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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 31351. |
tan90+sin90 +cose60= |
| Answer» Not defined?? | |
| 31352. |
In tiangleABC AB:20 cm BC:21 cm and AC:29 cm. Find the radius of circle |
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Answer» It is a complet question??? It\'s not a complete question C |
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| 31353. |
Prove that rectangle circumscribing the circle is the square |
| Answer» Circumscribing means circle is in the rectangle | |
| 31354. |
What is the probability that a leap year selected randomly will have 53 Sundays ? |
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Answer» Hmm 2/7 is the correct answer 2/7 2/7 The below answers are wrong. The probability for a leap year having 53 Sundays is 2/7. 1/7 1by 7 |
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| 31355. |
If the hcf of 65 and 117 is expressed in the form 65m_117,then |
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Answer» m = 2.. m=13 |
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| 31356. |
X+1/x-1 + x-2/x+2 = 4 - 2x+3/x-2 |
| Answer» Firstly solve into standard form ax^2+bx+c=0 then solve it | |
| 31357. |
TSA of cone |
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Answer» No yogita is somwhere wrong In which schl u study The Total surface area of a cone includes the curved surface as well as area of its base, which is given as-Base Area = πr2Curved Surface Area = πrlThus total surface area is given by- = πr2 + πrl = πrl (r + l) |
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| 31358. |
Uses of cube, cuboid,cone,frustum, cylinder in everyday life |
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| 31359. |
If tanA=8/15 Evaluate :(1+sinA)(2-2sinA)/(2+2cosA)(1-cosA) |
| Answer» 225/274 | |
| 31360. |
The value of k for which system of equation x+2y-3=0and 5x+ky+7=0has no |
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| 31361. |
pareshram aur abyash - safalt ki kunji ha |
| Answer» ,??,,,,???????? | |
| 31362. |
2018 paper cbse last year |
| Answer» | |
| 31363. |
Write the rational and irrational number lying between 0.25 and 0.32 |
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Answer» Rational Number =0.29Irrational Number=0.3165427439............ Rational No = 0.26 and irrational = 0.2602670 Rational number - 0.275 Irrational number - 0.277277727777..... |
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| 31364. |
Write the general form of an even integers |
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Answer» a=2q+rWhere r=0,1 2q 2q |
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| 31365. |
If the zeroes of the polynomial x3_3x2+x+1 are a-b,a,a+b,find a and b |
| Answer» a = 1 and b = √2... | |
| 31366. |
If -1 is a zero of the polynomial 2x cube -x square -5x -2Find its other zeroes |
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| 31367. |
Split 207 into 3part such that these are in AP and the product of the two smaller part is 4623 |
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| 31368. |
Define a circle . Find the circumference and area of a circle of radius r cm |
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Answer» A circle is a collection of all point in a plane which are at constant distance from a fixed point What is the answer |
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| 31369. |
P.T tanA / 1- cot A + cot A/1- tanA ,=1+ cotA+ tanA |
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| 31370. |
Blue print for maths cluster plzzzz.. |
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| 31371. |
4x22/7xr² = 2464 |
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Answer» R equal to root under 126 R is equal to 392 88/7(r2)=2464. r2=2464(7/88) r2=126 |
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| 31372. |
The tangent at any point of a circle is perpendicular to the radius through the point of contract. |
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| 31373. |
Find a quadratic polynomial whose one zero is 7 and sum of zeroes is -18 |
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Answer» Define polynomial x^2 + 11x -126. x^2+18x-175 X2+11x-126 |
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| 31374. |
If the pth term of an AP is q and qth term is p, prove that nth term is (p+q-n). |
| Answer» \xa0Let first term be a and common difference be d.pth term = a + (p-1)d = q -----(i)qth term = a\xa0+ (q-1)d = p -----(ii)(ii) - (i) gives(q - p)d = p - q or d = -1(i) gives a = q - (p-1)d = q - (p-1)(-1) = q + p - 1Hence,nth term = a + (n-1)d = q + p -1 + (n-1)(-1) = q + p -1 + n +1 = p + q - n | |
| 31375. |
Linear combination examples |
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| 31376. |
Which term of the ap 121,117,113... Is the first negative term |
| Answer» 32 term | |
| 31377. |
Project on displacement and rotation of geometrical figure |
| Answer» project on displacement and rotation of geometrical figure | |
| 31378. |
For the value of x .if the distance between the points A(0,0)&B(x,-4) is 5 units? |
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Answer» By distance formula √(x2-x1)square+(y2-y1)square is equal to distance between two coordinateBy appling this formula we find the value of x become distance 5 units so;√(x-0)square+(-4-0)square = 5 units√X square+16=5Squaring both side we getX square + 16 = 25 X square= 25-16X square=9X=√9X=3? The formula used to find the distance between two points is{tex}d = \\sqrt{(x2-x1)^{2}+(y2-y1)^{2} } Where,d = distance = 5\\\\(x1, y1) = First set of points, i.e A= (0,0)\\\\(x2, y2) = Second set of points i.e B= (x,-4)d = \\sqrt{(x2-x1)^{2}+(y2-y1)^{2} } \\\\ 5 = \\sqrt{(x-0)^{2}+(-4-0)^{2} } \\\\\\\\5 = \\sqrt{(x)^{2}+(-4)^{2} }\\\\\\\\Squaring both sides\\\\\\\\25 = x^{2} + 16\\\\\\\\25-16 = x^{2}\\\\\\\\9 = x^{2}\\\\\\\\x = 3{/tex} |
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| 31379. |
Xsquare -5x+6=0 |
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Answer» X: 3 and 2 x2 - 5x + 6 = 0x2 - 3x -2x + 6 = 0x(x - 3) - 2(x- 3) = 0(x - 3) = 0 or x - 2 = 0x = 3 or x = 2 |
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| 31380. |
X2-5x+6=0 |
| Answer» x2 - 5x + 6 = 0x2 - 3x -2x + 6 = 0x(x - 3) - 2(x- 3) = 0(x - 3) = 0 or x - 2 = 0x = 3 or x = 2 | |
| 31381. |
Si sin minus Cos y Sin A + Cos A + sin a + cos my minus minus cos squared minus one |
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| 31382. |
(. )+(. )+(. ):30Choose the number below: 11,13,15,17 |
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Answer» Put the number given Don\'t add anyone (11)+(15)+(17-13)= 30....Ab sahi h...? Where is 15adya singh all numbers are compulsory ?? (11) + (13)+(17-11) = 30... |
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| 31383. |
Prove that the quadrilateral circumscribing the circle is rhombus |
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| 31384. |
The largest number which divides 70 and 125 leaving reminders 5 and 8 respectively is, explain? |
| Answer» The largest number by which x , y divisible and gives the remainder a , and b is the HCF of ( x - a ) and ( y - b)__________________________According to the given problem ,The largest number which divides 70 and 125 leaving remainders 5 and 8 respectively areHCF of ( 70 - 5 ) = 65 and( 125 - 8 ) = 11765 = 5 × 13117 = 3 × 3 × 13HCF ( 65 , 117 ) = 13Required number is 13. | |
| 31385. |
The points (7,2) and (-1,0) lie on a liea) 7y=3x-7 b)4y=x+1c)y=7x+7 d)x=4y+1 |
| Answer» B | |
| 31386. |
Maths Exercise 6.3 qes.16 |
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| 31387. |
Prove that sec A (1-sin A ) ( sec A + tan A) =1 |
| Answer» SecA(1-sinA) (secA+tanA)=1/cosA(1-sinA) (1/cosA +sinA/cosA)=1/cosA(1-sinA) (1+sinA/cosA)=1/cosA(1-sinA) 1/cosA(1+sinA)=1/cos squareA (1-sin square A)=1/cos square A × cos square A=1 | |
| 31388. |
Q. In a triangle, AD is perpendicular to BC. Prove that AB square +CD square=ACsquate +BD square |
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| 31389. |
find k so that ×+2 is a factor of a 2x^3 +5x^2_kx+5 find k |
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| 31390. |
Statistics ch 14 |
| Answer» S | |
| 31391. |
2 underroot2 k whole square -4(1)(18)=0 |
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| 31392. |
Find the radius of the circle with circumstances 52 |
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Answer» Circumference=2×22×r=52×r 44r=52×7 44r=364. 364÷44=8.27unit Circumference =52. 2×22×r=52. 744r=52×744r=364R =364/44R=8.27 units Circumference hoga shayad2 ×22\\7 ×r =52 r= 52×7/ 2× 22 r= 8.27 units approx. |
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| 31393. |
In a circle of radius 21cm,an arc subtends an angle of 60degree at to centre |
| Answer» Area 231cm | |
| 31394. |
Chapre 9 example 6 |
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| 31395. |
what are the disadvantages of choosing basic mathematics |
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Answer» U have to write contemporary exam to opt maths even though taking basic Cant opt for maths in future You can take commerce and science but u cant take maths (PCM) in future By choosing basic maths you cannot take Commerce and Science for future studies |
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| 31396. |
What is absolute value |
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| 31397. |
Meaning of total radiating surface |
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| 31398. |
Last year class 10 questions paper |
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| 31399. |
If the arithmetic mean of x,x+3,x+6,x+9,andx+12is10,thex= |
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Answer» S they r in AP Thoda lenthy hai isliye typing se nhi ho paega Bhai dono ke d ko equal me rkh do ans aa jawga |
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| 31400. |
,mind map polynomial |
| Answer» See in osawal | |