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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 31301. |
Xam idea questions of chapter 4 |
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| 31302. |
Which book are best to cbse maths srandard |
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Answer» Ncert book ka koi faida nahi so, I suggest RD Sharma, NCERT Exampler and U like????????? Bese rs bhi achi h NCERT & rd According to me ... R.D .sharma best book of standard maths NCERT MATHS BOOK AND EXAMPLER |
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| 31303. |
What\'s formula Area of a triangle |
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Answer» 1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)) Wrong h.. Root 3 by 2 side square. ......... Nhi wrong h ye nhi h.... Root 3 by 4 a square 1/2*base*height Ye to mujhe bhi pta h 7th chapter wala btao .... 1/2(bh) |
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| 31304. |
if triangle PQR is right angled at P then value of cot (Q + R) is |
| Answer» 0 | |
| 31305. |
Water is flowing at the rate of 15km/hr through a pipe |
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| 31306. |
X square - 2 x + 1 equal to zero |
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Answer» x2 -2x + 1 = 0x2 - 1x - 1x + 1 = 0\xa0x ( x - 1) - a (x - 1) = 0(x - 1) (x - 1) = 0x - 1 = 0\xa0x = 1 X=1 |
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| 31307. |
For Practice give some problems on mean |
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| 31308. |
Tan/1-cot + cot/1-tan=cosec sec + 1 |
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| 31309. |
12.1 |
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| 31310. |
Prove the identity:-(tanA+coseB)^2-(cotB-secA)^2=2tanA.cotB(cosecA+secB) |
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| 31311. |
What is pai |
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| 31312. |
If four vertices of parallelogram are (1,2), (4,y), (x,6), (3,5) then find the value of xand y ? |
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| 31313. |
My question is how do I get 12chepter |
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| 31314. |
If the areas of two similar tringles are equal. Prove that they are congruent |
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Answer» Hai friend Without any given relation we are unable to find the answer |
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| 31315. |
A man goes 15 m due west and then 8m due north. How far is he from the starting point? |
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Answer» 289m How ❓ 17 m |
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| 31316. |
Find the 10th term from the end of the Ap 4,9,14,..........254 |
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Answer» 5 209 I think 49 4+45 4+9*5 A+9d |
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| 31317. |
If the circumference of two circles are equal then their areas are also equal. |
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Answer» Yes Yes |
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| 31318. |
x/x+1+x+1/x=34/15SOLVE AND X NOT EQUAL TO 0 OR -1 |
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| 31319. |
Use euclid division algorithm 1)125&32280 |
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| 31320. |
Find the value of α if the mode of data is 2015,20,25,18,13,15,25,15,18,17,20,25,20,α,18 |
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Answer» 15 Given mode = 20repeated 15,18,20,25 three timestherefore lambda = 20 |
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| 31321. |
If tan theta =1/2 and theta is an acute angle ,then prove that 1/2 sin theta cos theta =1/5 |
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Answer» Sorry....2/10 = 1/5. Tan theta = 1/2 = P/B. Now, by P.T , we get, Hypotenuse = √5. So, Sin theta = 1/√5 and cos theta = 2/√5. LHS = 1/2 sin theta × cos theta. 1/2 × 1/√5 × 2/√5 . 2/10 => 1/2 . Now, LHS = RHS. So, it\'s prove... |
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| 31322. |
If sin theta =m/n ,find value of tan theta +4/4cot +1 |
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| 31323. |
2+2= ??? |
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Answer» The answer of abhay chauhan is right....???? ????????????????????????????????????????????????????????????????????????????????????????????????Yes 8 4 ????? Accha pata ni..mai confirm ni hu No ankesh... 4 answer h ? Sayad 6 hoga ..bht tough h n...isliye conmfi ni h BC ye nahi pata. 5 Suhu sorry n 2 + 2 = 4 4 4? |
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| 31324. |
12th.exam.final date from |
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| 31325. |
In an AP the sum of m term is N and the end term is M. Prove that the sum of m + n terms is - M + n |
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| 31326. |
Use of math in life...don\'t take help from Google Baba ....give your opinion ???? |
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Answer» It was a bitter truth but ans is nothing ?. (Phir bhi sali pareshan karti hai)???????? ?? |
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| 31327. |
Need syllabus of basic maths |
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| 31328. |
Prove that pythagorus therorem |
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| 31329. |
Prove the root 5 is irrational |
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Answer» Let root 5 is a rational no. Root 5=p/q (where p and q are co prime)P=root5 qSquaring both sideP^2=5q^2 (let eqn. I)5 is a factor of q^25 is a factor of q also ,P= 5c for some integer cPut the value of eqn. ( 1 )5p^2=(5c)^25p^2=25c^2P^2=5c^25 is a factor of p^25 is a factor of p also,(Where p and q are integers )Therefore , our assumption is wrong Root 5 is irrational no. let root 5 be rationalthen it must in the form of p/q [q is not equal to 0][p and q are co-prime]root 5=p/q=> root 5 × q = psquaring on both sides=> 5 ×q ×q = p ×p ------> 1p ×p is divisible by 5p is divisible by 5p = 5c [c is a positive integer] [squaring on both sides ]p ×p = 25c ×c --------- > 2sub p ×p in 15 ×q ×q = 25 ×c ×cq ×q = 5 ×c ×c=> q is divisble by 5thus q and p have a common factor 5there is a contradictionas our assumsion p &q are co prime but it has a common factorso\xa0√5 is an irrational |
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| 31330. |
Where does the limit of step x is continuous |
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| 31331. |
Volume of the first term is 125 08.08.18 sakriy LCM and 20 cm find the height of the first term |
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| 31332. |
2x+y=-26y+2x=13Equate the equation |
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Answer» Yes answer not possible Answer not possible |
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| 31333. |
If p and q are prime positive integers prove that √p and √q is an irrational number |
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| 31334. |
The salary of an employee is 1550 for 24 working hours .calculate the salary for 30 hours. |
| Answer» 1990 | |
| 31335. |
If sinA=cosA then find the value of 2tanA+sin2a |
| Answer» 0 | |
| 31336. |
How to distinguish between the questions of linear equation and quadratic equation? |
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Answer» In linear equation higher degree =1 and in Quadratic equation higher degree =2 By the highest power |
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| 31337. |
If cos A+cos^2A=1,then the value of sin^2A+sin^4A is |
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Answer» CosA=1-Cos²A. ||. Cos A =Sin²A.......(1). ||. (CosA)+(Cos²A)=1. ......using (1). 1 |
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| 31338. |
If HCF of (26,169)=13,then LCM(26,169)is |
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Answer» 338 Product of 2 number = LCM × HCF => 26×169 = LCM × 13 => LCM = 4934 / 13 => LCM = 338. If cosA+cos^2A=1,then the value of sin^2A+sin^4A is Explain 13*x=26*169x=2*169x= 338x=lcm |
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| 31339. |
If the first three term of an A.P are b,c and 2b,then find the ratio of b and c |
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Answer» 2:3 c-b = 2b-c => 2c = 3b => b/c = 2/3 . So, the ratio between b and c is 2:3. |
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| 31340. |
Total surface area of cone |
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Answer» T.S.A of cone = πrl + πr² = πr (l+r). 2πr(r+h) Or koi Formula bhi launch krlo ? πr ( r+l) 2πr(h+r) |
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| 31341. |
Sin 60 is value |
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Answer» Root 3 /2 √3/2 90° √3/2 √3/2 The value of sin60 is √3/2. |
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| 31342. |
55+78 |
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Answer» 133 133!!!?? Oh...? Pata ni..maine bhi aise hi likh diya tha..? Hmm...?...vaise tumhe kha se answer mila...?? Maja aa gaya Baat shi h..? Areh.. Itna tough h to...kya hoga. .. ? Arey..aisa kaise..?? Na...? Aadya...?confirm ni h..? Actually...I\'m not confirm... But it may be 133... ???????????????????????????????????????????....Yes...May be...133 133 |
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| 31343. |
K sum |
| Answer» I think it is half question | |
| 31344. |
SinA/cosec-1+cosA/1+secA= sinA.cosA/sinA-cosA |
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| 31345. |
One marks ans give with explaintion necessary |
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Answer» No not that much Questions number 1 |
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| 31346. |
One marks ans give with explaination necessary |
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Answer» If u have time u can explain it No it is not necessary |
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| 31347. |
a+b2 |
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Answer» A2+2ab+b2 A2 + b2 +2ab |
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| 31348. |
What is the shape of coin |
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Answer» Cylindrical Thanks Circular Shape of coin is Cylindrical Thanks Cylindrical |
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| 31349. |
11.2 maths, question number 7. How we get the O |
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Answer» It\'s not zero it\'s angle of O variable ??????...Vo to construction ka question h...usme 0 kha se aa gya..? |
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| 31350. |
100-100÷100-100=2 #prove that #Dum hai to kar ke dikhaoo????? |
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Answer» Means well done Answer is (_1) ? Kya gajab...?? Are gajab Aadya singh LHS = (100-100)/(100-100) [(10)^2 - (10)^2]/10(10-10) [(10+10)(10-10)] / 10(10-10) 10+10/10 [Since,( 10 -10)gets cancelled by each other] 20/10 => 2 . Now, RHS = LHS...So, it\'s prove... Lo ji...ho gya prove....???? Answer 2 ayegya btau No Ans will be 1 |
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