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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3151. |
Evaluate: sin^6 theta-cos^6theta |
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| 3152. |
X^2 _ 2x_8 |
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| 3153. |
SinA-cosA+1/sinA+cisA-1 |
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| 3154. |
How can I post the figure of the Q? |
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| 3155. |
What is the first term of an ap whose sum =658 |
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| 3156. |
Find the perimeter of on equilateral having one of its sides as 2m+3n metres |
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| 3157. |
If alpha and beta are the zeros of quadritic polynomial then prove that |
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| 3158. |
2^2001 + 2^1999 whole ÷ by 2^2000 - 2^1998 |
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| 3159. |
Frustum |
| Answer» When one cone is cut from anywhere parallel to its base then the shape so formed after being cut is known as frustum . ex :- shape of bucket | |
| 3160. |
Is there anyone to talk |
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| 3161. |
What is an arithmetic progression |
| Answer» In mathematics, an arithmetic progression (AP) or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant | |
| 3162. |
Sb apni school ka name btao |
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| 3163. |
When the board exam held |
| Answer» You can check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 3164. |
Find the coordinates of the point in y axis which is nearest to the point (-2,5) |
| Answer» the point is (0,5) | |
| 3165. |
The radi of large circular cone that can be cut out of edge 4.2cm is |
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Answer» 2.1cm 2.1 |
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| 3166. |
For what values of K will the following pair of linear equation have infinitely many solutions? |
| Answer» Equation kya hai? | |
| 3167. |
512cube of which |
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Answer» 8,,,,,,,, 8 8 8.... 8 |
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| 3168. |
Which sample paper book is good for class 10 |
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| 3169. |
Aryaveer where r u |
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| 3170. |
By using the method of completing the square show that the equation 2x2+x+4=0 has no real roots |
| Answer» We have, 2x2 + x + 4 = 0Dividing both sides by 2, we get{tex}x^2 +{1 \\over 2}x + 2 = 0 {/tex}{tex}\\implies (x)^2 + {1 \\over 2}x + {1 \\over 16} = -2 + {1 \\over 16}{/tex}{tex}\\implies (x)^2 + 2(x) ({1 \\over 4})+ ({1 \\over4})^2= {- 32 +1 \\over 16}{/tex}{tex}\\implies (x + {1 \\over4})^2 = -{31 \\over 16} <0{/tex}Which is not possible, as square cannot be negative.So, there is no real value of x which satisfy the given equation.Therefore, the given equation has no real roots. | |
| 3171. |
what do you mean by fundamental theorem of arithmetic |
| Answer» Every composite number can be expressed as a product of its primes, and this factorisation is unique apart from the order in which it occurs | |
| 3172. |
Why is 2*2=4 |
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| 3173. |
The roots of the equation are xsq.p(p+1)=0where p is constant |
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| 3174. |
Hello guys... |
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| 3175. |
a÷x-a+b÷x-a=2 find x in terms of a and b |
| Answer» The given equation can be rewritten as{tex}\\frac { a ( x - a ) + b ( x - b ) } { ( x - b ) ( x - a ) } = 2{/tex}a(x -a) + b(x- b) = 2[x2 - (a + b)x + ab]ax- a2\xa0+ bx - b2 = 2x2- 2(a + b)x + 2ab2x2- 3(a + b)x + (a + b)2 = 02x2 - 2(a + b) x - (a + b)x + (a + b)2 = 0{tex}2x[x-(a+b)]-(a+b)[x-(a+b)]{/tex}[2x - (a + b)] [x - (a + b)] = 0{tex}x = a + b , \\frac { a + b } { 2 }{/tex} | |
| 3176. |
RIMSHA yahan aao |
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| 3177. |
Find the value of k , if the quadratic equation 3x^2 -k √3 X + 4 =0 has equal root |
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| 3178. |
RIMSHA come yrr |
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| 3179. |
FactoriseZeroes quadratic equation and verify |
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| 3180. |
write 23.426 in the foem of p/q |
| Answer» 11713/500 | |
| 3181. |
2/10=2 prove in mental math |
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Answer» Two/Ten T and t cancelThen w+o/e+n=23+15/5+1438/19=2 Proved 2/10=2/1 or 2/0 ;2/0 is not applicable so 2/1 =2 |
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| 3182. |
Jai ho |
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| 3183. |
in an ap, the sum of first n terms is 3n^2/2+5n/2. find its 25th term. |
| Answer» According to the question,we are given that,\xa0{tex}S _ { n } = \\frac { 3 n ^ { 2 } } { 2 } + \\frac { 5 n } { 2 } = \\frac { 3 n ^ { 2 } + 5 n } { 2 }{/tex}{tex}\\Rightarrow S _ { n - 1 } = \\frac { 3 ( n - 1 ) ^ { 2 } + 5 ( n - 1 ) } { 2 }{/tex}{tex}= \\frac { 3 \\left( n ^ { 2 } - 2 n + 1 \\right) + 5 n - 5 } { 2 }{/tex}{tex}= \\frac { 3 n ^ { 2 } - 6 n + 3 + 5 n - 5 } { 2 }{/tex}{tex}= \\frac { 3 n ^ { 2 } - n - 2 } { 2 }{/tex}Now,nth term = Tn=Sn-Sn-1={tex}= \\frac { 3 n ^ { 2 } + 5 n } { 2 } - \\frac { 3 n ^ { 2 } - n - 2 } { 2 } = \\frac { 3 n ^ { 2 } + 5 n - 3 n ^ { 2 } + n + 2 } { 2 }{/tex}={tex}\\frac{{6n + 2}}{2}{/tex}=3n+125th term=T25=3(25)+1=75+1=76. | |
| 3184. |
Perimeter of sphere |
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Answer» 0 no boundaries no edges 4πr^2 |
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| 3185. |
RIMSHA kahan ho aap |
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| 3186. |
Hi riya |
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| 3187. |
What is the completing squar method |
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| 3188. |
(cosecA - sinA) (secA - cos A) = 1/tanA +cotA |
| Answer» We haveL.H.S. =\xa0(cosecA - sinA)(secA - cosA){tex}= \\left( \\frac { 1 } { \\sin A } - \\sin A \\right) \\left( \\frac { 1 } { \\cos A } - \\cos A \\right) = \\left( \\frac { 1 - \\sin ^ { 2 } A } { \\sin A } \\right) \\cdot \\left( \\frac { 1 - \\cos ^ { 2 } A } { \\cos A } \\right){/tex}{tex}= \\frac { \\cos ^ { 2 } A \\sin ^ { 2 } A } { \\cos A \\sin A }{/tex}\xa0= cosA.sinA.R.H.S. =\xa0{tex}\\frac { 1 } { ( \\tan A + \\cot A ) } = \\frac { 1 } { \\left( \\frac { \\sin A } { \\cos A } + \\frac { \\cos A } { \\sin A } \\right) }{/tex}{tex}= \\frac { \\cos A \\sin A } { \\left( \\sin ^ { 2 } A + \\cos ^ { 2 } A \\right) } = \\cos A \\sin A{/tex}\xa0[{tex}\\because{/tex} sin2A + cos2A = 1]Hence, L.H.S. = R.H.S. | |
| 3189. |
If the sum of first n terms of an A.P is given by Sn=4n×4n-3n then find the nth term of an A.P |
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| 3190. |
Minimam value of 1/secA |
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Answer» 0 0 |
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| 3191. |
Minimam value of sinA |
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| 3192. |
Minimam value of cosA |
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| 3193. |
/2+/3 is irrational |
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| 3194. |
If secA =x+1/4x ,then prove that secA+tanA=2x or 1/2x |
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| 3195. |
What is tangent explain |
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| 3196. |
If -½ is one root of quadratic equation 2x²+Kx+1=0,Find k. |
| Answer» k=-3 | |
| 3197. |
Capter15(provality) question no. 20 ncrt book |
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Answer» π/24 This app is for ncert solution only. |
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| 3198. |
Can you please give me latest blue print of mathematics given by CBSE |
| Answer» Refer google or this app | |
| 3199. |
Good morning frnds ..... Mera toh Abhi hua h aur abh ka.....??? |
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| 3200. |
Solve for x : ax2+(4a2-3b)x-12ab=0 |
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