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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 31401. |
given triangle abc similar to triangle def find triangle abc /triangle def |
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| 31402. |
Explain me covalent and ionic bond✍️✍️✍️✍️✍️???? |
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Answer» It is science question Koi online h kyaaaa Hi.. Sing*** kiski id hain Hello frnds...and sis....i am out of my house...i will.come after 1 hrs.... Hlw queen? Hi Electromagnet answer do u know any one Hi The bond formed by sharing of eletron between atoms called ionic bond and the bond formed by sharing of electron between two atoms called covalent bond. Btw aapka naam? No I Don\'t u Do u know me Diksha? Good afternoon all Good afternoon miss? Good Afternoon ? When two elements form compounds by sharing electrons with each other,they are said to form covqlent comounds. The bond present between them is called covalent bond. When two elements form compounds in such a way that one of the elements gain electron(s) and the other loses electrons,they are said to form ionic compounds. The bond which is present between them is called ionic bond. |
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| 31403. |
Which chapter is most important in maths (standard) for board exam 2019-2020 |
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Answer» Tri, ap, stas and cir Circle Triconometry, SA n volumes Triangle All ar important Mensuration |
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| 31404. |
What is the hcf of smallest composite and prime number |
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Answer» Smallest prime number = 2Smallest composite number = 42 = 2\xa0× 14 =\xa02\xa0× 4HCF(2, 4) = 2 H.C.F of two smallest composite numbers is 2 nd H.C.F of two prime numbers is 1 |
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| 31405. |
What is the probability of impossible event |
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Answer» 0 0 0 0 Nice 0 0 |
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| 31406. |
What is the probability of sure ivent |
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Answer» 1 Nice 1 |
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| 31407. |
Formula of Area of triangle of ch 7 |
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Answer» Nice? 1/2[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)].. |
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| 31408. |
Given that HCF(306,657)=9, find LCM(306,657)=? |
| Answer» 22338 | |
| 31409. |
Solve the pair of equations : 8x+7y/xy=15 and 7x-2y/xy=5 where x, y, ≠0 |
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Answer» Value of X=1and Y=1 8x+7y/xy=15 and 7x-2y/xy=58x+7x=15 and 7x-2x=515x=15 and 5x=5x=1 and x=1Putting x=1 in eq.(1)8x+7y/xy=158x+7y=15xy8×1+7y=15×1×y8+7y=15y8=15y-7y8=8yy=1Hence x=1 and y=1 . |
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| 31410. |
Find the ratio in which the y axis divides the line segment joining the points (4,-6) and (-7,-4) |
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Answer» Let,A(4,-6) ,B(0,y) and C(-7,-4).AB=X1=4,Y1=-6 ,BC=X1=0,Y1=Y X2=0,Y2=y , X2=-7,Y2=-4 AB=BC(0-4) ² +(Y-6)²=(-7-0)²+(-4-Y)²16+Y²+36+2×Y×6=49 +16+y²-2×-4×-y16+y²+36+12y=49+16+y²+8y52+y²+12y=55+ý²-8y Pg 166 example 9 You can take help from book |
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| 31411. |
What is biquadratic |
| Answer» A quadratic equation which have degree 4 is called as Biquadartic equation. | |
| 31412. |
In triangle ABC , write sin A+B/2in terms of angle C |
| Answer» We know that in triangle ABCAngle (A + B + C) = 180Transfer angle on right side,Angle(A+B) = 180- Angle CDividing 2 on both side , we getAngle(A+B)/2 = 90 - Angle C/2Multiply sin on both sidesin A+B/2 = sin(90-C/2)sin A + B/2 = cos C/2 | |
| 31413. |
If S7=49 and S17=289 then find Sum of n terms. |
| Answer» Formula of first n terms in AP = {tex}S_n = \\frac{n}{2}(2a+(n-1)d){/tex}Substitute n = 7So,{tex} S_7 = \\frac{7}{2}(2a+6d){/tex}{tex}49 = \\frac{7}{2}(2a+6d){/tex}{tex}49 \\times \\frac{2}{7} = 2a+6d{/tex}14= 2a+6dSubstitute n = 17{tex}S_{17} = \\frac{17}{2}(2a+16d){/tex}{tex}289 = \\frac{17}{2}(2a+16d){/tex}{tex}289 \\times \\frac{2}{17} = 2a+16d{/tex}34= 2a+16d34= 2a+10d+6dUsing A34= 14+10d20 = 10dd=2Substitute the value of d in A14= 2a+122= 2aa=1So,\xa0{tex} S_n = \\frac{n}{2}(2(1)+(n-1)2){/tex}{tex}S_n = \\frac{n}{2}(2+(n-1)2){/tex}\xa0 | |
| 31414. |
the points (7,2)and (-1,0) lie on a line ? |
| Answer» The given points are (7, 2) and (-1, 0)The slope of the line is given by{tex}m=\\frac{y_2-y_1}{x_2-x-1}{/tex}Substituting the values{tex}m=\\frac{0-2}{-1-7}\\\\\\\\m=\\frac{-2}{-8}\\\\\\\\m=\\frac{1}{4}{/tex}Point slope form of a line is given by{tex}y-y_1=m(x-x_1)\\\\\\\\y-2=\\frac{1}{4}(x-7)\\\\\\\\4y-8=x-7\\\\\\\\4y=x+1{/tex}\xa0 | |
| 31415. |
Nature of root |
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Answer» And If D<0,then no real roots If D>0 ,then real and different rootsIf D=0 ,then real and equal roots |
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| 31416. |
To prove fundamental theorem of arthematic |
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| 31417. |
the given term a, b and c are in ap the sum of given ap is 22 and a×b×c=1155 find a, b and c |
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| 31418. |
The pth term of an A.P is 1/7 (2p-1). Find the sum of its first n terms |
| Answer» Aap AP mein se hi itne sum Kyon solve karti ho | |
| 31419. |
cos38° cos52° - sin38° sin52° =0 |
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Answer» Yes answer is zero Ncert solution m h 1/1+sin square A+1/1+cos squareA+1/1+sec square A+1/1+cos square A=2 RHS Cos 38* cos 52* --- sin 38* sin 52*Cos(90-52) cos (90-38) - sin 38* - sin52*Sin 52* × sin38* - sin 38 * - sin 52* = 0 therefore, LHS=RHS=0 hum ques ko iss form me likh skte h....becoz of identity that sin theta= cos(90°-theta)....sin52°sin38°-sin38°sin52°=0 |
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| 31420. |
Is there any difference between perimeter and circumference of a circle of radius ,r |
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Answer» Mathematically there is no difference but there may be any difference due to English grammar. No there is not any diff. Between circumference and perimeter No, perimeter is circumferance of circle. |
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| 31421. |
How to learn volumes and surface areas formulas?? |
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| 31422. |
(sin*/cosec*-1)+(cos*/1+sec*)=sin*cos*/sin*-cos* |
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| 31423. |
Write the area of semi circle of diameter |
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Answer» πd^2/4 Sorry area would be pie r sq./ 2 Pie r + 2 r |
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| 31424. |
Write the area of semi circle of diameter \'d\'? |
| Answer» Area of circle = πR2Area of cemicircle =1/2 πR2 = 1/4 π(R) x (2R) =1/4 πR2\xa0= πD2/4 | |
| 31425. |
The value of k for which the system of equation is 2x+y-3=0 and 5x+ky+7=0 is incostistant is |
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| 31426. |
The LCM of smallest two digit composite number and smallest composite number isA) 12B) 4C) 20D) 44 |
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Answer» 2 Smallest 2 digit composite number = 10 Smallest composite number = 4 So, LCM = 20... 4 How can you give me the solution for this answer C)20 |
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| 31427. |
Express 65 and 117 in the form of 65m and 117n |
| Answer» M = 2 and n = -1 | |
| 31428. |
A bicycle be makes 5000 revolution in moving 11km.Find diameter of a wheel ? |
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Answer» D=70cm 2πr×5000=11000mSo πr=11000÷10000=11/10mr=11×7/10×22=7/20mr=7/20m |
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| 31429. |
Pythagoras prove |
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| 31430. |
What is the value of cos 90 degrwe |
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Answer» 0 0 0 0 |
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| 31431. |
(Sec A + tan A -1 ) (Sec A - tan A +1 ) = 2 tan A |
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Answer» Question is wrong lhs=2 not 2tanA 1+2tanA -1 => 2 tanA.. LHS - (SecA)^2 - (tanA-1)^2 Sec^2A - (tan^2 - 2tanA+ 1) Sec^2A - tan^2A + 2tanA - 1 1+2tanA -1 Now, LHS = RHS. So, it\'s prove.. |
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| 31432. |
Maths AP main question |
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Answer» From this chapter ques of 3marks only came 5.3 q4 to 20 main and 5.3 q3 4 mark q very main |
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| 31433. |
Find the lcm 200 |
| Answer» 2×2×2×5×5 | |
| 31434. |
X2+4k+k |
| Answer» X2+5k | |
| 31435. |
The nth term of an ap is 2n + 1 then the sum of n terms of an ap is |
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Answer» n(n+2) An= 2n+1If n=1, than A1(first term of AP)= 2×1+1=3A2= 2×2+1= 5From A1 and A2 we can get common difference=5-3=2Sum of n terms =(n/2)[2a+(n-1)d]=(n/2)[2×3+(n-1)2]=(n/2)[6+2n-2]=(n/2)[4+2n]=(n/2)×2[2+n]=n(2+n)=n^2+2n |
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| 31436. |
A30-a200 of term of ap 3,7,10 |
| Answer» -680 | |
| 31437. |
To verify euclid division lemma |
| Answer» LCM(a × b) × HCF(a ×b) = a×b | |
| 31438. |
Leaders set high standards. Refuse to tolerate mediocrity or poor performance......singh pk? |
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Answer» ?????? Olay ke or the ke to it that w?????????????????????????????????????????????????????????????\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d??\u200d?????????????????????????????????????\u200d?????????????☺️???????®️®️5️⃣⏮️↔️®️®️5️⃣??????????????????⛷️????⛷️⛷️?⛷️?⛷️?⛷️?⛷️????????????️??️??️?\u200d❤️\u200d?\u200d??️?\u200d❤️\u200d?\u200d??️?\u200d❤️\u200d?\u200d???\u200d❤️\u200d?\u200d???\u200d?\u200d?\u200d??️?\u200d❤️\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d??\u200d?\u200d????????????????????????????????????????????????????????️???????????????????????⛑️??????????????????????????????????????️???️?️??️??️??️??️??️?????????????????????????????????????????????????jhhjhjjfjjjhjwkujhhjtjtjtjy the same? you have received?y?????jrhru Jkwwbywjwubwjwtjwkwywjhj?????☺️??☺️???????????jj???????????????????? Yeah ? ??? |
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| 31439. |
Construction circle |
| Answer» ?? | |
| 31440. |
The 4th term of AP is 14 and its 8th term is 30 . Find its first term and the last term |
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Answer» A=2 and D=4?? a + 3d = 14 ------(1) , a+7d = 30-----(2). Solve, both the equations, yoy will get the answer.. |
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| 31441. |
Blue print mill gaya kya |
| Answer» Standrad or basic | |
| 31442. |
What is emperical probability?? |
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Answer» Jab net chalega.?? Bye ....phir kb aaogi Brainly v ni chl ra.... Are wo to mere m vi ho ra h....an error occurred ?? Bye.. Ab ye bhi ni chl rha..? Ha..kr rhi..??ho ni rha.. Ok try kro.... Mere me nhi na ho rha..?net slow h Mne photo change kiya h Ho jyega show Oh..mere me kuch ni show kr rha..?? Hooo gya....wapas aao kr liya mne follow Kya hua Ok..try krti hu Avi mere profile m ladki ka photo h Haan....to live questions pr aao.....agar mai dikhu to mere ko touch kr dena...... Shreyad2400...new h bilkul..? To tumhara id.....??? Ha..? Brainly download kiya..... Good morning shreyas-s=Shreya ☺️☺️ Good morning..? Bye ☺️ Koi baat ni acha socho acha hi hoga ☺️☺️ Best of luck..thanku..pr mera luck ni accha.. Bye...☺️☺️ Best of luck for ur paper ☺️ Acha kl 15 min k liye aa jana 8:30 am.....brainly download kr k photo dekh lena meta..... Bye..good night..sweet dreams..take care..? Or..9 ko aungi..reason toh pata hi hoga na.. 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Hmm..kuch bhi keh lo..pr abhi time ni h..itna pakka h.. Tbtk k liye m tujhe kya bulau ?? Wse shreyas-s=Shreya apna time avi ni aaya h...pr apna v time aayega......baad m hi sahi..... Ha..ha..doctor jo ban jaoge..? Wo to m hu hiiii ????good boy.. Haan bach kr hi rhta hu.... Ha...toh phir gusse se bach ke rehna..? Haan pta h tera gussa ????? Unme se m vi hu na....trust krne walo pe....wo v special wala Ha..maine socha warning de du..mere gusse ka toh pata hi h..? Haan thik h...le lena badla ?? pr m kuch bura karunga hi ni... Trust krti hu..pr ab kum..yaha h kuch besties jinpe trust h mujhe..?..jo samajhte h mujhe.. Ohh...?hurt kroge bhi..toh bachoge ni baad me..??badla mai leke rahungi jo hurt krega...abhi ni toh future me..??? Haan baat to shi h name hi unique h hmara......mtlb dono ka☺️ Mujhpe pakka wala trust kr skti ho tum.....i will try to never hurt u..... Na..apko kaise bhulenge..name hi aisa h apka..? Toh phir..sahi bola na maine..? Pr bhulna ni mujhe Haan haan m v yhi soch rha tha.......chalo baat to bilkul sahi h...☺️☺️❤ Daro mat..simple reasons h..or ek reh gya...ab zyada trust ni krti mai kisi pe..it hurts too much.. Hmmm...suno..Padhai disturb hogi..abhi age bhi ni h ....maine besties ko promise kr rkha h galat ni krungi...parents ka trust ...apne mujhe dekha bhi ni h... Khatarnak reasons h kya???? Haan Batau reason...? What reasons Frnd toh ho na....or na bolne ke reasons h mere pass..?okk..?I hope smjh jaoge.. Kya nhi Ohh...nhi Koi baat ni .....its okay ☺️☺️ Mai to haan hi soch rha tha.....because tu confused thi....?? Jo pehle tha.. Answer..kya sunna chahte ho..?? Answer socha tanne.....Shreya Oh..? Ni phle bi padh ra tha???? Badi jaldi aa gye...??bht zyada padh liya.. Hii Oh..?? Tune jo dopher me answer diya tha....u were little bit confused...so think about that again pls pls my special friend shreyas-s=Shreya Ok.. I will b here after 15 mins Empirical probability can be defined as the number of outcomes in which a specified event occurs to the total number of trials. |
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| 31443. |
What is ythe formula of polynomial |
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| 31444. |
Class10 lab activity 13 Introduction of Trigonometry observations |
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| 31445. |
The product of the zeroes of -2xx+kx+6 |
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| 31446. |
Prove that a rectangular circumscribing a circle is a square |
| Answer» Diagram toh nhi kar sakti...Given: abcd is a rectangle circumscribing a circle.Ab = dcAd=bcYe do eq. One h.....reason (opposite sides of rectangle r equal)To PT: abcd is a sq.Proof: Tangents frm an external points to the circle are equal.Therefore,ap=as.......eq 2Bp=bq...........eq 3Dr=ds.......eq 3Cr=cq.........eq 4By adding these equationsAb+bp+dr+cr=as+bq+ds+cqAb+bp+dr+cr=as+ds+bq+cqAb+dc=ad+bcAb+ab=ad+ad(from eq 1)2ab=2adAb=adHence proved | |
| 31447. |
Show that the points (4,2), (7,5) and (9,7) are collinear |
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Answer» 1/2{4(5-7)+7(7-2)+9(2-5)1/2{-8+35-27}1/2×0=0 1/2[4(5-7)+7(7-2)+9(2-5)]=0 |
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| 31448. |
Easy method to find square root |
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Answer» U can find the method in 8 class maths book Better to search on goggle Yes |
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| 31449. |
If the points (-2,-1),(1,0),(x,3) and (3,y) form a parallelogram fond the value of x and y |
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Answer» And bisect each other at o p (x y)=-2+x/2;-1+3/2=-2+x/2;2/2=-2+x/2;1 From point A and C since pxy is the mid point of AC From point B and D p(xy )=3+1/2;y+0/2=2;y+0/2-2+x/2=2Y+0/2=1On. Solving this equation we get x=2, y=2 Let ABCD is a parallelogram |
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| 31450. |
Formulas of chapter 3 |
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