
State the fundamental theorem of arithmetic. |
| Answer» +,_,×,÷. | |
| 3124. |
√3+√3=? |
| Answer» 2√3 | |
| 3125. |
What a=77to the power 77 refers |
| Answer» | |
| 3126. |
How to find modal |
| Answer» | |
| 3127. |
if fi is 15 and fixi is 3p+36 and mean is 3 |
| Answer» P=3 | |
| 3128. |
Probability of getting 54 Sundays in a leap year |
| Answer» 52 weeks +2 days The 2 days can be (sun,mon)(mon, Tues)(Tues,wed)(we\'d, Thurs)(Thurs,Fri)(Fri,sat)(sat,sun)P(getting 54 Sundays in a leap year)=2/7 | |
| 3129. |
16+44 |
| Answer» 60 | |
| 3130. |
Diff between hcf lcm |
| Answer» | |
| 3131. |
2017 paper coming from ncrt book or reference books |
| Answer» most probably ncert | |
| 3132. |
X3+13x2+x-2 divide by 2x+2 |
| Answer» | |
| 3133. |
CSA of hemisphere |
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Answer» 2 π r×r 2pie r2 2πr^2 |
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| 3134. |
37 |
| Answer» Infinity.... | |
| 3135. |
Ek samanter shreni me 11th pad ,4th pad se 14 jayada hai samanya antr gyaat kre |
| Answer» | |
| 3136. |
Which question bank is best for preparetion? |
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Answer» Math:P.K.Garg. Science: u-like. social science: Kundra and bawa Oswall sample paper ? Crown and arihant sample papers |
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| 3137. |
Why sin of any acute angle triangle is always less than one????? |
| Answer» Because the value of sin 90° is 1 and actute angle is less than 90° | |
| 3138. |
sintita |
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Answer» perpendicular /hypotenuos Perpendicular / Hypotenuse Perpendicular /hypotenuse |
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| 3139. |
Solve equation :px+qy=p-qqx-py=p+q |
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Answer» By cross multiplication method se solve ho jayega X=1,Y=-1 |
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| 3140. |
Cot(a+b) Formula |
| Answer» Cot(a)cot(b)-1/cot(a)+cot(b). | |
| 3141. |
Sec(a+b) Formula |
| Answer» sec(a+b)=1/cos (a+b) | |
| 3142. |
√12%of 1/2 of 24of4 |
| Answer» | |
| 3143. |
Formula for cosec (a+b) |
| Answer» cosAcosB+sinAsinB | |
| 3144. |
How r u 2day |
| Answer» Bhadiya | |
| 3145. |
Explain how we do completing square method |
| Answer» | |
| 3146. |
Find the sum of the following AP x-y/x+y, 3x-2y/x+y, 5x-3y/x+y ,......to n terms |
| Answer» The given terms of arithmatic progression are{tex}\\frac { x - y } { x + y } , \\frac { 3 x - 2 y } { x + y } , \\frac { 5 x - 3 y } { x + y } , \\ldots{/tex} to n terms.First term(a)\xa0=\xa0{tex}\\frac { x - y } { x + y }{/tex}Common difference(d)\xa0=\xa0{tex}\\frac { 3 x - 2 y } { x + y } - \\frac { x - y } { x + y }{/tex}{tex}= \\frac { 3 x - 2 y - x + y } { x + y }{/tex}{tex}= \\frac { 2 x - y } { x + y }{/tex}\xa0Also we know thatSum of n terms (Sn) =\xa0{tex}\\frac { n } { 2 } [ 2 a + ( n - 1 ) d ]{/tex}{tex}= \\frac { n } { 2 } \\left[ 2 \\times \\left( \\frac { x - y } { x + y } \\right) + ( n - 1 ) \\left( \\frac { 2 x - y } { x + y } \\right) \\right]{/tex}{tex}= \\frac { n } { 2 } \\times \\frac { 1 } { x + y } [ 2 x - 2 y + ( n - 1 ) ( 2 x - y ) ]{/tex}{tex}= \\frac { n } { 2 ( x + y ) } [ 2 x - 2 y + 2 n x - n y - 2 x +y]{/tex}{tex}= \\frac { n } { 2 ( x + y ) } [ 2 n x - n y - y ]{/tex}{tex}{/tex} | |
| 3147. |
What is the answer if 9 having degree 0 |
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Answer» One 1 0 1 |
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| 3148. |
What is hcf 18 |
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Answer» 6 6 |
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| 3149. |
Water is flowing |
| Answer» Hi | |
| 3150. |
Diagram kaise draw karen yhan ? |
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Answer» Niche Jakarta dekhlo When?? To rudradeep us din Tumne kesse Kia tha No we can not draw diagrams here. |
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